i have a small area that i want to place 2 bench press machines. how much room will i need to reserve for those?

Answers

Answer 1

To place two bench press machines in a small area, you will need a space of approximately 10 feet by 10 feet. Let's discuss it in detail below. Here are the dimensions of the bench press machine, which can help determine the amount of space required to fit two bench press machines in a small area:

The length of the bench press machine is between 48 inches and 54 inches.

The width of the bench press machine is between 28 inches and 32 inches.

The height of the bench press machine is between 48 inches and 56 inches.

Based on the above dimensions of the bench press machine, two machines can be placed in a small area of 10 feet by 10 feet. However, for safe use, the following guidelines should be followed:

There should be at least 6 feet of distance between the two bench press machines. There should be at least 3 feet of clearance in the front of the bench press machine to allow for safe movement during exercises. There should be at least 2 feet of clearance behind the bench press machine to allow for a safe exit in case of an emergency.

Thus, to place two bench press machines in a small area, you will need a space of approximately 10 feet by 10 feet.

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Related Questions

Construct triange ABC, in which AB = 6 cm, angle BAC = 96 degrees and angle ABC = 35 degrees. Measure the length of BC. Give your answer to 1 d. P

Answers

From the construction of the triangle ABC we get that the measure length of BC is approximately 4.22cm

To construct triangle ABC, we can follow these steps:

Draw a line segment AB of length 6 cm.Draw an angle of 96 degrees at point A using a protractor.Draw an angle of 35 degrees at point B using a protractor.The intersection point of the two lines that were drawn in step 2 and 3 will be point C, which is the third vertex of the triangle.

To measure the length of BC in triangle ABC, we can use the law of sines.

The law of sines states that in any triangle ABC:

a / sin(A) = b / sin(B) = c / sin(C)

Where a, b, and c are the lengths of the sides of the triangle opposite to the angles A, B, and C, respectively.

In our triangle ABC, we know AB = 6 cm, angle BAC = 96 degrees and angle ABC = 35 degrees. We can find the measure of angle ACB by using the fact that the sum of the angles in a triangle is 180 degrees:

angle ACB = 180 - angle BAC - angle ABC

= 180 - 96 - 35 = 49 degrees

Now, we can apply the law of sines to find the length of BC:

BC / sin(35) = 6 / sin(96)

BC = 6 × sin(35) / sin(96)

Using a calculator, we can evaluate this expression to get:

BC ≈ 4.22 cm

Therefore, the length of BC in triangle ABC is approximately 4.22 cm.

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A survey was given to a random sample of 1050 voters in the United States to ask about their preference for a presidential candidate. Of those surveyed, 693 respondents said that they preferred Candidate A. Determine a 95% confidence interval for the proportion of people who prefer Candidate A, rounding values to the nearest thousandth

Answers

As per the confidence interval, the true proportion of people in the population who prefer Candidate A lies somewhere between 0.622 and 0.698, based on the results of the survey of 1050 voters.

To calculate the margin of error, we will use the following formula:

Margin of error = z x standard error

Where z is the critical value from the standard normal distribution corresponding to our desired confidence level (95%), and the standard error is given by:

Standard error = √[(sample proportion x (1 - sample proportion)) / sample size]

Using a z-table, we find that the critical value for a 95% confidence interval is 1.96

Plugging in the values we have, we get:

Standard error = √[(0.66 x 0.34) / 1050] = 0.0193

Margin of error = 1.96 x 0.0193 = 0.0378

Therefore, the 95% confidence interval for the proportion of people who prefer Candidate A is:

0.66 ± 0.0378

Rounded to the nearest thousandth, the lower bound of the confidence interval is 0.622 and the upper bound is 0.698.

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Amir drove from Jerusalem to the lowest place on Earth, the Dead Sea.
His altitude relative to sea level (in meters) as a function of time (in minutes) is graphed.
How long did it take Amir to reach sea level?

Answers

In order to solve this problem, we need to begin by examining the graph of Amir's altitude relative to sea level. We can see that the graph starts at an altitude of 700 meters and ends at an altitude of 400 meters.

We can also see that the slope of the graph is negative, which means that the altitude is decreasing over time. This means that it will take Amir some amount of time to reach sea level (which is 0 meters).

To calculate how long it took Amir to reach sea level, we can use the following equation:

Time = (Altitude Final - Altitude Initial) / (Rate of Change)

In this equation, the Rate of Change is the slope of the graph, which can be determined by examining the graph.

Plugging in our values, we get:

Time = (400 - 700) / (-6) = 100 / (-6) = -16.67 minutes

Therefore, it took Amir 16.67 minutes to reach sea level.

Pls solve 60 points if you do

Answers

Answer:

Cos2a - cot2a/sin2a - tan2a

Step-by-step explanation:

How do you make 5. 4 in three different ways!!!?!?

Answers

Answer:

10.0 -4.610.8÷2√29.16

Step-by-step explanation:

You want to make 5.4 in three different ways.

Arithmetic operations

You can add, subtract, multiply, or divide numbers to obtain a result of 5.4:

  2.9 +2.5 = 10.0 -4.6 = 2.0×2.7 = 10.8÷2 = 5.4

More complicated functions

  √29.16 = ∛157.464 = 5.4

  [tex]\displaystyle\sum_{n=1}^\infty{10.8(3^{-n})}=5.4[/tex]

Katie's car averages 32 miles per hour. She has marked her distance traveled after 12, 13, and 14 hours. List the elements in the range of the function that would be used to determine how far Katie has traveled at each mark. Separate each elements from least to element with a comma and write the
greatest.

Pls hurry

Answers

Katie's distance traveled after 12, 13, and 14 hours can be calculated by multiplying her average speed of 32 miles per hour by the number of hours traveled.

So, the distance traveled after 12 hours is 32 × 12 = 384 miles.
The distance traveled after 13 hours is 32 × 13 = 416 miles.
The distance traveled after 14 hours is 32 × 14 = 448 miles.

Therefore, the range of the function that would be used to determine how far Katie has traveled at each mark is:

384, 416, 448 (from least to greatest).
Final answer:

To determine the distance traveled by Katie at different marks, we can use the formula Distance = Rate × Time.

Explanation:

To determine how far Katie has traveled at each mark, we can use the formula:
Distance = Rate × Time

After 12 hours: Distance = 32 miles/hour × 12 hours = 384 milesAfter 13 hours: Distance = 32 miles/hour × 13 hours = 416 milesAfter 14 hours: Distance = 32 miles/hour × 14 hours = 448 miles

So, the elements in the range of the function that would be used to determine how far Katie has traveled at each mark are 384 miles, 416 miles, and 448 miles.

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The ratio of shirts to pants is 3 to 2. If there are 6 shirts, how many pants are there?

12
6
4
9

Answers

3 parts = 6
1 part = 2
Therefore, 2*2= 4 pants

Please help me with my math!

Answers

Answer:

35 passengers produce the maximum revenue for the bus company.

Step-by-step explanation:

Define the variables:

Let "x" be the total number of passengers.Let "y" be the total revenue of the bus company (in dollars).

If there are 30 or fewer passengers, each passenger will be charged $80. Therefore, the equation for the total revenue for 30 or fewer passengers is:

[tex]y = 80x,\quad x \leq 30[/tex]

If there are more than 30 passengers, each passenger will be charged $80 minus $2 for every passenger over 30. Therefore, the equation for the total revenue for more than 30 passengers is:

[tex]y = [80 - 2(x - 30)]x, \quad x > 30[/tex]

This simplifies to:

[tex]y = [80 - 2x + 60]x, \quad x > 30[/tex]

[tex]y = [140 - 2x]x, \quad x > 30[/tex]

[tex]y = 140x - 2x^2, \quad x > 30[/tex]

To maximize revenue, we need to find the value of x that maximizes the above equation.

Since this is a quadratic function, the maximum value occurs at the vertex of the parabola.

The x-value of the vertex of a parabola in the form y = ax² + bx + c is when x = - b/2a. Therefore, the x-value of the vertex is:

[tex]\implies x_{\sf vertex}=\dfrac{-140}{2(-2)}=\dfrac{-140}{-4}=35[/tex]

Therefore, the number of passengers that produce the maximum revenue for the bus company is 35.

Kaitlin is on vacation at a tropical bay that has three islands. She rents a boat on Island A and plans to navigate to Island C, which is 13 miles away. Based on the figure below, at what angle should she navigate to go to Island C?​

Answers

She should navigate at angle 76.86° to go to Island C.

How to find the angle for navigation?

The cosine rule is for solving triangles which are not right-angled in which two sides and the included angle are given. The following are cosine rule formula:

cosA = (b²  +  c² - a²)/2bc

where a, b and c are the lengths and A, B and C are the angles for the islands respectively

Using the formula:

cosA = (b²  +  c² - a²)/2bc

cosA = (13²  +  11² - 15²)/(2*13*11)

cosA = 5/22

A = arc cos(5/22)

A = 76.86°

Thus, θ = 76.86

Therefore, she should navigate at angle 76.86° to go to Island C.

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Tamarisk company began operations on january 2, 2019. It employs 9 individuals who work 8-hour days and are paid hourly. Each employee earns 9 paid vacation days and 7 paid sick days annually. Vacation days may be taken after january 15 of the year following the year in which they are earned. Sick days may be taken as soon as they are earned; unused sick days accumulate. Additional information is as follows. Actual hourly wage rate vacation days used by each employee sick days used by each employee 2019 2020 2019 2020 2019 2020 $6 $7 0 8 5 6 tamarisk company has chosen to accrue the cost of compensated absences at rates of pay in effect during the period when earned and to accrue sick pay when earned

Answers

The total cost of compensated absences for Tamarisk Company for the years 2019 and 2020 was $348 + $1,399 = $1,747.

To calculate the cost of compensated absences for Tamarisk Company, we need to calculate the number of vacation days and sick days earned by the employees in 2019 and 2020, and then calculate the cost of the days earned but not taken.

Each employee earns 9 vacation days per year. As they can be taken after January 15th of the year following the year in which they are earned, the vacation days earned by the employees in 2019 can be taken in 2020. Therefore, in 2019, no vacation days were taken by any employee.

In 2020, the employees took a total of 8 vacation days. As there are 9 employees, the total vacation days taken in 2020 were 9 x 8 = 72.

Sick Days:

Each employee earns 7 sick days per year, and unused sick days accumulate. In 2019, the employees used a total of 5 sick days. Therefore, the unused sick days at the end of 2019 were 9 x 7 - 5 = 58.

In 2020, the employees used a total of 6 sick days, and the unused sick days at the end of 2020 were 58 + 9 x 7 - 6 = 109.

To find the cost of compensated absences. The unused sick days and vacation days must be multiplied to get the hourly wage rate in effect in a year.

In 2019, the cost of compensated absences was 58 x $6 = $348.

In 2020, the cost of compensated absences was (72 + 109) x $7 = $1,399.

Therefore, the total cost of compensated absences for Tamarisk Company for the years 2019 and 2020 was $348 + $1,399 = $1,747.

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A student has 30 minutes to complete an exam. There are 9 multiple choice questions worth 3 points each. There are also 3 short answer questions worth 5 points each. It takes about 2 minutes to answer a multiple choice question and about 6 minutes to complete a short answer question. How many multiple choice questions and short answer questions should the student answer to maximize his score in the time remaining (Use x = multiple choice; y = short answer.)State the Objective Function (S for score) in the linear programming problem givenA. S = 5x + 3y B. S = 3x + 5y C. S = 2x + 6y D. S = 6y + 2x

Answers

The Objective Function in the linear programming problem given in the above-stated scenario is:

B. S = 3x + 5y

Linear programming is a statistical technique used to find a maximum or minimum value of an equation in order to find a solution to a problem. It is used to calculate how much to produce to maximize profits, how to allocate resources, and determine which investments to make.

Linear programming problems include an objective function, which is the equation to be maximized or minimized, and constraints that must be followed. Linear programming problems can be solved graphically or algebraically. In order to solve a linear programming problem, we first need to identify the objective function and constraints.

Objective Function in the linear programming problem:

The score of the student is to be maximized in the given time frame by answering the maximum number of questions of both types.

Therefore, the objective function is: S = 3x + 5y

Answer: B. S = 3x + 5y

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At which values in the interval [0, 2π) will the functions f (x) = 2cos2θ and g(x) = −1 − 4cos θ − 2cos2θ intersect?
a: theta equals pi over 3 comma 4 times pi over 3
b: theta equals pi over 3 comma 5 times pi over 3
c: theta equals 2 times pi over 3 comma 4 times pi over 3
d: theta equals 2 times pi over 3 comma 5 times pi over 3

Answers

The values in the interval [0, 2π) for which the two points would intersect as required is; Choice C; theta equals 2 times pi over 3 comma 4 times pi over 3.

What values of θ make the two functions intersect?

Recall from the task content; the given functions are;

f (x) = 2cos2θ and g(x) = −1 − 4cos θ − 2cos2θ

Therefore, for intersection; f (θ) and g(θ):

2 cos²θ = −1 − 4cos θ − 2cos²θ

4cos²θ + 4cosθ + 1 = 0

let cos θ = y;

4y² + 4y + 1 = 0

y = -1/2

Therefore; -1/2 = cos θ

θ = cos-¹ (-1/2)

θ = 2π/3, 4π/3.

Ultimately, the correct answer choice is; Choice C; theta equals 2 times pi over 3 comma 4 times pi over 3.

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Determine whether the following statement is true or false. If it is false, explain why. The probability that event A or event B will occur is P(A or B)= P(A) + P(B) - P(A or B). Choose the correct answer below. A. True B. False, the probability that A or B will occur is P(A or B)= P(A) middot P(B). C. False, the probability that A or B will occur is P(A or B)= P(A) + P(B). D. False, the probability that A or B will occur is P(A or B)= P(A) + P(B) - P(A and B).

Answers

False, the probability that A or B will occur is P(A or B) = P(A) + P(B) - P(A and B).

Define probability

Probability refers to the measure of the likelihood or chance of a particular event occurring. It is expressed as a number between 0 and 1, where 0 indicates an impossible event, and 1 indicates a certain event.

This formula is known as the Addition Rule for Probability and states that to calculate the probability of either event A or event B occurring (or both), we add the probability of A happening to the probability of B happening, but then we need to subtract the probability of both A and B happening at the same time to avoid double counting.

Option A is not the correct answer because it is missing the subtraction of P(A and B), options B and C are incorrect because they omit the subtraction and only add the probabilities of the events. Option D is close, but it is missing the addition of the probabilities of A and B.

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Give the coordinates for the translation of Rhombus ABCD with vertices A(-3,-2), B(0, 3),

C(5, 6), and D(2, 1).

Given the rule (x, y) = (x+2, y-6)

Answers

The new position of Rhombus ABCD after the translation can be described as follows: point A is now at (-1,-8), point B is at (2,-3), point C is at (7,0), and point D is at (4,-5).

To translate Rhombus ABCD using the rule (x, y) = (x+2, y-6), we add 2 to the x-coordinate and subtract 6 from the y-coordinate for each vertex.

Thus, the new vertices for the translated rhombus are:

A' = (-3+2, -2-6) = (-1, -8)

B' = (0+2, 3-6) = (2, -3)

C' = (5+2, 6-6) = (7, 0)

D' = (2+2, 1-6) = (4, -5)

Therefore, the coordinates for the translated Rhombus ABCD are A'(-1,-8), B'(2,-3), C'(7,0), and D'(4,-5).

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Solve

2n > 20









Pls help really quick

Answers

Answer:

n > 10

Step-by-step explanation:

2n > 20

2n/2 > 20/2

n > 10


An equation is given.

x² + 9 = 6x

What is one solution to the equation?

x=

Answers

Answer: x=3 I think

Step-by-step explanation:

x²-6x+9=0

using the almighty formula where a=1 , b=-6 , c=9

At the grocery store, students measure the weight of three drinks in ounces. How many more ounces are the of water than orange juice?

Orange juice 7.9
Water 13.4
Milk 8.5

Answers

Answer:

2

Step-by-step explanation:

literally just 2 it's quite simple

6. suppose that a brand of aa batteries reaches a significant milestone to their death on average after 7.36 hours, with standard deviation of 0.29 hours. assume that when this milestone occurs follows a normal distribution (a) calculate the probability that a battery does not reach this milestone in its first 8 hours of usage. (b) suppose that the company wants to sell a pack of n batteries of which (at least) 10 will last until after 7.5 hours of usage. if n12, what is the probability of this goal being met? (c) How many batteries n should be in the package in order for the probability to exceed 1%? Give the smallest number n which works.

Answers

The smallest number of batteries in the package for the probability to exceed 1% is a) 17. This can be calculated using the binomial distribution with parameters n=17 and b)p=0.2927 and number of batteries is c)4. (Where p is the probability from part a).

a) The probability that a battery does not reach the significant milestone after 8 hours of usage is 0.2927.

This can be calculated using the cumulative normal distribution function. The parameters are μ=7.36, σ=0.29, and x=8.

b) The probability that at least 10 batteries will last more than 7.5 hours is 0.7012.

This can be calculated using the binomial distribution with parameters n=12 and p=0.2927 (where p is the probability from part a).

c) The number of batteries should be in package is μ*4.2/7.5 = 4.

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The lengths of two sides of a triangle are 4 6. Which measurement cannot be the length of the third side?

Answers

Step-by-step explanation:

X = third side

  due to the triangle side length rule: sum of any two sides must be greater than the third side

so

4 + 6 > x       so x <10

x + 4 > 6       so  x > 2

x + 6 > 4     and  any value of x will work here

so  

2 < x < 10    <=====use this to answer your question as you didn't list the choices in your post

A person hikes 4 miles in 2.5 hours. Then find the unit rate in hours per mile. 29 POINTS IF YOU ANSWER- PLEASE IM BEGGING
RESPOND IN FULL DETAIL ------- NOTE (IT IS NOT 1.6 MILES PER HOUR) THEIR ASKING FOR HOURS PER MILE!!!!!!!!

Answers

NOT SURE IF THIS IS RIGJT
but hours per mile is just how many hours the person takes to hike 1 mile

so if it takes 2.5 hours for 4 miles

Then it would take 0.625 hours for 1 mile

you divide both numbers by 4

divide 210 kg of suger in the ratio 1:2​

Answers

Answer: 105:210

Step-by-step explanation:

1:2 = ?:210

? = 210/2 = 105

1:2 = 105:210

Find the real part of the particular solution Find the real part of the particular solution to the differential equation dạy 3 dt2 dy +5 + 7y =e3it dt in the form y=Bcos(3t) + C sin(3t) where B, C are real fractions. = Re(y(t)) = = symbolic expression ?

Answers

The real part of the particular solution to the differential equation is [tex](1/30)Re(e^(3it))(sin(3t) - cos(3t))[/tex]

The real part of the particular solution to the differential equation:

[tex]\frac{d^2y}{dt^2} +3\frac{dy}{dt} +7y = e^(3it)[/tex]

First, we assume a particular solution of the form:

[tex]y(t) = Bcos(3t) + Csin(3t)[/tex]

where B and C are real fractions.

Taking the first and second derivatives of y(t), we get:

[tex]\frac{dy}{dt} = -3Bsin(3t) + 3Ccos(3t)[/tex]

[tex]\frac{d^2y}{dt2} = -9Bcos(3t) - 9Csin(3t)[/tex]

Substituting these into the differential equation, we get:

[tex](-9Bcos(3t) - 9Csin(3t)) + 3(-3Bsin(3t) + 3Ccos(3t)) + 7(Bcos(3t) + Csin(3t)) = e^(3it)[/tex]

Simplifying and collecting terms, we get:

[tex](-9B + 21C)*cos(3t) + (-9C - 9B)*sin(3t) = e^(3it)[/tex]

Comparing the coefficients of cos(3t) and sin(3t), we get:

[tex]-9B + 21C = Re(e^(3it))[/tex]

[tex]-9C - 9B = 0[/tex]

Solving for B and C, we get:

[tex]B = -C[/tex]

[tex]C = (1/30)*Re(e^(3it))[/tex]

Therefore, the particular solution is:

[tex]y(t) = -Ccos(3t) + Csin(3t) = (1/30)Re(e^(3it))(sin(3t) - cos(3t))[/tex]

A differential equation is a mathematical equation that relates a function to its derivatives. It is a powerful tool used in many fields of science and engineering to describe how physical systems change over time. The equation typically includes the independent variable (such as time) and one or more derivatives of the dependent variable (such as position, velocity, or temperature).

Differential equations can be classified based on their order, which refers to the highest derivative present in the equation, and their linearity, which determines whether the equation is a linear combination of the dependent variable and its derivatives. Solving a differential equation involves finding a function that satisfies the equation. This can be done analytically or numerically, depending on the complexity of the equation and the available tools.

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show that a strictly diagonally dominant matrix is invertible. show furthermore that if all the diagonal entries are positive, then all the eigenvalues have positive real part.

Answers

Completing the proof that if A has strictly positive diagonal entries, then all of its eigenvalues have a positive real part.

For any square matrix A, a diagonal element is any element that is on the main diagonal, i.e., (i,i) for 1<=i<=n. If A has strictly diagonal dominance, then for each row i of A, the absolute value of the diagonal element of that row is more than the sum of the absolute values of the non-diagonal elements of that row.If A is invertible, then det(A) is nonzero. If all the diagonal entries are positive, then det(A) is also positive, which implies that all the eigenvalues of A have the same sign (either all are positive or all are negative).As a result, suppose all of A's diagonal entries are positive. Then all of A's eigenvalues are positive since they all have the same sign as det(A).

And if all of A's eigenvalues are positive, then all of their real parts are positive as well, hence completing the proof that if A has strictly positive diagonal entries, then all of its eigenvalues have a positive real part.

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Identify whether each of the following samples is a possible bootstrap sample from this original sample: 20, 24, 19, 23, 18 *Explain your answer (2pt cach) a. 20, 24, 21, 19, 18 b. 20, 20, 20, 20, 20

Answers

The two options are as follows: a. 20, 24, 21, 19, 18.

This sample is a possible bootstrap sample.

A bootstrap sample is created by taking samples from the original sample with replacement. Therefore, we can include the original data multiple times.

Here, 20, 24, 19, 23, 18 is the original sample.

Sample a includes 20, 24, 19, 23, and 18 which are part of the original data, and 21 which is not part of the original data. Since we can include the original data multiple times in bootstrap samples, a is possible.b. 20, 20, 20, 20, 20This sample is not a possible bootstrap sample.

In the original sample, we have five unique data points: 20, 24, 19, 23, and 18. Sample b includes only one unique data point, 20, repeated five times. We cannot create a bootstrap sample with the same data point repeated multiple times. Hence A is correct.

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Find dy/dx if y=u^3 + 2u and u= x^2 + 5

Answers

Answer: I hope this helped!

Step-by-step explanation:

.

Solution of inequality 1/(x - 5) < 3 is

Answers

Step-by-step explanation:

1/(x - 5) < 3

1 < 3(x - 5)

1/3 < x - 5

1/3 + 5 < x

5 1/3 = 16/3 = 5.33333... < x

or

x > 5 1/3

To compare the pain control offered by two different analgesics in pediatric patients, the authors selected the Wong-Baker FACES pain rating scale as the primary end point. Before beginning the clinical trial, the authors sought to validate this ordinal scale by showing a correlation with a previously validated visual analog scale. Which one of the following statistical test is most appropriate to assess whether a correlation exists between these two measurements?
A. Pearson correlation
B. Analysis of variance (ANOVA)
C. Spearman rank correlation
D. Regression analysis

Answers

The most appropriate statistical test to assess whether a correlation exists between the Wong-Baker FACES pain rating scale and a previously validated visual analog scale is the (C) Spearman rank correlation.

What is correlation?

Correlation refers to the connection between two variables in which a modification in one variable is linked to a modification in the other variable. Correlation can be positive or negative.

Spearman rank correlation- A non-parametric approach to test the statistical correlation between two variables is Spearman rank correlation, also known as Spearman's rho or Spearman's rank correlation coefficient. This is based on the ranks of the values rather than the values themselves. The results are denoted by the letter "r".

The formula for Spearman's rank correlation coefficient:

Rs = 1 - {6Σd₂}/{n(n₂-1)}

Where, Σd₂ = the sum of the squared differences between ranks.

n = sample size

Thus, the most appropriate statistical test to assess whether a correlation exists between these two measurements is the (C) Spearman rank correlation.

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(1 point) a bowl contains 6 red balls and 7 blue balls. a woman selects 4 balls at random from the bowl. how many different selections are possible if at least 3 balls must be blue?

Answers

The number of different selections possible if at least 3 balls must be blue is 35


1. Calculate the total number of possible selections (6 red + 7 blue = 13 total): 13C4 = 715
2. Calculate the number of possible selections that have fewer than 3 blue balls: 6C4 = 15
3. Subtract the number of possible selections with fewer than 3 blue balls from the total number of possible selections: 715 - 15 = 700
4. Divide the answer by the number of selections with exactly 3 blue balls: 700/7 = 100
5. Multiply the result by the number of selections with exactly 4 blue balls: 100 * 7 = 700
6. Finally, subtract the number of selections with 4 blue balls from the total number of possible selections: 715 - 700 = 35

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a card is drawn randomly from a standard 52-card deck. find the probability of the given event. write your answers as reduced fractions or whole numbers.

Answers

The probability of the given event is 11/13.

How to find the probability

A card is drawn randomly from a deck of 52 cards.

The probability that the card drawn is neither an ace nor a king is a question that can be answered with probability.

We know that there are 4 aces and 4 kings in a deck of 52 cards.

The probability of drawing an ace or a king is P(Ace or King) = 4/52 + 4/52 = 8/52 = 2/13

There are four of each card rank in a deck of 52 cards, and there are a total of 52 cards. A player must choose one of the 52 cards at random.

The probability of drawing an ace or a king is P(Ace or King) = 4/52 + 4/52 = 8/52 = 2/13

The probability of at drawing neither an ace nor a king is:

P(Not Ace and Not King) = 1 - P(Ace or King) = 1 - 2/13 = 11/13

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simplify 2^(x+2) /2^(x-1)​

Answers

Answer:

Step-by-step explanation:

When we divide two exponential expressions with the same base, we can subtract their exponents. Using this property, we can simplify the given expression as:

2^(x+2) /2^(x-1) = 2^x * 2^2 / 2^x * 2^(-1)

= 2^(x-1+2)

= 2^(x+1)

Therefore, the simplified expression is 2^(x+1).

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