How many grams of air are required to complete the combustion of 120 g of phosphorous to diphosphorous pentoxide, assuming the air to be 23% oxygen by mass?

Answers

Answer 1

Answer:

Explanation:

522 g

Explanation:

Your starting point here will be the balanced chemical equation for this combustion reaction

4

P

(s]

+

5

O

2(g]

2

P

2

O

5(s]

Notice that you have a

4

:

5

mole ratio between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need

5

4

time more moles of oxygen gas.

Use phosphorus' molar mass to determine how many moles you have in that

93.0-g

sample

93.0

g

1mole P

30.974

g

=

3.0025 moles P

Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction

3.0025

moles P

5

moles O

2

4

moles P

=

3.753 moles O

2


Related Questions

Draw the structure formula for
1-ethyl-2,3-dimethylbenzene

Please help me

Answers

Answer:

Please see the attached picture.

Explanation:

1) Draw a benzene ring

2) On the first carbon, add a CH₂CH₃ (known as ethyl) since its location number is 1.

3) 'Dimethyl' refers to 2 methyl (CH₃) branches. The location numbers are 2 and 3, thus add a CH₃ on the 2nd and 3rd carbons.

? I JUST DONT UNDERSTAND

Answers

Answer:

5SiO2 + 2CaC2 → 5Si + 2CaO + 4CO2

Explanation:

When you are balancing an equation, you use coefficients to change the number of atoms of each type that are on each side of the equation.

You cannot change subscripts, the small numbers to the right of the substances. You can only add coefficients, the large numbers to the left of substances.

A balanced equation has the same number and type of atoms on both sides of the equation (the reactants on the left, the products on the right).

To begin, this equation has:

1 Si

2 O

1 Ca

2 C  

on the left and

1 Si

1 Ca

3 O

1 C

on the right. Those numbers don't match!

By adding coefficients we end up with 5 Si, 10 O, 2 Ca and 4 C on both sides.

An empty steel container is filled with 2.0 atm of H₂ and 1.0 atm of F₂. The system is allowed to reach equilibrium according to the reaction below. If Kp = 0.45 for this reaction, what is the equilibrium partial pressure of HF?

Answers

The equilibrium partial pressure of HF is 0.55 atm.

The equation of the reaction is;

        H2(g) + F2(g) ⇄ 2HF

I         2           1             0

C       -x           -x            +x

E     2 - x        1 - x           x

We know that;

pH2 = 2.0 atm

PF2 =  1.0 atm

pHF = ??

Kp = 0.45

So;

Kp = (pHF)^2/pH2. pF2

0.45 = x^2/(2 - x) (1 - x)

0.45 =  x^2/x^2 - 3x + 2

0.45(x^2 - 3x + 2) = x^2

0.45x^2 - 1.35x + 0.9 =  x^2

0.55 x^2 + 1.35x - 0.9 = 0

x = 0.55 atm

Learn more about equilibrium: https://brainly.com/question/3980297

Compare the change in pH with the addition of acid and base to deionized water and to a buffer.

Answers

Answer:

case1.

The addition of acid and base leads to a change in pH of the water when adding to deionized water due to fact that acid and bases dissociated in dissolving in water. If the H+ ion increases in the water as acid addition hikes it, it will result in decreasing the pH value. The intensity of the acid also affects the dissociation of the ions.

case2

Buffers are normally formed by weak acid and its conjugate base, and adding acid to the buffer it absorbs the H+ ions so the pH will be lower and adding base or increase of OH- conjugate base resists the pH value to increase.

A gas takes
up a volume of 17 L, has a
pressure of 2.3 atm, and a temperature
of 299 K. If I raise the temperature to
350 K and lower the pressure to 1140
mmHg, what is the new volume?

Answers

Answer:

V₂ = 25.065 L

Explanation:

Given data:

Initial volume = 15L

Initial pressure = 1500 mmHg (1500/760 = 1.97 atm)

Initial temperature = 299 K

Final temperature = 350 K

Final volume = ?

Final pressure = 1050 mmHg (1050/760 = 1.38 atm)

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.97 atm × 15 L × 350 K / 299 K × 1.38 atm

V₂ = 10342.5 atm .L. K / 412.62 K.atm

V₂ = 25.065 L

How many moles are in 2.5L of 1.75 M Na2CO3

Answers

Answer: There are 4.375 moles in 2.5 L of 1.75 M [tex]Na_2CO_3[/tex]

Explanation:

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]      

Molarity of solution = 1.75 M

Volume of solution = 2.5 L  

Putting values in equation , we get:

[tex]1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol[/tex]

How many atoms are in 90.43 moles of copper

Answers

409 g P2O5 2) 5.44 x 1025 atoms Cu

Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 8.12×10²³ atoms are in  90.43 mole of copper.

What is mole?

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. It measure the number of elementary entities of a given substance that are present in a given sample. There are so many formula for calculating mole.

we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number

number of atoms/molecules=number of moles × 6.022×10²³(Avogadro number)

number of moles of copper=90.43 moles

Substituting all the given values in the above equation, we get

number of atoms/molecules= 90.43 × 6.022×10²³

number of atoms/molecules=8.12×10²³ molecules

Therefore, 8.12×10²³ atoms are in 90.43 mole of copper.

To know more about mole, here:

https://brainly.com/question/15209553

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Who knows how to do this please help

Answers

Answer: You forgot to zero the balance

Explanation:

Which postmortem parameter is fixed by 8 hours?

1)cloudiness of the eyes

2)rigor mortis

3)livor mortis

4)putrefaction

Answers

The postmortem cooling or algor mortis gets fixed by 8- 10 hours after death. The temperature of the body after death can be used to determine the time since death.

What is the final volume?

Answers

Answer:

Option A. 9.4 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 8 L

Initial temperature (T₁) = 293 K

Final temperature (T₂) = 343 K

Final volume (V₂) =?

V₁ / T₁ = V₂ / T₂

8 / 293 = V₂ / 343

Cross multiply

293 × V₂ = 8 × 343

293 × V₂ = 2744

Divide both side by 293

V₂ = 2744 / 293

V₂ = 9.4 L

Therefore, the final volume of the gas is 9.4 L

plz help :(
In a high-pressure system,
a.
air molecules are far apart and pressing on Earth’s surface.
b.
air molecules are far apart and rising away from Earth’s surface.
c.
air molecules are close together and pressing on Earth’s surface.
d.
air molecules are close together and rising away from Earth’s surface.

Answers

Answer:

c.

air molecules are close together and pressing on Earth’s surface.

Explanation:

i hope this helps!

what is derived from sheep and goats that is used in break fluid

A bones and horns
B Fats and Fattys acids
C Manure
D Wool and Lanolin

Answers

the answer is A I took the test

Yes it is a just make sure tho

Calculate the mass, in grams, of 0.540 mol of manganese (Mn).
Report your answer with three significant figures.

Answers

Answer:

m = 29.6 grams

Explanation:

Given that,

Number of moles = 0.540

The molar mass of manganese = 54.93 g/mol

We know that,

Number of moles = given mass/molar mass

[tex]m=n\times M\\\\m=0.540 \times 54.93\\\\m=29.6\ g[/tex]

So, the required mass of the Manganese is equal to 29.6 grams.

Given 1.67 moles of K, how many moles of KBr are produced?
2 K+ 1 Br2---> 2 KBr

Answers

Answer:

[tex]\displaystyle 1.67 \ mol \ KBr[/tex]

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Chemistry

Atomic Structure

Moles

Stoichiometry

Using Dimensional AnalysisAnalyzing Reactions RxNExplanation:

Step 1: Define

[RxN - Balanced] 2K + Br₂ → 2KBr

[Given] 1.67 moles K

[Solve] moles KBr

Step 2: Identify Conversions

[RxN] 2 mol K → 2 mol KBr

Step 3: Stoichiometry

[DA] Set up conversion:                                                                                 [tex]\displaystyle 1.67 \ mol \ K(\frac{2 \ mol \ KBr}{2 \ mol \ K})[/tex][DA] Multiply/Divide [Cancel out units]:                                                         [tex]\displaystyle 1.67 \ mol \ KBr[/tex]

hi, if your looking for extra points (50+) and br ainiest here is ur chance, answer this question correctly plz

Answers

C! the others don’t make sense

help plz and will give brainly

Answers

I think D or C is my top answers

Please help ASAP! Please and thank you have a great and blessed day!,

Answers

the answer is “Mineral”
Yea I confirm that the answer I indeed mineral.

hi!! can somebody help me with this question?


which is the best example of commensalism?

A. honey bees feed on the pollen of cornflowers and help the flowers reproduce

B. barnacles ride on a gray whales back to obtain food, and the whale is not harmed

C. squirrels and chipmunks eat the same nuts in a forest where food is scarce

D. prairie dogs often collect and eat food in groups so they are better protected from enemies


thx to anybody that helps! ♡︎

Answers

Answer:

B: Barnacles ride on a gray whale's back to obtain food, and the hale is not harmed.

Explanation:

I got it right on Edge.

Does the magnetic field lines of repelling magnets always combine. True or False?

Answers

Its true they are always combine

Answer:

True

Explanation:

yes magnetic feild lines is always combined

A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NaOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H8O6 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 20.74 Concentration of NaOH in mol/L, 0.201 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg).

Answers

Answer:

The correct answer is - 733.69 mg.

Explanation:

given:

The volume of ascorbic acid = 50 ml

The volume of NaOH = 20.74 ml

Molarity of NaOH = 0.201 M

formula = C6H8O6

Solution:

moles of NaOH for titration = molarity of NaOH × The volume of NaOH

= 0.201 × 20.74 × 10^-3

=4.16874 × 10^-3

then molecular weight of ascorbic acid

= 6 × 12+ 8×1+ 6× 16

=176g/mol

the molecular mass would be

= 4.16874 × 10^-3 × 176

= 733.69 × 10^-3 g

=733.69 mg

Balance Ca + HCI +CaCl2 + H2

Answers

Answer:

Ca + 2 HCl -- CaCl2 + H2

Explanation:

There are two hydrogen on the right side, so we multiply the left side( HCl) by 2 to get 2 hydrogen on the left. This automatically gives you 2 Cl on left side and there are already 2 cl on the right side, so now this equation is balanced.

what is the mass of 1.25 L of ammonia gas at STP

Answers

Answer:

mass 1.25 Liters NH₃(gas) = 0.949 grams (3 sig-figs)

Explanation:

At STP (Standard Temperature-Pressure conditions => 0°C(=273K) and 1atm pressure,  1 mole any gas will occupy 22.4 Liters.

So, given 1.25 Liters ammonia gas at STP, convert to moles then multiply by formula wt. (17g/mole gives mass of NH₃.

moles NH₃(gas) = 1.25L NH₃(gas)/22.4L NH₄(gas)· NH₃(gas)mole⁻¹ = 0.0558 mole NH₃(gas).  

Converting to grams NH₃(gas) = 0.0558 mole NH₃(gas) x 17 g·mol⁻¹ = 0.949 grams NH₃(gas).

A severe storm would be most likely to damage a coastal area by causing
A.
volcanoes.
B.
pollution.
C.
erosion.
D.
earthquakes.

Answers

D earthquakes


my teacher told me

A severe storm would be most likely to damage a coastal area by causing pollution. Therefore, the correct option is option B.

What is coastal area?

The region where land joins the ocean, or even as a line defining the border between the land as well as the shoreline, is known as the coast, sometimes referred as the coastline and seashore. The terrain of the area's surroundings has an impact on shorelines, as do water-induced erosion processes like wave action.

The length of the shoreline on Earth is about 620,000 kilometers. Natural ecosystems' coasts are significant zones and frequently the site of a diverse range of biodiversity. They are home to significant ecosystems on land, such as freshwater and estuarine wetlands, that are crucial for the survival of bird populations or other land animals. A severe storm would be most likely to damage a coastal area by causing pollution.

Therefore, the correct option is option B.

To know more about coastal area, here:

https://brainly.com/question/14105067

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Who among, Amit and Saaketh, is correct? Explain.​

Answers

Answer:

What is their question answers exactly? I won't be able to explain who is correct.

Explanation:

Answer:

Not a lot to draw from this question if im going to be honest

Explanation


If 280.4 g of KOH react with an excess of FeCl3, how many grams of Fe(OH)3 will be produced?
FeCl3 + 3 KOH — Fe(OH)3 + 3 KCI
How many grams will be produced?

Answers

Answer:

From 00:11

Balance the Molecular Equation

From 01:35

Ions for the Complete Ionic Equation

From 03:04

Net Ionic EquationExplanation:

Do you think humans are responsible for global warming trends? Why or why not?

Answers

Answer:

Yes. At least some. There has been ups and downs in temperature ever since the Earth was created, and this is just another up in temperature. I do think that humans have made it worse though, with all of the greenhouse gases and things like that.

oil has a density of 8.5kg/L. what is the volume of 5.4kg oil

Answers

Answer:

0.64 L

Explanation:

Step 1: Given data

Density of oil (ρ): 8.5 kg/LMass of oil (m): 5.4 kgVolume of oil (V): ?

Step 2: Calculate the volume corresponding to 5.4 kg of oil

Density is an intrinsic property and it is equal to the quotient between the mass and the volume.

ρ = m/V

V = m/ρ

V = 5.4 kg/(8.5 kg/L) = 0.64 L

What volume of 1.75 M hydrochloric acid (HCl aq) must be diluted with water to prepare 0.500 L of 0.250 M hydrochloric acid?

Answers

Answer:

[tex]V_1=0.0714L[/tex]

Explanation:

Hello there!

In this case, since we need to dilute the 1.75-M HCl, and the total number of moles remain unchanged, we can write:

[tex]n_1=n_2[/tex]

And in terms of volume and concentration:

[tex]C_1V_1=C_2V_2[/tex]

Thus, we can solve for the volume of the concentrated HCl as shown below:

[tex]V_1=\frac{C_2V_2}{C_1}[/tex]

Therefore, we plug in the data to get:

[tex]V_1=\frac{0.250M*0.500L}{1.75 M}\\\\V_1=0.0714L[/tex]

Best regards!

HELP and give brainlys out to ppl who actually know the answer please help

Answers

Answer:

b. snake and earthworm

Explanation:

embryos are different from each other in early stages- all the others look similar

PLS HELP THIS IS DUE IN 10 MINS!
Compare and contrast floods and droughts. Give two examples of how they are the same and two examples of how they are different.

Answers

Same: Both are natural disasters. Both are becoming more common to due climate change.

Different: Floods are an excess amount of water whereas droughts are a lack of water for a prolonged period of time. Floods are more common in coastal areas whereas droughts are most common in the Midwest and South.
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