if the circumference of a circle is 52 cm, what is the radius? round to the nearest tenth. PLESE HELP I DONT HAVE THAT MUCH TIME :(

Answer:

[tex]x = \frac{3}{2} [/tex]

Step-by-step explanation:

[tex] \frac{x + 6}{x + 1} = \frac{6}{2} [/tex]

[tex] \frac{6}{2} = 3[/tex]

so, the solution of the equation will be as follows:

[tex] \frac{x + 6}{x + 1} = 3[/tex]

3(x+1) = x + 6

3x + 3 = x + 6

3x - x = 6 - 3

[tex]x = \frac{3}{2} [/tex]

so, the answer will be x = 3/2

Answer: B

Step-by-step explanation:

2(—2) + 10 = 6.

2(0) + 6 = 6.

2(2) + 2 = 6.

2(4) + (—2) = 6

Answer:

36

Step-by-step explanation:

2850/78 = 36.538

Answer:

36.538

Step-by-step explanation:

since he has 2,850 worth of string and he needs 78 pieces, you would divide 2,850 by 78 which gives you 36.53846154 but you would make it 36.538. if you needed to round by the tenths, its 36.5, hundredths is 36.54, and thousandths is 36.538.

Answer:4x1/3=4/3

Step-by-step explanation:

In the pictures there’s 4 one thirds and if u add them together is 4/3

Answer:

4-  

30 minutes --- 562.5 miles  

240 minutes --- 300 miles  

480 minutes --- 0 miles

600 minutes --- 150 negative miles (they would have already arrived).

 5- 240 CDs will weigh 720 ounces.

Step-by-step explanation:

4- Given that Bryan family's summer house is 600 miles away, and after 30 minutes, they are 562.5 miles left to their destination, to determine the distance in the following minutes the following calculations must be performed:

30 minutes --- 562.5 miles

240 minutes --- 300 miles

600 - 562.5 = (37.5) / 30 = (1.25) x 240 = 300 miles

480 minutes --- 0 miles

600 - 562.5 = (37.5) / 30 = (1.25) x 480 = 600 miles

600 minutes --- 150 negative miles

600 - 562.5 = (37.5) / 30 = (1.25) x 600 = 750 miles

5- Given that Jasmine mails 2 CDs in an envelope and the envelope weighs 6 ounces, to calculate the weight of 240 CDs the following algebraic calculation must be performed:

6/2 x 240 = X

3 x 240 = X

720 = X

Thus, 240 CDs will weigh 720 ounces.

Answer:

what grade are u?

Step-by-step explanation:

I'm assuming you want to know what "x"is. If so then for the first one x is 1/7. For the second one x= 5. And the last one is x= 3.

Step-by-step explanation:

To check you just substitute what ever x equals into the equation so 35x+5=10 would be 35(1/7)+5=10 and it should equal 10=10, which means infinite solutions. If you were not trying to find out what x equals then what are you looking for exactly?

Answer:

Let me see what i can do, I'll try. Hope this helps

Answer:

yo i know the answer its 5$ for me to help

Step-by-step explanation:

What is the question exactly? Ill answer when you tell me

Answer:

Hi how are you doing today Jasmine

Answer:

James walks 2.2 kilometers it is because 4.1-1.9=2.2

Step-by-step explanation:

and to check u can add 2.2 in 1.9 ko get 4.1 so james walked 2.2 distance kilometers from his house.

Answer:

Step-by-step explanation:

d + (d+1.9) = 4.1

2d = 2.2

d = 1.1 km

Answer:

The answer is 0.5

Step-by-step explanation:

The formula for a circumference of a circle is 3.14×diameter

3.14 × (3×2)

3.14×6

18.85

Answer:

sorry no idea

Step-by-step explanation:

Answer:

252 Cake Cones

Step-by-step explanation:

You have to make your own formula with the numbers in the problem. Here's how I set it up:

w= number of waffle cones

c=number of cake cones

We know that the number of waffle cones is the number of cake cones plus 50, so we write that out here: w=c+50

And we know that the sales total was $1422.50. That is, the number of waffle cones times the cost per cone plus the number of cake cone times their cost per cone, and we can write that out here: (3.25× w) + (1.75×c) =1,422.50.

Now, we can substitute our first formula into the second formula to solve for  C. The new equation reads: 3.25(c+50) + 1.75c=1,422.50

Distribute 3.25 to c and 50: 3.25c +162.50+1.75c=1,422.50

Combine like terms: 5c +162.50=1422.50

Subtract 162.50 from both sides: 5c=1260

Divide both sides by 5: C=252

TO CHECK YOUR WORK

Now that you have solved for C, plug that figure back into the first equation to solve for w: (252)+50=w, W=302

Now plug both numbers into your equation for the total cost:

3.25(302) + 1.75(252)=1,422.50

981.5+441= 1,422.50

You're done!

Answer:

An ordered pair that is a solution to the equation is (2,3).

Step-by-step explanation:

To find an ordered pair that is a solution to the equation, we attribute a value to one of the variables(x or y), and find the other.

4x-y=5​

Using y = 3

4x - 3 = 5

4x = 8

x = 8/4 = 2

An ordered pair that is a solution to the equation is (2,3).

your answer is C

your answer is C

your answer is C

your answer is C

your answer is C

Answer:

C

Step-by-step explanation:

2x+5=13

2x+5-5=13-5

2x=8

2x/2=8/2

X=4

Answer:

for n ≤ 3

we are going to put a circle on the 3 and make it filled in then you are going to start an arrow starting from the 3 going to the left all the way to the -10.

Answer:

n ≥ -1 or n ≤ 3

Combined:

-1 ≤ n ≤ 3

Since the inequalities are ≤, it'll be a closed circle

The closed circle will start AT -1 and another closed circle will end at 3

Answer:

8

Step-by-step explanation:

Hello There!

The median is the middle number of the set

So the first thing we want to do is put the numbers in order from greatest to least

0, 3, 4, 8, 10, 15, 20

Then we go to the middle number

The middle number is 8 so the answer is 8

Answer:

Im pretty sure its 10

Answer:

B. 4.73 and 4.97

Step-by-step explanation:

To solve this question, we need to understand the Empirical Rule and the Central Limit Theorem.

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Standard deviation of 0.92, sample of 500:

This means that [tex]\sigma = 0.92, n = 500, s = \frac{0.92}{\sqrt{500}} = 0.04[/tex]

By the central limit theorem, which interval do 99.7% of the sample means fall within?

Within 3 standard deviations of the mean. So

4.85 - 3*0.04 = 4.85 - 0.12 = 4.73

4.85 + 3*0.04 = 4.85 + 0.12 = 4.97

So, option B.

Answer:

4.73 and 4.97

Please give me brainliest, I really need it.

Answer:

360 - 98 = 262

Step-by-step explanation:

Answer:

[tex]P(X=8) = 0.0194[/tex]

[tex]P(X \ge 8)= 0.9820[/tex]

[tex]P(X \ge 1)= 1[/tex]

[tex]P(X\le 1) = 0.0000049[/tex]

Step-by-step explanation:

Given

[tex]\lambda = 15[/tex]

Poisson distribution is given by:

[tex]P(X=x) = \frac{\lambda^x e^{-\lambda}}{x!}[/tex]

Solving (a): 8 bugs

This implies that:

[tex]x = 8[/tex]

So, we have:

[tex]P(X=8) = \frac{15^8 * e^{-15}}{8!}[/tex]

[tex]P(X=8) = \frac{783.99418938}{40320}[/tex]

[tex]P(X=8) = 0.0194[/tex]

Solving (b): At least 8 bugs

This is represented as: [tex]P(X \ge 8)[/tex]

Using complement rule:

[tex]P(X \ge 8)= 1 - P(X<8)[/tex]

Where

[tex]P(X<8) = P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5) + P(X=6) + P(X=7)[/tex]

[tex]P(X<8) = \frac{15^1 * e^{-15}}{1!} + \frac{15^2 * e^{-15}}{2!} + \frac{15^3 * e^{-15}}{3!} + \frac{15^4 * e^{-15}}{4!} + \frac{15^5 * e^{-15}}{5!} + \frac{15^6 * e^{-15}}{6!} + \frac{15^7 * e^{-15}}{7!}[/tex]

[tex]P(X<8) = (\frac{15^1}{1!} + \frac{15^2}{2!} + \frac{15^3 }{3!} + \frac{15^4}{4!} + \frac{15^5}{5!} + \frac{15^6}{6!} + \frac{15^7}{7!}) e^{-15}[/tex]

[tex]P(X<8) = (15 + 112.5 + 562.5 + 2109.375 + 6328.125 + 15820.3125 + 33900.6696429) *e^{-15}[/tex]

[tex]P(X<8) = 58848.4821429 *e^{-15}[/tex]

[tex]P(X<8) = 0.0180[/tex]

So:

[tex]P(X \ge 8)= 1 - P(X<8)[/tex]

[tex]P(X \ge 8)= 1 - 0.0180[/tex]

[tex]P(X \ge 8)= 0.9820[/tex]

Solving (c): At least 1

This is represented as: [tex]P(X \ge 1)[/tex]

Using complement rule:

[tex]P(X \ge 1)= 1 - P(X<1)[/tex]

[tex]P(X<1) = P(X = 0)[/tex]

[tex]P(X<1) = \frac{15^0 e^{-15}}{0!}[/tex]

[tex]P(X<1) = \frac{e^{-15}}{1}[/tex]

[tex]P(X<1) = e^{-15}[/tex]

So:

[tex]P(X \ge 1)= 1 - P(X<1)[/tex]

[tex]P(X \ge 1)= 1 - e^{-15[/tex]

[tex]P(X \ge 1)= 0.99999969409[/tex]

[tex]P(X \ge 1)= 1[/tex]

Solving (d): Not more than 1

This implies at most 1.

It is represented as:

[tex]P(X\le 1)[/tex]

It is calculated using:

[tex]P(X\le 1) = P(X = 0) + P(X =1)[/tex]

[tex]P(X = 0) = e^{-15}[/tex]

[tex]P(X=1) = \frac{15^1 * e^{-15}}{1!}[/tex]

[tex]P(X=1) = 15 * e^{-15}[/tex]

So:

[tex]P(X\le 1) = e^{-15} + 15 * e^{-15}[/tex]

[tex]P(X\le 1) = 0.00000489443[/tex]

[tex]P(X\le 1) = 0.0000049[/tex]

Answer:

wouldn't this be 18.052

Step-by-step explanation:

add 15 and 2 then add 1 (from 0.7 plus 0.3) then add the other decimals

Answer: 18.052

Step-by-step explanation:

We just need to add them all.

15.352+0.7=16.052 16.052+2=18.052

Answer:

The answer is 8

Step-by-step explanation:

Answer:

A) 35

Step-by-step explanation:

x + 50 + 95 = 180

x + 145 = 180

x = 180 - 145

x = 35

Answer: option D

Step-by-step explanation: just did it

C was wrong and showed option D was the correct answer

Answer:

[tex]E(x) = \frac{1}{2}[/tex] -- Component A

[tex]E(x) = \frac{1}{3}[/tex] -- Component B

Step-by-step explanation:

Given

Distribution = Exponential

[tex]\lambda = 2[/tex] --- Component A

[tex]\lambda = 3[/tex] --- Component B

Solving (a): The mean time of A

The mean of an exponential distribution is:

[tex]E(x) = \frac{1}{\lambda}[/tex]

We have:

[tex]\lambda = 2[/tex] --- Component A

[tex]E(x) = \frac{1}{2}[/tex]

Solving (b): The mean time of B

The mean of an exponential distribution is:

[tex]E(x) = \frac{1}{\lambda}[/tex]

We have:

[tex]\lambda = 3[/tex] --- Component B

[tex]E(x) = \frac{1}{3}[/tex]

Answer:

2x-15=15

where x=15

2(15)-15=15

30-15=15

Answer:

2x-15=15

where x=15

2(15)-15=15

30-15=15