If f(x) = 3x - 1 and g(x) = x + 2, find (f+ g)(x).

Answer:

D is correct answer to the question

Answer:

x + 5 = 3x -1

7x + 21 = 5x + 35

5x + 5 = 6x - 5

Step-by-step explanation:

7x+21=5x+35

-5x -5x

2x+21=35

-21 -21

2x=14

÷2 ÷2

x=7

x+5=3x-1

-x -x

5=2x-1

+1 +1

6=2x

÷2 ÷2

x=3

5x+5=6x-5

-5x -5x

5=x-5

+5 +5

x=10

Hope this helps! :)

Answer:

Step-by-step explanation:

Answer:

[tex]A=-323[/tex]

Step-by-step explanation:

A = (-123)+77+(-257)+23-43

A = -46+(-257)+23-43

A = -303+23-43

A = -280-43

A = -323

Hope this helps

Answer:

[tex]\frac{3}{4}[/tex]

Step-by-step explanation:

Vowels: A, E, I, O, U

There are only 2 vowels out of 8 on the spinner, which means that 6 out of 8 aren't vowels.

[tex]\frac{6}{8}[/tex] = [tex]\frac{3}{4}[/tex]

Hope this is helpful

Answer:

The height of the triangle is [tex]6[/tex] cm.

Step-by-step explanation:

----------------------------------------

The formula for solving the area of a triangle is  [tex]A=\frac{1}{2}bh[/tex] where [tex]b[/tex] stands for base and [tex]h[/tex] stands for height.

Let's substitute 30 [tex]cm^2[/tex] for the area and 10 for the base.

[tex]30=\frac{1}{2} (10)h[/tex]

-------------------->>>>

Now, let's solve to find the height.

[tex]30=\frac{1}{2}(10)h[/tex]

Multiply [tex]\frac{1}{2}[/tex] times [tex]10[/tex]

[tex]30=5h[/tex]

Divide both sides by 5.

[tex]6=h[/tex]

-----------------------------------------

Hope this is helpful.

Answer:

6 cm

Step-by-step explanation:

thanks for the pts

✌️❤️✌️

9514 1404 393

Answer:

  x = -1/3

Step-by-step explanation:

Maybe you mean ...

  (1/49)^(x +2) = 7^(x -3)

Taking logarithms base 7, we have ...

  -2(x +2) = x -3

  -2x -4 = x -3 . . . . . eliminate parentheses

  -1 = 3x . . . . . . . . . . add 3+2x

  x = -1/3 . . . . . . . . . divide by the coefficient of x

This is confirmed by a calculator in the first attachment.

_____

As written, the equation is ...

  ((1/49)^x) +2 = (7^x) -3

Multiplying both sides by 7^(2x) gives us ...

  1 + 2·7^(2x) = 7^(3x) -3·7^(2x)

Subtracting the left side gives us the cubic equation in 7^x:

  (7^x)^3 -5·(7^x)^2  -1 = 0

This has one irrational real root (found using a graphing calculator). The solution is ...

  x ≈ 0.83111881051

This answer is confirmed in the second attachment. (10^-16 is essentially zero for this purpose.)

__

Additional comment

Part of the reason for going to the trouble to solve the "as written" equation is to show you that it is possible, though messy. What we'd like to emphasize here is that grouping symbols are needed when exponents contain math operations.

In typeset text, the superscript font indicates the grouping of parts of an exponent. In plain text, we cannot tell if 7^x-3 means (7^x)-3 or 7^(x-3). The Order of Operations tells us to interpret it the first way: (7^x) -3, because exponentiation is done before addition. That leads to trouble in this problem.

Answer:

s

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answer:

12/37

Step-by-step explanation:

SOH - CAH - TOA

O = opposite

A = adjacent

H = hypotenuse

Sin = O/H

Sin N = 12/37

Answer:Find sin N

sinN=

hypotenuse/opposite

​12/37

Step-by-step explanation:

Answer:

4.9 hours

Step-by-step explanation:

3185/650 = 4.9

9514 1404 393

Explanation:

Given:

Prove:

Proof:

∠BOA +∠BOC +∠AOC = 360° . . . . . sum of arcs of a circle is 360°

2α +∠BOA = 180°, 2β +∠AOC = 180° . . . . . sum of triangle angles is 180°

∠BOA = 180° -2α, ∠AOC = 180° -2β . . . . solve statement 2 for central angles

(180° -2α) +∠BOC +(180° -2β) = 360° . . . . . substitute into statement 1

∠BOC = 2(α +β) . . . . . add 2α+2β-360° to both sides

∠BOC = 2×∠BAC . . . . . substitute given for α+β; the desired conclusion

Answer:

x = 2

Step-by-step explanation:

Given

2.5(6x - 4) = 10 + 4(1.5 + 0.5x) ← distribute parenthesis on both sides

15x - 10 = 10 + 6 + 2x , that is

15x - 10 = 16 + 2x ( subtract 2x from both sides )

13x - 10 = 16 ( add 10 to both sides )

13x = 26 ( divide both sides by 13 )

x = 2

Answer:

2

Step-by-step explanation:

15x-10=10+6+2x

15x-2x=10+10+6

13x=26

divide 13 both sides

x=2

Answer:

(3, 3) (1, -1)

Step-by-step explanation:

Answer:

(1, - 1) , (3, 3 )

Step-by-step explanation:

Given the 2 equations

3 + y - 2x = 0 → (1)

3x² + 2y² - 4xy = 9 → (2)

In (1) subtract 3 - 2x from both sides

y = 2x - 3 → (3)

Substitute y = 2x - 3 into (2)

3x² + 2(2x - 3)² - 4x(2x - 3) = 9 ← distribute and simplify left side

3x² + 2(4x² - 12x + 9) - 8x² + 12x = 9

3x² + 8x² - 24x + 18 - 8x² + 12x = 0

3x² - 12x + 18 = 9 ( subtract 9 from both sides )

3x² - 12x + 9 = 0 ( divide through by 3 )

x² - 4x + 3 = 0 ← in standard form

(x - 1)(x - 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 3 = 0 ⇒ x = 3

Substitute these values into (3) for corresponding values of y

x = 1 : y = 2(1) - 3 = 2 - 3 = - 1 ⇒ (1, - 1 )

x = 3 : y = 2(3) - 3 = 6 - 3 = 3 ⇒ (3, 3 )

Answer:

Instrumental variable

Step-by-step explanation:

cov(z,u)  shows that the instrumental variable is exogenous. An instrumental variable can also be regarded as a third variable, It is included in the model if you have an issue of endogeneity in your regression model. An endogeneity problem arises if there are other variables are being influenced by other independent variable in the same regression model. we use z to account for these behaviours in the model. this variable controls for measurement errors as well as confounding errors.  

Answer:

18 i think sorry if i am wrong

Step-by-step explanation:

Answer:

x = 4 , y = 0

Step-by-step explanation:

x -    y = 4 --------- ( 1 )  

x + 2y = 4 -------- ( 2 )

( 1 ) x - 1 => - x + y = - 4  -------------( 3 )

( 2 )      =>    x + 2y = 4  ----------- ( 2 )

( 2 ) + ( 3 ) => 0 x  + 3y = 0

               => y = 0

Substitute y = 0 in ( 1 ) => x - y = 4

                                  => x - 0 = 4

                                        x = 4

Answer:

11.16

Step-by-step explanation:

4sf=four numbers

if 0 is first number, leave it out because 0 is a significant figure

Answer:

11•16

u won't add zero because its less than 5.

Answer:

i think its A but im not sure its correct

Step-by-step explanation:

Answer:

232

Step-by-step explanation:

In picture

Brainliest please

Answer:

see below

Step-by-step explanation:

-X – 10 > 14 + 2x.

Subtract 2x from each side

-x-2x -10 > 14+2x-2x

-3x -10 > 14

Add 10 to each side

-3x -10+10 > 14+10

-3x > 24

Divide each side by -3, remembering to flip the inequality

-3x/-3 < 24/-3

x < -8

Answer:

9x^2 + 27x + 18

Step-by-step explanation:

(9x + 9)(x + 2)

=9x(x + 2) +9(x + 2)

=9x^2 + 18x + 9x + 18

=9x^2 + 27x + 18

Answer:

Exponent

Step-by-step explanation:

^ means raised to the power of

The number being raised is known as the exponent

In this case it's the exponent is 4

Answer:

Step-by-step explanation:

Answer:

1/9

Step-by-step explanation:

You combine the fractions finding the least common denominator. Once you do that, you get your answer of 1/9.

I hope this information was of any use to you.

Answer:

[tex]x^2+4x-7=(x+4)^2-23[/tex] where [tex]a=4[/tex] and [tex]b=-23[/tex]

Step-by-step explanation:

Given: [tex]x^2+4x-7[/tex]

Complete the square: [tex](x^2+4x+16)-23[/tex]

Reduce trinomial: [tex](x+4)^2-23[/tex]

Therefore, [tex]x^2+4x-7=(x+4)^2-23[/tex] where [tex]a=4[/tex] and [tex]b=-23[/tex].

Answer:

Assuming you want to know there was for UK it was [tex]\frac{3}{8}[/tex]

Step-by-step explanation:

Let's add the fractions together

[tex]\frac{1}{3} +\frac{1}{6}+\frac{1}{8\\}\\\frac{8}{24} +\frac{4}{24} +\frac{3}{24} =\frac{15}{24}[/tex]

The remainder is the amount in UK so

[tex]\frac{24}{24} -\frac{15}{24} =\frac{9}{24} \\[/tex]

Simplified it's [tex]\frac{3}{8}[/tex]

Answer:

Step-by-step explanation:

             Statements                                  Reasons

1). AD ≅ BC                                           1). Given

2). ∠D ≅ ∠C                                          2). Given

3). ∠DEA ≅ ∠CEB                                 3). Vertically opposite angles

4). ΔADE ≅ Δ BCE                                4). AAS postulate of congruence

5). AE ≅ BE                                           5). CPCTC

Hence, proved.