I need help please but if you can give me the step by step it would be helpful thank you

Answer: if the bus takes 5 hours to go the distance then it will take the y,x distances to go the 5 hours.

Step-by-step explanation:

Answer:

When the two lines being crossed are Parallel Lines the Consecutive Interior Angles add up to 180°. so yes

Step-by-step explanation:

Answer:

Tommy has f amount of marbles. His wife has 20 times Tommy's amount.

Step-by-step explanation:

f×20

Answer:

3.89 minutes

Step-by-step explanation:

Firstly, we have this in a table using the range

There are 6 ranges

We put the frequency alongside

Afterwards we calculate the midpoint of the range

For example, midpoint of range 1-4 is (1+4)/2 = 5/2 = 2.5

We multiply the midpoint by the frequency which gives another column

Then we calculate the mean, where the mean is the summation of all frequencies and their midpoints

We subtract each midpoint from the mean, square the results, then multiply each by their frequency

Lastly, we apply the standard deviation formula

Please check attachment for the tabular representation and formulas

Answer:

Ratio of Boys : 28/53

Ratio of Girls : 25/53

Step-by-step explanation:

Girls : Boys

25 : 28

(Add them up) 25 + 28 = 53

53 = Total of both B & G

Hope this helps. :)

Answer:

yes it is a proportional relationship

Step-by-step explanation:

:) gl!

Answer:

0.6 a  +  1.2 b

Step-by-step explanation:

Solution :

The diameter of the tank = 3 m = 300 cm

Radius of the tank = 1.5 m = 150 cm

Height of the tank = 8 m = 800 cm

The rate of increase of height of water level = 26 cm/min

∴ [tex]$\frac{dh}{dt} = 20 \ cm/min$[/tex]

The water is leaking at a rate of  =  10700 cubic centimeters per min

∴ rate out = 10,700 [tex]$cm^3 / cm $[/tex]

At time 't', the height of water level is 'h' with radius 'r' and volume 'V'.

By the property of similarity of triangles we can write

[tex]$\frac{h}{r} = \frac{800}{150} $[/tex]

[tex]$\frac{h}{r} = \frac{16}{3} $[/tex]

[tex]$r = \frac{3}{16}h$[/tex]

Volume of water at time 't' is given as

[tex]$V= \frac{1}{3} \pi r^2 h $[/tex]

[tex]$V= \frac{1}{3} \pi \left(\frac{3}{16}h\right)^2 h $[/tex]

[tex]$V =\frac{3}{256} \pi h^3$[/tex]

Now differentiating w.r.t 't'

[tex]$\frac{dv}{dt} = \frac{9}{256} \pi h^2 \frac{dh}{dt}$[/tex]

The rate of increase in tank =  rate of inward flow - rate of outward flow

[tex]$\frac{dv}{dt} $[/tex]  = rate of inward flow  - 10,700

rate of inflow = 10,700 + [tex]$ \frac{9}{256} \pi h^2 \frac{dh}{dt}$[/tex]

Substituting the values we get

rate of inflow = 10,700 + [tex]$ \frac{9}{256} \times 3.14 \times (250)^2 \times 26$[/tex]

∴ rate of inward flow = [tex]$1.9 \times 10^5 \ cm^3/min$[/tex]

Answer: -7

Step-by-step explanation:

I’m doing the test

Answer:

b. (5,-2)

Step-by-step explanation:

When we substitute the x and y values into the equation and simplify the equation we end up with these equations:

-2 ≤ 0

-2 ≥ -9

Once simplified, the equations are proven to be correct.

(I hope this helps)

Answer:

The answer is B, (5,-2)

Step-by-step explanation:

If you input the x and y values from (5,-2) into the system on inequalities both the equations end up being true, while all the other make one or more solution set incorrect when you input the x and y values.

Answer:

2

Step-by-step explanation:

2 seems to be the only one that is correct

Correct Statements: (modified the statements that are incorrect)

1. The coordinates of point A are (-3, 3)

2. Already correct

3. The coordinates of point C are (-2, -2)

4. Point B is the closest to the y-axis (only one away)

5. Point A is 3 away and Point B is 1 away

(sorry if this is confusing but this is what I got)

Answer:

Please check the explanation.

Step-by-step explanation:

Determining the length of BC

From the diagram, it is clear that

Since points A and C are located on a horizontal straight line. Thus, the length of BC can be determined by counting the x-axis units from reaching x = -8 to x = 8. i.e. 8-(-8) = 8+8 = 16

Thus, the length of BC = 16 units

Determining the length of CD

Given

The distance between C(8, 10) and D(2, -2)

[tex]\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]

[tex]CD=\sqrt{\left(2-8\right)^2+\left(-2-10\right)^2}[/tex]

      [tex]=\sqrt{6^2+12^2}[/tex]

      [tex]=\sqrt{36+144}[/tex]

      [tex]=\sqrt{180}[/tex]

      [tex]=\sqrt{36\times 5}[/tex]

      [tex]=6\sqrt{5}[/tex]

Thus, the length of CD [tex]=6\sqrt{5}[/tex] units

Determining the length of ED

Given

The distance between E(-8, -4) and D(2, -2)

[tex]ED=\sqrt{\left(2-\left(-8\right)\right)^2+\left(-2-\left(-4\right)\right)^2}[/tex]

      [tex]=\sqrt{10^2+2^2}[/tex]

      [tex]=\sqrt{100+4}[/tex]

      [tex]=\sqrt{104}[/tex]

       [tex]=\sqrt{26\times \:4}[/tex]

        [tex]=2\sqrt{26}[/tex]

Thus, the length of ED [tex]=2\sqrt{26}[/tex] units

Determining the length of EB

From the diagram, it is clear that

Since points E and B are located on a vertical straight line. Thus, the length of EB can be determined by counting the y-axis units from reaching y = -4 to y = 10. i.e. 10-(-4) = 10+4 = 14

Thus, the length of EB = 14 units

Answer:

0 and 1

Step-by-step explanation:

If a polynomial P(x) is divided by (x + h), then by the Remainder theorem

The remainder is the value of P(- h)

(1)

For P(x) divided by (x - 1) , then the remainder is P(1) = 0

(2)

For P(x) divided by (x + 2) then the remainder is P(- 2) = 1

9514 1404 393

Answer:

  {-6, -4, -2}

Step-by-step explanation:

If the domain is positive integers, the range is negative even integers. The only ones on the list are ...

  -2, -4, -6

Answer:

B

Step-by-step explanation:

3 3/4 +r _3 3/4= 5 3/8_3 3/4

Answer:

Step-by-step explanation:

A number line going from negative 8 to positive 4 in increments of 2. There are 4 equal spaces between each number. Negative 3.5 is plotted on the mark 1 space to the left of 4.

A number line going from negative 20 to negative 10 in increments of 2. There are 4 equal spaces between each number. Negative StartFraction 21 Over 2 EndFraction is plotted on the mark 1 space to the left of negative 10.

A number line going from negative 10 to positive 4 in increments of 2. There are 4 equal spaces between each number. Negative StartFraction 7 Over 2 EndFraction is plotted on the mark labeled negative 6.

A number line going from negative 2 to positive 8 in increments of 2. StartFraction 9 Over 2 EndFraction is plotted on the mark 1 space to the left of 4.

Answer:

B

Step-by-step explanation:

Trust me on this, also can I have brainiest please?

Hope you do well! :D

Answer:

the mean is 55.6; if she redid the D and F papers the mean would increase because you would get a higher average than before. Higher scores mean that the number that you add are larger evidently ending up in a larger value

Step-by-step explanation:

if you want to find mean, all you do is add the numbers together and then divide by the total number of values that you added.

so this would be 74+12+61+86+45 and that is 278. Then there is a total of 5 so you divide 278 by 5 which gives you 55.6.

Answer:

[tex]\boxed{x = 4, ~y = -1,~ and~z = 3}[/tex]

.

Step-by-step explanation:

(eq-1) → x + y + z = 6

(eq-2) → x - y + z = 8

(eq-3) → x + y - z = 0

.

Eliminate eq-1 and eq-3

[tex]x + y + z = 6[/tex]

x + y - z = 0    

[tex]2z = 6[/tex]

[tex]z = \frac{6}{2}[/tex]

[tex]z = 3[/tex]

.

Eliminate eq-1 and qe-2

[tex]x + y + z = 6[/tex]

x - y + z = 8    

[tex]2y = -2[/tex]

[tex]y = \frac{-2}{2}[/tex]

[tex]y = -1[/tex]

.

Substitute the value of z and y to on of equations

[tex]x + y + z = 6[/tex]

[tex]x + (-1) + 3 = 6[/tex]

[tex]x + 2 = 6[/tex]

[tex]x = 6 - 2[/tex]

[tex]x = 4[/tex]

Answer:

The solution for the following system is: [tex]\mathbf{x=4, y=-1, z=3}[/tex]

Step-by-step explanation:

We need to find the solution to the following system.

[tex]x+y+z=6 \ and \ x-y+z=8 \ and \ x+y-z=0[/tex]

Let:

[tex]x+y+z=6 --eq(1)\\ x-y+z=8 --eq(2)\\ x+y-z=0--eq(3)[/tex]

Adding eq(1) and eq(2)

[tex]x+y+z=6 \\x-y+z=8 \\-------\\2x+2z=14 --eq(4)[/tex]

Adding eq(2) and eq(3)

[tex]x-y+z=8 \\ x+y-z=0\\-------\\2x=8\\x=8/2\\x=4[/tex]

We get value of x=4

Now, putting value of x in eq(4) to find value of z

[tex]2x+2z=14\\Put x=4\\2(4)+2z=14\\8+2z=14\\2z=14-8\\2z=6\\z=6/2\\z=3[/tex]

We get value of z=3

Now, putting value of x and z in eq(1) to find value of y

[tex]x+y+z=6\\Put \ x=4, z=3\\4+y+3=6\\y+7=6\\y=6-7\\y=-1[/tex]

So, value of y=-1

The solution for the following system is: [tex]\mathbf{x=4, y=-1, z=3}[/tex]

Answer:

Step-by-step explanation:

Fatal accidents involving light tracks:

Fatal accidents involving cars:

Probability of a fatal accident involving a light track:

Answer:

234

Step-by-step explanation:

48 x 3=144

30 x 3=90

144+90=234

This question is incomplete, the complete question is;

The owner of a small local bakery wants to determine how many fruit-filled pastries she should bake each day. Each pastry costs $.60 to make and sells for $1.00 each. Each pastry that is not sold at the end of the day is sold the next day for $.30 as day-old merchandise. She has determined that her average daily sales of this type of pastry are 193, with a daily standard deviation of 41. Flag this Question Question 114 pts

-What is the value of Co

-What is the value of Cu

Answer:

- the value of the cost overage Co is  $ 0.3

- the value of the cost shortage Cu is  $ 0.40

Step-by-step explanation:

Given that;

Revenue per unit R                         =       $ 1.00

Cost per Unit C                               =       $ 0.60

Salvage value per unit  S                =       $ 0.30

Mean Demand μ                              =          193

Standard Deviation of demand  σ  =          41

-To get the value of our cost overage Co;

we simply say

Co = Cost per Unit C - Salvage value per unit  S  

Co = 0.6 - 0.30 = 0.30

therefore the value of the cost overage Co is  $ 0.30

- To find the value of Cost Shortage Cu;

Cu = Revenue per unit R - Cost per Unit C

Cu = 1.00 - 0.60 = 0.40

therefore the value of the cost shortage Cu is  $ 0.40

Answer:

33 nickels, 17 quarters

Step-by-step explanation:

q=quarters, n=nickels

Since total number of coins = 50 and he only has quarters and nickels,

q + n = 50.

Since a quarter is 0.25 dollars, a nickel is 0.05 dollars, and his total is $5.90,

0.25q + 0.05n = 5.90

Multiply the entire second equation by -4 to get -q and eliminate q from both equations: -4(0.25q + 0.05n = 5.90)

So, q + n = 50

And -q -0.2n = -23.6

Cancel q's and add down to combine both equations, so 0.8n = 26.4

Solve for n by dividing 0.8 by both sides, so n = 33

Plug n back into the first equation: q + 33 = 50 and q is thus 17.

Hope this helps!

Answer:

EF=18 inches

Measure of angle F = 134

Step-by-step explanation:

It's an isosceles triangle because the two given angles are equal. So, hypothetically, if you flipped the triangle to have side EG on the ground, then given the rules of isosceles triangles, side EF is equal to side GF.

To find the angle of F just add the given angles and substract from 180

Answer:1) 9/8×4/3

2)9/8÷3/4

3)3/2

Step-by-step explanation:

Answer:

(25 and 8) = 200

(32,24 and 18) =288

(22 and 4)=44

(14 and 12) = 84

(9,8 and 7)= 504

(27,12 and 36) =108

Answer:

The container can hold 22 gallons of water.

Step-by-step explanation:

Let 'g' be the number of gallons a container can hold

Given that 11 gallons of water have been added to the container.

Thus, the equation becomes

[tex]\frac{2}{3}g-\frac{1}{6}g=11[/tex]

Multiply by LCM 6

[tex]\frac{2}{3}g\cdot \:6-\frac{1}{6}g\cdot \:6=11\cdot \:6[/tex]

[tex]4g-g=66[/tex]

[tex]3g=66[/tex]

Divide both sides by 3

[tex]\frac{3g}{3}=\frac{66}{3}[/tex]

[tex]g=22[/tex]

Therefore, the container can hold 22 gallons of water.