Answers
Answer:
4
Explanation:
Shaded means that the family members are affected (which in this case means having dimples)
Answer:
5
Explanation:
Related Questions
What is the significance of Non-Homologous end joining and homology directed
repair with respect to the use of CRISPR-Cas9 technology:
Answers
There are fewer mistakes or mutation hazards if the DNA template used for repair is the same as the original, undamaged DNA sequence.
Compared to non-homologous end joining, homology guided repair has some advantages.When chromosomal DSBs arise, the cell uses two sorts of repair pathways:
non-homologous end joining (NHEJ) and homology-directed repair (HDR). Fundamentally,
NHEJ-break ends can be ligated without a template but HDR-breaks require one to direct healing.
Which is more useful: NHEJ or HDR?Both of these repair processes are frequently active in cells, albeit the HDR pathway often works poorer than the NHEJ pathway in the absence of a homologous template.
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Why are dATP, dCTP, dTTP and dGTP added to a PCR reaction tube?
They catalyze the polymerase.
They provide the building blocks of DNA.
They buffer the mixture.
They allow the DNA in the sample to anneal.
Answers
The dATP, dCTP, dTTP and dGTP are added to a PCR reaction tube because they provide the building blocks of DNA.
Members of the dNTPs include deoxyadenosine triphosphate (dATP), deoxythymidine triphosphate (dTTP), deoxycytidine triphosphate (dCTP), deoxyguanosine triphosphate (dGTP), and deoxyuridine triphosphate (dUTP). ) It is included.
Deoxynucleoside Triphosphates (dNTPs) dNTPs are composed of four basic nucleotides, dATP, dCTP, dGTP, and dTTP, as building blocks of new DNA strands. These four nucleotides are usually added to the reaction PCR reaction tube in equimolar amounts for optimal base incorporation. The main components of a PCR reaction are Taq polymerase, primers, template DNA, and nucleotides (DNA building blocks). The components are assembled in a tube along with the necessary cofactors for the enzyme and undergo repeated heating and cooling cycles to allow DNA synthesis.
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If a bear lived off just plants and berries, how much would they need to survive
Answers
Answer:
2-2.25 pounds at 140 calories/ounce on average.
5-6 pounds at 140 calories/ounce during the fall before hibernation.
Explanation:
How many calories do bears eat?On average, Bears eat around 5,000 calories a day. However, Bears eat around 20,000 calories a day during the fall season in preparation for hibernation. If a bear were to eat a solely plant-based diet, it would need to eat plants and berries that are high in calories per ounce to satisfy these metrics. Keep in mind that the climate and agriculture of where this bear is located may decrease its access to highly caloric plants. Therefore, the bear may need to compensate with more plant volume in its diet to ensure that its daily caloric metric can be accommodated.Please let me know if this helped!!!
discuss differences between dicot and monocot plant in terms of external structure
Answers
The difference between dicot and monocot plants in terms of external structure are:
1. Leaf structure:
Dicot leaves have a network of veins and tend to be arranged in pairs opposite each other on the stem. Monocot leaves, on the other hand, have parallel veins and are usually arranged in sets of three or more.2. Flower structure:
Dicot flowers typically have four or five petals and sepals that are arranged in a spiral pattern.Monocot flowers usually have three petals and sepals that are arranged in a symmetrical pattern.3. Root structure:
Dicot plants tend to have a taproot system, which is a single main root that branches off into smaller roots. Monocot plants typically have a fibrous root system, which is a network of many thin roots that branch off from the base of the plant.4. The number of cotyledons:
Dicots typically have two cotyledons, or embryonic leaves, in the seed.Monocots typically have one cotyledon in the seed.5. Stem structure:
Dicots have a ring of vascular bundles that surrounds the stem.Monocots have scattered vascular bundles throughout the stem.To learn more about dicots and monocots:
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From some observations, a student noticed there are fruit flies flying around and landing on a banana in the kitchen. The student wondered if a certain type of fruit will attract more fruit flies than another. The student set up four jars of the exact same size on the countertop in an area where the light remains the same. They weighed the following fruits and placed 110 grams of each fruit into the jars: banana, strawberry, peach, watermelon. The student had 4 vials of fruit flies (all female, same species, same number) and placed each vial directly in front of jar. The student asked a friend to take the cover off of two of the vials while they removed the other covers simultaneously. An hour later the student recorded the number of fruit flies in each jar and continued to record data every twelve hours for 5 days in a row. In this experiment, what is the independent variable?
Question 1 options:
The number of flies in each jar.
The different types of fruit.
The jars, countertop and species of fruit fly.
The time of day the experiment was set up.
Answers
Answer:
b
Explanation:
Which of the following not true of the translocation step of translation elongation in bacteria? a. The tRNA associated with the polypeptide moves from the site to the site upon peptide bond formation: b. The deacylated tRNA moved from the site to the € site c. All of the Biven answers are True d. EF-G hydrolyzes GTP to GDP e. EF-G binds to the A site, mimicking EF Tu-aminoacyl-tRNA complex
Answers
Upon peptide bond formation, the tRNA linked to the polypeptide shifts from the P site to the A site is not true of the translocation step of translation elongation in bacteria.
What happens as a result of the protein synthesis stage called translocation?MRNA and tRNAs are translocated dynamically through the ribosome during protein synthesis. Along with the movement of their associated codons in the mRNA, tRNAs migrate sequentially from the A (aminoacyl) site to the P (peptidyl) site to the E (exit) site.
What transpires when translation is prolonged?The ribosome continues to translate each codon in turn throughout the elongation phase. A bond known as a peptide bond is used to connect each relevant amino acid to the expanding chain. Up until all of the codons are read, elongation continues.
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What do you think would happen to a plant leaf if the
stomata were on the top side of the leaf and always
open? Explain your answer.
Answers
If the stomata were on the top side of the leaf and always open, the plant leaf would likely overheat and dry out due to increased exposure to direct sunlight.
What do you mean by stomata?
Stomata are microscopic pores found on the surface of plant leaves and stems. They are responsible for controlling the exchange of gases such as oxygen, carbon dioxide and water vapor between the plant and the atmosphere. They also regulate the amount of water lost through transpiration.
The plant would quickly lose its moisture through transpiration, and the leaf may become damaged or die. Additionally, the plant would be unable to absorb carbon dioxide for photosynthesis, resulting in stunted growth and poor health.
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A line is a collection of
Answers
A line Is a collection of points
researching into this i found some other students also agreed that points are a solid answer and go o gle agreed aswell
PLEASE HELP
Amino acids are the monomers of
proteins. What are proteins?
A. polymers
B. chemical reactions
C. muscles
Answers
Explanation: Proteins are Polymers made out of Amino Acids which are monomers.
Proteins are the main component of Muscles but Proteins are not just muscles.
Where on the ocean floor will you find the greatest amount of living organisms?
Answers
Answer: The majority of marine organisms are found in coastal areas.
Explanation: As opposed to open ocean or deep water habitats. Coastal areas receive more sunlight and are usually warmer than open ocean or deep water habitats.
Answer:
coral reefs
Explanation:
because there are so many organisms living there
during the transcription of a given portion of a dna molecule _____.
Answers
During the transcription of a given portion of a dna molecule mRNA is synthesized on only one of the chains.
When both strands are transcribed, they make different copies of mRNA that can code for different proteins, and since a single molecule of DNA cannot make different proteins, only one strand of DNA is used during transcription. only. Instructions stored in DNA are read and processed by the cell in two steps: transcription and translation.
Each of these phases is a distinct biological process that involves several molecules. During transcription, a portion of the cell's DNA serves as a template for the formation of RNA molecules.
mRNA is produced during transcription. In the transcription process, single-stranded DNA is deciphered by RNA polymerase to synthesize mRNA. Physically, mRNA is a chain of nucleotides known as ribonucleic acid and is single-stranded.
Messenger RNA is translated simultaneously by multiple ribosomes in both prokaryotic and eukaryotic cells. As the ribosome moves away from the initiation site, another ribosome can bind to the mRNA and initiate synthesis of a new polypeptide chain.
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How does the circulatory system help the muscles to function
Answers
Answer:
The circulatory system helps the muscular system by pumping blood and oxygen to the working muscles. The circulatory system also helps the muscular system because it allows muscles to receive the oxygen they need to function properly.
Explanation:
4 Answer:
How would the average body temperature of a healthy human, which is
37 degrees C, be represented in Kelvins?
a. 0°K
b. 236°K
c. 310°K
d. 37°K
5 Answer:
Which of the following would require the greatest number of calories?
a. heating 1 g of water from 10°C to 80°C
b. heating 10 g of water from 10°C to 40°C
c. heating 100 g of water from 10°C to 20°C
d. heating 1000 g of water from 10°C to 12°C
6 Answer:
If a 10.0 g piece of metal required 100 cal to raise its temperature
by 20°C, what would you report as its specific heat?
a. 10 cal/g·°C
b. 200 cal/g·°C
c. 0.5 cal/g·°C
d. 2 cal/g·°C
7 Answer:
Which of the following does not happen during the phase change from
solid to liquid?
a. Heat is absorbed.
b. The temperature rises.
c. Melting occurs.
d. Molecules move faster.
8 Answer:
How much heat is needed to vaporize 100 g of water at 100 degrees C?
a. 54,000 cal
b. 100 cal
c. 80 cal
d. 800 cal
Answers
Answer:
4.) 310°K
5.)c.
6.)200 cal...
7.)b.
8.)54.000cal
Complete the sentence. Lobbyists of ______________ use access to political leaders and other federal members to attempt to influence environmental policy.
the courts
Congress
interest groups
the presidency
Answers
Lobbyists of interest groups use access to political leaders and other federal members to attempt to influence environmental policy and is therefore denoted as option C.
What is Interest group?They are also referred to as advocacy group, or pressure group, and consists of any association of individuals or organizations that seeks to influence public policy on the basis of a particular common interest or concern.
They do that as a result of the access they have to political leaders and other federal members through various means such as affiliations etc. They do that so as to benefit from them through the various rule and laws passed by them as the political leaders are usually in charge of them due to them being placed in the different arms of government and is therefore the reason why it was chosen as the correct choice.
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If ouabain was used to block Na+–K+-ATPase pumps, A) the concentration of K+ would be equal on both sides of the membrane.
B) the cell would maintain steady state with a different membrane potential. C) the membrane potential would become more negative. D) Na+ would go to equilibrium across the cell membrane
Answers
If ouabain was used to block Na+–K+-ATPase pumps, the cell would maintain a steady state with different membrane potential. Here option B is the correct answer.
Ouabain is a drug that blocks the activity of the Na+–K+-ATPase pumps, which are responsible for pumping potassium ions (K+) into the cell and sodium ions (Na+) out of the cell.
By blocking these pumps, ouabain prevents the maintenance of the normal concentration gradient of K+ and Na+ across the cell membrane, and as a result, it alters the membrane potential. The membrane potential would not become more negative and the Na+ would not go to equilibrium across the cell membrane.
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Which statement is correct concerning the energetic coupling of reactions shown in Figure 8.9?
A. Products of the coupled reaction have lower free energy than products of the uncoupled reaction.
B. Substrate A has higher free energy in the coupled versus the uncoupled reaction.
C. The activated substrate BP has higher free energy than substrate B.
D. AB synthesis from A + BP is exergonic because phosphorylation of substrate B is exergonic.
Answers
A. Products of the coupled reaction have lower free energy than products of the uncoupled reaction is correct statement concerning the energetic coupling of reactions.
Energetic coupling is a mechanism that involves the transfer of energy from an exergonic reaction to an endergonic reaction, allowing the latter to proceed. The exergonic reaction (in this case the phosphorylation of substrate B) releases energy, which is used to drive the endergonic reaction (in this case the AB synthesis from A + BP). As a result, the products of the coupled reaction have lower free energy than the products of the uncoupled reaction. This is because the energy released from the exergonic reaction is used to drive the endergonic reaction, thus decreasing the overall energy required for the coupled reaction to occur.
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Question 8(Multiple Choice Worth 3 points)
(04.01 MC)
Starting with the European settlers, humans have introduced earthworms from Europe and Asia into North American forests. These introductions continue through the transport of soil that contains non-native earthworms, such as during construction and through the release of non-native earthworms used for fishing. The effects of non-native earthworms are especially large in forests that did not have any native earthworms. For example, forests of the Great Lakes region did not previously have earthworms until humans introduced them. When non-native earthworms are introduced, the thick layer of leaves, known as leaf litter, covering the ground disappears quickly, thereby altering biogeochemical cycles.
What is a possible negative consequence of introducing the non-native earthworms to forests in the Great Lake regions?
PLease hurry
The earthworms reduce the resources available to other animals that eat dead plant matter.
The earthworm decreases the energy flow from one tropic level to the next.
The earthworms provide an additional food source for primary consumers.
The earthworms burrow, which reduces the nutrients, flow of air, and water underground.
Answers
Answer:
The earthworms reduce the resources available to other animals that eat dead plant matter.
Explanation:
The introduction of non-native earthworms in the Great Lakes region can have negative consequences on the ecosystem, including reducing the leaf litter and other organic matter in the soil, which is a main food resource for many species of animals and invertebrates, causing a decline in the population of those species. I apologize for any confusion my previous response may have caused.
is there an impact on the environment if blue whales went extinct? Who or what would it impact? Helllpppp please
Answers
Answer: Phytoplankton and the single-celled variety that krill eat are responsible for absorbing a massive amount of carbon from the atmosphere. In the absence of whales, krill would likely eat much of the free-floating phytoplankton on the ocean's surface, resulting in a marked acceleration in climate change.
Explanation:
Humans selectively fish out the largest species from Earth's oceans, causing their populations to dwindle. If that weren't alarming enough, the extinction of those animals—think a great white shark, bluefin tuna, and blue whale—could ripple down the food chain and spell extinction for entire ecosystems.
Answer:
algae population.
Explanation:
this would affect other aquatic life because algae absorbes oxygen and may cause fish to die of lack of food and oxygen
25 points help please
A litter of 6 kittens are born to the same parents. Some kittens have gray fur and some kittens have black fur.
Which statement about the kittens' genetic information is true?
Question 17 options:
They carry mutations in the gene for fur color
They all inherited identical genetic information from their parents
They have different alleles for fur color
Some kittens have more genes for fur color than others
Answers
Answer:
They have different alleles for fur color
Explanation:
In a chromosome the alleles are either dominant or recessive, The parents fur color will decide causing different fur colors.
RbCl will give__________ color in the flame test A. Purple B. Green. C. Yellow: D. Red.
Answers
RbCl will give a yellow color in the flame test.
In a flame test, a small amount of a compound is placed on a platinum wire and heated in a flame. The electrons in the compound become excited by the heat and emit light, which is seen as a color.
Different elements produce different colors in the flame test. RbCl or Rubidium Chloride when heated in a flame, it produces yellow color due to the excitation of electrons from ground state to the excited state.
The color is specific to the element and can be used to identify the element in a sample. It's a qualitative analytical technique used for identifying specific metal ions in a sample. This method is also commonly used in laboratories for the analysis of minerals and salts.
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A blastocyst is floating inside of Daria's uterus. In what stage is Daria's pregnancy?
Answers
The growing human organism is referred to as an embryo from the time it attaches to the uterine wall until the eighth week after pregnancy and as a fetus from the start of the ninth week following fertilization until delivery.
What pregnancy stage is the embryonic stage?Following conception, your child enters the embryonic stage, a time of significant change. It lasts from the fifth to the tenth week of pregnancy. The infant is referred to as an embryo during this period.
Describe the organogenesis stage.The development and organogenesis of tissues occur during weeks six through eight of the human embryo. Organogenesis, often known as the embryonic period, runs from weeks three to eight during which time this process takes place.
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The molecule on which an enzyme acts is called
Answers
The molecule on which an enzyme act is called a substrate.
What are enzymes?Enzymes are molecules found in the body that speed up the rate of chemical reactions.
Proteins called enzymes operate as biological catalysts by quickening chemical reactions.
Substrates are the molecules that enzymes can interact with, and the enzyme changes the substrates into new molecules known as products.
Enzymes can be classified into the following categories based on the type of reaction they catalyze:
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answer all of these questions for *80 POINTS**
Answers
Answer: the first one is C, the second one is A, the third one is also A
Explanation:
The element boron has
[how many valence electrons.
Answers
Answer:
3
Explanation:
When counting valence electrons you only look at the columns from 1-2 and 13-18
Notice how when counting, there are 8 columns, with the Noble gases being on the very right with a full shell of 8 valence electrons. Hence when counting from left to right, add a VE for every column (skip the transition metals)
Which of the following is not a way in which evolutionary theory explains pro-social behavior? a. social exchange b. kin selection c. the reciprocity norm
Answers
Social exchange the following is not a way in which evolutionary theory explains pro-social behavior.
What three categories of prosocial activity are there?With this in mind, prosocial behavior can be viewed as requiring three elements: (1) the capacity to adopt another person's viewpoint and recognize that they are experiencing a problem; (2) the capacity to ascertain the cause of that problem; and (3) the motivation to assist them in resolving the issue.
What do prosocial conduct theories entail?Prosocial actions are those taken with the intention of assisting others. Concern for other people's rights, feelings, and welfare underpins these behaviors. Empathy and compassion for others are two behaviors that might be categorized as prosocial.
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is the sand efective by destructive constructive
Answers
Answer:
The sand can be considered as both destructive and constructive depending on the context.
Constructively, sand can be used to create landforms such as beaches and dunes through natural processes such as erosion and sedimentation. Sand can also be used in construction, for example as an ingredient in concrete or as a medium for sandblasting.
Destructively, sand can cause erosion and damage to coastal structures and infrastructure. Sand can also cause problems for vehicles and aircraft by creating dust storms and reducing visibility.
It's worth noting that the destructive effects of sand can be mitigated by proper management and planning, such as constructing barriers to protect against coastal erosion or taking measures to control dust storms.
For a molecule of glucose to be converted into an amino acid, which of these events must occur?
A. Anitrogen atom must be added to a carbon chain.
B. A phosphorus atom must be removed from a carbon chain.
C. A hydrogen atom must be added to a carbon chain.
D. Two carbon atoms must be joined together.
Answers
Answer:
. An nitrogen atom must be added to a carbon chain.
In eukaryotic cells, a terminator in mRNA synthesis is _____.
Answers
Hlnts stop codon particular nucleotide sequence in DNA, which tells the RNA polymerase to stop specific nucleotide sequence in mRNA to cease transcription, acts as a terminator in eukaryotic cells' mRNA synthesis.
Polymerase I transcribes ribosomal RNA, Polymerase II transcribes mRNA and miRNAs, and Polymerase III transcribes tRNA and other short RNAs in eukaryotes. Eukaryotes have three RNA polymerases, known as Polymerases I, II, and III. Although eukaryotic termination has not received as much attention as prokaryotic termination, the fundamental mechanisms are understood, and it has been noted that many eukaryotic RNA polymerase termination patterns exist. For instance, Polymerase III, like Rho-independent termination in prokaryotes, depends on a certain sequence and RNA secondary structure to cause transcript cleavage. Contrary to Polymerases I and II, which also call for the binding of termination factors, this is different.
Although both are termination factor dependent, Polymerases I and II employ different mechanisms to terminate transcription. Polymerase I uses a process similar to the prokaryotic Rho-dependent mechanism, whereas Polymerase II termination is more complex and involves two RNA polymerase-associated proteins, CPSF and CstF, which are responsible for recruiting the cleavage and polyadenylation enzymes, in a process that seems to couple termination with polyadenlyation.
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unlike life at the top of a body of water ,life at the bottom of the body of water
Answers
Life at the bottom of a body of water, also known as the benthic zone, is vastly different from life at the top of a body of water.
What is Benthic zone?The benthic zone is the region of the ocean or other body of water that is in contact with the bottom.
One of the main differences is the amount of light available. In the benthic zone, there is very little light, as most of it is blocked by the water above. This means that the organisms living in this zone have adapted to live in low light conditions, and many of them are bioluminescent.
Another difference is the pressure. At the bottom of the ocean, the water pressure is much higher than at the surface, and organisms living in this zone have adapted to withstand this pressure. Some have thicker cell walls or other structural adaptations to deal with the increased pressure.
The benthic zone also has different types of habitats and environments, such as rocky shores, sandy bottoms, or coral reefs, each with its own unique set of organisms that have adapted to that specific habitat.
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Put the following phyla in order from least diverse (in terms of number of named species) to most diverse: Annelida, Mollusca, Arthropoda, Rotifera.
a. Annelida, Rotifera, Mollusca, Arthropoda
b. Mollusca, Rotifera, Annelida, Arthropoda
c. Rotifera, Annelida, Arthropoda, Mollusca
d. Rotifera, Annelida, Mollusca, Arthropoda
Answers
d. Rotifera, Annelida, Mollusca, Arthropoda
Rotifera is a phylum that contains around 2000 known species, which makes it the least diverse among the four phyla mentioned. Annelida is a phylum that contains around 15,000 known species, which makes it slightly more diverse than Rotifera but less diverse than Mollusca and Arthropoda. Mollusca is a phylum that contains around 85,000 known species, which makes it more diverse than Annelida but less diverse than Arthropoda. Arthropoda is the most diverse phylum among the four mentioned, with over 1.2 million known species. It contains a wide range of animals, including insects, crustaceans, arachnids, and millipedes. Arthropoda is the most diverse animal phylum known to man.
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