HELP PLEASE WITH THESE IM SO LOST AND NEED HELP! 1-4!

Answer:

True

Step-by-step explanation:

When conducting Analysis of Variance test (ANOVA) ; our hypothesis are stated as follows ;

The null hypothesis; H0 ; stats that there is no difference in means between any of the population ;

H0 : μ1 = μ2

While the alternative hypothesis which is the opposite of the null hypothesis will be of the claim that ; atleast one of the population means is different from another.

Hence, once there is sufficient evidence to indicate that atleast one of the population means is different from another, then we reject the Null.

Step-by-step explanation:

foctorized 990 = 9×10×11

so, (X+2)(X+3)(X+4)=9×10×11

we can choose one of the factors, and get the answer with the same x values

x+2 = 9 , => x =7

x+3 = 10, => x = 7

x+4 = 11, => x = 7

Answer:

30.00×.06=1.8+30.00=31.8

Answer:

2 -> 3

14 -> -3

7 -> -2

-1 -> 2

Step-by-step explanation:

Given the function

f(x) = x² - 2x - 1

If x = 2

f(x) = 2² - 2(2) - 1

f(x) = 4 - 4 - 1

f(x) = -1

If x = -2

f(x) = (-2)² - 2(-2) - 1

f(x) = 4 + 4 - 1

f(x) = 7

If x = 3

f(x) = 3² - 2(3) - 1

f(x) = 9 - 6 - 1

f(x) = 2

If x = -3

f(x) = (-3)² - 2(-3) - 1

f(x) = 9 + 6 - 1

f(x) = 14

Answer:

20

Step-by-step explanation:

i dont know

look it up

Answer:

a. There are 1365 choices of eleven questions.

b. 1764 groups of eleven questions contain five that require proof and six that do not.

Step-by-step explanation:

The order in which the questions are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

a. How many different choices of eleven questions are there?

Eleven questions from a set of 15. So

[tex]C_{15,11} = \frac{15!}{11!4!} = 1365[/tex]

There are 1365 choices of eleven questions.

b. Suppose seven questions require proof and nine do not. How many groups of eleven questions contain five that require proof and six that do not?

5 from a set of 7 and 6 from a set of 9. So

[tex]C_{7,5}C_{9,6} = \frac{7!}{5!2!} \times \frac{9!}{6!3!} = 1764[/tex]

1764 groups of eleven questions contain five that require proof and six that do not.

Answer:

Uh, think you can give a picture?

Step-by-step explanation:

Answer:

The mean is the better center for the given dot plot.

What is Dot plot?

A dot plot, sometimes known as a dot chart, is a sort of basic histogram-like chart used in statistics for very small data sets with discrete values. To create a dot plot, count the number of data points in each bin and draw a stack of dots with that number of dots on top for each bin.

Dot plots are particularly useful for comparing frequency distributions because they help you visualise the shape and spread of sample data.

First the mean of the data

= (1+ 2+ 3+ 4+ 5)/ 5

= 15 /5

= 3

So, the mean is 3.

Thus, the data is skewed and there are outliers.

Hence, the mean a better center for this data.

Step-by-step explanation:

Answer:

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jurvjyrbsurksbksyrbbkursvkurwvkrskuvrskusbrsibyrsriuvvsiruisrbisburisbriusrbisurbiurs

kzrqyeyjacjyeaciarcyirwvuowurvow

vyveaibyraiiuvrslurwc

Answer:

iii) a=3b/2

Step-by-step explanation:

7a-2b= 5a+b

7a-5a=2b+b

2a=3b

a=3b/2

I hope this helps!

Answer:

c

Step-by-step explanation:

4/6 is reduced to two thirds

Answer:

1) 8 + 2i

2) -13

3) 15 + 3i

4) 1

5) 24 - 10i

Step-by-step explanation:

Working with imaginary numbers is similar to working with a variable when it comes to addition and subtraction, so for problems 1 and 3, it is a matter of combining like terms.

1) The like terms are 7i and -5i; 5 and 3. We can combine them.

8 + 2i

2) We can start to compute the problem by noticing it is a special product of difference of squares. The expression can also be written as:

(3i)^2 - (2)^2

9i^2 - 4

i is defined as the square root of negative 1, so i^2 is -1. We can substitute that in:

9(-1) - 4

-9 - 4

-13

3) We can combine the like terms, 12i and -9i; 5 and 10:

15 + 3i

4)The powers of i repeat every four numbers. For example:

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

i raised to a power divisible by four is always 1, so i^24 is 1.

5) We can start by normally distributing in this problem:

12 - 18i + 8i - 12i^2

As said before, i^2 is -1:

12 - 10i + 12

24 - 10i

Answer:

Answer:

isosceles

Step-by-step explanation:

Two sides are the same length as indicated by the lines on the sides.

This tells use that the triangle is isosceles

Answer:

Hi, this an isoceles triangle

Step-by-step explanation:

An isoceles triangle has 2 equal sides

A right angled one has a right angle (90 degrees)

An equilateral traingle has all of his sides equal

A scalene has all of his sides different.

So this must be an isoceles triangle because there is basically a proof of the two equal sides (the bars).

Hope its clear!

Answer:

the answer would be A because of the x+6 so the for a is the one that starts on 6

Step-by-step explanation:

Answer:

it should be A, the y intercept matches up with it

Step-by-step explanation:

he made a mistake in step 3 because you not supposed to add that value behind that division

and you divide first

Answer:

mistake is in step 4. he shouldn't have added first

Answer:

B. [tex]\sqrt{16} *\sqrt{4}[/tex]

Step-by-step explanation:

[tex]=\sqrt{16*4}[/tex]

[tex]=\sqrt{64}[/tex]

[tex]=8[/tex]

--------------------

[tex]=\sqrt{16} *\sqrt{4}[/tex]

[tex]=4*2[/tex]

[tex]=8[/tex]

--------------------

Hope this helps.

Answer:

16 Miles

Step-by-step explanation:

For every week you simply multiply the number of miles from the previous week by 2, therefore

Week 1: 1

Week 2: 2

Week 3: 4

Week 4: 8

Week 5: 16

Answer:

4c^2+7c-5=0

4c^2+7c=5

4c^2+7c=5

4c^2+7c-5=0\quad :\quad c=\frac{-7+\sqrt{129}}{8},\:c=\frac{-7-\sqrt{129}}{8}\quad \left(\mathrm{Decimal}:\quad c=0.54472\dots ,\:c=-2.29472\dots \right)

Hope This Helps!!!

Answer:

C) c = -7 ± √129 / 8

Step-by-step explanation:

x = (-b ± √ (b² – 4ac) ) / 2a

[quadratic formula]

where ax² + bx + c = 0.

[quadratic / square trinomial]

given 4c² + 7c – 5 = 0,

↓ ↓ ↓

a b c

where c = x,

c = (-b ± √ (b² – 4ac) ) / 2a.

c = (-(7) ± √ ((7)² – (4)(4)(-5)) ) / 2(4)

c = (-7 ± √ (49 – (-80)) ) / 8

c = (-7 ± √ (129) ) / 8

c = -7 ± √129 / 8

Answer:

[tex](a)\ \bar x_1 - \bar x_2 = 2.0[/tex]

[tex](b)\ CI =(1.0542,2.9458)[/tex]

[tex](c)\ CI = (0.8730,2.1270)[/tex]

Step-by-step explanation:

Given

[tex]n_1 = 60[/tex]     [tex]n_2 = 35[/tex]      

[tex]\bar x_1 = 13.6[/tex]    [tex]\bar x_2 = 11.6[/tex]    

[tex]\sigma_1 = 2.1[/tex]     [tex]\sigma_2 = 3[/tex]

Solving (a): Point estimate of difference of mean

This is calculated as: [tex]\bar x_1 - \bar x_2[/tex]

[tex]\bar x_1 - \bar x_2 = 13.6 - 11.6[/tex]

[tex]\bar x_1 - \bar x_2 = 2.0[/tex]

Solving (b): 90% confidence interval

We have:

[tex]c = 90\%[/tex]

[tex]c = 0.90[/tex]

Confidence level is: [tex]1 - \alpha[/tex]

[tex]1 - \alpha = c[/tex]

[tex]1 - \alpha = 0.90[/tex]

[tex]\alpha = 0.10[/tex]

Calculate [tex]z_{\alpha/2}[/tex]

[tex]z_{\alpha/2} = z_{0.10/2}[/tex]

[tex]z_{\alpha/2} = z_{0.05}[/tex]

The z score is:

[tex]z_{\alpha/2} = z_{0.05} =1.645[/tex]

The endpoints of the confidence level is:

[tex](\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}[/tex]

[tex]2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}[/tex]

[tex]2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}[/tex]

[tex]2.0 \± 1.645 * \sqrt{0.0735+0.2571}[/tex]

[tex]2.0 \± 1.645 * \sqrt{0.3306}[/tex]

[tex]2.0 \± 0.9458[/tex]

Split

[tex](2.0 - 0.9458) \to (2.0 + 0.9458)[/tex]

[tex](1.0542) \to (2.9458)[/tex]

Hence, the 90% confidence interval is:

[tex]CI =(1.0542,2.9458)[/tex]

Solving (c): 95% confidence interval

We have:

[tex]c = 95\%[/tex]

[tex]c = 0.95[/tex]

Confidence level is: [tex]1 - \alpha[/tex]

[tex]1 - \alpha = c[/tex]

[tex]1 - \alpha = 0.95[/tex]

[tex]\alpha = 0.05[/tex]

Calculate [tex]z_{\alpha/2}[/tex]

[tex]z_{\alpha/2} = z_{0.05/2}[/tex]

[tex]z_{\alpha/2} = z_{0.025}[/tex]

The z score is:

[tex]z_{\alpha/2} = z_{0.025} =1.96[/tex]

The endpoints of the confidence level is:

[tex](\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}[/tex]

[tex]2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}[/tex]

[tex]2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}[/tex]

[tex]2.0 \± 1.96 * \sqrt{0.0735+0.2571}[/tex]

[tex]2.0 \± 1.96* \sqrt{0.3306}[/tex]

[tex]2.0 \± 1.1270[/tex]

Split

[tex](2.0 - 1.1270) \to (2.0 + 1.1270)[/tex]

[tex](0.8730) \to (2.1270)[/tex]

Hence, the 95% confidence interval is:

[tex]CI = (0.8730,2.1270)[/tex]

Answer:

It is one-half the area of a rectangle with sides 6 units × 2 units.

Step-by-step explanation:

Area of the triangke ABC = 6

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: 8 \frac{1}{3}\:(or) \:8.333}}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {Step-by-step\:explanation:}}}[/tex]

[tex]3 \frac{3}{4} \times 2 \frac{2}{9} [/tex]

➺[tex] \: \frac{15}{4} \times \frac{20}{9} [/tex]

➺[tex] \: \frac{300}{36} [/tex]

➺[tex] \: \frac{25}{3} [/tex]

➺[tex] \: 8 \frac{1}{3} [/tex]

➺[tex] \: 8.333[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\pink{Mystique35 }}{\orange{❦}}}}}[/tex]

Given:

The graph of a function.

As [tex]x\to -5^-, f(x)\to \_\_\_[/tex].

As [tex]x\to -5^+, f(x)\to \_\_\_[/tex]

To find:

The correct values for the given blanks.

Solution:

From the given graph it is clear that the function approaches to infinity as x approaches to -5 from the left side. So,

As [tex]x\to -5^-, f(x)\to \infty[/tex].

From the given graph it is clear that the function approaches to negative infinity as x approaches to -5 from the right side. So,

As [tex]x\to -5^+, f(x)\to -\infty[/tex].

Therefore, the correct option (d).

Answer: D

Step-by-step explanation:

Answer:

What do you need help with?

Step-by-step explanation:

You didn't put a question

Answer:

A. 25

Step-by-step explanation:

From the diagram given, we can deduce that <D EG = <F EG

Therefore:

3y + 4 = 5y - 10

Collect like terms and solve for y

3y - 5y = -4 - 10

-2y = -14

Divide both sides by -2

y = -14/-2

y = 7

✔️m<D EG = 3y + 4

Plug in the value of y

m<D EG = 3(7) + 4

m<D EG = 25°

Answer: a) a) 0.700, (0.676, 0.724)

Step-by-step explanation:

Confidence interval for population proportion p :

[tex]\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

[tex]\hat{p}[/tex] = Sample proportion, n= sample size, z* = Critical value.

Let p denote the proportion of all people who voted.

As per given, n= 1000

[tex]\hat{p}=\dfrac{700}{1000}\\\\=0.7[/tex]

z* for 90% confidence = 1.645

Required confidence interval :

[tex]0.7\pm (1.645)\sqrt{\dfrac{0.7(1-0.7)}{1000}}\\\\=0.7\pm(1.645)\sqrt{0.00021}\\\\=0.7\pm (1.645)(0.0145)\\\\=0.7\pm 0.0238525\\\\=(0.7-0.0238525,0.7+0.0238525)\\\\=(0.6761475,\ 0.7238525)\approx(0.676, 0.724)[/tex]

hence, the correct option is a) a) 0.700, (0.676, 0.724)

Answer:

I thinks they take 5 hours to meet each other