Answer:
34.67 WExplanation:
Power is the rate at which work is done and can be found by using the formula
[tex]p = \frac{w}{t} \\ [/tex]
p is the power in Watts (W)
w is the workdone in joules
t is time in s
but workdone = force × distance
From the question
force = 780 N
distance = 2 m
workdone = 780 × 2 = 1560 N
Since we now have the value of workdone we can find the power
We have
[tex]p = \frac{1560}{45} = 34.6666666... \\ [/tex]
We have the final answer as
34.67 WHope this helps you
How does NaOH form a basic solution when it dissolves in water
When NaOH is added to water, it separates into Na+ and OH-. The hydroxyls make it more basic.
What is basic solution?A basic solution is an aqueous solution containing more OH⁻ ions than H⁺ ions.
When NaOH as a solute is mixed into the solvent like water, it separates NaOH into Na+ and OH-. The sodium ions Na⁺ have little effect on the solution, but the hydroxyls OH⁻ ions makes the solution more basic.
Thus, NaOH form a basic solution by the presence of OH⁻ ions into it.
Learn more about basic solution.
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Maria drove 100 miles in 2 hrs. what was marias speed?
A student on a bicycle decided to determine his acceleration when coasting down a steep hill. The student started from a full stop and reached a velocity of 8.75 m/s in 3.8 s. What was his average acceleration? Assume that downhill is the positive direction.
Answer:
A=2.2
Explanation:
You have to lay everything out first.
You are given the:
Velocity and the time
V=8.75m/s
t=3.8s
Now you need to know what you are looking for, and that is the average acceleration.
Write down the formula (teachers like this)
A=v/t
Now calculate:
8.75/3.8= 2.3026315789473
You can now round down since the number next to the decimal is below 5
The number of significant digits will be 2 because that is the lowest number in the question. This means you will only need to display 2 numbers.
The final answer will be:
A=2.2
:)
*make sure to show your work step by step, some nice teachers give extra marks for that*
I hope this helped, goodluck! :D
which constellation is in contrast with ursa major
Answer: Ursa Major (/ˈɜːrsə ˈmeɪdʒər/; also known as the Great Bear) is a constellation in the northern sky, whose associated mythology likely dates back into prehistory. Its Latin name means "greater (or larger) she-bear," referring to and contrasting it with nearby Ursa Minor, the lesser bear.
Bordering constellations: Draco; Cameloparda...
Brightest star: ε UMa (Alioth) (1.76m)
Meteor showers: Alpha Ursa Majorids; Leonid...
Symbolism: the Great Bear
What is Newton's 1st Law?
Forces come in pairs that are equal in size and opposite in direction.
F=ma
An object in motion will stay in motion at the same speed and in the same direction (ie with constant velocity) unless a force makes it change.
Answer:
An object in motion will stay in motion at the same speed and in the same direction (ie with constant velocity) unless a force makes it change.
Explanation:
Help it multiple-choice 16 and 17 only
Answer:
16. c
17. d
Explanation:
16. Newton’s third law states that a force will always have an opposite but equal force as a reaction, so every force comes as a pair of action-reaction forces. For example, if you push on a book, the book also pushes on you.
17. If 1cm represents 15N, then 5cm must represent 15N*5=75N.
The diagram shows a 1-newton metal disk resting on an index card that is balanced on top of a glass.
Metal disk
Index
card
Glass
When the index card is quickly pulled away from the glass in a horizontal direction, the disk falls straight down into the glass,
Which statement explains this action?
o The action is a result of the disk's shape.
The action is a result of the disk's charge.
o The action is a result of the disk's inertia.
o The action is a result of the disk's temperature.
Answer:
The action is a result of the disk’s inertia.
Explanation:
what is the net force required to give an automobile with a mass of 1,600 kg an acceleration of 4.5m/s
Hi there!
Recall Newton's Second Law:
[tex]\large\boxed{\Sigma F = ma}}[/tex]
∑F = Net force (N)
m = mass (kg)
a = acceleration (m/s²)
We are already given the mass and acceleration, so we can plug these values into the equation:
∑F = 1600 · 4.5 = 7200 N
which planet should punch travel to if his goal is to weigh in at 118 lb? refer to the table of planetary masses and radii given to determine your answer.
The planet that Punch should travel to in order to weigh 118 lb is Pentune.
The given parameters:Weight of Punch on Earth = 236 lbDesired weight = 118 lbThe mass of Punch will be constant in every planet;
[tex]W = mg\\\\m = \frac{W}{g}\\\\m = \frac{236}{g}[/tex]
The acceleration due to gravity of each planet with respect to Earth is calculated by using the following relationship;
[tex]F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}[/tex]
where;
M is the mass of Earth = 5.972 x 10²⁴ kgR is the Radius of Earth = 6,371 kmFor Planet Tehar;
[tex]g_T =\frac{G \times 2.1M}{(0.8R)^2} \\\\g_T = 3.28(\frac{GM}{R^2} )\\\\g_T = 3.28 g[/tex]
For planet Loput:
[tex]g_L =\frac{G \times 5.6M}{(1.7R)^2} \\\\g_L = 1.94(\frac{GM}{R^2} )\\\\g_L = 1.94g[/tex]
For planet Cremury:
[tex]g_C =\frac{G \times 0.36M}{(0.3R)^2} \\\\g_C = 4(\frac{GM}{R^2} )\\\\g_C = 4 g[/tex]
For Planet Suven:
[tex]g_s =\frac{G \times 12M}{(2.8R)^2} \\\\g_s = 1.53(\frac{GM}{R^2} )\\\\g_s = 1.53 g[/tex]
For Planet Pentune;
[tex]g_P =\frac{G \times 8.3 }{(4.1R)^2} \\\\g_P = 0.5(\frac{GM}{R^2} )\\\\g_P = 0.5 g[/tex]
For Planet Rams;
[tex]g_R =\frac{G \times 9.3M}{(4R)^2} \\\\g_R = 0.58(\frac{GM}{R^2} )\\\\g_R = 0.58 g[/tex]
The weight Punch on Each Planet at a constant mass is calculated as follows;
[tex]W = mg\\\\W_T = mg_T\\\\W_T = \frac{236}{g} \times 3.28g = 774.08 \ lb\\\\W_L = \frac{236}{g} \times 1.94g =457.84 \ lb\\\\ W_C = \frac{236}{g}\times 4g = 944 \ lb \\\\ W_S = \frac{236}{g} \times 1.53g = 361.08 \ lb\\\\W_P = \frac{236}{g} \times 0.5 g = 118 \ lb\\\\W_R = \frac{236}{g} \times 0.58 g = 136.88 \ lb[/tex]
Thus, the planet that Punch should travel to in order to weigh 118 lb is Pentune.
The complete question is below:
Which planet should Punch travel to if his goal is to weigh in at 118 lb? Refer to the table of planetary masses and radii given to determine your answer.
Punch Taut is a down-on-his-luck heavyweight boxer. One day, he steps on the bathroom scale and "weighs in" at 236 lb. Unhappy with his recent bouts, Punch decides to go to a different planet where he would weigh in at 118 lb so that he can compete with the bantamweights who are not allowed to exceed 118 lb. His plan is to travel to Xobing, a newly discovered star with a planetary system. Here is a table listing the planets in that system (find the image attached).
In the table, the mass and the radius of each planet are given in terms of the corresponding properties of the earth. For instance, Tehar has a mass equal to 2.1 earth masses and a radius equal to 0.80 earth radii.
Learn more about effect of gravity on weight here: https://brainly.com/question/3908593
The ratio between the force of friction and the normal force is called:
A.the drag
B.rolling friction
C.the coefficient of friction
D.the starting friction
Answer:
C.the coefficient of friction
Explanation:
Hope this helps. can i have brainliest thanks!
A 2 kg wagon is being pulled by a kid with a force of 0.1 N to the right. Determine the acceleration of the wagon
Answer:
0.2 m/s^2
Explanation:
a = fm
a = 2 x .1
a = 0.2 m/s^2
In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the two balls collide, the final momentum of the cue ball is 0.01 kg m/s
Answer: 0.22
Explanation: Subtract 0.01kg from 0.23kg
45. What is the wovelength of a 30. Hertz periodic
wave moving ol 60. meters per second?
a. 0.50m
c. m
b 20m
d 1800 m
The wavelength is 2m.
Hence, Option c) 2m is the correct answer
Given that;
Frequency; [tex]f = 30Hz[/tex]
Speed; [tex]v = 60m/s[/tex]
Wavelength; [tex]\lambda =\ ?[/tex]
using the expression for the relations between wavelength, frequency and speed of wave:
[tex]\lambda = \frac{v}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is frequency and v is speed.
We substitute our given values into the equation
[tex]\lambda = \frac{60m/s}{30Hz}\\\\\lambda = \frac{60m/s}{30s^{-1}}\\\\\lambda = 2m[/tex]
The wavelength is 2m.
Hence, Option c) 2m is the correct answer.
To learn more about wavelength, click here: https://brainly.com/question/1347107
The frequency of the moving wave is 30 Hz and if it is moving at the speed of 60 m/s then the wavelength will be equal to 2 m.
What is Wavelength?The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm).
The wavelength is more frequently described in nanometers (nm), which are units of 10⁻⁹ m, or angstroms, which are units of 10⁻¹⁰ m, for infrared (IR), visible light (UV), and gamma radiation.
As per the provided given data in the question,
Frequency, f = 30 Hz
Speed, v = 60 m/s
Then, the wavelength of the moving wave will be,
λ = v/f
= 60/30
λ = 2 meters.
Therefore, the wavelength will be 2 meters.
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15. Find the density of a certain object that has the dimensions 2cm x 6cm x 7cm and a
mass of 42g.
16. What is the volume of a container of liquid that has a density of 120g/ml and a mass
of 17g.
17. If the mass of an object has a mass of 23g and a volume 123ml, what is its density.
“Express your answer in Kg/ml!"
18. What is the volume of a cubed object with a measure of 12cm on one of its sides, if
the mass of that same object is 45g and its density is 240g/cm3?
19. An object with a density of 3g/ml is placed into a body of water. Since the density of
water is 1g/ml, will this object sink or float.
This question is asking for five different questions about density, mass and volume which can be all summarized with the following definition of density as the degree of compactness of the objects taken into consideration:
[tex]\rho =\frac{m}{V}[/tex]
In such a way, we can proceed as follows:
15. the mass is given as 42 g and the volume can be found by multiplying the given dimensions:
[tex]V=2cm*6cm*7cm=84 cm^3[/tex]
And the density turns out to be:
[tex]\rho =\frac{42g}{84cm^3}=0.5 g/cm^3[/tex]
16. both mass and density are given as 17 g and 120 g/mL respectively, so that we have to solve for the volume as shown below:
[tex]V=\frac{m}{\rho} =\frac{17g}{120g/mL} =0.14 mL[/tex]
17. the mass is given as 23 g and the volume as 123 mL, so that the density is calculated as shown below:
[tex]\rho=\frac{23g}{123 mL} =0.19 g/mL[/tex]
Which can be converted to kg/mL as follows:
[tex]0.19\frac{g}{mL} *\frac{1kg}{1000g}=0.00019 kg/mL[/tex]
18. the mass is given as 45 g and the density as 240 g/cm³, so we can solve for the volume as follows:
[tex]V=\frac{m}{\rho} =\frac{45g}{240g/cm^3}=0.19 cm^3[/tex]
19. In this case, since the water has lower density than the object, we can infer that the latter is heavier than the former, this means that the object will sink according to the Archimedes principle.
Learn more:
(Density) https://brainly.com/question/952755What is the momentum of a 5 kg object that has a velocity of 1. 2 m/s? 3. 8 kg • m/s 4. 2 kg • m/s 6. 0 kg • m/s 6. 2 kg • m/s.
Answer:
6 kg.m/s
Explanation:
Momentum is the product of mass and velocity. So,
p = mvHere,
p denotes momentum [?]m denotes mass [5kg]v denotes velocity [1.2 m/s]→ p = 5 kg × 1.2 m/s
→ p = (5 × 1.2) kg.m/s
→ p = (5 × 12/10) kg.m/s
→ p = 12/2 kg.m/s
→ p = 6 kg.m/s
Therefore, momentum of the object is 6 kg.m/s.
The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
MOMENTUM:Momentum of a substance is the product of its mass and velocity. That is;
Momentum (p) = mass (m) × velocity (v)
According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:
Momentum = 5kg × 1.2m/s
Momentum = 6kgm/s.
Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
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if the spring balance with the iron ball is relaesed what reading will the spring balance record and wht
Answer:
when it is released the reading will be zero because gravitational force acts on it you can also say as free fall body
Explanation:
Which shows the weight of an atom?
atomic mass
atomic number
chemical symbol
none of the above
Answer:
Atomic mass
Explanation:
Answer:
atomic mass
Click thanks if thankc if this helped
when did humans learn that the earth is not the center of the universe?
Answer:
When did humans learn that the Earth is not the center of the universe?
Answer
1
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4 Answers
Asked in 3 Spaces


Science - Next Generation
Alexander Somm
, Consultant, Investor Relations at Novelpharm AG (2015-present)
Answered Oct 16
What, it isn’t?!
Sorry, I had to.
As far as I have read and understood, the Sumerians and later the Babylonians both had astronomical calendars that already differentiated planets and stars. Earth was not the center to them, the Sun likely was. That was around 2,200 - 1,600 BC.
After that, Greek philosopher Aristarchus of Samos (310 - 230 BC) was the first (recorded) to have believed the solar system was organized around the Sun, rather than the Earth. His heliocentric model was unpopular during Aristarchus’ lifetime, although it would inspire astronomers centuries later, such as Copernicus and Galileo.
Now, there are numerous archeological findings (cave paintings) and studies, that all suggest an understanding of complex astronomy in prehistoric times dating back as far as 40,000 years. This also explains how early, prehistoric migrants may have navigated the seas.
Explanation:
hope it helps
have a good day
Which model below shows the positions of the Sun, Moon, and Earth that have the greatest effect on ocean tides?
Answer:
Below!
Explanation:
Referring to the picture, we can conclude that the picture J will have the most effect on ocean tides.
Whichever model is similar to model J in the picture will be your answer.
Hoped this helped.
what does the geocentric model of the solar system look like
which technique of extrasolar planet detection can tell us about the orbital period of a planet?
what are some examples of non-inertial reference frames, and how exactly can we prove they're non inertial?
Answer:Passengers instinctively use the car as a frame of reference, while a physicist uses Earth. ... In such a frame of reference, Newton's laws of motion take the form given in Dynamics: Newton's Laws of Motion The car is a non-inertial frame of reference because it is accelerated to the side.
Explanation: Example of inertial and Noninertial Frame of Reference
The momentum of a system is conserved:
I. when no net external force act on the system
II. when no internal forces act on the system
III. always
Answer:
I. when no net external force act on the system
Explanation:
Suppose you are exerting an external force F on an object, it's velocity keeps increasing. Which means its momentum = velocity * mass is also increasing. In this case the initial momentum of that object is not preserved (but increased).
A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head on collision with a 14.0 kg raft moving to the right at 16.0 m/s after the collision the raft moves to the left at 14.4 m/s assuming water simulates a frictionless surface, what is the final velocity of the canoe?
Answer:
The final velocity of the canoe is -14.1 m/s or 14.1 m/s to the right.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Please HELP
6. A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed
of 10.0-m/s.
a.
If the rope can only tolerate 400-N of force, what is the maximum speed the bucket can
experience before the rope snaps? {Hint: Let the centripetal force be 400-N and solve for the speed)
Answer:
Explanation:
hope this helps
The maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.
What is force?Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.
Newton is a unit of force used by physicists that is part of the International System (SI). The force required to move a body weighing one kilogram one meter per second is known as a newton.
Given:
The mass of the bucket, m = 3.4 kg,
The length of the rope, r = 1 m,
The speed of the bucket, v = 10 m / s,
The force of the rope, F = 400 N,
Calculate the maximum speed by the formula given below,
[tex]F_c = mv^2 / r[/tex]
400 = 3.4 v² / 1
v² = 400 / 3.4
v² = 117.6
v = 10.85 m / s
Therefore, the maximum speed of the bucket can experience before the rope snaps if A 3.4-kg bucket of water is attached to a 1.0-m rope. The bucket is swung in a circle at a speed of 10.0-m/s is 10.85 m / s.
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what voltage is measured across the 15 ohm resistor
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.50 m. It takes the ball 0.70 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path. (3 points)
0.60 N, along the line tangent to the circle
0.015 N, along the line tangent to the circle
0.60 N, toward the center of the circle
0.015 N, toward the center of the circle
Answer:
0.60N along the line tangent to the circle
Answer:
A is the answer
Explanation:
Just got finished with the quiz! Hope this helps <3
The gravitational potential energy of the ball changes as it bounces. Where is the ball located when its gravitational potential energy is greatest? Where is the ball when its gravitational potential energy has the least value?
When the planet is closest to the Sun, speed v and kinetic energy are the highest, and gravitational potential energy is the lowest. When the planet moves farther away, the speed and kinetic energy decrease, and the gravitational potential energy increases.
Depth perception is also known as ___________ vision.
Answer:
depth from optical expansion
Explanation:
Stewart (70 Kg) is attracted to Ms. Little (60 Kg) who sits 2 m away. What is the gravitational attraction between them? G=6.67×10^-11 (-11 is an exponent)
Happy Holidays!
We can use the following equation to solve for the gravitational force:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]
Fg = force due to gravity (N)
G = Gravitational constant
m1,m2 = masses of the objects (kg)
r = distance between the objects (m)
Plug in the given values into the equation:
[tex]F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}[/tex]