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Hey

I think that the answer placeholder :)

Sry if im wrong tho

Answer:

The answer is placeholder.

Answer:

def isMagicSquare(myArray: list) -> bool :

   row_num = len(myArray)

   cols_num = [len(x) for x in myArray]

   count =0

   for x in cols_num:

       if row_num == x:

           count += 1

   if count == len(cols_num):

       return True

   else:

       return False

print(isMagicSquare([[1,2,3,1],[3,34,2,4],[43,5,7,5],[2,3,4,5]]))

Explanation:

In object-oriented programming, a method is a function defined in a class. Methods are actions that can be taken or executed in a class or to a class object.

The "isMagicSquare" is a python function or method in a class that returns true if a two array or list is a perfect square (same column and row length).

Answer:

depends on which flash drive

Explanation:

32GB-1000 photos

Well, It just depends on which size you get. You could get a 512 MB or 10 GB. I prefer somewhere in the middle because I don't need to store a lot of stuff in my Flash drive.

verdade pois tem muita filmagem e é dificil escolher a melhor imagem

Answer:

3

Explanation:

Answer:

it would be 3

Explanation:

because origanally a router is a dwvice that forwards data packets between computer networks.

Answer:

Click on the link or copy and paste it to your browser

Explanation:

Answer:

can u explain more specific plz

Explanation:

Answer:

1st is ambient noise

2nd is first person narration

3rd is dynamic microphone

4th is sound affects

5th is sound balance

6th is condenser microphone

Explanation:

hope this helped brainliest pls

Answer:

myRaft.moveRaft('Skykomish')​

Explanation:

myRaft = raft(30)

myRaft.moveRaft('Skykomish')

If you add the following line, you can see that the raft is now located on the Skykomish River.

myRaft.moveRaft('Skykomish')​ is the line of code will move the raft to the Skykomish River. Hence, option B is correct.

Given that the North and South Forks of the Skykomish Rivers pass through it, the Upper Sky Valley is a canoeist and angler's dream. The Sky Valley's world-class whitewater rapids are a great option if you're searching for a wilder ride than floating around or wading into many fishing holes.

The Skykomish River will be navigable from its mouth to the point where its north and south forks meet. There will be no impediments in the Snoqualmie River from its mouth to Snoqualmie Falls. As long as the fishery is open, which is anticipated to last until anglers are allowed to keep up to two coho salmon that are at least 12 inches in length.

Thus, option B is correct.

For more information about Skykomish River, click here:

https://brainly.com/question/29104642

#SPJ2

Answer:

class Car:

   def __init__(self, model_year, purchase_price):

       self.model_year = model_year

       self.purchase_price = purchase_price

       self.current_year = 0

       self.current_value = 0

   def set_current_year(self, year):

       self.current_year = year

   def calc_current_value(self, current_year):

       if self.current_year == 0:

           return "Must first input the current year"

       depreciation_rate = 0.15

       car_age = current_year - self.model_year

       self.current_value = round(self.purchase_price - (car_age * (self.purchase_price * 0.15)))

   def print_info(self):

       print("Car's information:")

       print(f"Model year: {self.model_year}")

       print(f"Purchase price: {self.purchase_price}")

       if self.current_value > 0:

           print(f"Current value: {self.current_value}")

       else:

           print("Current value: Unknown")

Explanation:

The python program above defines the class "Car" that accepts the model year and purchase price of an instance. The class has a set method for the current year variable that is used to calculate and update the current value variable of the object. The print_info method prints the car model year, purchase price and its current value after nth years.

Answer:

P₂ = 0.5 W

Explanation:

It is given that,

The attenuation of a signal is -10 dB.

We need to find the final signal power if it was originally  5 W.

Using attenuation for signal :

[tex]dB=10\text{log}_{10}(\dfrac{P_2}{P_1})[/tex]

Put dB = -10, P₁ = 5 W

Put all the values,

[tex]-10=10\text{log}_{10}(\dfrac{P_2}{5})\\\\-1=\text{log}_{10}(\dfrac{P_2}{5})\\\\0.1=\dfrac{P_2}{5}\\\\P_2=5\times 0.1\\\\P_2=0.5\ W[/tex]

So, the final signal power is 0.5 W.

The final signal power if it was originally 5W is; 0.5 W

We are given;

Formula for attenuation signal is;

dB = 10log_10_ (P2/P1)

Where P2 is final signal power

Thus;

-10 = 10log_10_(P2/5)

-10/-10 = log_10_(P2/5)

-1 = log_10_(P2/5)

0.1 = P2/5

P2 = 0.1 × 5

P2 = 0.5 W

Read more about signal power at; https://brainly.com/question/13315405

Answer:

<?php

function MinMax($x,$y) {

 if($x > $y){

     echo("The minimum is ".$y." and the maximum number is ".$x);

 }

 else{

   echo("The minimum is ".$x." and the maximum number is ".$y);    

 }

}

MinMax(20,4);

?>

Explanation:

<?php

This defines the user function with two parameters x and y

function MinMax($x,$y) {

This checks if parameter x is greater than parameter y

 if($x > $y){

If yes, it prints x as the maximum and y as the minimum

     echo("The minimum is ".$y." and the maximum number is ".$x);

 }

If otherwised

 else{

If yes, it prints y as the maximum and x as the minimum

   echo("The minimum is ".$x." and the maximum number is ".$y);    

 }

}

This calls the function

MinMax(20,4);

?>

Answer:

1.MS PowerPoint

Answer:

First one is INHERITANCE. Second one is AGGREGATION.

Answer:

The main difference between the two file formats is that in DOC, your document is saved in a binary file that includes all the related formatting and other relevant data while a DOCX file is actually a zip file with all the XML files associated with the document.

Answer:

finding area of a circle

def area(radius):

   int(radius)

   formula = radius * radius * 3.14

   print(formula)

radius_input = int(input('Insert the radius of your circle: '))

area(radius_input)

hope this helped :D

Answer:

Rear bumper cover

Explanation:

Complete question

A) management of entry and exit code is managed by OpenMP library reducing the possibility of programming errors.

B) programmers don't need to worry about race conditions.

C) a thread cannot block inside a critical section.

D) deadlock cannot occur.

Answer:

A. Management of entry and exit code is managed by OpenMP library reducing the possibility of programming errors

Explanation:

This is a multiple choice question and this is the answer because:

1. OpenMp is inclusive of an APL/compiler directives:

2. any code which follows #pragma omp parallel is a parallel region and it is performed by large number of threads that are same as the number of processing cores that are in the system.

3. The critical-section compiler directive acts more like a binary semaphore or mutex lock,it makes sure that only one thread is active in the critical section at the same time.

Answer:

The output is:

0

2

4

Explanation:

First of all, the print statement must be indented with a tab, otherwise it is not part of the for loop.

The range(3) creates an array with values 0,1,2. The variable 'counter' gets those values one after another, and the print statement outputs this value doubled, hence the 0, 2 and 4 output.

Answer:

#################

# Python Practice

#################

# Part 1

# ------------------------------------------------------

run_compare = 3

ran_compare = 0

while run_compare != ran_compare:

   num1 = int(input('Please input the first number: '))

   num2 = int(input('Please input the second number: '))

   def compare(number1, number2):

       if number1 < number2:

           print(f'{num1} is less than {num2}')

       elif number1 > number2:

           print(f'{num1} is greater to {num2}')

       else:

           print(f'{num1} is equal than {num2}')

   compare(num1, num2)

   ran_compare += 1

# ------------------------------------------------------

# Part 2

run_name = 6

ran_name = 0

names = []

# ------------------------------------------------------

while run_name != ran_name:

   name = input(str('Please insert a name: '))

   names.append(name)

   print(names)

   ran_name += 1

# ------------------------------------------------------

give me a second im going to resolve the last part but this is what i have so far

Following are the program to the given question:

Program Explanation:

Program:

import random as r#import package random

def compare(n1, n2):#defining a method compare that takes two parameters  

   if n1<n2:#defining if block that checks n1 value less than n2 value

       print("{} is less than {}".format(n1, n2))#print value with the message

   elif n2<n1:#defining if block that checks n2 value less than n1 value

       print("{} is less than {}".format(n2, n1))#print value with the message

   else:#defining else block

       print("{} and {} are equal".format(n1, n2))#print value with the message

def eliminate(n, names):#defining a method eliminate that takes two parameters

   r.shuffle(names)#calling the shuffle method

   for i in range(n):#defining a for loop that checks n values

       names.pop()#calling pop method to remove value

   return names #return a names value  

for i in range(3):#defining a for loop that inputs value

   i1 = int(input("Enter an integer: "))#defining i1 value to input value

   i2 = int(input("Enter another integer: "))#defining i2 value to input value

   compare(i1, i2)#calling the compare method  

   print()#using print to break line  

names= [] #defining an empty list      

for i in range(6) :#defining a loop that inputs name value

   name = input("Enter name: ")#defining name variable that inputs value

   names.append(name)#calling append method  

n = int(input("\nHow many people you would like to vote off the island: "))#defining n variable that input value

new_names = eliminate(n, names)#defining new_names that calling eliminate method

print("\nRemaining people that did not get voted off the island:")#print message

if(len(new_names) != 0):#defining if block that checks new_names length not equal to 0

   for name in new_names:#defining a for loop that checks name is in new_names

       print(name)#print name value

else:#defining else block  

   print("None")#print message None

Output:

Please find the attached file.

Learn more:

brainly.com/question/21922031

for x in range(5,76,5):

   print(x, end=" ")

I wrote my code in python 3.8. Hope this helps

Answer:

option  b and c are correct answers.

Explanation:

Let see each option in detail.

a) Sending email is not a risk.

b) Granting access is a problem because the other person can undermine the network

c) Unknow senders can send virus or other malicious code to corrupts you data.

d) Unwanted advertisement is not a big deal.

Answer:

Granting administrator access to a non-administrator  

 Opening files from unknown senders

Explanation:

Psst those are the answers

n = 1

lst = []

while n > 0:

   lst.append(n := int(input()))

lst.pop(-1)

print(str(min(lst)) +" and "+str(max(lst)))

I wrote this code in python 3.8. I hope this helps