I NEED HELP PLSSSSSS

This is the answer which is not right because this is for points...

Answer:

[tex]f(x) = \left \{ {{x + 3} \quad \text{if} \ -3 \leq x < -1\atop {5} \quad \text{if} \ -1 \leq x \leq1} \right.[/tex]

Step-by-step explanation:

You can find the first function if you know the general form of a line:

[tex]y = mx + b[/tex]

where [tex]m[/tex] is the slope and [tex]b[/tex] the intercept point with the [tex]y[/tex]-axis.

So in the first case the slope is 1 because the next formula

[tex]m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2-0}{-1+3} = 1[/tex]

And you can find the interception point if extend the line, then in our case is  3.

So the function is:

[tex]f(x) = x + 5[/tex]

In the other case is constant function that's mean that the function has the next form

[tex]f(x) = k[/tex]

Where [tex]k[/tex] is a constant.

So you only have to observe what is the value for each point in the interval, in this occasion is 5.

So the final answer is:

[tex]f(x) = \left \{ {{x + 3} \quad \text{if} \ -3 \leq x < -1\atop {5} \quad \text{if} \ -1 \leq x \leq1} \right.[/tex]

Answer:

Step-by-step explanation:

No . B'  (reflection of B) and C' (reflection of C) are in the right position,  but D' should be at  (4, 1) and A' should be at (-2,-4).

Let

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots[/tex]

Differentiating twice gives

[tex]\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots[/tex]

[tex]\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n[/tex]

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

[tex]\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0[/tex]

[tex]\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0[/tex]

Then the coefficients in the power series solution are governed by the recurrence relation,

[tex]\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}[/tex]

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

[tex]k=0 \implies n=0 \implies a_0 = a_0[/tex]

[tex]k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}[/tex]

[tex]k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}[/tex]

[tex]k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}[/tex]

It should be easy enough to see that

[tex]a_{n=2k} = \dfrac{a_0}{(2k)!}[/tex]

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

[tex]k = 0 \implies n=1 \implies a_1 = a_1[/tex]

[tex]k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}[/tex]

[tex]k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}[/tex]

[tex]k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}[/tex]

so that

[tex]a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}[/tex]

So, the overall series solution is

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)[/tex]

[tex]\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}[/tex]

Answer:

1799 members in the art club i think but i don't have a bar graph

Step-by-step explanation:

^^

Answer: Yes

Step-by-step explanation:

A: 12 minutesAnswer to B: 36 minutesAnswer to C:

Answer:

2, -6

Step-by-step explanation:

x^2 + 4x - 12

A = 1

B = 4

C = -12

i used the "X" method to solve for the solutions. i think it's easier than using the quadratic formula but it doesn't always work

for the "X" method you have to multiply your A value and your C value together so 1 x (-12) = -12. that is going to be the top part of the X

the bottom part of the x will be your B value which is 4

we have to find multiples of -12 that will also add to 4

so -2 and 6 multiply to -12 but also add to 4 so we know these numbers will work

i added added two drawings to show how i found the solutions using the "X" method and the quadratic formula

Step-by-step explanation:

Answer:

i think 9900

Step-by-step explanation:

225x20 = 4500

180x30 = 5400

5400+4500 = 9900

Answer: 18

Step-by-step explanation:

The question is asked to know 30% of 60, we get

60 x 30% = 60 x 0.3 = 18

Answer:

18

Step-by-step explanation:

We know that 30% means 30/100

30/100 multiplied by 60

hence, the answer is 18

Answer:

it would be c because its moved 2x up

Step-by-step explanation:

[tex]\int {12x+5} \, dx[/tex]

For this problem, let's first apply the intergral sum rule.

[tex]\int {12x+5} \, dx = \int{12x} \, dx + \int{5}x \,dx[/tex]

Then, we'll use the reverse power rule on each of these integrals.

[tex]\int{12x} \,dx = 6x^2+C[/tex]

[tex]\int{5} \,dx = 5x+C[/tex]

So the indefinite integral of [tex]\int{12x+5} \,dx[/tex] is [tex]6x^2+5x+C[/tex].

Remember that we need our constant of integration, [tex]C[/tex], because of if we take the derivative of a constant, it'll be 0.

Hope this helps!

Hi there!

[tex]\int\limits {12x+5} \, dx[/tex]

Recall the following rules:

[tex]\int\limits {x^n} \, dx = \frac{x^{n+1}}{n+1}[/tex]

Use this rule to evaluate. Remember to include the constant:

[tex]\int\limits {12x+5} \, dx = \frac{12x^{1+1}}{1+1} + 5x +C[/tex]

[tex]\int\limits {12x+5} \, dx = 6x^2 + 5x + C[/tex]

Answer:

-23 over 10

Step-by-step explanation:

Hope this helped :)

Answer:

253/20

Step-by-step explanation:

(−2 1/5) × (−5 3/4) =

1. change both mixed numerals into fractions.

= -11/5 × (-23/4)

2. Since both numbers are negative, the product is positive. Multiply both numerators together. Multiply both denominators together.

= 253/20

253 is the product of 2 prime numbers, 11 and 23. 20 is the product of 2² and 5. There are no common factors in the numerator and denominator, so this fraction cannot be reduced.

Answer: 253/20

Answer:

help please, i’m struggling on this

Answer:

3,280/38650 x 100% = 8%

Answer:

6^3

Step-by-step explanation:

3 × 3 × 3 × 3 × 3 × 3=729

6^3=216

3 × 3 × 3 × 3 × 3 × 3=729

3^6=729

Hope this helps :)

3 × 3 × 3 × 3 × 3 × 3

63

9 × 9 × 9

36

[tex]\begin{array}{cccccccc}\\ \underline{-3}&,&12&,&-33&,&102\\ \cline{1-7} &&(-3)(\underline{-3})+3&&(-3)(12)+3&&(-3)(-33)+3 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{ccc} -303&,&912\\ \cline{1-3} (-3)(102)+3&&(-3)(-303)+3 \end{array}[/tex]

Answer:

B

Step-by-step explanation:

it is the opposite of A, which is true, as |-8| = 8

Check the picture below.

=5/3   =−1

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

The amount that will be spent is $24.50, the amount saved will be $10.50, and the percentage saved will be 30%.

The amount that will be spent will be:

= 7/10 × $35 = $24.50

The amount that will be saved will be:

= $35 - $24.50 = $10.50

The fraction of the original price that is saved will be:

= 10.50/35 × 100

= 30%

Read related link on:

https://brainly.com/question/25763817

Step-by-step explanation:

7 √(1/3) - 2 1/3 √(1/3) +3√147

→7(1/√3) - (7/3)(1/√3) +3√(3×7×7)

→ (7/√3) - (7/3√3) +3×7√3

→ (7/√3) - (7/3√3) + 21√3

On Rationalising the denominators then

→ [ 7√3/(√3×√3)]-[7√3/(3×√3×√3) +21√3

The Rationalising factor of√3 =√3

→ (7√3/3)-[7√3/(3×3)]+21√3

→ (7√3/3)-(7√3/9)+21√3

LCM of 3 and 9 = 9

→ [(3×7√3)-(7√3)+(9×21√3)]/9

→ (21√3-7√3+189√3)/9

→[(21-7+189)√3]/9

→ [(210-7)√3]/9

→ 203√3/9 Ans.

Hope this helps.

Answer:

the answer is 24.23 $ thats what i got

Answer:

A. 2.11 and  B. 26.39+2.11=28.50

Step-by-step eplanation:

Using simple interest, it is found that:

a) The monthly payment will be of $222.57.

b) In total, the car will cost $18,251.9275.

c) $16,025.1775 will be paid in interest.

The amount of money accrued after t years, using simple interest, with an initial value of P and a decimal rate of r is given by:

[tex]A(t) = P(1 + rt)[/tex]

In this problem:

Item a:

The amount of money accrued will be of:

[tex]A(6) = 12618.25[1 + 0.045(6)] = 16025.1775 [/tex]

Payment over 6 x 12 = 72 months, hence, the monthly payment will be of:

[tex]m = \frac{16025.1775}{72} = 222.57[/tex]

The monthly payment will be of $222.57.

Item b:

The total cost is composed by:

Hence:

[tex]T = 0.15(14845) + 16025.1775 = 18251.9275[tex]

In total, the car will cost $18,251.9275.

Item c:

As found in item a, $16,025.1775 will be paid in interest.

A similar problem is given at https://brainly.com/question/13176347

Answer:

A

Step-by-step explanation:

5 times 10= 50

5 times -5= -25

50-25=25

The element which should be used to help clarify a complicated idea in a text is ; A research question.

According to the question;

A research question is the best fit which should be used to help clarify a complicated idea in a text.

This is so because; a research question provides a basis for accessing all perspectives there is to the complicated idea.

Read more:

brainly.com/question/18675306

Answer:

D

Step-by-step explanation:

how is this math? 0-0