How many grams of chlorine are required in order to consume 85g of
sodium?
2 Na +1 C12
+ 2 Naci

Answers

Answer 1
Check the attached photo out...
How Many Grams Of Chlorine Are Required In Order To Consume 85g Ofsodium?2 Na +1 C12+ 2 Naci

Related Questions

What is measured by the heat of reaction?

Answers

Answer:

The heat of reaction is basically the energy that is being released and or absorbed when chemicals are transformed in a type of chemical reaction. However, the heat of reaction or also called reaction enthalpy is mostly or typically expressed as a molar enthalpy in kJ/mol and or as just a specific enthalpy in kJ/kg or kJ/L.

1. a) Define the term electricity ?

Answers

Answer:

a form of energy resulting from the existence of charged particles (such as electrons or protons), either statically as an accumulation of charge or dynamically as a current.

Explanation:

Someone drops a book on the floor and it makes a loud noise. At the time you turn and look at the person who dropped the book .
In the scenario above turning and looking at the person who dropped the book is an example of a :

Answers

Answer: curiosity?

Explanation:

What is the mass percent of potassium sulfate in solution if 78g of potassium sulfate is dissolved in 500 mL of water? (The density of water is 1.00 g/mL)

Answers

Answer:

13.5 %

Explanation:

First we calculate the mass of 500 mL of water, using its density:

Volume * Density = Mass500 mL * 1.00 g/mL = 500 g

Then we calculate the mass percent of potassium sulfate, using the formula:

Mass of Potassium Sulfate / Total Mass * 100%

78 g / (78 + 500) g * 100 % = 13.5 %

FREE BRAINLIST NEED HELP ASAP

Answers

sulfur.
there’s no neutrons and 16 protons

The half-life of 226Ra is 1.60x103 years. How long until only 12.5% of the original sample of 226Ra remains?

Answers

Answer:

4.80×10³ years

Explanation:

Let the original amount (N₀) of ²²⁶Rn = 1 g

Therefore,

12.5% of the original amount = 12.5% × 1 = 12.5/100 × 1 = 0.125 g

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Original amount (N₀) = 1

Amount remaining (N) = 0.125 g

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

0.125 = 1/2ⁿ × 1

0.125 = 1/2ⁿ

Cross multiply

0.125 × 2ⁿ = 1

Divide both side by 0.125

2ⁿ = 1/0.125

2ⁿ = 8

Express 8 in index form with 2 as the base

2ⁿ = 2³

n = 3

Thus, 3 half-lives has elapsed.

Finally, we shall determine the time taken for only 12.5% of the original sample of ²²⁶Rn to remain.

This can be obtained as follow:

Half-life (t½) = 1.60×10³ years

Number of half-lives (n) = 3

Time (t) =?

t = n × t½

t = 3 × 1.60×10³

t = 4.80×10³ years.

Thus, it will take 4.80×10³ years for 12.5% of the original sample of ²²⁶Rn to remain.

PLEASE HELP 30 POINTS PLS PLS

Answers

22-yes, they belong to the same group
23- they are metals
24-Atoms of group 1 elements all have one electron in their outer shell. This means Na and K have the same valence electrons.
25-Metals are solids at room temperature, therefore Na and K are solid.
26- mass number=A=235
Protons=z=92
Neutrons=mass number-protons
Neutrons=A-Z
Neutrons=235-92
Neutrons=143

What is the percent composition of hydrogen in glucose

Answers

Answer:

67%

Explanation:

Thus the % composition of glucose by mass is carbon 40.0 % oxygen 53.3 % hydrogen 6.7 % in this way, the % composition by mass of any compound can be calculated provided that is formed is known.

8. Zeolite is used to remove moisture from methane. A vertical column is filled with 1000.0 kg of dry zeolite. The zeolite has the capacity to hold 0.100 kg water/kg dry zeolite. Once the zeolite becomes saturated with moisture, it must be regenerated by heating. The inlet moisture content of the methane is 7.00% (by mass) and the outlet moisture content is 0.05% (by mass). How much methane (kg) will be produced before the zeolite must be regenerated

Answers

Answer:

Follows are the solution to this question:

Explanation:

Methane inlet humidity content of [tex]=7.00\%[/tex]

Methane moisture outlet content [tex]=0.05\%[/tex]

Zeolite absorption humidity [tex]= 6.95\%[/tex]

Dry zeolite 1 kg will accommodate water[tex]= 0.1000 \ kg[/tex]

One kilogram of Dry Zeolite will carry water from [tex]=0.1000\ kg[/tex]

The water can contain 1000 kg of zeolite [tex]= 100 \ kg[/tex]

Methane which would be made [tex]=\frac{100}{6.95\%}= 1,439 \ kg[/tex]

That's why it will be producing 1439 kg of methane.

The amount of methane that can be produced before the regeneration of zeolite is 1,439 kg.

What is zeolite?

Zeolite belongs from the family of hydrated aluminosilicate minerals, in which alkali and alkaline earth metals are present.

In the question, it is given that:

Capacity of 1kg of zeolite to hold water = 0.100kg

Capacity of 1000kg of zeolite to hold water = 100kg

Inlet moisture content of the methane = 7.00 % (by mass)

Outlet moisture content of the methane = 0.05% (by mass)

Capacity of zeolite to absorb methane content = 6.95 %

Amount of methane before the regeneration of zeolite = 100kg / 6.95% = 14.39% of kg = 1,439 kg

Hence, 1,439 kg methane will be produced before the zeolite must be regenerated.

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Mg(s) + Cu(NO3)2(aq) → Mg(NO3)2(aq) + Cu(s)
How will the rate of the chemical reaction change if the solid piece of magnesium metal is ground into a powder?
Select one:
a. Increase
b. Cannot be predicted
c. Will not change
d. Decrease

Answers

Answer: increase

Explanation: when Mg is powder it has greater surface area and

Reaction occurs faster

Assuming the partial pressure of oxygen in air (0.20 atm) and nitrogen in air (0.80 atm). Calculate the mole fractions of oxygen and nitrogen in water at 298 K. FOR THIS QUESTION report the mole fraction of OXYGEN

Answers

Answer:

oxygen = 4.7 * 10^-6

Nitrogen = = 9.7 * 10^6

Explanation:

partial pressure of oxygen = 0.20 atm

partial pressure of Nitrogen = 0.80 atm

calculate the mole fractions of oxygen and Nitrogen in water

Temp = 298k

applying henry's law

molar conc of oxygen in water ( Coxygen )

= Kp = 1.3 * 10^-3 Mol/L.atm * 0.20 atm = 2.6 * 10^-4 Mol

molar conc of Nitrogen in water ( Cnitrogen )

= Kp = 6.8 * 10^-4 Mol/L.atm * 0.80 atm = 5.4 * 10^-4

next Given that the number of moles in 1 liter of water = 55.5 mol  

therefore the mole fraction of oxygen

= 2.6 * 10^-4 / 55.5

= 4.7 * 10^-6

mole fraction of Nitrogen

= 5.4 * 10^-4  / 55.5

= 9.7 * 10^6

Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. what is the balanced equation?

Answers

Fe(s) + 3CuNO3(aq) —> Fe(NO3)3(aq) + 3Cu(s)


The mass ratio of H to O in water (H2O) is 1:8. What is the mass
ratio of H to O in hydrogen peroxide (H2O2)?

Answers

Answer: 1:16

Explanation:

Rank the following compounds in order of decreasing acidity. Be sure to answer all parts. A) Benzyl alcohol B) Methylbenzene C) Benzoic acid

Answers

Benzyl alcohol = 15.4
Methyl benzene = 41
Benzoic acid = 5

so
B , A , C

The order of decreasing the acidity of the given compounds:

Benzoic acid > Benzyl alcohol > Methylbenzene.

What is the acidic strength?

The acidic strength of an acid can be described as the ability of the acid to lose its H⁺ ion. In general, the dissociation of acid can be represented as:

HA  →  H⁺  +  A⁻

Some examples of strong acids are hydrochloric acid, sulfuric acid (H2SO₄), perchloric acid  (HClO₄), etc.

The benzoic acid is a very strong acid with pka value of 4.5 as it contains the (-COOH) group. The Benzyl alcohol with pka value of 15.4 as it contains the (-CH₂OH) group attached to the benzene ring. The methylbenzene with pka value of 41 has the lowest acidity as it contains the methyl group attached to the benzene ring.

Therefore, the order of acidic strength for the given compounds is  Benzoic acid > Benzyl alcohol > Methylbenzene.

Learn more about acidic strength, here:

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calculate the percentage mass of calcium chloride, CaCi^2​

Answers

Answer: m-%(Ca) = 40.08 / 110.98

Explanation: molar mass of CaCl2 is 40.08+ 2·35.45 = 110.98

Think you have one mole substance. It contains 40.08 g Ca

QUESTION 6 Consider the following reaction between the diatomic and monatomic forms of iodine: I2 (g) <-> 2I (g) When 0.095 M I2 is initially placed in a previously empty container and sealed, the system slowly reaches equilibrium. When equilibrium is reached, it is found that there is an equilibrium concentration of 0.0055 M of the monatomic form of iodine. Calculate the (unitless) equilibrium constant Kc. Round your answer to two sig figs, and express it in scientific notation.

Answers

Answer: The equilibrium constant is [tex]3.3\times 10^{-4}[/tex]

Explanation:

Initial concentration of [tex]I_2[/tex] = 0.095 M  

The given balanced equilibrium reaction is,

                            [tex]I_2(g)\rightleftharpoons 2I(g)[/tex]

Initial conc.          0.095 M       0 M

At eqm. conc.     (0.095-x) M   (2x) M

Given : 2x = 0.0055

x = 0.00275

The expression for equilibrium constant for this reaction will be,

[tex]K_c=\frac{[l]^2}{[I_2]}[/tex]  

Now put all the given values in this expression, we get :

[tex]K_c=\frac{(0.0055)^2}{(0.095-0.00275)}[/tex]

[tex]K_c=\frac{(0.0055)^2}{0.09225}=0.00033[/tex]

Thus the equilibrium constant is [tex]3.3\times 10^{-4}[/tex]

When optically active (S)-2-methylcyclopentanone is treated with an acid (H3O ), the compound loses its optical activity. Explain this observation and draw a mechanism that shows how racemization occurs. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph.

Answers

Answer:

See explanation

Explanation:

When (S)-2-methylcyclopentanone is treated with an acid, the carbonyl oxygen atom is protonated.

This leads to the emergence of a positive charge on the cabonyl oxygen. Then the C=O bond is now transformed into H-C-OH where C is a carbocation which leads to a racemic mixture. Loss of a proton from the adjacent carbon atom completes the mechanism.

In this process, the optically active (S)-2-methylcyclopentanone is converted to a pair of diastereomers thereby loosing its optical activity.

Which of the following statements is correct?

A. 2 moles of O2 is equal to 64 g of O2.

B. 2 moles of O2 is equal to 32 g of O2.

C. 2 moles of O2 is equal to 2 g of O2.

D. 1 moles of O2 is equal to 2 g of O2.

Answers

Answer:

pretty sure its B but if not I'm sorry

2 moles of O₂ is equal to 64 g of O₂ is the only correct statement among the given statements. Hence, Option (A) is correct. It can be solved by mole concept

What is Mole concept ?

The mole, symbol mol, is the SI base unit of amount of substance.

The quantity amount of substance is a measure of how many elementary entities of a given substance are in an object or sample.

formula ;

n = given weight / molecular weight

  = 64 / 32

  = 2 moles

Therefore, 2 moles of O₂ is equal to 64 g of O₂ is the only correct statement among the given statements. Hence, Option (A) is correct.

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Which of these processes removes carbondioxide from the air?

Answers

Answer:

It’s Photosynthesis

Explanation:

Don’t click the file it’s a virus ! Also I hope I helped!

How many moles of NaHCO3 are in 2.4 x
1024 molecules of NaHCO:?

Answers

Answer:

4.0 moles NaHCO

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 2.4 × 10²⁴ molecules NaHCO

[Solve] moles NaHCO

Step 2: Identify Conversion

Avogadro's Number

Step 3: Convert

[DA] Set up:                                                                                                     [tex]\displaystyle 2.4 \cdot 10^{24} \ molecules \ NaHCO(\frac{1 \ mol \ NaHCO}{6.022 \cdot 10^{23} \ molecules \ NaHCO})[/tex][DA] Divide [Cancel out units]:                                                                       [tex]\displaystyle 3.98539 \ moles \ NaHCO[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

3.98539 moles NaHCO ≈ 4.0 moles NaHCO

Is water an element or compound

Answers

Answer:

Compound

Explanation:

H2O is made up of multiple types of atoms, which makes it a compound. It isn't an element because they only consist of one type of atom.

PLEASE PLEAS HELP I REALLY NEED IT

Answers

Answer:  

A i took the quiz

Explanation:

A chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms,

zinc nitrate and the precipitate gold.

Answers

Explanation:

Gold (AU)................

How many grams are in 1.2 x 10^24 atoms of sodium?

Answers

Use avagadros number

How many moles of LiOH are in a 4.5 M solution containing 1.5 L of water?

Answers

Answer:

d

Explanation:

Match the box basically lol

Answers

Transform goes to the bottom one divergent goes to the first one and convergent goes to the middle one

A change resulting in one or more new substances being formed is a?

A. nuclear reaction
B.physical property
C. chemical change
D.physical change

Answers

Answer:

C. Chemical change

Explanation:

A physical change is where something is changed but it doesnt affect the build up of the chemical. For example, if you broke sticks and threw them on the ground, that would be a physical change because the change is happening to the physical being of the object and not its chemical buildup. However, if you lit those sticks on fire, that would be considered a chemical change because you end up with two substances, ash and the remnants of the stick. A nuclear reaction would result in something blowing up so its not that. And a physical property is like what it looks like or how it smells. Hope I helped you!

Mg(s) + 2HCl (aq) -----> MgCl2 (aq) + H2

You have 6.00 g HCl and 4.8 g Mg.
What is the limiting reaction

Answers

Answer:

HCl is the limiting reactant

Explanation:

To find the limiting reactant of a reaction we must find the moles of each one as follows:

Moles Mg (Molar mass: 24.305g/mol)

4.8g Mg * (qmol / 24.305g) = 0.20 moles Mg

Moles HCl (Molar mass: 36.46g/mol)

6.00g HCl* (1mol / 36.46g) = 0.165 moles HCl

Based on the chemical reaction, for a complete reaction of 0.20 moles of Mg are necessaries:

0.20 moles Mg * (2mol HCl / 1mol Mg) = 0.40 moles HCl

As there are just 0.165 moles of HCl:

HCl is the limiting reactant

Identify the techniques used in the work-up and characterization of benzoic acid. The analytical method used to confirm the structure and functional groups of the product NMR spectroscopy The technique used to separate the pure product from any excess reagent, impurities, and byproducts Recrystallization The quick, numeric analysis used to characterize the product and assess the purity Melting point.

Answers

Answer:

Explanation:

[tex]\text{From the list of the options given; we are to identify the suitable techniques} \\ \\ \text{for the characterization of benzoic acid.}[/tex]

[tex]\text{The analytical method used to confirm the structure and functional groups}\\ \\ \text{present in the product is} \ \ \mathbf{IR \ spectroscopy.}[/tex]

[tex]\text{The technique used to separate pure products from any excess reagents,} \\ \\ \text{impurities, and byproducts is}\ \ \mathbf{Recrystallization.}[/tex]

[tex]\text{The quick, numeric analysis done to characterize the product and assess the purity is}[/tex][tex]\mathbf{melting \ point.}[/tex]

How many Calories are in 5,926 joules

Answers

5926 Joule/Gram °C (J/g∙°C)

=

1415.40078 Calorie/Gram °C (cal/g∙°C)
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