hita's Question Bank- CTEVT
Baishakh] Q.No. 12 What is radiocarbon dating?
VER QUESTIONS​

yes

Explanation:

because hindi ko tlaga ala

Answer:

the answer is repel

Explanation:

Answer:

Radient to ElEcTrIcAAl

Explanation:

The FitnessGram Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. A single lap should be completed each time you hear this sound. Remember to run in a straight line, and run as long as possible.

Answer:

The value is [tex]u_x = 597 \ m/s[/tex]

Explanation:

From the question we are told that

    The distance of the target from the riffle is  [tex]d = 40 \ m[/tex]

    The height at which the bullet hit the target is  [tex]y = 2.2 \ cm = 0.022 \ m[/tex]

Considering the vertical motion  

Generally from kinematic equations we have that

        [tex]y = u_y t + \frac{1}{2} * gt^2[/tex]

At the initial stage the velocity is  zero  i.e [tex]u_y = 0 \ m/s[/tex]

=>     [tex]0.022 = 0 * t + \frac{1}{2} * 9.8 t^2[/tex]

=>    [tex]t = 0.067 \ s[/tex]

Generally the velocity of the bullet when it leaves the riffle is mathematically represented as

         [tex]u_x = \frac{ d}{t}[/tex]

=>     [tex]u_x = \frac{40 }{ 0.067 }[/tex]

=>     [tex]u_x = 597 \ m/s[/tex]

Answer: ur mom

Explanation:

Answer:

√3 * Gm²/d²

Explanation:

m1 = m, m2= m, distance = d. hence:

F = Gm²/d²

Let the origin be A, the point x = d be B and the point above the first two is C.

The net force acting on the third mass (point C) [tex]F_{net}[/tex] = [tex]F_A+F_B[/tex]

Let j represent the vertical component and i the horizontal component. Hence:

[tex]F_B=-F_j\\\\F_A=-F(icos\frac{\pi}{6}+jsin\frac{\pi}{6} )=-F(i\frac{\sqrt{3} }{2}+j\frac{1}{2} )\\\\F_{net} =F_A+F_B\\\\F_{net} =-F_j+{-F(i\frac{\sqrt{3} }{2}+j\frac{1}{2} )}\\\\F_{net} =-\frac{F}{2} \sqrt{3}(i+j\sqrt{3} )\\\\The\ magnitude\ of\ the\ net\ force\ is:\\\\|F_{net}|=\frac{F}{2}\sqrt{3}(\sqrt{1^2+\sqrt{3}^2 })=\frac{F}{2} \sqrt{3}(\sqrt{4})\\\\|F_{net}|=\frac{F}{2} \sqrt{3}*2=F*\sqrt{3}\\\\|F_{net}|=\sqrt{3}*\frac{Gm^2}{d^2}[/tex]

Answer:

Explanation:

For equilateral triangle,

[tex]\theta = 30^o[/tex]

Force between masses,

[tex]F_1 = \frac{G*m*m}{d^2}\\\\F_! = \frac{Gm^2}{d^2}[/tex]

Therefore,

[tex]F_net = 2F_1cos\theta\\\\F_net = 2 * \frac{Gm^2}{d^2} * cos30\\\\F_net = 3^{0.5} * \frac{Gm^2}{d^2}[/tex]

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Answer:

62.5m

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 5s

Acceleration  = 5m/s²

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use the motion equation given below:

S = ut + [tex]\frac{1}{2}[/tex] at²

S is the distance traveled

u is the initial velocity

a is the acceleration

t is the time taken

Now, insert the parameters and solve;

 S =( 0 x 5) +( [tex]\frac{1}{2}[/tex] x 5 x 5²) = 62.5m

Answer:

Explanation:

From the question we are told that

Constant speed =48mile/hr

Diameter of a wheel = 22inch therefore [tex]r=\frac{22}{2} =>11[/tex]

Generally Convert from mile/hr to inches/sec

The length in inches is equal to the miles multiplied by 63,360.

an hour is 3600seconds

[tex]\frac{48*63360}{3600}[/tex]

48miles/h = 849.8 inch/sec

[tex]V_a =844.8 inch/sec[/tex]

therefore

[tex]\omega= \frac{v}{r}[/tex]

[tex]\omega= \frac{844,8}{11}[/tex] =>[tex]76.8 sec ^-^1[/tex]

a)Considering the velocity of Vb  in inches per seconds

Generally the formula is stated as

[tex]V_b= V_a + V_b_/_a[/tex]

[tex]V_b = 844.8 + \omega r[/tex]

[tex]V_b= 1639.6in/s[/tex]

b)Considering the velocity of Vc  in inches per seconds

Since the tire doesn't slip as earlier stated in the question

Therefore [tex]V_c = 844.8 -w(r) =0[/tex]

c)Considering the velocity of Ve  in inches per seconds

Generally the formula is stated as

[tex]V_e=V_a + V_e_/_a[/tex]

[tex]V_e = 844.8 \uparrow \theta -844.8 \uparrow = 844.8\sqrt{2}[/tex]

Expressing result with vector

[tex]V_e =844.54 + 20.85j[/tex]

d)Considering the velocity of Vd  in inches per seconds

Generally the formula is stated as

[tex]V_d= V_a + V_d_/_a[/tex]

Mathematically

[tex]V_d =844.8 \uparrow +( 844.8\frac{\sqrt{3} }{2} \uparrow + \frac{844.8}{2} \uparrow)[/tex]

[tex]V_d= (1576.4 \uparrow + 422.4\uparrow)[/tex]

[tex]V_d= 1632.028in/s[/tex]

Explanation:

The width of the central maximum is given by

W = 2 λ L / a

where W is the width of the central maximum

λ is the wavelength of the light used.

L is the distance between the aperture and screen

a is the width of the slit or aperture

So we can see that if any one quantity is varied by keeping others constant in the above formula , there would be a change in width of central maximum.

Answer:

Explanation:Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, ... This article is about the physical phenomenon. ... If the diameter of the tube is sufficiently small, then the combination of surface tension (which is caused by cohesion ... They derived the Young–Laplace equation of capillary action.

Answer:

A I think

Explanation:

because what is the most frequency a because it has more frequency I think I'm not that sure

Answer:

PART A: Maximum speed = 0.314 m/s

PART B: Maximum acceleration = 1.23 m/s²

Explanation:

A simple Harmonic motion is a repetitive motion through an equilibrium point.

Amplitude = 8.0cm = 8/100 = 0.08m (highest displacement)

period (T) = 0.80s

A) maximum speed [tex](V_{max)[/tex]

[tex]V_{max} = 2\pi fA\\where:\\A = Amplitude = 0.08m\\f = frequency = \frac{1}{period(T)} = \frac{1}{0.8} = 1.25 Hz\\\therefore 2\pi fA = 2\pi \times 1.25 \times 0.08\\= 0.314\ m/s[/tex]

B) maximum acceleration [tex](a_{max})[/tex]

[tex]a_{max} = (2\pi f)^2A\\where:\\f = 1.25Hz\\A = 0.08m\\a_{max} = (2\pi \times 1.25)^2 \times 0.08\\= 1.23\ m/s^2[/tex]

Answer:

3.1 m/s

Explanation:

The total distance she has to run is the addition of the three lengths:

47 + 63 + 76 = 186 meters.

She needs to cover it one minute (60 seconds). Therefore her speed must be:

186 m / 60 s = 3.1 m/s

Answer:

1)    x_{cm} = 5 m ,  2)  I = 168.32 kg m²

Explanation:

1) An important concept of center of mass is

          [tex]x_{cm} = \frac{1}{M} \sum x_{i} m_{i}[/tex]

where M is the total mass of the system

Let's apply this equation to our case, suppose that all masses are equal and are worth 1 kg

         [tex]x_{cm}[/tex] = ⅓ (1 0 + 1 5 + 1 10)

         x_{cm} = 5 m

2) In this para indicates that there is an axis of rotation at the point xo = 3.8 m and they ask to calculate the moment inertia.

Let's use the parallel axes theorem

          I =    I_{cm} + M D

where    I_{cm}  is the moment of inertia with respect to the center of mass, D the distance between the two axes of rotation and M the total mass of the system

Let's look for the moment of inertia of the center of mass

         [tex]I_{cm}[/tex] = 1  0 + 1  5² + 1  10²

         I_{cm} = 125 kg m²

the total moment of inertia is

        I = 125 + 3 3.8²

        I = 168.32 kg m²

The moment of inertia of the 3-mass system about the new axis is 54.32 kgm/s².

We have three masses each of mass = 1kg such that they are in line with mass m at origin, m at 5m and m at 10m

(a) The center of mass:

[tex]X=\frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3} \\ \\ X =\frac{ 1*0+1*5+1*10}{1+1+1}\\ \\ X = 5m[/tex]

Hence the center of mass of the system is at x = 5m.

(b) The moment of inertia about the axis passing through x = 3.8m

from the parallel axis theorem:

[tex]I = I_{cm} + Md^2[/tex]

where, [tex]I_{cm}[/tex] is the moment of inertial along an axis passing through the center of mass of the system, M is the total mass of the system and d is the distance of the given axis from center of mass.

M = 3kg

d = 5 - 3.8 = 1.2m

[tex]I_{cm}=1*5^2+1*0+1*5^2\\\\ I_{cm}=50 kgm/s^2[/tex]

Md² = 3×(1.2)²

Md² = 4.32 kgm/s²

I = 50 + 4.32

I = 54.32 kgm/s² is the moment of inertial about the given axis.  

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Answer:

resonance frequency is the frequency when capacitive reactance and inductive reactance become equal and opposite to each other and all impedence is given by resistance.

Explanation:

              f=1/2[tex]\pi[/tex][tex]\sqrt{LC}[/tex]

Potential energy of a particle is directly proportional its position, thus, potential energy of particle increases with increase in the height of the particle and decreases with a decrease in the height of the particle.

The potential energy of a particle is the energy possessed by the particle by virtue of its position. This potential energy is form of mechanical energy and it is expressed mathematically as the product of the mass of the particle, acceleration due to gravity and the particles displacement or position.

P.E = mgh

where;

P.E is the potential energy of the particle

m is the mass of the particle

g is the acceleration due to gravity

h is the position of the particle.

Potential energy of a particle is directly proportional its position, thus, potential energy of particle increases with increase in the height of the particle and decreases with a decrease in the height of the particle.

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Answer: Kinetic Energy to Electrical.

Explanation: The magnet is rotated as a result of the spinning wheels, and this results in a powerful stream of electrons, therefore converting kinetic to electrical.

Answer:

W = 12 J

Explanation:

Given that,

Force, F = 4 N

The object moves in rightward direction for a distance of 3 m.

Work done on the object is given by :

[tex]W=F\times d\\\\=4\ N\times 3\ m\\\\=12\ J[/tex]

So, the work done on the object is 12 J.

Answer:

ight bet

Explanation:

Explanation:

To derive an equation you must indicate the variable you want to solve for.

Here we have tension of an object A and Tension 1.

Two variables or unknown are given hence we cannot derive any other equations.

Answer:

The value  [tex]F  =  0.1396 \ N [/tex]

Explanation:

From the question we are told that

   The volume blood  ejected is  [tex]V = 65 \ cm^3 = 65*10^{-6} \ m^3[/tex]

    The velocity of the blood ejected is  [tex]v = 103 \ cm/s = \frac{103}{100} = 1.03 \ m/s[/tex]

    The density of blood is  [tex]\rho = 1060 \ kg/m^3[/tex]

     The heart beat is [tex]R = 59 \ bpm(beats \ per \ minute) = \frac{59}{60}= 0.9833\ bps[/tex]

The average force exerted by the blood on the wall of the aorta is mathematically represented as

      [tex]F = 2 * \rho * V * R * v[/tex]

=>    [tex]F  =  2 * 1060  *  65*10^{-6}  *  0.9833 *  1.03[/tex]

=>    [tex]F  =  0.1396 \ N [/tex]

Answer:

x = A cos (w \sqrt{2y_{o}/g})

a) maximun  Ф= \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) minimun     Ф = [tex]\frac{\pi }{2}[/tex] - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

Explanation:

For this exercise let's use kinematics to find the time it takes for the mass to reach the floor

         y = y₀ + v₀ t - ½ g t²

as the mass is released from rest, its initial velocity is zero (vo = 0) and its height upon reaching the ground is zero (y = 0)

      0 = y₀ - ½ g t²

      t = [tex]\sqrt{2y_{o}/g}[/tex]

The bucket-spring system has a simple harmonic motion, which is described by

     x = A cos wt

in this expression we assumed that the phase constant (Ф) is zero

let's replace the time

     x = A cos (w \sqrt{2y_{o}/g})

this is the distance where the system must be for the mass to fall into it.

a) The new system has a total mass of m ’= 3.0 kg, so its angular velocity changes

          w = [tex]\sqrt{k/m}[/tex]

In the initial state

         w = \sqrt{k/2}

When the mass changes

         w ’= \sqrt{k/3}

the displacement in each case is

         x = A cos (wt)

for the new case

        x ’= A cos (w’t + Ф)

the phase constant is included to take into account possible changes due to the collision of the mass.

we see that this maximum expressions when the cosine is maximum

        cos (w´t + Ф) = 1

         w’t + Ф = 0

        Ф = -w ’t

        Ф = - [tex]\sqrt{k/3}[/tex] [tex]\sqrt{2y_{o}/g}[/tex]

       \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) the function is minimun if

        cos (w’t + fi) = 0

        w’t + Ф = π / 2

        Ф = π / 2 - w ’t

        Ф = [tex]\frac{\pi }{2}[/tex] - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

Answer:

the velocity is 210 - hq squared which equals to 14

Answer:

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

Explanation:

By the Principle of Energy Conservation we understand that the minimum speed needed by the ball is that speed such that maximum height reached is equal to the diameter of the vertical circle, that is:

[tex]K =U_{g}[/tex] (1)

Where:

[tex]K[/tex] - Translational kinetic energy, measured in joules.

[tex]U_{g}[/tex] - Gravitational potential energy, measured in joules.

By definitions of translational kinetic and gravitational potential energies, we expand the equation above and clear the initial speed of the ball:

[tex]\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g\cdot h[/tex]

[tex]v = \sqrt{2\cdot g\cdot h}[/tex] (2)

Where:

[tex]m[/tex] - Mass, measured in kilograms.

[tex]v[/tex] - Initial speed, measured in meters per second.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]h[/tex] - Maximum height of the ball, measured in meters.

If we know that [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]h = 5\,m[/tex], then the initial speed of the ball is:

[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]

[tex]v\approx 9.903\,\frac{m}{s}[/tex]

The minimum speed needed at the top of the circle so that the cord remains tensioned and the ball's path remains circular is approximately is 9.903 meters per second.

Answer:

Impulse = 0.1 Kgm/s

Explanation:

Given the following data;

Force, F = 10N

Time, t = 0.01 seconds

To find impulse

An impulse can be defined as the net force acting an object for a very short period of time.

Mathematically, impulse is given by the formula;

Impulse = force * time

Substituting into the equation, we have;

Impulse = 10 * 0.01

Impulse = 0.1 kgm/s

Therefore, the impulse of the hammer is 0.1 kilogram meter per seconds.

The impulse of the hammer is 0.1 Ns.

To solve the given problem we need to use the formula for calculating impulse.

Impulse: This can be defined as the product of force and time on a body.

The formula of impulse is given below.

I = Ft....................... Equation 1

Where :

From the question,

Given:

Substitute these values into equation 1

Hence, The impulse of the hammer is 0.1 Ns.

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Answer:

The value is  [tex]m = 69.24 \ kg[/tex]

Explanation:

From the question we are told that

   The value of the external force is  [tex]F = 59.0 \ N[/tex]

    The magnitude of the astronaut's acceleration is  [tex]a = 0.852 \ m/s[/tex]

Generally Newton's Second Law of Motion from the mass of the astronauts is mathematically represented as

            [tex]m = \frac{F}{a}[/tex]

=>         [tex]m = \frac{59 }{0.852 }[/tex]

=>         [tex]m = 69.24 \ kg[/tex]  

Answer:

PLEASE MARK AS BRAINLIEST!!

Explanation:

ANSWER IS IN THE IMG BELOW

Answer:

B

Explanation:

I'm learning it in science.

Answer:

its not b i just took the test and b was wrong

Explanation:

The Pelican  must aim differently than where the fish appears to be because light is refracted from air to water.

Refraction is the change in the direction of a wave at the interface between two media. The effects of refraction are easily seen when light is travelling from air to water hence objects are not really where they appear to be when viewed above the water surface.

Hence, the Pelican  must aim differently than where the fish appears to be because light is refracted from air to water.

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