If the position of a particle on the x-axis at time t is −5t2, then the average velocity of the particle for 0 ≤ t ≤ 3 is

Answers

Answer 1

Answer:

v = 15 m / s

Explanation:

In this exercise we are given the position function

          x = 5 t²

and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval

          [tex]v= \frac{v_{f} - v_{o} }{t_{f} - t_{o} }[/tex]

let's look for the displacements

        t = 0     x₀ = 0 m

        t = 3     [tex]x_{f}[/tex] = 5 3 2

                     x_{f} = 45 m

 

we substitute

           [tex]v = \frac{45 -0}{3 - 0}[/tex]

           v = 15 m / s


Related Questions

Does an object with constant speed also have constant velocity?. Single choice.

Answers

Answer: No, constant speed does not mean constant velocity.

A classic often used example would be to consider a car driving in circles. If the speedometer reads say 20 mph the entire time, then the speed of the car is held constant (ie the same). But the velocity is changing because velocity measures direction along with speed. The car is changing direction as it moves in a circle.

Which of the following is most likely to be a conductor?
OA. Aplastic
OB. A molecule containing only nonmetal atoms
OC. A covalently bonded molecule
D. Acompound containing metallic bonds

Answers

Answer:

D.

Explanation:

A compound containing metallic bonds

hope it helps!

Gasoline is an example of an accelerant. True False

Answers

Answer:

true

Explanation:

Answer:

I believe its true

Explanation:

Gasoline is the most common fire accelerant used but it could also be present at a scene as an ignitable liquid due to gasoline being a common fuel. Although ignitable liquids are the most common fire accelerants it is possible to have other chemicals being used as a fire accelerant.

A heat lamp produces 32.8 watts of power at a wavelength of 6.5 mm. How many photons are emitted per second

Answers

Answer: 1.1x10^21 photons / sec

Explanation:energy per photon

.. E / photon = hc / L = (6.626x10^-34 J x sec) x (3.00x10^8 m/sec) / (6.5x10^-6m)

.. E / photon = 3.06x10^-20 J / photon

then

.. (32.7 watts) x (1 J/sec / 1watt) x (1 photon / 3.06x10^-20J) = 1.1x10^21 photons / sec

The number of photons are emitted per second will be "1.07".

According to the question,

Power,

P = 32.8 watts

           = 32.8 J/s

Wave length,

λ = 6.5 μm

          = [tex]6.5\times 10^{-6}[/tex]

As we know,

→ [tex]E = \frac{hc}{\lambda}[/tex]

By substituting the values, we get

      [tex]= \frac{32.8}{\frac{(4.42\times 10^{-34})(3\times 10^{-4})}{4.5\times 10^{-6}} }[/tex]

      [tex]= \frac{32.8}{3.055e}[/tex]

      [tex]= 1.07[/tex]

Thus the above answer is correct.

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4 pleasee i have to submit in 10 minutes

Answers

Answer:

True

Explanation:

Describe what happens to the moving boat when the oars are out of the water and the forward thrust is zero

Answers

Answer:

The boat won't be able to move if the oars were out and there was no thruster. If there was a flow of the water then yes there would be a moving boat.

1. what is the term used for the movement of air from sea to land
2.Is it true that air blows from low pressure to high pressure zone. Explain
3.What is the ore of gold silicon ​

Answers

Answer:

1.Sea breeze

2. False

3.

a)Gold nugget

b)Silica sand

Explanation:

1.

The movement of air / wind blowing from the sea to the land is called sea breeze. This occurs due to high temperature differences between the water body and the land. The land is at its maximum heating, causing low pressure zones. High pressure zones in the adjacent water body causes the air to from from the sea to the land to occupy the zones of low pressures created.

2.

Air blows from areas with high pressures to those with low pressures. When an area experiences high temperatures, it causes the environment to have low pressure, creating voids , which are empty spaces that require to be filled. Additionally, the high temperatures heat the air around to cause it to rise creating the voids. Due to low pressure created, air from high pressure zones move in to occupy these zones. Hence air flows from areas with high air pressures to those with low pressures.

3.The ore for Gold is Gold nugget where as that for silicon is silica sand.

A 15 kg box is sliding down an incline of 35 degrees. The incline has a coefficient of friction of 0.25. If the box starts at rest, how fast is it moving after it travels 3 meters?

Answers

The box has 3 forces acting on it:

• its own weight (magnitude w, pointing downward)

• the normal force of the incline on the box (mag. n, pointing upward perpendicular to the incline)

• friction (mag. f, opposing the box's slide down the incline and parallel to the incline)

Decompose each force into components acting parallel or perpendicular to the incline. (Consult the attached free body diagram.) The normal and friction forces are ready to be used, so that just leaves the weight. If we take the direction in which the box is sliding to be the positive parallel direction, then by Newton's second law, we have

• net parallel force:

F = -f + w sin(35°) = m a

• net perpendicular force:

F = n - w cos(35°) = 0

Solve the net perpendicular force equation for the normal force:

n = w cos(35°)

n = (15 kg) (9.8 m/s²) cos(35°)

n ≈ 120 N

Solve for the mag. of friction:

f = µ n

f = 0.25 (120 N)

f ≈ 30 N

Solve the net parallel force equation for the acceleration:

-30 N + (15 kg) (9.8 m/s²) sin(35°) = (15 kg) a

a ≈ (54.3157 N) / (15 kg)

a ≈ 3.6 m/s²

Now solve for the block's speed v given that it starts at rest, with v₀ = 0, and slides down the incline a distance of ∆x = 3 m:

v² - v₀² = 2 ax

v² = 2 (3.6 m/s²) (3 m)

v = √(21.7263 m²/s²)

v ≈ 4.7 m/s

True or False? The horizontal component of velocity of a projectile remains constant; the vertical component of velocity changes throughout the trajectory.

Answers

Answer:

False!!

Explanation:

A truck travels at a constant acceleration of 3.6 m/s2. Find the mass of the truck if a
39,600 N net force is required to produce this acceleration.

Answers

Answer:

The mass of the truck is 11,000 Kg.

Explanation:

Mechanical Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object.

It's given a truck travels at a constant acceleration of [tex]a=3.6~m/s^2[/tex] when a net force of F=39,600 N is applied.

To find the mass of the truck, solve the equation for m:

[tex]\displaystyle m=\frac{F}{a}[/tex]

[tex]\displaystyle m=\frac{39,600}{3.6}[/tex]

Operating:

m = 11,000 Kg

The mass of the truck is 11,000 Kg.

PLZ HELP MEEEEEEE,;-;

Answers

Answer:

thxs for the points

Explanation:

because just started

A ball of mass 0.0887 kg is dropped from a height 1.76 m above the ground. The acceleration of gravity is 9.8 m/s 2 . Neglecting air resistance, determine the

Answers

Use GPE = mgh = 0.0887 x 1.76 x 9.8 = 1.53 joules

Answer:

determine the.........

What is the amount of space that a gas takes up called?
ASAP 20 points???

Answers

Answer:

Mass is the amount of matter an object has, and volume is the amount of space the matter takes up. Solids are easy to recognize. They have definite shape, mass, and volume. Trees are solids.

Explanation:

The amount of space occupied by a gas is called volume of the gas. The volume of a gas depends on the temperature and pressure.

What is volume ?

Volume is a physical parameter describing the space occupied  by a substance. Volume is an extensive property. Therefore, volume is dependent upon amount of the substance.

The total amount of a substance is called its mass. Density describes how closely its particles are packed in a given volume. Hence, volume is the ratio of mass to the density.

Volume of a gas changes with its temperature and pressure. As the pressure increases, volume increases whereas, as the temperature increase, volume increases.

Find more on volume:

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tenses of
write=
read=

Answers

Answer:

present

Explanation:

read doesn't change but write is in present tense

TNT is an example of a high explosive. True False

Answers

The answer is true I think I had this question too

The statement "TNT is an example of a high explosive." is true.

What is TNT?

TNT, short for trinitrotoluene, is a highly explosive chemical compound that is widely used in military and industrial applications. It is a pale yellow crystalline solid that is highly sensitive to heat, shock, and friction. TNT is made by the nitration of toluene, a colorless liquid hydrocarbon that is derived from petroleum.

TNT is known for its high explosive power, which makes it a popular choice for use in bombs, missiles, and other weapons. When TNT is detonated, it releases a large amount of energy in the form of a shock wave and high-temperature gases. This explosive power is due to the presence of three nitro groups (-NO2) in the TNT molecule, which makes it highly unstable and reactive.

Despite its explosive properties, TNT is relatively stable under normal conditions and can be stored and transported safely. It is also relatively easy to manufacture, which has made it a popular choice for military applications since World War I. Today, TNT is still used in a variety of military and industrial applications, although it has been largely replaced by more powerful explosives in some applications.

Therefore, The correct answer is True. TNT (trinitrotoluene) is a high explosive that is commonly used in military and industrial applications. It is highly sensitive to heat, shock, and friction and can release a large amount of energy when it detonates.

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5. Rashmi is watching her favourite TV show. Her grandmother asks her to look for her senga
which has fallen on the ground. Rashmi bringshermagnet and searches the neede
(a) Which property of magnet do you think helped Rashmi find the needle?
(b) Which value is displayed by Rashmi ?​

Answers

Answer:

a) Magnet attracts to ferromagnetic substances like Iron.

b) Scientific thinking (critical thinking)

A pressure sensor inside of a mixing tank is designed to turn red when the pressure inside the tank exceeds 1.9 kPa. If the sensor is a square, 10 cm on each side, how great a force must be exerted on the sensor in order for it to turn red?

Answers

Answer:

19 N

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = 1.9 kPa

Length (L) = 10 cm

Force (F) =?

Next, we shall convert 1.9 KPa to N/m². This can be obtained as follow:

1 KPa = 1000 N/m²

Therefore,

1.9 KPa = 1.9 KPa × 1000 N/m² / 1 KPa

1.9 KPa = 1900 N/m²

Thus, 1.9 KPa is equivalent to 1900 N/m².

Next, we shall convert 10 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

10 cm = 10 cm × 1 m / 100 cm

10 cm = 0.1 m

Thus, 10 cm is equivalent to 0.1 m

Next, we shall determine the area of the square. This can be obtained as follow:

Length (L) = 0.1 m

Area of square (A) =?

A = L²

A = 0.1²

A = 0.01 m²

Thus, the area of the square is 0.01 m².

Finally, we shall determine the force that must be exerted on the sensor in order for it to turn red. This can be obtained as follow:

Pressure (P) = 1900 N/m²

Area (A) = 0.01 m²

Force (F) =?

P = F/A

1900 = F / 0.01

Cross multiply

F = 1900 × 0.01

F = 19 N

Therefore, a force of 19 N must be exerted on the sensor in order for it to turn red.

A car is traveling with 90km/hr and another car with 20m/s in opposite direction. Calculate the relative velocity.

Answers

90 km/h is 25 m/s
the relative velocity when cars are traveling in opposite directions is the sum of the two
25+20= 45 m/s

How much energy is required to raise the temperature of 5.0 g of silver from 298 K to
334 K?

Answers

Answer:

43.2J

Explanation:

Q = m × c × ∆T

Where:

Q = amount of energy

m = mass (grams)

c = specific heat capacity

∆T = change in temperature

Mass = 5.0g

Specific heat capacity of Silver (Ag) = 0.240 J/g°C

We need to convert the temperature from Kelvin (K) to °C

Initial temperature = 298 - 273 = 25°C

Final temperature = 334 - 273 = 61°C

Q = 5 × 0.240 × (61°C - 25°C)

Q = 1.2 × 36

Q = 43.2J

If you run North for 5 meters and then East for 15 meters and then
South for 2 meters all in 22 seconds. What was your speed?
0 points

Answers

Answer:

1m/s

Explanation:

D = 22m

T = 22s

S = 22÷22

= 1 m/s

Why is it colder in winter than summer? Give two reasons.

Answers

Answer:

Actually, the sun goes a bit down, like it's not all the way up as to summer. How I know is that you actually can go online maybe search for some videos and see proof, I don't really know how to explain it.

Explanation:

Reason #1: If you check, go out for 12 hours and see, I think the sun is a little down.

Reason #2:

The earth’s axis is tilted.

From a Brainly user of this question for more info:

The Earth is NOT farther away from the sun in USA Winter, and NOT closer to the sun in USA Summer. In 2021, we will be NEAREST to the sun on January 2, and FARTHEST from the sun on July 5 !

NEAREST to the sun next Saturday.

FARTHEST from the sun next July 5.

The transfer of heat by the movement of a fluid is called:
A.
Conduction

B.
Radiation

C.
Convection PLS HELP ASAP!!!

Answers

Answer: C

Explanation:

Convective heat transfer, or convection, is the transfer of heat from one place to another by the movement of fluids, a process that is essentially the transfer of heat via mass transfer.

in addition to genetics, and blank and blank may also cause premature gray hair?

Answers

Answer: heretidey and stress

Explanation:

A 57.0 kg person in a
rollercoaster moving through
the bottom of a curved track of radius
42.7 m feels a normal force of 995 N.
How fast is the car moving?

Answers

Answer:

The linear speed of the car is approximately 27.30 m/s

Explanation:

The question parameters are;

The mass of the person on the rollercoaster, m = 57.0 kg

The radius of the rollercoaster track, r = 42.7 m

The normal force felt by the person, F = 995 N

The centripetal force acting on the person keep the circular motion is given by the following equation;

[tex]Centripetal \, force \ F_c = \dfrac{m \times v^2}{r}[/tex]

Where;

v = The linear velocity of motion = The linear speed of the car

The centrifugal force, F, is the force normal force felt by the person and is equal to the centripetal force, therefore, we have;

[tex]Centripetal \, force \ F_c = Centrifugal \, force \ F = \dfrac{m \times v^2}{r}[/tex]

From which we have;

[tex]F = 995 = \dfrac{57 \times v^2}{42.7}[/tex]

[tex]\therefore v = \sqrt{\dfrac{995 \times 42.7}{57} } \approx 745.38[/tex]

The linear speed of the car = v ≈ 27.30 m/s

The angular speed of the car, ω = v/r ≈ 27.30/42.7 ≈ 0.639 rad/s

Answer: 18.1 m/s

Explanation:

A man speeding at 40m/s decides to outrun the cops and starts to accelerate at a rate of 2.5m/s² for 12 seconds. How far did he travel in this time?

Answers

Answer:

The distance traveled by the man during the acceleration is 1186.32 meters

Explanation:

The initial velocity of the man = 40 m/s

The added acceleration rate of the man to outrun = 2.5 m/s²

The time of acceleration = 12 seconds

The relevant kinematic equation of motion is given as follows;

s = u·t + 1/2·a·t²

Where;

u = The initial velocity of the car the man is driving = 40 m/s

t = The time of travel during acceleration of the car the man is driving = 12 seconds

a = The acceleration by the man to outrun the cops = 2.5 m/s²

s = The distance traveled by the man during the acceleration

Substituting, gives;

s = 40 × 12 + 1/2 × 9.81 × 12² =  1186.32

The distance traveled by the man during the acceleration = s = 1186.32 m.

1 Statues can be sculpted from

Answers

Answer:

Other materials from which statues can be sculpted include: contemporary media such as scrap metal, plastic, aluminium, concrete or "found" items, although this latter form of junk art is usually limited to abstract rather than representational works.

A billiard ball moving at 5 m/s strikes another ball which is initially at rest. After the collision, the first ball moves at a velocity of 4.35 m/s at an angle of 30o below its original motion. Find the velocity and angle of the second ball after the collision. Assume that the collision is perfectly elastic.

Answers

Answer:

The velocity of the second ball is approximately 2.588 m/s

The angle direction of the second ball is 75° counterclockwise from the horizontal

Explanation:

The initial velocity of the first billiard ball = 5 m/s

The initial velocity of the billiard ball the first billiard ball strikes = 0 m/s

The final velocity of the first billiard ball = 4.35 m/s

The final direction of motion of the first billiard ball = 30° below its original motion

For perfectly elastic collision, whereby the target is at rest initially, by conservation of momentum, we have;

m₁ × [tex]\underset{v_1}{\rightarrow}[/tex] = m₁·[tex]\underset{v'_1}{\rightarrow}[/tex] + m₂·[tex]\underset{v'_2}{\rightarrow}[/tex]

Which gives;

m₁ × 5·i = m₁·((√3)/2×5·i - 2.5·j) + m₂·[tex]\underset{v'_2}{\rightarrow}[/tex]

∴ m₂·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁ × 5·i - m₁·((√3)/2×5·i - 2.5·j)

m₂·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁ × 5·(1 - √3/2)·i + m₁·2.5·j = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j

Therefore, given that the mass of both billiard balls are equal, we have, m₁ = m₂, which gives;

m₂·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁·[tex]\underset{v'_2}{\rightarrow}[/tex]  = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j

∴ [tex]\underset{v'_2}{\rightarrow}[/tex] = 2.5·(2 - √3)·i + 2.5·j

The magnitude of the velocity of the second ball is [tex]\underset{v'_2}{\rightarrow}[/tex] = √((2.5·(2 - √3))² + 2.5²) ≈ 2.588 m/s

The direction of the second ball, θ = arctan(2.5/((2.5·(2 - √3))) = 75° counterclockwise from the horizontal.

An alkane has molecular weight 86. Write its molecular formula. What will be its physical state?

Answers

C6H14

Gaseous state

it's unsaturated hence gaseous

2. If the initial speed of the baseball in question 1 is v. = 0.0 m/s, what will its speed be when it leaves the pitcher's
hand?

Answers

Answer:

Object A has 3 times the mass of object B.

Explanation:

Have a nice rest of your day :)

Which of the technologies could mostly like be found in a wearhouse

Answers

Resources for a business
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