Answer:
We found out more about how the universe had started (Big Bang theory), how the planets were created and how stars are born.
pls help me with this
Answer:
A screw
Explanation:
How high can a 40 N force move a load, when 395 J of work is done? (Show work)
A 40 N force would move a load 9.875 m high when 395 J of work is done on the load.
What is work done?The total amount of energy transferred when a force is applied to move an object through some distance
The work done is the multiplication of applied force with displacement.
The SI unit of work done by an object is Joules.
IJ is the work done when a force of 1 N displaces an object by 1 m .
Work Done = Force * Displacement
For the given problem Force =40N and work done = 395 J
By using the above formula
Work Done = Force * Displacement
395 j = 40 N × height
height =9.875 m
Thus a 40 N force supported by a work done of 395 J moves the load up to 9.875 m height
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As you enter the lab, you find two bottles labeled "concentrated ammonium phosphate." In one paragraph, using your own words, describe the steps you could take to change one of the bottles into a diluted solution, and one of the bottles into a saturated solution.
Answer:
Butane is a four member carbon chain.
The properties of butane are as follows.
Butane is less denser than water.
In the presence of air, it readily burns to form water vapour and carbon dioxide. The reaction is as follows.
It has a boiling point of .
Butane has faint petroleum like odor.
Butane does not react with water.
Butane has weak dispersion force and water has strong hydrogen bonding. The weak dispersion force is unable to break the hydrogen bonding hence, butane does not dissolve in water.
Thus, we can conclude that the chemical properties butane burns readily in air and does not react with water are true out of the given list of options.
Explanation:
The law of __________________________ says that people think of similar objects as belonging together.
Answer:
Explanation:is the law means that the police are the law
Using the statistical definition of entropy, what is the entropy of a system where W = 4?
A. 1.87 × 10–23 joules/kelvin
B. 1.56 × 10–23 joules/kelvin
C. 1.91 × 10–23 joules/kelvin
D. 2.07 × 10–23 joules/kelvin
Answer: S = 1.91x10^(-23) J/K
Explanation:
The statistical definition of entropy says that:
S = k*Ln(W)
where:
W is the number of macrostates, in this case W = 4.
k is a constant:
k = 1.38x10^(-23) J/K
then the entropy of this system will be:
S = (1.38x10^(-23) J/K)*ln(4) = 1.91x10^(-23) J/K
Then the correct option is C.
Answer:
C. 1.91 × 10–23 joules/kelvin
can i be marked brainiest, please? Explanation:
A man speeding at 40m/s decides to outrun the cops and starts to
accelerate at a rate of 2.5m/s2 for 12 seconds. What is the criminal's new
speed?
Answer:
70 m/s.
Explanation:
Given that,
Initial speed, u = 40 m/s
Acceleration = 2.5 m/s²
Time, t = 12 s
We need to find criminal's new speed. Let it is v. Using equation of motion to find it as follows :
v = u +at
Substitute all the values
v = 40 + 2.5(12)
v = 70 m/s
So, the new speed is 70 m/s.
Which of the following is an example of light energy being changed to chemical energy?
Group of answer choices
A flashlight with rechargeable batteries
A solar panel that charges a battery
Food that is eaten to provide mechanical energy
Answer:
A solar panel
Explanation:
A washing machine is being dragged with a starting force of 380.8 N to the West, but this is reduced by friction. If the mass of the washing machine is 37 kg
and the coefficient of friction is 0.54, what was the Net acceleration experienced by the washing machine?
A 10.27 m/s^2 South
B 5 m/s^2 South
C 19.01 m/s^2 South
D 7.6 m/s^2 South
Answer:
B. [tex]5\,\frac{m}{s^{2}}[/tex] South
Explanation:
The correct statement is:
A washing machine is being dragged with a starting force of 380.8 N to the South, but this is reduced by friction. If the mass of the washing machine is 37 kg and the coefficient of friction is 0.54, what was the Net acceleration experienced by the washing machine?
The net force of the washing machine moving on the horizontal ground is equal to the external force minus the friction force, where the normal force from the ground on the washing machine is equal to its weight. The free body diagram of the washing machine is presented below. The equation of equilibrium associated with the acceleration of the washing machine is:
[tex]\Sigma F = P -\mu_{k}\cdot m \cdot g = m\cdot a[/tex] (1)
Where:
[tex]P[/tex] - External force exerted on the washing machine, measured in newtons.
[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.
[tex]m[/tex] - Mass, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]a[/tex] - Net acceleration of the washing machine.
If we know that [tex]P = 380.8\,N[/tex], [tex]m = 37\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\mu_{k} = 0.54[/tex], then the net acceleration experienced by the washing machine is:
[tex]a = \frac{P}{m}-\mu_{k}\cdot g[/tex]
[tex]a = \frac{380.8\,N}{37\,kg}-(0.54)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]
[tex]a = 4.996\,\frac{m}{s^{2}}[/tex]
The correct answer is B.
What kind of waves are light waves and radio waves
Answer:
Electromagnetic waves
Explanation:
True or False? Will mark Brainlest
Answer:
False
Explanation:
They had no free oxygen though they has oceans forming and it was very hot and today is much different hope that helps!
A boy throws a stone vertically in the air with an initial speed of 40m/sec.At the instant the stone is thrown,a monkey at the top of a tree h m high falls freely.How long will it take for the stone to hit the monkey if they meet at a point mid way between the ground and the top of tree?
∞infinaty stones∞
because why not
Cuatro niños jalan de manera separada un mismo carrito de baleros con un mismo desplazamiento, pero uno con un ángulo de 45°, otro con un ángulo de 35°, otro de 20° y el ultimo con un ángulo de 0°, medidos con respecto al eje horizontal. ¿Cuál de los cuatro realiza un mayor trabajo, si la fuerza que se aplica cada uno de ellos es la misma? Selecciona el ángulo:
Answer:
El niño que aplica una fuerza a un ángulo de 0º realiza el mayor trabajo.
Explanation:
Si consideramos que las fuerzas aplicadas en el carrito de baleros es constante tanto en magnitud como en dirección, el trabajo realizado por cada niño ([tex]W[/tex]), medido en joules, puede definirse mediante la siguiente expresión:
[tex]W =F\cdot x\cdot \cos \alpha[/tex] (1)
Donde:
[tex]F[/tex] - Magnitud de la fuerza aplicada por el niño, medida en newtons.
[tex]x[/tex] - Distancia desplazada por el carrito de baleros, medida en metros.
[tex]\alpha[/tex] - Dirección de la fuerza aplicada, medida en grados sexagesimales.
De (1) tenemos que la fuerza efectiva que empuja el carro es:
[tex]F_{e} = F\cdot \cos \alpha[/tex]
La fuerza aplicada por cada niño es despejada:
[tex]F = \frac{F_{e}}{\cos \alpha}[/tex]
A mayor ángulo, tenemos un menor valor del coseno y, por ende, mayor valor de la fuerza aplicada. Ahora, el mayor trabajo realizado se realiza con el menor ángulo posible y bajo esta consideración, el niño que aplica una fuerza a un ángulo de 0º realiza el mayor trabajo.
Which electron dot diagram shows the bonding between 2 chlorine atoms?2 dots then C l with 2 dots above and 1 dot below then 2 dots then 2 dots then C l with 2 dots above and 1 dot below then 2 dots.2 dots then C l with 2 dots above and 2 dots below then 2 dots then C l with 2 dots above and 2 dot below then 2 dots.2 dots then C l with 2 dots above and 2 dots below then 1 dot then C l with 2 dots above and 2 dots below then 2 dots.2 dots then C l with 2 dots above and 1 dot below then 3 dots then 3 dots then C l with 2 dots above and 1 dot below then 2 dots.
Answer:
It is B
Explanation:
Answer: 2nd answer
Explanation: took exam
A machine that uses 200 w of power moves an object a distance of 15 m in 25 sec. Find
the force needed and the work done by this machine,
Answer:dummy
Explanation:
Dum dum
A force of 30 N stretches a very light ideal spring 0.73 m from equilibrium. What is the force constant (spring constant) of the spring
The forces constant (spring constant) of the spring will be 41.09 N/m.
What is spring force?The force required to extend or compress a spring by some distance scales linearly concerning that distance is known as the spring force. Its formula is;
F = kx
The given data in the problem is;
F is the spring force = 30 N
K is the spring constant= ?
x is the displacement of spring = 0.73 m
The spring constant is;
K =F/x
K=30/0.73
K=41.09 N/m
Hence the force constant (spring constant) of the spring will be 41.09 N/m.
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Asha walks 15 m west, then 20 m north, then 15 m east. Calculate the distance
covered by Asha.(a) (Numbering problem)_
Distance walked to the west= 15m
" " " " north= 20m
" " " " east = 15m
Total Distance= (15+ 20+ 15) m
= 50m
Asha covered 50m distance in total.
A hot air balloon holds 7.40 x 107 liters of gas. In order for the hot air balloon to rise into the sky, it must be heated to 120°C. Once the balloon is up in the air, the air needs to be cooled in order for the balloon to land. If the temperature of the balloon is decreased to 40.0°C, what will the new volume of the gas be?
Remember to pay close attention to the units of temperature before beginning your calculations.
Answer:
2.467×10^7 litres
Explanation:
Using the formula V1/T1 = V2/T2
V1 and V2 are the initial and final volume respectively
T1 and T2 are their respective temperatures
Given
V1 = 7.4×10^7litres
T1 = 120°C
T2 = 40°C
Required
V2
From the formula
V2 = V1T2/T1
V2 = 7.4×10^7(40)/120
V2 = (7.4×10^7)/3
V2 = 2.467×10^7 litres
Hence the new volume of the gas will be 2.467×10^7 litres
URGENTE : Un cuerpo de 8m³ flota en el agua. Si el volumen sumergido es de 5m³. Determina el modulo de la fuerza de empuje (en kn) que presenta
Answer:
La magnitud del empuje hacia arriba o fuerza hacia arriba que actúa sobre el cuerpo es 48,853 kN
Explanation:
Los parámetros dados son;
El volumen del cuerpo = 8 m.³
El volumen del cuerpo sumergido = 5 m³
Por el principio de Arquímedes, que establece que el empuje hacia arriba, [tex]F_b[/tex], actuar sobre un cuerpo en un fluido es igual al peso del fluido desplazado por el cuerpo
Matemáticamente, tenemos;
[tex]F_b[/tex] = ρ × g × V
Dónde;
ρ = La densidad del fluido = La densidad del agua = 997 kg / m³
g = La aceleración debida a la gravedad = 9,8 m / s²
V = El volumen del fluido desplazado = El volumen del cuerpo sumergido = 5 m.³
∴ [tex]F_b[/tex] = 997 kg / m³ × 9,8 m / s² × 5 m³ = 48,853 N = 48,853 kN (hacia arriba)
La magnitud del empuje hacia arriba o la fuerza hacia arriba que actúa sobre el cuerpo = 48,853 kN.
I dropped the ball from the roof of a building the speed when I hit the ground is 52 m/s how tall is the building
Answer:
Height of building = 135.2 m
In raising an object vertically at a constant speed of 2 m / s 10 watts of power is developed the weight of the object is
Answer:
5NExplanation:
Power = Workdone/Time
Since workdone = Force * distance = mgh
Power = mgh/t
Given
Power = 10watts
speed = 2m/s
Power = Weight * velocity
Substitute
10 = Weight * 2
Weight = 10/2
Weight = 5N
Hence the weight of the object is 5N
how to create or build a homemade golf club. is this possible? If so, what suggestion did you find? Do you have an original idea on how to build a homemade golf club? what types of materials and tools would you need? what skills are necessary to construct the club?
Answer:
All you need is golfing equipment make a small hole in the ground and have like something to cover the sun off of you and boom you got a golfing spot and a golf club no skills needed. Oh and you need a small flag for your gold hole but then your good and you can have fun
Explanation:
A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the
ground. How long will it take, in seconds, for the ball to hit the ground?
Answer:
0.73 sExplanation:
The time taken can be found by using the formula
[tex] t = \frac{d}{v} \\ [/tex]
d is the distance
v is the velocity
From the question we have
[tex]t = \frac{3.5}{4.8} \\ = 0.72916...[/tex]
We have the final answer as
0.73 sHope this helps you
Which of the following actions will induce an emf in a conductor?
a. Move a magnet near the conductor.
b. Move the conductor near a magnet.
c. Rotate the conductor in a magnetic field.
d. Change the magnetic field strength.
e. all of the above
Answer:
b . Move the conductor near a magnet
Answer:
(e) all the above....
Explanation:
That's all
Cause you know.......
Which is heavier: 30 kilogram or 300 milligrams?
Answer:
30 killograms is 85.9803
and 300 milligrams is 0.000661387 pounds
Explanation:
12. The diameter of a circle is 2.42m. Calculate its
area in proper significant figure
Answer:
A = 4.6 [m²]
Explanation:
The area of a circle can be calculated by means of the following equation.
[tex]A=\frac{\pi }{4} *D^{2}[/tex]
where:
A = area [m²]
D = diameter = 2.42 [m]
Now replacing:
[tex]A=\frac{\pi }{4} *(2.42)^{2} \\A = 4.6 [m^{2} ][/tex]
A train going 14m/s moves 250 m while accelerating to a stop. What is the train’s deceleration?
Answer:
-0.056 is the deceleration
A 75 kg ball carrier is running to the right at 6.5 m/s. An 80 kg defender is chasing the ball carrier running at 7.0 m/s. The defender catches the ball carrier in a completely inelastic collision. What was the kinetic energy of the ball carrier/defender system BEFORE the tackle?
Answer:
3,544.375Joules
Explanation:
Kinetic energy is the energy possessed by a body by virtue of its motion, It is expressed as;
Kinetic energy = 1/2mv²
m is the mass of the body
v is the velocity
For the ball carrier;
KE = 1/2(75)(6.5)²
KE = 3168.75/2
KE = 1584.375Joules
For the defender;
KE = 1/2(80)(7)²
KE = 3920/2
KE = 1960Joules
The kinetic energy of the ball carrier/defender system BEFORE the tackle = KE for the carrier + KE for the defender
kinetic energy of the ball carrier/defender system BEFORE the tackle= 1584.375+1960 = 3,544.375Joules
Incident ray X passes parallel to the principal axis of a concave lens. Incident ray Y passes parallel to the principal axis of a convex lens.
How do the rays behave differently after passing through each lens?
Ray X continues moving in the same direction, and ray Y refracts and passes through the focal point located behind the lens.
Both rays refract and move as though they passed through the focal point.
Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Both rays continue moving in the same direction.
Answer:
Explanation:
It would be option C. Ray x appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Answer:
c. Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Explanation:
The image shows Earth’s orbit around the Sun.
An illustration with a circle representing the sun and a smaller circle representing a planet. The sun is at a focus of a draw ellipse that the planet is on. There are lines drawn radially out from the Sun to the elliptical path of the planet. The planet is at the part of the ellipse that is closest to the sun. The position of the planet is labeled W and the position opposite the planet is labeled X.
Which describes the changes in Earth’s motion?
The speed increases from W to X because a component of the gravitational force acts in the direction opposite to the velocity.
The speed increases from W to X because a component of the gravitational force acts in the direction of the velocity.
The speed increases from X to W because a component of the gravitational force acts in the direction opposite to the velocity.
The speed increases from X to W because a component of the gravitational force acts in the direction of the velocity.
(last choice)
The speed increases from X to W because a component of the gravitational force acts in the direction of the velocity.
D)The speed increases from X to W because a component of the gravitational force acts in the direction of the velocity.
Does gravitational force increase with distance?The gravitational force is inversely proportional to the square of the separation distance between the 2 interacting gadgets, extra separation distance will result in weaker gravitational forces. so as items are separated from every other, the pressure of gravitational attraction between them also decreases.
The force of gravity relies immediately upon the masses of the 2 gadgets, and inversely on the square of the gap between them. this means that the pressure of gravity will increase with mass, but decreases with growing distance among items.
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Draw a picture showing the possible phases of the moon in this binary star
system, do they look the same or different from those we see in the sky in
reality? (You might want to think about scale and how far the suns would be
when considering your answer.)
(Help ASAP)