How many moles are present in 29.4g of Aluminum (AI)? *

Answer:

it is formed by covalent bonds. the oxygen atom shares one elctron with each chlorine atom, forming single covalent bonds ( cl — o — cl )

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Answer:

what are the awnser choices

Answer: D: plutonium-239

Explanation: Got it right on the quiz

The table below shows a list of radioisotopes and their half-lives.

A 2-columns table with 10 rows. Column 1 is labeled radioisotope. Column 2 is labeled half-life. Lithium-5, 3 × 10⁻²² seconds; polonium-211, 0.516 seconds; Barium-139, 82.7 minutes; uranium-240, 14.1 hours; Bismuth-210, 5.012 days; uranium 232, 68.9 years; carbon-14, 5730 years; plutonium-239, 24,065 years; beryllium-10, 1.6 × 10⁵ years; uranium-238, 4.5 times 10 to the 9 years.

The radioisotope that has the longest half-life is the best to use in powering planet and space exploration vehicles because they can travel farther. The radioisotope is the best to use is:

d) plutonium-239

Plutonium-239 has the longest half-life of all the radioisotopes listed, at 24,065 years. This means that it will take 24,065 years for half of the plutonium-239 in a sample to decay. This makes it a good choice for powering planet and space exploration vehicles because it will last for a long time.

The other radioisotopes listed have much shorter half-lives. Lithium-5 has a half-life of 3 × 10⁻²² seconds, polonium-211 has a half-life of 0.516 seconds, barium-139 has a half-life of 82.7 minutes, uranium-240 has a half-life of 14.1 hours, bismuth-210 has a half-life of 5.012 days, uranium-232 has a half-life of 68.9 years, carbon-14 has a half-life of 5,730 years, and beryllium-10 has a half-life of 1.6 × 10⁵ years.

So, the best radioisotope to use for powering planet and space exploration vehicles is plutonium-239. It has the longest half-life, which means that it will last for a long time and provide a steady source of power.

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Answer:

A

Explanation:

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Answer:

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CaO + 2H2O + Ca(OH)2 is a balance chemical equation. Therefore, option A is correct.

A balanced chemical equation is one that has the same number of atoms of each type in the reaction on both the reactant and product sides. In a balanced chemical equation, both the mass and the change are equal.

When a chemical reaction occurs, the mass of the products should be equal to the mass of the reactants, according to the law of conservation of mass. As a result, the number of atoms in each element remains constant during the chemical reaction. As a result, the chemical equation must be corrected.

The chemical equation is said to be balanced if there are no inequalities. Every element in this example now has an equal number of atoms on both the reactant and product sides.

Thus, option A is correct.

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Answer:

Hello

so ur answer is

56.74L

Explanation:

thanks... hope it helps

there are 12 atoms of mg in the following equations

Answer:

[tex]\boxed {\boxed {\sf 12 \ Mg \ atoms }}[/tex]

Explanation:

We are given this formula:

[tex](Mg_3N_2)_4[/tex]

We want to find the number of magnesium atoms. We can see that there is a subscript of 3 after the magnesium, so there are 3 magnesium atoms in 1 molecule of the compound.

However, there is a subscript of 4 that comes after the entire compound, so there are actually 4 molecules, with each molecule containing 3 magnesium atoms. Multiply 4 and 3.

There are 12 magnesium atoms.

Explanation:

The balanced equation for the reaction between NaOH and H2SO4 is given as;

2NaOH + H2SO4 → Na2SO4 + 2H2O  

2 mol of NaOH reacts with 1 mol of H2SO4

5g of NaOH was dissolved in 1000cm3.

Mass = 5 g

Molar mass = 40 g/mol

Volume = 1000 cm3 = 1 L

Number of moles = Mass / Molar mass

Number of moles = 5 / 40 = 0.125 mol

Molarity = Number of moles / Volume

Molarity = 0.125 / 1 = 0.125 M

25cm3 of this solution neutralized 28.3cm3 of solution containing 7.2gdm-3 of impure H2SO4.

CaVa / CbVb = Na / Nb ; where a = acid and b = base

Va = 28.3cm3

Vb = 25cm3

Ca = ?

Cb = 0.125 M

Na = 1

Nb = 2

I. The molarity of H2SO4

Solving for Ca;

Ca = CbVb * Na / (Va * Nb)

Cb = (0.125 * 25 * 1 ) / ( 28.3 * 2)

Cb = 0.0552 M

II. The concentration of the pure acid on gdm-3

Molarity = Mass conc / Molar mass

Mass Conc = Molarity * Molar mass

Mass Conc = 0.0552 * 98.079

Mass Conc = 5.41 g/dm3

III. % impurity of the acid

Percentage Impurity = Mass of pure / Mass of Impure   *  100

Percentage Impurity = 5..41 / 7.2 * 100

Percentage Impurity = 75.14%

Answer:

B. The bonds are polar and the molecule is nonpolar.

Explanation:

Each bond in the molecule is polar, as indicated by the partial charges on the atoms of the molecule. However, the four atoms are arranged symmetrically around the central atom. In this case, the effects of the partial charges on opposite sides cancel out. As a result, the molecule as a whole is nonpolar. If exposed to an electric field, the molecule will not orient itself in any particular direction.

answer:

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Answer:

Number of moles = 0.075 mol

Explanation:

Volume = 500.0 mL = 0.5 (Converting to L by dividing by 1000)

Molarity = 0.15 M

Number of moles = ?

The relationship between the quantities is given as;

Molarity  = Number of moles / Volume

Number of moles = Molarity * Volume

Number of moles = 0.15  * 0.5

Number of moles = 0.075 mol

Answer:

6 N.

Every thing has equal and opposite reaction.

Answer:

The answer is C I believe, I do not know for sure but I think that is the answer..

I'm sorry if I'm wrong.

Explanation:

Answer:

Temporary hardness is a type of water hardness caused by the presence of dissolved bicarbonate minerals (calcium bicarbonate and magnesium bicarbonate). ... However, unlike the permanent hardness caused by sulfate and chloride compounds, this "temporary" hardness can be reduced by boiling the water.

Answer:

carbon monoxide (CO)

Explanation:

carbon monoxide (CO) is oxidized because it gains oxygen to turn to carbon dioxide (CO2)

Answer:

iron and carbon:steel:copper and tin: metal

Answer:

A

Explanation:

If a convergent boundary involves a continental landmass and an ocean basin, a subduction zone forms. Subduction occurs where a plate moves underneath the other.

A sample of gas at 62.0°C occupies a volume of 4.80 L at a pressure of 2.90 atm. 0.506 moles of gas are contained in the sample.

Inside the World System of Units, the mole is indeed the unit of substance amount (SI). How many fundamental entities of a particular substance are present in an object and sample is determined by the quantity of that material. There are precisely 6.022×10²³ elementary entities in a mole.

An elementary entity can be an atoms, a molecule, an ion, and ion pair, or a fundamental particle like an electron depending upon what the substance is. For instance, although having differing volumes and masses, 10 moles liquid water as well as ten moles of mercury both contain the same quantity of material, as well as the mercury includes exactly one atom with each molecule of water.

PV = nRT

n = PV/RT

P = 2.90 atm

V = 4.80 L

R = 0.08206 L atm / mol K

T = 62.0 + 273 = 335 K

n = (2.90 •4.80) / (0.08206 • 335)

   = 0.506 moles of gas

Therefore, 0.506 moles of gas are contained in the sample.

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Answer:

10 atm.

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

P1 = 5 atm

P2 = ?

V1 = 4L

V2 = 2L

T1 = 25°C = 25 + 273 = 298K

T2 = 25°C = 298K

Using P1V1/T1 = P2V2/T2

5 × 4/298 = P2 × 2/298

20/298 = 2P2/298

Cross multiply

298 × 20 = 298 × 2P2

5960 = 596P2

P2 = 5960 ÷ 596

P2 = 10 atm.

✧ [tex] \underline{ \underline{ \large{ \tt{A \: N \:S \: W \: E \: R}}}} : [/tex]

[tex] \underline{ \underline{ \large{ \text{Molecular \: Formulaes}}}} : [/tex]

⇾ [tex] \large{ \text{Potassium \: Hydroxide : K \: OH}}[/tex]

⇾ [tex] \large{ \text{Sodium \: Chloride : NaCl}}[/tex]

⇾ [tex] \large{ \text{Sodium \: Hydroxide : NaOH}}[/tex]

⇾ [tex] \large{ \text{Calcium \: Chloride : CaCl}}[/tex]

⇾ [tex] \large{ \text{Sodium \: Bicarbonate} : \tt{Na ( HCO)_{ 3} }}[/tex]

---------------------------------------------------------

☥ [tex] \underline{ \underline{ \large{ \tt{ \: E \: X\: P \: L\: A\: N \: A \: T \: I \: O \: N}}} }: [/tex]

[tex] \underline{ \underline{ \text{Writing \: a \: molecular \: formula}}} : [/tex]

To write a molecular formula , the following steps are usually adopted only when we know the symbol and valencies of elements and radicals present in a molecule.

Step 1 : First , the name of the compound is written.

Step 2 : The symbols of basic and acidic radicals are written side by side.

Step 3 : The valency of each radical is written at the right upper corner of the symbol. The valency of one radical is transferred to another radical and it is written on the right hand side at the bottom corner. If necessary , L.C.M of the valencies us taken to get a simple whole number.

Step 4 : If a compound radical takes part in the molecular formula , the radical is enclosed in brackets and the valency number is written on the right side of the bracket at the bottom of the formula.

For instance :

[tex] \text{Calcium \: \: \: \: \: \: Sulphate}[/tex] [ compound ]

1. [tex] \sf{Ca \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: SO_{4} }[/tex] [ Symbol of basic and acidic radicals ]

2.We know : Valencies of calcium and sulphate are 2 and 2 respectively

3. [tex] \sf{Ca_{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (SO_{4} )_{2} }[/tex] [ Valencies are exchanged and compound radical is enclosed in bracket ]

4.[tex] \sf{CaSO_{4}}[/tex] [ L.C.M is taken to get molecular formula of calcium sulphate ]

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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Answer:

0.05 M

Explanation:

First we convert 12 g of NaHSO₄ into moles, using the given molar mass:

We can now calculate the molarity of the resulting solution, using the calculated number of moles and the given volume:

Answer:

The molarity of the resulting NaHSO₄ solution is 0.05 [tex]\frac{moles}{liter}[/tex]

Explanation:

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

[tex]Molarity=\frac{moles of solute}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

Molar mass is the amount of mass that a substance contains in one mole. Being the molar mass of the compound NaHSO₄ equal to 120.1 g/mole, then the number of moles that 12 grams contain is calculated by:

[tex]12 g*\frac{1 mole}{120.1 g} = 0.1 moles[/tex]

And being 2 L the volume of the solution, then replacing in the definition of molarity you get:

[tex]Molarity=\frac{0.1 moles}{2 L}[/tex]

Molarity= 0.05 [tex]\frac{moles}{liter}[/tex]

The molarity of the resulting NaHSO₄ solution is 0.05 [tex]\frac{moles}{liter}[/tex]

Answer: yes, it's soluble in water.

Answer: 3.6 x 1023 molecules and 0.143 Litres

Answer:

-Warm air sinks, creating an area of low pressure.

Explanation:

Heat will weigh more, than cool air!

Answer:

theirs nothing there?!!!??!?!?!??!!?!?!?!?!??!?!??!?!?!??!?!

Explanation:

whys it just a blank picture

Answer:

C energy source

Explanation:

I got this right

Answer:

c

Explanation: