how would you write 4.3756 in standard decimal form

Answers

Answer 1
It can be 5.64x10^-7
5.64x 10^8

Related Questions

(kg)
The table shows the relationship between the masses of two objects, the distance between the
two objects, and the gravitational force between the objects
Mass
of Object 1 Mass of Object 2 Distance between Gravitational
(kg)
Objects 1 and 2 Force between
(m)
Objects 1 and 2
(N)
1
16
2G
2
1 G
3
3
9 G
9
3
3
3G
1
2
1
6. Which conclusion is supported by the data in the table? (1 point)
An increase in the mass of an object causes the same decrease in the gravitational force
An increase in the distance between the objects causes the same decrease in the gravitational force
An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass.
An increase in the mass causes a greater change in the gravitational force than the same increase in the distance between the objects

Answers

Answer:

(C) an increase in tue distance between the ibject causes a greater change in the gravitational force than the same increase in mass

Hope this helps

Answer:

C: An increase in the distance between the objects causes a greater change in the gravitational force than the same increase in mass.

Explanation:

it's C on edge! hope this helps!!~ (❁´▽`❁)*✲゚*

What is the lithosphere?
A. the outer layer of the Earth's crust
B. the inner core
C. the middle portion of the mantle
D. the outer core

Answers

A. The outer layer of the earth

Answer:

a. outer layer

Explanation:

lithosphere is right underneath the continental and ocean crust. it is approximately 100 km in deep and it is a brittle layer. It is broken into tectonic plates.

the inner core is located at the very center and its full of iron and nickel (so its not B)

on top of that is the outer core which is liquid (not D)

the middle portion of the mantle is the asthenosphere and mesosphere. they are right beneath the lithosphere. (not C)

so the best answer is A

The reason why you should always exercise your abdominal during an exercise session is :

(A) because you will be fully warmed up
(B) you can focus on this muscle better
(C) because is the abdominal muscle is needed in all exercises during a workout
(D) because most people do it that way
(E) it does not really matter if you exercise the abdominal first or last

Answers

The answer to the question is C

The wavelength of a water wave is 54 m. It has a frequency of 0.03 Hz. What is the velocity of the wave?

Answers

Answer:

1.62 m/s

Explanation:

Wavelength of the water wave= 54 m

The frequency is 0.03 Hz

Therefore the velocity can be calculated as follows

Velocity= frequency × wavelength

= 0.03 × 54

= 1.62 m/s

What's a Weber?
in electromagnetism​

Answers

Answer:

In physics, the weber is the SI derived unit of magnetic flux. A flux density of one Wb/m2 (one weber per square metre) is one tesla.

Hope it helps !

Answer:

Weber unit of magnetic flux in the international system of units (SI), defined as the amount flux that, linking an electrical circuit of one turn (one loop of wire) , produces in it an electromotive force of one volt as the flux is reduced to zero as a uniform rate in one second .

it was named in honour of the 19th century German physicist Wilhelm Eduard Weber

A PERSON GETTING OUT OF MOVING BUS FALLS IN THE DIRECTION OF MOTION OF THE BUS. WHY? ​

Answers

Answer:

PLEASE MARK AS BRAINLIEST!!

Explanation:

A getting passenger getting down from a moving bus, falls in the direction of the motion of the bus. This is because his feet come to rest on touching the ground and the remaining body continues to move due to inertia of motion.

Answer:

When the person steps on the ground, his feet do not move but his upper body moves in the direction of the bus due to inertia of its motion. Since his upper body moves in the forward direction and his lower body does not move, the person falls in the forward direction.

Describe the Rutherford model

Answers

Answer:

The Rutherford model was devised by the New Zealand-born physicist Ernest Rutherford to describe an atom. Rutherford directed the Geiger–Marsden experiment in 1909, which suggested, upon Rutherford's 1911 analysis, that J. J. Thomson's plum pudding model of the atom was incorrect.

Atomic theory year: 1911

Explanation:

Hope this helps, Merry Christmas, and have a good day

Find the total charge of a system consists 2X10^4 electrons.

Answers

ANSWER: The first thing to learn is how to convert numbers back and forth between scientific notation and ordinary decimal notation. The expression "10n", where n is a whole number, simply means "10 raised to the nth power," or in other words, a number gotten by using 10 as a factor n times:

105 = 10 x 10 x 10 x 10 x 10 = 100,000 (5 zeros)

108 = 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 = 100,000,000 (8 zeros)

Notice that the number of zeros in the ordinary decimal expression is exactly equal to the power to which 10 is raised.

If the number is expressed in words, first write it down as an ordinary decimal number and then convert. Thus, "ten million" becomes 10,000,000. There are seven zeros, so in powers of ten notation ten million is written 107.

A number which is some power of 1/10 can also be expressed easily in scientific notation. By definition,

1/10 = 10-1     ("ten to the minus one power")

More generally, the expression "10-n" (where n is a whole number) means ( 1/10 )n. Thus

10-3 = ( 1 / 10 )3 = 1 / ( 10 x 10 x 10) = 1/1000

10-8 = ( 1 / 10 )8 = 1/100,000,000

Scientific notation was invented to help scientists (and science students!)deal with very large and very small numbers, without getting lost in all the zeros. Now answer the following on a separate sheet of paper and check your answers by clicking on "Answers":

Explanation:

800 because 10x10x10x10 equals 400 and 400x2 equals800

A child of mass m is at the edge of a merry-go-round of diameter d. When the merry-go-round is rotating with angular acceleration α, the torque on the child is τ. The child moves to a position half way between the center and edge of the merry-go-round, and the angular acceleration increases to 2α. The torque on the child is now

Answers

Answer:

The torque on the child is now the same, τ.

Explanation:

It can be showed that the external torque applied by a net force on a rigid body, is equal to the product of the moment of inertia of the body with respect to the axis of rotation, times the angular acceleration.In this case, as the movement of the child doesn't create an external torque, the torque must remain the same.The moment of inertia is the sum of the moment of inertia of the merry-go-round (the same that for a solid disk) plus the product of  the mass of the child times the square of the distance to the center.When the child is standing at the edge of the merry-go-round, the moment of inertia is as follows:

       [tex]I_{to} = I_{d} + m*r^{2} = m*\frac{r^{2}}{2} + m*r^{2} = \frac{3}{2}* m*r^{2} (1)[/tex]

So, τ = 3/2*m*r²*α (2)When the child moves to a position half way between the center and the edge of the merry-go-round, the moment of inertia of the child decreases, as the distance to the center is less than before, as follows:

       [tex]I_{t} = I_{d} + m*\frac{r^{2}}{4} = m*\frac{r^{2}}{2} + m*\frac{r^{2}}{4} = \frac{3}{4}* m*r^{2} (3)[/tex]

Since the angular acceleration increases from α to 2*α, we can write the torque expression as follows:

       τ = 3/4*m*r² * (2α) = 3/2*m*r²

        same result than in (2), so the torque remains the same.

A car is moving at 25.5 m/s when it accelerates at 1.94 m/s^2 for 2.3 s. What is the car's final speed? (Keep in mind direction and round to 2 decimals)

Answers

Answer:

29.96m/s

Explanation:

Given parameters:

Initial speed  = 25.5m/s

Acceleration  = 1.94m/s²

Time  = 2.3s

Unknown:

Final speed of the car  = ?

Solution:

To solve this problem, we are going to apply the right motion equation:

    v = u  + at

v is the final speed

u is the initial speed

a is the acceleration

t is the time taken

 Now insert the parameters and solve;

      v  = 25.5 + (1.94 x 2.3)  = 29.96m/s

A 200 g air-track glider is attached to a spring. The glider is pushed 10.0 cm against the spring, then released. A student with a stopwatch finds that 10 oscillating take 12.0 s. What is the spring constant?

Answers

Answer:

5.5N/m

Explanation:

Calculation for What is the spring constant

First step is to calculate the time period

T = 12 second/10

T = 1.2 second

Now let calculate the spring constant using this formula

k=4π²m/T²

Where,

m=0.2kg

T=1.2second

k represent spring constant=?

Let plug in the formula

k=4π²×0.2kg/(1.2)²

k=39.48×0.2kg/1.44

k=7.90/1.44

k=5.48N/m

k=5.5N/m ( Approximately)

Therefore the spring constant will be 5.5N/m

A ray moving in water at 55.5 deg
enters plastic, where it bends to
48.7 deg. What is the index of
refraction for the plastic?
( water n = 1.33, Air n = 1.00 )

Answers

Answer:

Refractive index of the plastic = 1.46

Explanation:

By Snell's law,

[tex]\frac{\text{sin}\theta _{2} }{\text{sin}\theta _{1}}=\frac{n_1}{n_2}[/tex]

Here, [tex]\theta _1[/tex] = Angle of incidence in medium 1 (Plastic)

[tex]\theta_2[/tex] = Angle of refraction in medium 2 (Water)

[tex]n_1[/tex] = Refractive index of medium 1 (Plastic)

[tex]n_2[/tex] = Refractive index of medium 2 (Water)

By substituting values in the formula,

[tex]\frac{\text{sin}(48.7)}{\text{sin}(55.5)}=\frac{1.33}{n_2}[/tex]

[tex]n_2=\frac{1.33\times \text{sin}(55.5)}{\text{sin}(48.7)}[/tex]

    = 1.46

Therefore, refractive index of the plastic = 1.46

52. Serves as an air passageway
a. Oropharynx
c. Nasopharynx
b. Laryngopharynx
d. Larynopharynx

Answers

Answer:

Nasopharynx

Explanation:

The nasopharynx is posterior to the nasal cavity and serves only as a passageway for air.

Which best describes the law of conservation of mass?
O The coefficients in front of the chemicals in the reactants should be based on the physical state of the products,
O Products in the form of gases are not considered a part of the total mass change from reactants to products
O When reactants contain both a solid and a liquid, the solid counts toward the overall mass and the liquid does not
O The mass of the reactants and products is equal and is not dependent on the physical state of the substances.​

Answers

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

A chimpanzee climbs a vine up and to the right for a total displacement of 50 m 50m50, start text, m, end text that makes a 60 ° 60°60, degree angle from the ground. What was the horizontal displacement of the chimpanzee in m mstart text, m, end text?

Answers

Answer:

25m

Explanation

Let the horizontal displacement formula be expressed as;

Dx = Dcos theta

theta is the angles subtended by the displacement

Given

D = 50m

theta = 60°

Required

horizontal displacement of the chimpanzee

Substitute into the formula

Recall that: Dx = Dcos theta

Dx = 50cos60°

Dx = 50(0.5)

Dx = 25m

Hence the horizontal displacement of the chimpanzee is 25m

Two masses 1.2kg and 1.8kg are connected to the ends of a rod of length 2m. Find the moment of inertia about the axes, 1)going through the mid point of the rod. 2)going through the centre of mass of two masses.​

Answers

Answers: 1) 3 kg m²

                2) 2.88 kg m²

Explanation: Question 1

                      I = m(r)²+ M(r)²

                      I = 1.2 kg × (1 m )² +1.8 kg ×(1 m )²

                    ∴  I =   3 kg m²

                       

                      Question 2

ACCORDING TO THE DIAGRAM DRAWN FOR QUESTION 2

we have to decide where the center of gravity (G) lies and obviously it should lie somewhere near to the greater mass. (which is 1.8 kg). Since we don't know the distance from center of gravity(G) to the mass (1.8 kg) we'll take it as 'x' and solve!!

moments around 'G'

F₁ d ₁ = F₂ d ₂

12 (2-X) = 18 (X)

24 -12 X =18 X

∴  X = 0.8 m

∴ ( 2 - x ) = 1.2 m

∴ Moment of inertia (I) going through the center of mass of two masses,

⇒ I = m (r)² +M (r)²

⇒ I = 1.2 × (1.2)² + 1.8 × (0.8)²

⇒ I = 1.2 × 1.44 + 1.8 × 0.64

⇒ I = 1.728 + 1.152

⇒ ∴ I = 2.88 kg m²

∴ THE QUESTION IS SOLVED !!!

Using the law of conservation of energy, what is the kinetic energy at e?

Answers

Answer:

Send the pic so I can see

The velocity of a wave is 500 m/s . The wavelength of the wave is 3.2 m . What is the frequency of the wave ?

Answers

Answer:

f=156.25Hz

Explanation:

v=fT

500=fx3.2

500=3.2f

divide both sides by 3.2

f=156.25Hz

two asteroids crashed the crash caused both asteroids to change speeds scientist want to use the change

Answers

Answer:

The force each one experienced

Explanation:

Hope this helps :)

How long( in hours, will it take for 500 000 C of charge to flow through a diode if it requires
0.05 Amp to operate it.

Answers

Answer:

277.78 hours

Explanation:

The formula for calculating the amount of charge is expressed as;

Q = It

I is the current

t is the time

Given

I =0.05A

Q = 50,000C

Required

Time t

Recall that: Q = It

t = Q/I

t = 50,000/0.05

t = 1,000,000secs

Convert to hours

1,000,000secs  = 1,000,000/3600

1,000,000secs = 277.78 hours

Hence it will take 277.78 hours for the charge to flow through the diode

12) Consider two identical bricks, each of dimensions 20.0 cm x 10.0 cm x 6.0 cm. One is stacked
on the other, and the combination is then placed so that they project out over the edge of a
table. What is the maximum distance that the end of the top brick can extend beyond the table
edge without toppling?
A) 7.5 cm
B) 10 cm
C) 12.5 cm
D) 15 cm

Answers

Answer:

7.5

Explanation:

Ishan is testing materials to see whether they will stick to a magnet. How can
he use his imagination in this experiment?
OA. To think of different materials to test
OB. To carefully record the results in a chart
O C. To do the test the same way each time
O D. To remember which materials are magnetic

Answers

Answer:

The Answer is A "To think of different materials to test"

Explanation:

APE X

A small, 300 g cart is moving at 1.10 m/s on an air track when it collides with a larger, 4.00 kg cart at rest. After the collision, the small cart recoils at 0.890 m/s. What is the speed of the large cart after the collision (answer in m/s please)?

Answers

Answer:

0.0158m/s

Explanation:

Using the law of conservation of energy which states that the sum of momentum before collision is equal to the sum after collision. It is expressed mathematically as;

m1u1 + m2u2 =  m1v1 + m2v1

m1 and m2 are the masses of the object

u1 and u2 are the initial velocities

v1 and v2 are the final velocities

Given

m1 = 300g  = 0.3kg

u1 = 1.10m/s

m2 = 4.00kg

u2 = 0m/s (at rest)

v1 = 0.890

v2 = ?

Substitute the given values into the formula;

0.3(1.10) + 0 = 0.3(0.89) + 4v2

0.33 = 0.267 + 4v2

0.33-0.267 = 4v2

0.063 = 4v2

v2 = 0.063/4

v2 = 0.0158m/s

Hence the speed of the large cart after the collision is 0.0158m/s

The speed of the large cart will be "0.0158 m/s".

According to the question:

Mass,

[tex]m_1 = 300 \ g = 0.3 \ kg[/tex][tex]m_2 = 4.00 \ kg[/tex]

Final velocity,

[tex]u_1 = 1.10 \ m/s[/tex][tex]u_2 = 0 \ m/s[/tex]

Initial velocity,

[tex]v_1 = 0.890 \ m/s[/tex][tex]v_2 = \ ?[/tex]

By using the law of conservation, we get

→ [tex]m_1 u_1 +m_2 u_2 =m_1 v_1 +m_2 v_1[/tex]

By substituting the values, we get

→ [tex]0.3(1.10)+0 = 0.3(0.89)+4v_2[/tex]

→              [tex]0.33=0.267+4 v_2[/tex]

   [tex]0.33-0.267 = 4 v_2[/tex]

              [tex]0.063 =4v_2[/tex]

                   [tex]v_2 = \frac{0.063}{4}[/tex]

                       [tex]= 0.0158 \ m/s[/tex]

Thus the response above is appropriate.

Learn more about speed here:

https://brainly.com/question/14478313

give 2 reasons why a person should move away from "isolating muscles"

Answers

Answer:

1) - They should move away because its cold

2) - You can get hypothermia......

Explanation:

A herdsman yelling out to a fellow herdsman heard his voice reflected by a cliff 4s later.What is
the velocity of sound in air if the cliff is 680m away​

Answers

Answer:

v = 340 m/s

Explanation:

Given that,

A herdsman yelling out to a fellow herdsman heard his voice reflected by a cliff 4s later.

The cliff is 680 m away

We need to find the velocity of sound in air.

Velocity = distance/time

Distance = 2 × 680 = 1360 m

[tex]v=\dfrac{1360\ m}{4\ s}\\\\=340\ m/s[/tex]

So, the velocity of sound in air is 340 m/s.

What is the centripetal force necessary to keep a 0.4 kg object rotating in a circular path
of radius 3m?

Answers

Answer:

ertdhrsg

Explanation:

gesrgsg

A race car starts from rest and accelerates down a track at a rate of 3.0 m/s2
How fast is the car moving after 10 seconds?

Answers

Answer:

30 m/s

Explanation:

We are given:

Initial Velocity (u) = 0 m/s

Acceleration of the Car (a) = 3 m/s²

Time Interval (t) = 10 seconds

Speed of the Car After 10 seconds:

From the First equation of motion:

v = u + at

replacing the given values

v = 0 + (3)(10)

v = 30 m/s

Hence, the car is moving at a velocity of 30 m/s after 10 seconds

A 250 N to the east and a 30 N force to the west act on an object. What is the net force on the object? (Remember ΣF also equals the sum of all forces)

Answers

Answer:

280N

Explanation:

As the statement put in parenthesis state-You need to add up all the forces acting on the object to find the net force, so over here-

250+30=280N

Give reason:
a) In 'coin on card' experiment a smooth card is used.​

Answers

Answer:

Please mark as brainliest!!

Explanation:

In coin card experiment smooth card is used so that the card can slide easily from glass.

Answer:

In coin card experiment smooth card is used so that the card can slide easily from glass.

. A pendulum of length l = 9.8 m hangs in equilibrium and is then given velocity
v
=0.2
m/s at its lowest point. What is the amplitude of the subsequent oscillation?

Answers

Answer:

the amplitude of the sequence oscillation=

ASO = length × velocity

= 9.8 × 0.2 = 19.6

ASO = 19.6

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