If RT = 90, find the length of RO. (SU = 25)(SO is perpendicular to RT)

To determine if the given vectors form a fundamental set of solutions on the interval (-∞, ∞) for the system ′ = , we need to check if they are linearly independent. If they are linearly independent, they form a fundamental set of solutions, and the general solution can be obtained by taking linear combinations of these vectors.

To determine if the vectors form a fundamental set of solutions, we need to check if they are linearly independent. If they are linearly independent, it means that no vector can be expressed as a linear combination of the others.

Let's denote the given vectors as v1, v2, ..., vn. We can create a matrix A by placing these vectors as its columns. If the determinant of A is non-zero, the vectors are linearly independent, and they form a fundamental set of solutions.

If the vectors are linearly independent, the general solution to the system is given by the linear combination of these vectors, where the coefficients can be any constants. Each solution can be expressed as a linear combination of the vectors, and the general solution represents all possible solutions to the system.

On the other hand, if the vectors are linearly dependent, they do not form a fundamental set of solutions. In this case, additional vectors are needed to form a complete set of solutions.

By determining the linear independence of the given vectors, we can conclude whether they form a fundamental set of solutions and obtain the general solution accordingly.

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To find the equation for the line tangent to the parametric curve at the point where t=3, we need to find the values of x and y at t=3 and the corresponding slopes.

Given the parametric equations: x=t^3−9t and y=9t^2−t^4.

At t=3, we have:

x = (3)^3 - 9(3) = 0

y = 9(3)^2 - (3)^4 = 54

To find the slope at t=3, we need to find dy/dx:

dy/dt = 18t - 4t^3

dx/dt = 3t^2 - 9

dy/dx = (dy/dt) / (dx/dt)

      = (18t - 4t^3) / (3t^2 - 9)

At t=3, we have:

dy/dx = (18(3) - 4(3)^3) / (3(3)^2 - 9)

     = -6

Therefore, the slope of the tangent line at t=3 is -6. To find the equation of the tangent line, we use the point-slope form- y - 54 = (-6)(x - 0)

Simplifying  y = -6x + 54

So the equation of the tangent line at t=3 is y = -6x + 54x

For t=-3, we can repeat the same process to find the equation of the tangent line. However, since the curve is symmetric about the y-axis, the tangent line at t=-3 will have the same equation as the tangent line at t=3, except reflected across the y-axis. Therefore, the equation of the tangent line at t=-3 is y = 6x + 54.

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The system has infinitely many solutions, and one of them is (9, -3/4).

To have a system of linear equations with infinitely many solutions, the two equations must represent the same line. Therefore, we need to obtain a second equation that has the same slope and y-intercept as 2x + 8y = 12.Here's how we can do that:2x + 8y = 12 is equivalent to 2(x + 4y) = 12, which reduces to x + 4y = 6.To create a second equation that represents the same line, we can multiply this equation by a constant, say 2, which gives us:2(x + 4y) = 12 (original equation)2x + 8y = 12 (distribute 2 on the left side)4x + 16y = 24 (multiply both sides by 2)Dividing both sides by 4, we get x + 4y = 6, which is the same as the first equation. Therefore, the system of equations is:2x + 8y = 124x + 16y = 24This system of equations is consistent and has infinitely many solutions because the two equations are equivalent and represent the same line, and every point on this line satisfies both equations.The solution to this system can be found using either equation by solving for one variable in terms of the other and substituting into either equation. For instance, we can solve for y in terms of x as follows:x + 4y = 6 => 4y = 6 - x => y = (6 - x)/4Substituting this expression for y into the first equation gives us:2x + 8((6 - x)/4) = 122x + 2(6 - x) = 1230 - 2x = 12 => 2x = 18 => x = 9Substituting x = 9 into y = (6 - x)/4 gives us:y = (6 - 9)/4 = -3/4Therefore, the system has infinitely many solutions, and one of them is (9, -3/4).

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The radius of the cone-shaped hole is approximately 4.08 ft.

Given that the volume of a cone-shaped hole is 50π ft³ and the depth of the hole is 9 ft, we need to find the radius of the cone-shaped hole.

To find the radius of the cone-shaped hole, we'll use the formula for the volume of a cone.

V = (1/3)πr²h

Where V = Volume, r = Radius, h = Height

So, the radius of the cone-shaped hole can be calculated as follows:

Volume of the cone = 50π ft³

Height of the cone = 9 ft

V = (1/3)πr²h50π

= (1/3)πr²(9)

Multiplying both sides by 3/π, we get:

150 = r²(9)r²

= 150/9r²

= 16.67 ft²

Taking the square root of both sides, we get:

r = 4.08 ft

Therefore, the radius of the cone-shaped hole is approximately 4.08 ft.

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The value of a is -1/2 when the slope of a line passing through points A(2a,3) and B(-1,3) is 6.

The slope formula can be used to find the value of a in the equation,  which states that the slope of a line passing through two points (x1, y1) and (x2, y2) is given by the formula (y2 - y1) / (x2 - x1).

In this case, the two points are A(2a, 3) and B(-1, 3), and we know that the slope is 6.

By substituting values into the slope formula:

(3 - 3) / (-1 - 2a) = 6

Simplifying the equation:

0 / (-1 - 2a) = 6

-1 - 2a = 0

-1 = 2a

Dividing both sides by 2:

-1/2 = a

So, the value of "a" is -1/2.

Therefore the value of a is -1/2 when the slope of a line passing through points A(2a,3) and B(-1,3) is 6.

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The solution is: the volume of the soup can is 311.01 cm³.

Here,

we know that

the volume of the soup can =pi*r²*h

here, we get,

diameter=6 cm

---------->

so, radius is:

r=6/2

-----> r=3 cm

h=11 cm

so, we get,

the volume of the soup can

=3.14*3²*11

-----> 311.01 cm³

Hence, The solution is: the volume of the soup can is 311.01 cm³.

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The equation is solved for x as x = √12 - 2

Real numbers are simply defined as the combination of rational and irrational numbers, in the number system.

Note that algebraic expressions are defined as expressions that are made up of terms, variables, coefficients, factors and constants

From the information given, we have that;

5(x+2)² = 60

Divide both sides by the multiplier, we have;

(x + 2)²= 60/5

Divide the values

(x + 2)²= 12

Now, find the square root of both sides, we get;

x+ 2= √12

Now, collect the like terms, we have;

x = √12 - 2

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The equation of the circle that forms the section of the rollercoaster is:x² + y² = 900

The shape of this particular section of the rollercoaster is a half of a circle. Center the circle at the origin and assume the highest point on this leg of the roller coaster is 30 feet above the ground.To find the equation of the circle that forms the section of the rollercoaster, we can use the standard form equation of a circle which is:(x - h)² + (y - k)² = r²Where (h, k) is the center of the circle and r is the radius. Since the center is at the origin, h = 0 and k = 0. We only need to find the value of the radius, r.The highest point on the rollercoaster is at the center of the circle. Since it is 30 feet above the ground, it means that the distance from the center to the ground is also 30 feet. Thus, the radius is equal to 30 feet.

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The value of the degrees of freedom for a two-mean pooled t-test with samples of size 15 and 32 is 45.

The degrees of freedom for a two-mean pooled t-test can be calculated using the formula:

df = (n1 - 1) + (n2 - 1)

Substituting n1 = 15 and n2 = 32, we get:

df = (15 - 1) + (32 - 1) = 14 + 31 = 45

Therefore, the value of the degrees of freedom for a two-mean pooled t-test with samples of size 15 and 32 is 45.

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a. Adding a control group in the design of this study would provide a baseline for comparison, as it would receive no treatment or a placebo.

b. The experimental design for this study would look like this:

Group 1: Glucosamine Treatment (100 Dogs)

Group 2: Chondroitin Treatment (100 Dogs)

Group 3: Control Group (100 Dogs)

c. Blocking on clinics would be a better variable to use as a blocking variable because dogs from the same clinic are likely to be more similar to each other in terms of environmental factors than dogs from different clinics, allowing for better control of environmental factors.

a. Adding a control group in the design of this study would provide a baseline for comparison, as it would receive no treatment or a placebo. This would allow researchers to determine if any observed changes in joint and hip health are due to the supplements or simply due to natural variations over time.

b. To assign the 300 dogs to three groups for a completely randomized design, the following steps could be taken:

Number the 300 dogs from 1 to 300.

Use a random number generator to assign each dog to one of three groups: glucosamine, chondroitin, or control.

Divide the 300 dogs into three equal-sized groups of 100 dogs each.

Administer the appropriate treatment to each group for six months.

Evaluate changes in joint and hip health after six months of treatment.

The experimental design for this study would look like this:

Group 1: Glucosamine Treatment (100 Dogs)

Group 2: Chondroitin Treatment (100 Dogs)

Group 3: Control Group (100 Dogs)

c. Blocking on clinics would be a more appropriate variable to use for blocking than breed of dog.

This is because dogs from the same clinic are likely to be more similar to each other in terms of environmental factors, such as diet and exercise, than dogs from different clinics.

Therefore, by blocking on clinics, researchers can reduce the effects of these environmental factors and better isolate the effects of the supplements on joint and hip health.

In contrast, blocking on breed of dog may not be as effective since dogs of the same breed can come from different clinics and have different lifestyles, making it harder to control for environmental factors.

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The coordinates of the point on the directed line segment from (−3,−5) to (7,10) that partitions the segment into a ratio of 2 to 3 are (1 + √3, 4 + √6) and (1 - √3, 4 - √6).

To find the coordinates of the point that partitions the segment from (−3,−5) to (7,10) into a ratio of 2:3, we can use the ratio formula.

Let (x, y) be the coordinates of the point we're looking for. Then the distance from (−3,−5) to (x,y) is 2/5 of the total distance, and the distance from (x,y) to (7,10) is 3/5 of the total distance.

Using the distance formula, we can find the total distance between the two points:

d = √[(7 - (-3))² + (10 - (-5))²] = √[(10)² + (15)²] = √325

The distance from (−3,−5) to (x,y) is (2/5)√325, and the distance from (x,y) to (7,10) is (3/5)√325.

We can set up two equations based on the coordinates:

(x - (-3))² + (y - (-5))² = (2/5)√325)²

(x - 7)² + (y - 10)² = (3/5)√325)²

Expanding and simplifying these equations, we get:

(x + 3)² + (y + 5)² = 52

(x - 7)² + (y - 10)² = 117

Solving these equations simultaneously will give us the coordinates of the point that partitions the line segment into a 2:3 ratio. One possible method is to solve for y in terms of x in both equations, and then set the two expressions equal to each other:

(x + 3)² + (y + 5)² = 52

(x - 7)² + (y - 10)² = 117

y = -5 ± √(52 - (x + 3)²)

y = 10 ± √(117 - (x - 7)²)

-5 ± √(52 - (x + 3)²) = 10 ± √(117 - (x - 7)²)

Squaring both sides of the equation and simplifying, we get:

x² - 2x + 28 = 0

This quadratic equation has two solutions:

x = 1 ± √3

Substituting each value of x into either equation for y, we get the coordinates of the two points that partition the segment into a 2:3 ratio:

(1 + √3, 4 + √6) and (1 - √3, 4 - √6)

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The required exponential regression equation is y = 6682 · 0.949ˣ

Given is a table we need to create an exponential regression for the same,

The exponential regression is give by,

y = a bˣ,

So here,

x₁ = 4, y₁ = 5,434

x₂ = 6, y₂ = 4,860

x₃ = 10, y₃ = 3963

Therefore,

Fitted coefficients:

a = 6682

b = 0.949

Exponential model:

y = 6682 · 0.949ˣ

Hence the required exponential regression equation is y = 6682 · 0.949ˣ

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The teacher will have a total of 120 pens if 12 sets of pens are ordered.

To find the total number of pens a teacher will have if 12 sets of pens are ordered, we can start by finding the total number of pens in one set and then multiply it by 12.

In one set, there are 4 blue pens, 3 black pens, 2 red pens, and 1 purple pen. To find the total number of pens in one set, we can simply add the number of pens of each color:

Total pens in one set = 4 + 3 + 2 + 1 = 10

Therefore, the numerical expression to represent how many pens a teacher will have if 12 sets of pens are ordered is:

12 × 10 = 120

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The mass, in grams, of a piece of metal that has a volume of 3.83.8 cubic centimeters is approximately 0.3 g (rounded to the nearest tenth of a gram).

To determine the mass, in grams, of a piece of metal that has a volume of 3.83.8 cubic centimeters, we can use the proportional relationship between the mass and the volume of the pieces of metal. The table below lists the masses and volumes of several pieces of the same type of metal:

Volume (cubic centimeters)  Mass (grams)

72.7 31.29314.1 47.519112.1 140.239

We can find the mass of a piece of metal that has a volume of 3.83.8 cubic centimeters by using the proportional relationship between the masses and the volumes of the pieces of metal.

Here's how:

1.

We need to find the constant of proportionality that relates the masses and the volumes.

To do this, we can use any two pairs of values from the table.

Let's use the first and second pairs:

(mass) / (volume) = (31.293 g) / (72.7 cm³)

(mass) / (volume) = (47.519 g) / (14.1 cm³)

We can cross-multiply to get:

(31.293 g) × (14.1 cm³) = (72.7 cm³) × (mass)

(47.519 g) × (72.7 cm³) = (14.1 cm³) × (mass)

2.

We can solve for the mass in either equation.

Let's use the first one:

(31.293 g) × (14.1 cm³) = (72.7 cm³) × (mass)

mass = (31.293 g) × (14.1 cm³) / (72.7 cm³)

mass = 6.086 g

We have found that the mass of a piece of metal that has a volume of 72.7 cm³ is 6.086 g.

This means that the constant of proportionality is 6.086 g / 72.7 cm³ ≈ 0.08383 g/cm³.

3.

Finally, we can use the constant of proportionality to find the mass of a piece of metal that has a volume of 3.83.8 cubic centimeters.

We can use this formula:

(mass) / (volume) = 0.08383 g/cm³

mass = (volume) × 0.08383 g/cm³

mass = 3.83.8 cm³ × 0.08383 g/cm³

mass ≈ 0.321 g

Therefore, the mass, in grams, of a piece of metal that has a volume of 3.83.8 cubic centimeters is approximately 0.3 g (rounded to the nearest tenth of a gram).

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The given series is absolutely convergent and conditionally convergent.

To determine whether the series

Š 15 - cos(3n) / [tex]n^{(2/3)}[/tex] - 2

is absolutely convergent, conditionally convergent, or divergent, we need to check both the absolute convergence and conditional convergence.

First, we consider the absolute convergence of the series. We take the absolute value of the series to obtain:

Š |15 - cos(3n)| / [tex]\ln^{(2/3)}[/tex] - 2|

By using the limit comparison test with the series 1/n^(2/3), we can conclude that the series is convergent, and therefore, absolutely convergent.

Next, we consider the conditional convergence of the series. We take the series:

Š 15 - cos(3n) / [tex]n^{(2/3)}[/tex] - 2

and group the terms for even and odd values of n, respectively:

Š (15 - cos(3n)) / [tex]n^{(2/3)}[/tex] - 2 = [15 / [tex]n^{(2/3)}[/tex] - 2] - [cos(3n) / [tex]n^{(2/3)}[/tex] - 2]

The first term in the above equation converges to 0, as n approaches infinity. However, the second term is an alternating series, which does not converge to 0. Thus, by the alternating series test, the series is conditionally convergent.

Therefore, the given series is absolutely convergent and conditionally convergent.

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To determine whether the series Š 15 - cos(3n) / n^(2/3) - 2 n = 1 is absolutely convergent, conditionally convergent, or divergent, we need to first check if the series converges absolutely.

To do this, we need to find the absolute value of each term in the series:

|15 - cos(3n)| / |n^(2/3) - 2|

Since the absolute value of cosine is always less than or equal to 1, we can simplify the expression to:

(15 + 1) / |n^(2/3) - 2|

= 16 / |n^(2/3) - 2|

Next, we need to determine whether the series Σ 16 / |n^(2/3) - 2| converges or diverges.

We can use the limit comparison test with the p-series Σ 1/n^(2/3):

lim(n → ∞) (16 / |n^(2/3) - 2|) / (1/n^(2/3))

= lim(n → ∞) (16n^(2/3)) / |n^(2/3) - 2|

We can simplify this expression by dividing the numerator and denominator by n^(2/3):

= lim(n → ∞) (16 / |1 - 2/n^(2/3)|)

Since the limit of the denominator is 1 and the limit of the numerator is 16, we can apply the limit comparison test and conclude that the series Σ 16 / |n^(2/3) - 2| converges if and only if Σ 1/n^(2/3) converges.

However, the series Σ 1/n^(2/3) is a p-series with p = 2/3, which is less than 1. Therefore, Σ 1/n^(2/3) diverges by the p-series test.

Since Σ 16 / |n^(2/3) - 2| converges if and only if Σ 1/n^(2/3) diverges, we can conclude that Σ 16 / |n^(2/3) - 2| diverges.

Therefore, the original series Š 15 - cos(3n) / n^(2/3) - 2 n = 1 is also divergent.

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Answer:Supplementary

Step-by-step explanation:

They add to 180, making them supplementary.

There is no incorrect statement to fix. The incorrect statement has not been specified in the question. Thus, we need to check for the correctness of both statements.

After Christmas, artificial Christmas trees are 60% off. Employees get an additional 10% off the sale price. We know the original prices of both trees, which are $115 and $205 respectively. Let's calculate the new price of Tree A and Tree B.

Tree A original price $115. Tree B original price $205. After Christmas, both trees are 60% off. Let's calculate the new price of Tree A and Tree B. Tree A:  [tex]$115 - (60/100) x $115 = $46 [/tex].

Therefore, the sale price of Tree A is $46.

Employees get an additional 10% off the sale price.

Therefore, the discounted price for the employees is  [tex]$46 - (10/100) x $46 = $41.4 [/tex].

Tree B:  [tex]$205 - (60/100) x $205 = $82 [/tex].

Therefore, the sale price of Tree B is $82. Employees get an additional 10% off the sale price.

Therefore, the discounted price for the employees is [tex]$82 - (10/100) x $82 = $73.8[/tex].

As we calculated above, the statements are correct. Hence, there is no incorrect statement. Thus, no fix is required. Therefore, the answer is "There is no incorrect statement to fix."

There is no incorrect statement to fix. The original prices of Tree A and Tree B are correctly calculated, as well as the discounted prices for employees. The given statements are accurate and do not require any correction.

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The incorrect statement is, “Tree A is $46 after all discounts are applied.”

After Christmas, the artificial Christmas trees are 60% off and employees get an additional 10% off the sale price.

Two trees are Tree A and Tree B.

Tree A original price is $115.

After a 60% discount, the price is:60/100 x $115 = $69

The sale price of Tree A is $69.

After the employees' 10% discount: 10/100 x $69 = $6.9

Discounted price of Tree A is: $69 - $6.9 = $62.1

Tree B original price is $205.

After a 60% discount, the price is: 60/100 x $205 = $123

The sale price of Tree B is $123.

After the employees' 10% discount:10/100 x $123 = $12.3

Discounted price of Tree B is: $123 - $12.3 = $110.7

Therefore, the incorrect statement is “Tree A is $46 after all discounts are applied.”

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If the slope of "fitted-line" is given to be 8.42, then the correct interpretation is Option(c), which states that "On average, every $1 million increase in salary is linked with 8.42 point increase in "winning-percentage".

The "Slope" of the "fitted-line" denotes the change in response variable (which is winning percentage in this case) for "every-unit" increase in the predictor variable (which is salary of head coach, in millions of dollars).

In this case, the slope is 8.42, which means that on average, for every $1 million increase in salary of "head-coach", there is an increase of 8.42 points in "winning-percentage".

Therefore, Option (c) denotes the correct interpretation of slope.

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The given question is incomplete, the complete question is

Abigail gathered data on different schools' winning percentages and the average yearly salary of their head coaches (in millions of dollars) in the years 2000-2011. She then created the following scatterplot and regression line.

The fitted line has a slope of 8.42.

What is the best interpretation of this slope?

(a) A school whose head coach has a salary of $0, would have a winning percentage of 8.42%,

(b) A school whose head coach has a salary of $0, would have a winning percentage of 40%,

(c) On average, each 1 million dollar increase in salary was associated with an 8.42 point increase in winning percentage,

(d) On average, each 1 point increase in winning percentage was associated with an 8.42 million dollar increase in salary.

Answer: The Total number of Students who like Milk is 12 and the total number of Students who like Tea is 9.

Step-by-step explanation:

Let us start off by subtracting the number of students who like both milk and tea from the total number of students:

33-12 = 21

Rest of the 21 Students like either Milk or Tea. Now with the help of the ratio, we find the total number of students who like Milk alone:

21 x  4/7 = 12

(4 Being the ratio of students who like Milk and 7 being the total ratio of 4+3 )

12 Students like Milk while:

21-12= 9 (or) 21 x 3/7= 9

9 Students like Tea.

The longest line segment is line segment A.

option A.

The length of the longest line is calculated by converting the unit measurement of both lines to the same units as shown below.

the length of line A = 8.3 feet

the length of line B = 2 m

The given conversion factor is;

3.28 ft = 1 m

The length of line B is feet is calculated as follows;

Length of line B (ft) = length in meters  x conversion factor

the length of line B = 2 m  x  3.28 ft / 1 m

the length of line B = 6.56 feet

Thus, we can conclude that the length of line A is greater than the length of line B.

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A) A counterexample for ∀x(x² ≥ x) is x = -1.

B) A counterexample for ∀x(x > 0 ∨ x < 0) is x = 0.

C) No counterexample exists for ∀x(x = 1).

A) The statement claims that for all integers x, x² is greater than or equal to x. However, when x = -1, we get (-1)² = 1, which is not greater than or equal to -1.

B) The statement claims that for all integers x, x is either greater than 0 or less than 0. However, when x = 0, it is not greater than 0 nor less than 0, disproving the claim.

C) The statement is not universally quantified, as it claims that every integer x is equal to 1. This is clearly false, as there are many other integers besides 1.

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We start by rearranging the given differential equation into the standard form of a separable differential equation:

[tex]\frac{dh}{dt} = (\frac{-R}{v}) (\frac{h}{R+h})[/tex]

=> [tex](\frac{v}{R+h)} \frac{dh}{h} = \frac{-R}{v} dt[/tex]

Integrating both sides with respect to their respective variables, we get:

[tex]ln|h+R| - ln|R| = (\frac{-R}{v}) t + C[/tex]

where C is the constant of integration. Simplifying, we have:

[tex]ln|h+R| = (\frac{-R}{v})t + ln|CR|[/tex]

where CR is a positive constant obtained by combining R and the constant of integration.

Taking the exponential of both sides, we get:

[tex]|h+R| = e^{(\frac{-R}{v}) t} + ln|CR|)[/tex]

=> [tex]|h+R| = e^{(\frac{-R}{v}) t} CR[/tex]

We take cases for h+R being positive and negative:

Case 1: h+R > 0

Then we have:  [tex]|h+R| = e^{(\frac{-R}{v}) t} CR[/tex]

[tex]h = (e^{(\frac{-R}{v}) t} CR) - R[/tex]

Case 2: h+R < 0

Then we have:

[tex]|h+R| = e^{(\frac{-R}{v}) t} CR[/tex]

=>[tex]h =- ((e^{(\frac{-R}{v}) t} CR)+R[/tex]

Therefore, the general solution to the given differential equation is:

[tex]h(t)=e^{(\frac{-R}{v}) t} CR)-R[/tex] if h+R > 0,

[tex]- (e^{\frac{-R}{v} }t ) CR)+R[/tex]if h+R < 0}

where CR is a positive constant determined by the initial conditions.

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If an auditorium has a total of 1280 seats, there are 40 seats in each row.

The total number of seats in the auditorium is modeled by the function f(x) = [tex]2x^{2} -24x[/tex], where x represents the number of seats in each row. We need to find the value of x when f(x) equals 1280.

Setting the equation equal to 1280, we have:

[tex]2x^{2} -24x[/tex] = 1280

Rearranging the equation, we get:

[tex]2x^{2} -24x[/tex] - 1280 = 0

To solve this quadratic equation, we can either factor it or use the quadratic formula. Factoring is not straightforward in this case, so we'll use the quadratic formula

x = (-b ± √(b^2 - 4ac)) / (2a)

For our equation, a = 2, b = -24, and c = -1280. Plugging in these values, we have:

x = (-(-24) ± √((-24)^2 - 4(2)(-1280))) / (2(2))

Simplifying further, we get:

x = (24 ± √(576 + 10240)) / 4

x = (24 ± √10816) / 4

x = (24 ± 104) / 4

This gives us two possible solutions: x = (24 + 104) / 4 = 128/4 = 32 or x = (24 - 104) / 4 = -80/4 = -20.

Since the number of seats cannot be negative, the valid solution is x = 32. Therefore, there are 32 seats in each row of the auditorium.

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Answer:

25 degrees

Step-by-step explanation:

these angles are equal. set them equal to each other and solve for x.

75 = 3x

x = 25

The answer is , This is a linear function, where the slope is -50 and the y-intercept is 82.  And the domain is  z ≥ 0.

The function that gives the daily profit for selling z shirts can be found using the formula f(x) = 82 – 50z.

This is a linear function, where the slope is -50 and the y-intercept is 82.

To find and interpret the given function values, we can substitute different values of z into the equation f(z) = 82 – 50z.

For example: If the company sells 0 shirts, the profit would be:

f(0) = 82 – 50(0) = $82

This means that the company would make $82 in profit even if they didn't sell any shirts.

If the company sells 1 shirt, the profit would be:

f(1) = 82 – 50(1) = $32

This means that the company would make $32 in profit if they sold one shirt.

Each additional shirt sold would result in a decrease of $50 in profit because the slope of the function is -50.

Therefore, if the company sold 2 shirts, they would make $32 – $50 = -$18 in profit, which means they would be operating at a loss.

The appropriate domain for this function is any non-negative value of z, because the company cannot sell a negative number of shirts.

So the domain is: z ≥ 0.

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Carla will run on Sunday, November 12 and then run and swim on Thursday, November 16.

Carla runs every 3 days and swims every Thursday.

Carla ran and swam on Thursday 9 November.

The next time Carla will run will be 3 days later: Sunday, November 12.

The next Thursday after November 9 is November 16.

Therefore, Carla will run on Sunday, November 12 and then run and swim on Thursday, November 16.

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Answer:

I’ve got a level 4 in pre algebra state test so this should be simple

Step-by-step explanation:

in order to convert this just Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 1010. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

the answer would be: 1.716×10^11

And this is positive and not negative

Answer:

y=-4x

Step-by-step explanation:

Yes, you are correct. An equation in n variables is linear if it can be written in the form:

a1x1 + a2x2 + ... + an*xn = b

where a1, a2, ..., an are constants and x1, x2, ..., xn are variables. In this equation, each variable x appears with a coefficient a that is a constant multiplier.

Additionally, the variables can only appear to the first power; that is, there are no higher-order terms such as x^2 or x^3.

The equation is called linear because the relationship between the variables is linear; that is, the equation describes a straight line in n-dimensional space.

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The area bounded by f(x) = √x and g(x) = x/2 on the interval [0,16] is 64.

To find the area bounded by the given functions, we need to determine the points of intersection. Setting f(x) = g(x), we get:

√x = x/2

Squaring both sides, we get:

x = 0 or x = 16

So the points of intersection are (0,0) and (16,8).

Next, we need to determine which function is on top in the interval [0,16]. We can do this by comparing the values of the two functions at x = 8, which lies in the middle of the interval. We have:

f(8) = √8 = 2√2

g(8) = 8/2 = 4

Since f(8) < g(8), the function g(x) is on top in the interval [0,16]. Therefore, the area bounded by the two functions is given by:

∫[0,16] (g(x) - f(x)) dx

= ∫[0,16] (x/2 - √x) dx

= [x^2/4 - (2/3)x^(3/2)] [0,16]

= (16^2/4 - (2/3)16^(3/2)) - (0 - 0)

= 64

Hence, the area bounded by the two functions is 64.

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