Answer: We can first find the dot product of vec r with hat j and hat k:
vec r * hat j = (3 hat i - 2 hat j + 6 hat k) * (- hat j) = -2
vec r * hat k = (3 hat i - 2 hat j + 6 hat k) * hat k = 6
Substituting these values into the expression given, we get:
(vec r * hat j).(vec r * hat k) - 12 = (-2) * (6) - 12 = -24
Therefore, the value of (vec r * hat j).(vec r * hat k) - 12 is -24.
Step-by-step explanation:
Let f be the function given by f(x) = e-2x2.
a) Find the first four nonzero terms and the general termof the power series for f(x) about x = 0.
b) Find the interval of convergence of the power series forf(x) about x = 0. Show the analysis that leads to yourconclusion.
c) Let g be the function given by the sum of the first fournonzero terms of the power series for f(x) about x = 0. Show thatabsolute value(f(x) - g(x)) < 0.02 for -0.6<= x <=0.6.
a) The first four nonzero terms of the power series for f(x) about x=0 are
e^6 - 2x^2 + (2x^4)/2! - (2x^6)/3!
The general term of the power series is (-2)^n (2x)^(2n) / (2n)!
b) The interval of convergence of the power series is (-∞, ∞).
c) To estimate the error between f(x) and its partial sum g(x) given by the sum of the first four nonzero terms of the power series, we can use the Lagrange form of the remainder
|R4(x)| = |f(x) - g(x)| ≤ M |x|^5 / 5!
a) To find the power series for f(x) about x = 0, we can use the Maclaurin series formula
f(x) = Σ[n=0 to ∞] (fⁿ(0)/n!) xⁿ
where fⁿ(0) denotes the nth derivative of f evaluated at x=0.
In this case, we have
f(x) = e^6(-2x^2)
fⁿ(x) = dⁿ/dxⁿ(e^6(-2x^2)) = (-2)^n(2x)^ne^6(-2x^2)
So, we can write the power series as
f(x) = Σ[n=0 to ∞] ((-2)^n(2x)^n e^6(0))/n!)
= Σ[n=0 to ∞] ((-2)^n (2x)^n /n!)
To find the first four nonzero terms, we substitute n = 0, 1, 2, and 3 into the above formula
f(0) = e^6
f'(0) = 0
f''(0) = 24
f'''(0) = 0
So, the first four nonzero terms of the power series are:
e^6 - 2x^2 + (2x^4)/2! - (2x^6)/3!
The general term of the power series is
(-2)^n (2x)^(2n) / (2n)!
b) To find the interval of convergence of the power series, we can use the ratio test
lim [n→∞] |((-2)^(n+1) (2x)^(2n+2) / (2n+2)! ) / ((-2)^n (2x)^(2n) / (2n)!)|
= lim [n→∞] |-4x^2/(2n+1)(2n+2)|
= lim [n→∞] 4x^2/(2n+1)(2n+2)
Since this limit depends on the value of x, we need to consider two cases
i) If x = 0, then the power series reduces to the constant term e^6, and the interval of convergence is just x=0.
ii) If x ≠ 0, then the series converges absolutely if and only if the limit is less than 1 in absolute value
|4x^2/(2n+1)(2n+2)| < 1
This is true for all values of x as long as n is sufficiently large. So, the interval of convergence is the entire real line (-∞, ∞).
c) We can use the Lagrange form of the remainder to estimate the error between f(x) and its partial sum g(x) given by the sum of the first four nonzero terms of the power series
|R4(x)| = |f(x) - g(x)| ≤ M |x|^5 / 5!
where M is an upper bound for the fifth derivative of f(x) on the interval [-0.6, 0.6].
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PLEASE HELP !!!! HELP!!label each equation is proportionality or non proportional Help
y=9/x
y=x-12
h=3d
f=1/3e
Answer:
y=9/x => proportional
y = x - 12 ==> non-proportional
h = 3d ==> proportional
f = 1/3 e = proportional
Step-by-step explanation:
A proportional equation is of the general form
y = kx (directly proportional) or
y = k/x (inversely proportional)
k is known as the constant of proportionality
y = 9/x ==> k = 9 proportional
y = x - 12 cannot be expressed as y = kx or y = k/x
h = 3d ==> k = 3 proportional
f = 1/3 e ==> k = 1/3 proportional
Question 19 (2 points)
According to research conducted by the Department of Education, 80% of college
students took a mathematics course as part of their general education requirements.
If ten college students are selected at random, what is the probability at least one of
the ten has not taken a mathematics course?
0.0800
0.1073
0.7927
0.8000
Answer:
The probability that a single college student has not taken a mathematics course is 1 - 0.8 = 0.2.
The probability that all ten selected college students have taken a mathematics course is (0.8)^10 = 0.1074 (rounded to four decimal places).
Therefore, the probability that at least one of the ten selected college students has not taken a mathematics course is:
1 - 0.1074 = 0.8926 (rounded to four decimal places).
So the answer is 0.8926, which is closest to option C (0.7927).
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PLEASE HELP YOU WILL BE BRAINIEST!!! Use the chart!!!!
Question 8 of 10
Which of the following rational functions is graphed below?
A. F(x) = 1/4x
B. F(x) = 4/x
C. F(x) = 1/x+4
D. F(x) = 1/x-4
Option D, F(x) = 1/x-4, is the rational function that best fits the graph.
What are some examples and functions of reason?Any function that can be expressed as a polynomial divided by a polynomial is said to be rational. Since polynomials are defined everywhere, the domain of a rational function is the set of all numbers except the zeros of the denominator.
The graph features a vertical asymptote at x = 4 and a horizontal asymptote at y = 0, as can be seen by looking at it.
Option A, F(x) = 1/4x, has a horizontal asymptote at y = 0, but does not have a vertical asymptote at x = 4.
Option B, F(x) = 4/x, has a vertical asymptote at x = 0, but not at x = 4.
Option C, F(x) = 1/x+4, has a vertical asymptote at x = -4, but not at x = 4.
Option D, F(x) = 1/x-4, has a vertical asymptote at x = 4, and does not have any other vertical asymptotes.
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Find the center and radius of the circle whose equation is x^2+y^2+4y=32
Answer:
center: (0, -2)
radius: 6
Step-by-step explanation:
You have to "complete the square" this allows you to fold up the expressions and put the equation in a standard kinda of format where you can pick the center and radius right out of the equation.
see image.
Find the potential inside and outside a sphere shell that carries a uniform surface charge $\sigma_0$, using results of Ex. 3.9
Inside the sphere, the potential is given by [tex]$V(r)=\frac{Q}{4\pi\epsilon_0r}$[/tex], where Q is the total charge enclosed within the sphere. Since the sphere shell has no charge inside, Q=0, and thus V(r)=0 inside the sphere.
Outside the sphere, the potential is given by
[tex]$V(r)=\frac{Q}{4\pi\epsilon_0r} + \frac{Q'}{4\pi\epsilon_0r'}$[/tex]
where Q is the total charge of the sphere shell, Q'= σ4πR²is the charge on an imaginary sphere of radius r'>R enclosing the sphere shell, and r is the distance from the center of the sphere. Using the result from Ex. 3.9, the potential outside the sphere becomes
[tex]$V(r)=\frac{Q}{4\pi\epsilon_0r} + \frac{\sigma_0 R^2}{2\epsilon_0 r}$[/tex]
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A psychologist theorized that people could hear better when they have just eaten a large meal. Twenty individuals were randomly assigned to eat either a large meal or a small meal. After eating the meal, their hearing was tested. Assuming hearing ability was measured on an interval scale and that the scores were normally distributed, the research hypothesis would be ________ and the most appropriate statistic for testing the research hypothesis would __________
A. non-directional; t-test for independent means
B. directional; t-test for independent means
C. non-directional; t-test for dependent means
D. directional; t-test for dependent means
The correct research hypothesis and distribution is directional, t-test for independent means.
What is the research hypothesis?The research hypothesis that "people can hear better when they have just eaten a large meal" is a directional hypothesis because it predicts the direction of the effect (i.e., hearing ability will improve after a large meal).
The appropriate statistical test to use would be a t-test for independent means, which compares the means of two independent groups to determine if there is a statistically significant difference between them.
Therefore, the correct answer is B. Directional; t-test for independent means.
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If two objects are pushed by the same amount of force, the one with the greater mass will move more slowly. For a science project, Kendra used centimeter cubes, each with the same mass and volume, to build the two rectangular prisms shown. If each rectangular prism is pushed by the same amount of force, which one will move more slowly? Compare the volumes using
> or <?
Both rectangular prisms will move at the same speed and volume of A > volume of B
What is rectangular prism ?
A rectangular prism is a three-dimensional solid shape that consists of six rectangular faces. It is also known as a rectangular cuboid, and it is a special case of a parallelepiped, which is a six-faced polyhedron where each face is a parallelogram. The rectangular prism has parallel and congruent rectangular bases that are connected by rectangular faces that are perpendicular to the bases.
The rectangular prism has several important properties. One of the most important is its volume, which is given by the formula V = lwh, where l is the length, w is the width, and h is the height of the rectangular prism.
Comparing their masses and volumes.
If the mass is the same for both rectangular prisms, then they will move at the same speed if pushed by the same amount of force. The mass of an object is a measure of the amount of matter it contains, and since both prisms have the same mass, they contain the same amount of matter. The force required to move an object is proportional to its mass, so if both objects have the same mass, they will require the same amount of force to move. Therefore, they will move at the same speed.
We can compare their volumes using the inequality sign:
volume of A > volume of B
This is because the area of the base of A is greater than the area of the base of B, and the height of A is less than the height of B. So, A has a greater volume than B.
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explain why a set in r5 ust be linearly independent when is linearly indedependent and v4 is not in span
A set in R⁵ must be linearly independent because of the dimensionality of the space.
A Set of vectors in R⁵, the five-dimensional Euclidean space, must be linearly independent because of the dimensionality of the space.
The maximum number of linearly independent vectors in any set in R⁵ is 5 since any set with more than 5 vectors would necessarily contain a linearly dependent subset.
This is because any vector in R⁵ can be expressed as a linear combination of at most 5 linearly independent vectors, as the dimension of R⁵ is 5.
Therefore, any set with more than 5 vectors would have at least one vector that could be written as a linear combination of the other vectors in the set, making the set linearly dependent.
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The given question is incomplete, the complete question is
Explain why a set in R⁵ must be linearly independent.
use the method of lagrange multipliers to find the minimum value of f subject to the given constraint. f(x,y)
The minimum value of f subject to the given constraint is -62.42 (abs min).
We need to find the minimum and maximum values of f(x,y) = 2x-5y subject to the constraint g(x,y) = x2+3y2 = 111.
Using Lagrange multipliers, we solve the equations:
∇f= λ∇g and g(x,y) = 111.
This gives,
2 = λ2x (1) equation.
-5 = λ6y (2) equation.
From (1) we have λ=1/x. Substituting this into (2)
we have x=-6y/5 (3).
By substituting (3) into constraint g(x,y) we have
(-6y/5)2+3y2 = 111
y2(-36/25 + 3) = 111
y = ±5√37/√13.
We have given some corresponding points in question (-6√37/√13, 5√37/√13) and (6√37/√13, -5√37/√13).
Evaluating f at these critical points:
f(-6√37/√13, 5√37/√13)
= 13√37/√13
≈ -62.42 (abs min)
f(6√37/√13, -5√37/√13)
= 37√37/√13
≈ 62.42 (abs max)
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Full Question:
Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=2x−5y subject to the constraint x2+3y2=111, if such values exist.
I am in my room (State 1). There is a 65% chance that I stay here and do my work like I am supposed to. There is a 35% chance I go get a snack and procrastinate (State 2). Once I have gone to get the snack, there is a 15% chance that I go back to work (go back to State 1), and there is an 85% chance that I get another snack and procrastinate further (stay in State 2).
Create a diagram and a transition matrix for this case.
Answer:
Here is a diagram and transition matrix for this case:
Diagram:
+---(0.65)---> State 1 (work)
|
Start ---+
|
+---(0.35)---> State 2 (procrastinate)
|
+---(0.15)---> State 1 (work)
|
+---(0.85)---> State 2 (procrastinate)
Transition matrix:
| State 1 | State 2 |
----------+-----------+-----------+
State 1 | 1.00 | 0.00 |
----------+-----------+-----------+
State 2 | 0.15 | 0.85 |
----------+-----------+-----------+
In the transition matrix, the rows represent the starting state and the columns represent the ending state. The entries in the matrix represent the probabilities of transitioning from the starting state to the ending state. For example, the entry in row 1 and column 2 (0.00) represents the probability of transitioning from State 1 to State 2, which is 0.00.
You randomly select 500 students and observe that 85 of them smoke. Estimate the probability that a randomly selected student smokes.
a. 0.27
b. 0.50, since there are two possible outcomes for every student surveyed. smoke, don't smoke
c. 0.17
d. 1.2
Option C is the correct answer. 0.17 is the probability that a randomly selected student smokes out of 500 students, given 85 smoke.
By dividing the total number of students observed (500) by the number of students who smoke (85) in this scenario, it is possible to estimate the probability of smoking among the 500 students.
This results in a ratio of 0.17, or 17%. The estimated likelihood that a randomly chosen student smokes is therefore 0.17, meaning that roughly 17 out of every 100 students in the population smoke. It is crucial to remember that this is only an estimate, and the true probability could change slightly depending on the size and sampling method.
The estimated probability does, however, have a tendency to converge to the true probability when the sample size is sufficient.
Hence, the probability that a randomly selected student smokes is 0.17
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Assume the weight of a randomly chosen American passenger car is a uniformly distributed random variable ranging from 1,557 pounds to 4,665 pounds.
(a) What is the mean weight of a randomly chosen vehicle? (Round your answer to nearest whole number.)
Mean weight (b) What is the standard deviation of a randomly chosen vehicle? (Round your answer to 4 decimal places.)
Standard deviation (c) What is the probability that a vehicle will weigh less than 1,946 pounds? (Round your answer to 4 decimal places.)
Less than 1,946 pounds (d) What is the probability that a vehicle will weigh more than 4,455 pounds? (Round your answer to 4 decimal places.)
More than 4,455 pounds (e) What is the probability that a vehicle will weigh between 1,946 and 4,455 pounds? (Round your answer to 4 decimal places.)
The probability of the randomly chosen American passenger car is a uniformly distributed random variable ranging from 1,557 pounds to 4,665 pounds is given as:
In statistics, a uniform distribution is a kind of probability distribution where all possible outcomes have an identical likelihood of occurring. Because there is an equal chance of getting a heart, club, diamond, or spade, a deck of cards has uniform distributions.
PDF of Uniform Distribution f(x) = 1/(b-a) for a <x<b
b = Maximum Value
a = Minimum Value
Mean = (a + b)/2
Standard Deviation [tex]\sqrt{((b- a)^2/12)}[/tex]
a) Mean = a + b/2=3111
mean weight of a randomly chosen vehicle is 3111
b) Standard Deviation = [tex]\sqrt{((b- a)^2/12)}[/tex] =897.2023
f(x) = 1/(b-a)
= 1/(4665-1557)
=1/3108
= 0.0003
the standard deviation of a randomly chosen vehicle is 0.0003.
c) P(X < 1946) = (1946-1557) x f(x)
= 389 x 0.0003
= 0.1167
the probability that a vehicle will weigh less than 1,946 pounds is 0.1167.
d) P(X > 4455) = (4665-4455) x f(x)
=210 x 0.0003
= 0.063
the probability that a vehicle will weigh more than 4,455 pounds is 0.063.
e) To find P(a< X< b)=( b - a) x
f(x) P(1946 < X < 4455)
= (4455-1946) x f(x)
=2509 x 0.0003
= 0.7527
the probability that a vehicle will weigh between 1,946 and 4,455 pounds is 0.7527.
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(x^2-x-12)/(x+5)=x-6
There is no value of x that solves the proportion (x^2-x-12)/(x+5) = x-6.
How to solve the proportion?The proportion for this problem is defined by the equation presented as follows:
(x^2-x-12)/(x+5) = x-6.
As the measures are proportional, we can apply cross multiplication, hence:
x² - x - 12 = (x + 5)(x - 6)
x² - x - 12 = x² - x - 30
-12 = -30.
-12 = -30 is a false statement, hence there is no value of x which can solve the proportion (x^2-x-12)/(x+5)=x-6 presented in this problem.
Missing InformationThe problem asks for the value of x that solves the proportion (x^2-x-12)/(x+5) = x-6.
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Mason earns $8.10 per hour and worked 40 hours. Noah earns $10.80 per hour. How many hours would Noah need to work to equal Mason’s earnings over 40 hours?
Answer:
Noah would need to work 30 hours to equal Mason's earning for 40 hours
Step-by-step explanation:
Mason;
8.10 x 40 = 324
324 ÷ 10.80 = 30 hours.
Helping in the name of Jesus.
Answer:
30 hours
Step-by-step explanation:
40 times 8.10 is 324 and 324 divided by 10.8 is 30 hours
FI;LL IN THE BLANK. An online retailer has determined that the average time for credit card transactions to be electronically approved K 1.6 seconds. (Round your answers to three decimal places.) (a) Use on exponential density function to find the probability that a customer warts less than a second for credit card approval. (b) Find the probability that a customer waits more than 3 seconds. ____ (c) What Is the minimum approval time for the slowest 5% of transactions? ____sec
(a) By using the exponential density function, the probability that a customer warts less than a second for credit card approval is 0.334
(b) The probability that a customer waits more than 3 seconds is 0.154
(c) The minimum approval time for the slowest 5% of transactions is 4.013 seconds
(a) To find the probability that a customer waits less than a second for credit card approval, we need to use the exponential density function:
f(x) = [tex]\lambda e^{-\lambda x}[/tex]
Where λ is the rate parameter, which in this case is the reciprocal of the mean approval time. So, λ = 1/1.6 = 0.625.
The probability that a customer waits less than a second can be calculated by integrating the density function from 0 to 1:
P(X < 1) = ∫[tex]0^1 \lambda e^{-\lambda x}[/tex] dx
P(X < 1) = [tex][-e^{-\lambda x}]0^1[/tex]
P(X < 1) = [tex]-e^{(-0.625)}[/tex] + 1
P(X < 1) = 0.334
Therefore, the probability that a customer waits less than a second for credit card approval is 0.334.
(b) To find the probability that a customer waits more than 3 seconds for credit card approval, we can use the same exponential density function and integrate from 3 to infinity:
P(X > 3) = ∫[tex]3^{\infty} \lambda e^{-\lambda x}[/tex] dx
P(X > 3) = [[tex]-e^{-\lambda x}[/tex])][tex]3^{\infty}[/tex]
P(X > 3) = [tex]e^{-1.875}[/tex]
P(X > 3) = 0.154
Therefore, the probability that a customer waits more than 3 seconds for credit card approval is 0.154.
(c) We can use the exponential distribution's inverse function to find this value:
P(X > x) = 0.05
[tex]e^{-\lambda x}[/tex] = 0.05
-xλ = ln(0.05)
x = ln(0.05)/(-λ)
x = ln(0.05)/(-0.625)
x = 4.013 seconds
Therefore, the minimum approval time for the slowest 5% of transactions is 4.013 seconds.
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Problem 2 (Vector and Matrix Refresh) Seven data points are arranged as columns of a data matrix X given as follows: 2 1 0 0 -1 0 -2 X = 2 0 1 0 0 -1 -2 a) Draw all data points on a 2D plane by hand. Properly label the two axes. Clearly provide important tick values to facilitate a precise graphical description of the data. b) Consider each point as a vector. Calculate the angle in between (2 27 and the five other points (excluding [0 07), respectively, using the inner/dot product formula that involves the angle. Note that the angle between two vectors can be negative. c) Calculate the matrix outer product for X, namely, R = XXT. Show the intermediate steps of calculating each element of the 2-by-2 matrix R. d) The matrix outer product can also be calculated via R =
a) The drawing of all data points on a 2D plane is illustrated below.
b) The angle in between the five other points is 27
c) The matrix outer product for X is R = XXT.
d) The matrix outer product can also be calculated via R is (2,27)
The data matrix X is a 2-by-7 matrix, where each column represents a data point with two components. We can visualize each data point as a vector in a two-dimensional plane, where the horizontal axis represents the first component and the vertical axis represents the second component.
To draw all data points on a 2D plane, we can plot each column of X as a vector starting from the origin. Proper labeling of the two axes and providing important tick values will facilitate a precise graphical description of the data.
Next, we can use the inner product formula to calculate the angle between the first data point (2, 27) and the other five data points, respectively.
The inner product, also known as the dot product, is a way to measure the similarity between two vectors by multiplying their corresponding components and summing the products.
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Given the coordinates shown and given that SU = 10, what are the coordinates of U if STUV is a kite?
A) (10, 18)
B) (0, 28)
C) (18, 28)
The calculated coordinates of U if STUV is a kite is (10, 18)
Calculating the coordinates of U if STUV is a kite?From the question, we have the following parameters that can be used in our computation:
The figute of a kite
Also, we have
S = (0, 18)
And the distance SU to be
SU = 10
If the quadrilateral STUV is a kite, then the coordinates S and U are on the same horizontal level (according to the figure)
So, we have
U = (0 + 10, 18)
Evaluate
U = (10, 18)
Hence, the coordinates of U if STUV is a kite is (10, 18)
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Please answer the attached question
The values of e and f in the given equation are: e = 2√3 ± √(4√3), e = 2√3 ± 2√2, and f = 4√3.
How are radicals solved?Equations containing radicals can be made simpler by solving the resultant equation after squaring both sides of the equation to remove the radical. Nonetheless, caution must be exercised to guarantee that any solutions found are reliable and adhere to any variables' limitations.
The given equation is [tex](e - 2\sqrt{3} )^2[/tex] = f - 20√3.
Expanding the left side of the equation we have:
[tex](e - 2\sqrt{3} )^2[/tex] = (e - 2√3)(e - 2√3)
= [tex]e^2[/tex] - 2e√3 - 2e√3 + 12
= [tex]e^2[/tex] - 4e√3 + 12
Substituting back in the function
[tex]e^2[/tex] - 4e√3 + 12 = f - 20√3
[tex]e^2[/tex] - 4e√3 - f + 20√3 - 12 = 0
Using the quadratic formula:
e = [4√3 ± √(16*3 + 4(f - 20√3 + 12))] / 2
e = [4√3 ± √(4f - 64√3)] / 2
e = 2√3 ± √(f - 16√3)
Now for,
(e - 2√3)² = f - 20√3
(2√3 + √(f - 16√3) - 2√3)² = f - 20√3
f - 20√3 = f - 16√3
f = 4√3
Hence, the values of e and f in the given equation are: e = 2√3 ± √(4√3), e = 2√3 ± 2√2, and f = 4√3.
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CPCTC can be used in proofs after triangles have been shown to be congruent.
A) True
B) False
Answer:
True.
Step-by-step explanation:
CPCTC is commonly used at or near the end of a proof, which asks the student to show that two angles or two sides are congruent. It means that once two triangles are proven to be congruent, then the three pairs of sides that correspond must be congruent and the three pairs of angles that correspond must be congruent.
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 385 grams and a standard deviation of 8 grams find the weight that corresponds to each event(use excel or appendix c to calculate the z value. Round your final answers to 2 decimal places)
URGENT
the weight that corresponds to each of the events are:
a) The weight is less than 380 grams: [tex]$P(X < 380)=0.266$[/tex].
b) The weight is between 375 and 395 grams: [tex]$P(375 < X < 395)=0.7887$[/tex].
c) The weight is greater than 400 grams: [tex]$P(X > 400)=0.0304$[/tex].
How to deal with Normal distribution?Let X be the weight of a small Starbucks coffee. We are given that X is normally distributed with mean [tex]$\mu=385$[/tex] grams and standard deviation [tex]$\sigma=8$[/tex].
We want to find the weight that corresponds to each of the following events:
a) The weight is less than 380 grams.
b) The weight is between 375 and 395 grams.
c) The weight is greater than 400 grams.
To solve these problems, we first standardize the distribution by finding the corresponding z-scores using the formula:
[tex]$z=\frac{X-\mu}{\sigma}$$[/tex]
a) The weight is less than 380 grams.
We want to find P(X<380). We can find the z-score for X=380 as follows:
[tex]$z=\frac{380-385}{8}=-0.625$$[/tex]
Using a standard normal table or calculator, we find that the probability P(Z<-0.625)=0.266. Therefore,
[tex]$P(X < 380)=P\left(Z < -\frac{0.625}{1}\right)=0.266$$[/tex]
b) The weight is between 375 and 395 grams.
We want to find [tex]$P(375 < X < 395)$[/tex]. We can find the z-scores for X=375 and X=395 as follows:
[tex]$z_1=\frac{375-385}{8}=-1.25,\quad z_2=\frac{395-385}{8}=1.25$$[/tex]
Using a standard normal table or calculator, we find that the probability P(-1.25<Z<1.25)=0.7887. Therefore,
[tex]$P(375 < X < 395)=P\left(-1.25 < Z < 1.25\right)=0.7887$$[/tex]
c) The weight is greater than 400 grams.
We want to find P(X>400). We can find the z-score for X=400 as follows:
[tex]$z=\frac{400-385}{8}=1.875$$[/tex]
Using a standard normal table or calculator, we find that the probability P(Z>1.875)=0.0304. Therefore,
[tex]$P(X > 400)=P\left(Z > \frac{1.875}{1}\right)=0.0304$$[/tex]
Therefore, the weight that corresponds to each of the events are:
a) The weight is less than 380 grams: [tex]$P(X < 380)=0.266$[/tex].
b) The weight is between 375 and 395 grams: [tex]$P(375 < X < 395)=0.7887$[/tex].
c) The weight is greater than 400 grams: [tex]$P(X > 400)=0.0304$[/tex].
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After solving the problem Is the statement true or false
Answer:
True
Step-by-step explanation:
Since x = 3 since we are given that f(3) = 16, x = 3.
The equation is:
[tex]f(x) = x^{2} + 2x + 1[/tex]
and x = 3, we can easily sustitute x with 3. When we do so, our equation will look like:
[tex]f(3) = 3^{2} + 2(3) + 1[/tex]
Now, we will solve.
3^2 is = 9
2(3) = 6
Now, we will plug into the equation:
[tex]f(3) = 9 + 6 + 1[/tex]
Combine like terms (constants)
[tex]f(3) = 16[/tex]
The school cafeteria served 2,420 cups of milk in March and 1,660 cups of milk in April. How many quarts of milk did the cafeteria serve in those two months?
Solve on paper. Check your work on Zearn.
1 quart = 4 cups
The cafeteria served
total quarts of milk in March and April.
Hence, throughout March and April, the cafeteria served 1020 quarts of milk.
what is unitary method ?The unitary method is a mathematical approach where issues are solved by determining a single unit rate. To relate various quantities to one another, proportions must be used. This approach is frequently employed in issues involving direct and inverse proportionality. In inverse proportionality, the product of the two quantities is constant, whereas in direct proportionality, the two numbers fluctuate in the same ratio.
given
We must first determine the total number of cups of milk served in both March and April in order to calculate the total number of quarts of milk served in both months.
4080 cups of milk totaled from 2420 + 1660 cups.
We can convert the total number of cups to quarts by dividing by 4 because 1 quart equals 4 cups:
4080 cups of milk divided by 4 equals 1020 quarts total.
Hence, throughout March and April, the cafeteria served 1020 quarts of milk.
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Which construction is shown in the diagram below?
Answer:
Step-by-step explanation:
i think it B
-6(4p+5) > 34-8p HELP ASAP
Answer:
p < -4
Step-by-step explanation:
-6(4p+5) > 34 - 8p
-24p - 30 > 34 - 8p
-16p - 30 > 34
-16p > 64
p < -4
HELP ILL GIVE YOU ONE HUNDRED POINTS AND BE MARKED BRAINLIEST IF YOU HELP MME ITS DUE TODAY!!!!
Answer: Somewhere around 40%, write 0.4.
Step-by-step explanation:
I took all of the outcomes from the games got the. probabilities of winners and got 40%.
let be the space spanned by the two functions and . find the matrix of the linear transformation from into itself with respect to the basis .
When space is spanned by the two functions of linear transformation from into itself with respect to the basis we need to apply T to each basis vector vi to get the column vectors T(vi) = [T(vi)]B.
where [T(vi)]B is the coordinate vector of T(vi) with respect to the basis B. Arrange the column vectors [T(v1)]B, [T(v2)]B, ..., [T(vn)]B into a matrix. This matrix is the matrix of T with respect to the basis B.
In this case, you have two functions that span a vector space, so you need to specify the basis B. Once you have chosen the basis, you can apply the above steps to find the matrix of the linear transformation.
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What is the meaning of "complex numbers with absolute value 1 "?
Answer:
A complex number is said to have an absolute value of 1 if the magnitude of its real and imaginary parts together is equal to 1. Mathematically, |z| = (a²+b²)^½ = 1, where z is the complex number with real part ‘a’ and imaginary part ‘b’.Tristan is going to invest $73,000 and leave it in an account for 18 years. Assuming
the interest is compounded continuously, what interest rate, to the nearest tenth of a
percent, would be required in order for Tristan to end up with $104,000?
Answer:
2%
Step-by-step explanation:
Given,P = $73000
A = $104000
T = 18 years, Compounded annually.
To find: r%
Soln: By formula, A = 73000*(1+r/100)^18
=> (104/73)^1/18 = (100+r)/100
=> 1.0198 = 100+r/100
=> 101.98 -100 = r
=> 1.98 = r
To the nearest percent, 2 = r
Hence, Rate of interest = 2%