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Answer:

33 squares of chocolate need

Answer:

33 Biscuits

Step-by-step explanation:

Uni method

How much biscuits do we need for 1 square of chocolate?

22/16 = 1.3

For 1 square of chocolate she needs 1.3 Biscuits.

So for 24 biscuits,

24 * 1.3

=33 biscuits

Answer:

The derivative of any constant number is 0.

So,

Differentiating with respect to "x",

d f(x)/dx

=d 25/dx

=0

The zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3

The function is given as:

y = 6x^2 + x - 35

Expand the function

y = 6x^2 + 15x - 14x - 35

Factorize the function

y = (2x + 5) * (3x - 7)

Set the function to 0

(2x + 5) * (3x - 7) = 0

Split

2x + 5 = 0 or 3x - 7 = 0

Solve for x

x = -2.5 or x = 7/3

Hence, the zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3

Read more about quadratic functions at:

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Answer:

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Answer:

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.

A Let tower be AB

Let point be C

Distance of point C from foot of tower = 30m Hence,

BC = 30m

Angle of elevation = 30°

So < ACB = 30°

Since tower is vertical,

< ABC = 90°

Answer:

The value of equipment after 2 years is $58,800

Step-by-step explanation:

f(n) = 67,500(14/15)ⁿ

where f(n) is the value after n years.

1 – 1 / 15 = 14 / 15.

Answer:

n ∝ (1/l) (√F/m)

Step-by-step explanation:

Since frequency, n of vibration of a stretched string is a function of its tension F, the length l and the mass per unit length m, and has dimensions [T]⁻¹ where T = time, its dimension must be equal to that of the combination of F, L and m

Since n = f(F,L,m)

n = kFᵃLᵇmˣ

dimension of n = (dimension of F)ᵃ × (dimension of L)ᵇ × (dimension of m)ˣ

Since n = frequency, dimension of n = [T]⁻¹

F = Force, dimension of F = [M][L][T]⁻²

Also, L = length, dimension of L = [L] and

m = mass per unit length, dimension of m = [M][L]⁻¹

So, n = FᵃLᵇmˣ

[T]⁻¹  = ([M][L][T]⁻²)ᵃ( [L] )ᵇ([M][L]⁻¹)ˣ

[T]⁻¹  = ([M]ᵃ[L]ᵃ[T]⁻²ᵃ[L]ᵇ([M]ˣ[L]⁻ˣ

[M]⁰[L]⁰[T]⁻¹  = ([M]ᵃ ⁺ˣ)([L]ᵃ ⁺ ᵇ ⁻ˣ)([T]⁻²ᵃ)

equating the exponents on both sides, we have

a + x = 0  (1 )⇒ x = -a

a + b - x = 0 (2) ⇒

-2a = -1 (3) ⇒ a = 1/2

Substituting x into 2, we have

a + b -(-a) = 0

a + b + a = 0

2a + b = 0

b = -2a

b = -2 (1/2)

b = -1

x = -a = -1/2

So, substituting the variables into n, we have

n = kFᵃLᵇmˣ

n = kFᵃLᵇmˣ

[tex]n = kF^{\frac{1}{2} }L^{-1}m^{-\frac{1}{2} }[/tex]

n = k/l(√F/m)

n ∝ (1/l) (√F/m)

Answer:

x ≥ 12

Step-by-step explanation:

-3/4x +2 ≤ -7

Subtract 2 from each side

-3/4x +2-2 ≤ -7-2

-3/4x  ≤ -9

Multiply each side by -4/3, remembering to flip the inequality

-3/4x * -4/3 ≥ - 9 *(-4/3)

x ≥ 12

Answer:

x>=12

Step-by-step explanation:

-3/4x + 2<=-7

-3/4x <= -7 -2

-3/4x<=-9

cross multiply

-3x<=-36

dividing throughout by -3

x>=12

Answer:

The second choice

Step-by-step explanation:

For this, we can use the process of elimination. The first choice is crossed out, since they are mix and matching the numbers. The third choice is also crossed out since the second choice is correct. The second choice is correct because 9/11*3=27/33.

Answer:

They are similar because 9/11 = 27/33

Answer:

Yes, because they are identical to eachother

Step-by-step explanation:

9514 1404 393

Answer:

  (1, 155)

Step-by-step explanation:

Let f(x) = 17n(x) +2, where n(1) = 9.

Then we have ...

  f(1) = 17n(1) +2 = 17×9 +2 = 153 +2

  f(1) = 155

A point on the new graph would be (1, 155).

domain is  (- infinity, infinity)

range is (- infinity, infinity)

Answer:

[tex]\displaystyle 8^\bigg{\frac{8}{3}}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \bigg(8^\bigg{\frac{2}{3}} \bigg)^4[/tex]

Step 2: Simplify

9514 1404 393

Answer:

  (d)  (−5, 6), (2, 5), (−1, 1)

Step-by-step explanation:

No answer choices have any points in common, so we only need to find one translated point to determine the correct answer choice.

For the point on the y-axis, (0, 2), the translation is ...

  (x, y) ⇒ (x +2, y+3)

  (0, 2) ⇒ (0 +2, 2 +3) = (2, 5) . . . . matches choice D

Answer:

i cant see the photo

Step-by-step explanation:

Answer:

The corrects answers are: C, D, E, F

Step-by-step explanation:

Answer:

15.99

Step-by-step explanation:

5.33+5.33+5.33

Answer: Isolate the term that contains the squared variable. Then, take the square root of both sides and solve.

Step-by-step explanation:

To solve an equation by using the square root property, you will first isolate the term that contains the squared variable. You can then take the square root of both sides and solve for the variable. Make sure to write the final answer in simplified form.

Answer:

x = 18

y = 38

Step-by-step explanation:

Let the smaller number be = x

Let the larger number be = y

Sum of the number, x + y = 56 --------- ( 1 )

Seven  times smaller number = 7x

Three times larger number = 3y

Seven times smaller = 12 more than 3times larger , 7x = 12 + 3y ----- ( 2 )

Solve ( 1 ) and ( 2 )

x + y = 56  => x = 56 - y

Substitute x in ( 2 )

7x - 3y = 12

7(56 - y) - 3y = 12

392 - 7y - 3y = 12

-10y =  12 - 392

-10y = - 380

y = 38

Substitute y in ( 1 )

x + y = 56

x + 38 = 56

x = 56 - 38

x = 18

Answer:

I thing option A. all real numbers.

but IAM not exactly sure....

Answer:

all real numbers is correct answer

Answer: Nonlinear function

Step-by-step explanation:

Answer:

B, 8 (2a+3b).

Step-by-step explanation:

First, let's let A=1 and B=2. 16a+24b would equal 64, and so would B, which is 8 (2a+3b). Then lastly you solve, and you get 64 for both of them, which means B is equal to that expression.

Answer:

B

Step-by-step explanation:

8(2a) = 16a

8(3b) = 24b

16a + 24b

Answer:

Eighty thousand

Step-by-step explanation:

Look at the place value chart.

Answer:

(S, FS, FFS, FFF)

Step-by-step explanation:

According to the Question,

So, the sample space for this random experiment is

{S, FS, FFS, FFF}

The person stops trying when he successfully enters the code or when he has failed at all 3 attempts .

Answer:

breadth = 10 cm

length = 13 cm

Step-by-step explanation:

so,

perimeter = 46cm

2(l+b) = 46cm

or, 2(3+b+b) = 46cm ( because l = 3+b)

or, 2(3+2b) = 46cm

or, 6 + 4b = 46cm

or, 4b = 46cm - 6

or, 4b = 40cm

or, b = 40/4 cm

so, b = 10 cm

now,

l = 3cm + b

l = 3 cm + 10cm

= 13cm

Answer:

Let us assume the breadth of the rectangle be 'b' cm.

So length of the rectangle will be b+3 cm.

Now

Perimeter =46

[tex] \large \mid\orange {2(l + b) = 46}[/tex]

[tex] \large \mid\orange {2(b+3+b)=46}[/tex]

[tex] \large\mid \orange {2(2b+3) = 46}[/tex]

[tex] \large\mid \orange {4b + 6 = 46}[/tex]

[tex] \large \mid \orange{4b = 46 - 6}[/tex]

[tex] \large\mid \orange {4b = 40}[/tex]

[tex] \large \mid \orange{b = \frac{40}{4} }[/tex]

[tex] \large\mid \orange {b = 10}[/tex]

[tex] \large \orange{l=b+3= \:10 + 3 = 13 cm }[/tex]

Length = 13cm

Breadth = 10cm

Given:

The system of equations is:

[tex]x+3y=5[/tex]

[tex]x-3y=-1[/tex]

The given matrices are [tex]\left[\begin{array}{cc}5&3\\-1&-3\end{array}\right] [/tex], [tex]\left[\begin{array}{cc}1&5\\1&-1\end{array}\right][/tex], [tex]\left[\begin{array}{cc}1&3\\1&-3\end{array}\right][/tex].

To find:

The correct names for the given matrices.

Solution:

We have,

[tex]x+3y=5[/tex]

[tex]x-3y=-1[/tex]

Here, coefficients of x are 1 and 1 respectively, the coefficients of y are 3 and -3 respectively and constant terms are 5 and -1 respectively.

In the x-determinant, the coefficients of x are in the first column and the constant terms are in the second column. So, the x-determinant is:

[tex]\left[\begin{array}{cc}1&5\\1&-1\end{array}\right][/tex]

In the y-determinant, the constant terms are in the first column and the coefficients of y are in the second column. So, the y-determinant is:

[tex]\left[\begin{array}{cc}5&3\\-1&-3\end{array}\right] [/tex]

In the system determinant, the coefficients of x are in the first column and the coefficients of y are in the second column. So, the system determinant is:

[tex]\left[\begin{array}{cc}1&3\\1&-3\end{array}\right][/tex]

Therefore, the first matrix is y-determinant, second matrix is x-determinant and the third matrix is the system determinant.

Answer:

m = +/- 12

Step-by-step explanation:

A quadratic function has only one x-intercept when the discriminant is equal to 0. The discriminant is b^2 - 4(a)(c).

When we plug in what we know, we have:

m^2 - 4(18)(2) = 0.

Then using algebraic properties, solve for m.

m^2 - 144 = 0

m^2 = 144

m = +/- 12

When you plug in positive or negative 12, and then factor you will see that it comes out to a difference of squares, proving that there is only one x-intercept.

Answer: C

Step-by-step explanation:

EDGE 2023

Answer:

the price per candy is $0.16

and she has $16.00 in her pocket.

Step-by-step explanation:

x = the money in her pocket.

y = the price per candy

x + 3.2 = 120×y

x - 2.4 = 85×y

y = (x - 2.4)/85

=>

x + 3.2 = 120×(x - 2.4)/85 = (24x - 57.6)/17

=>

(17x + 17×3.2)/17 = (24x - 57.6)/17

17x + 54.4 = 24x - 57.6

54.4 = 7x - 57.6

112 = 7x

x = 16

y = (16 - 2.4)/85 = 13.6/85 = 0.16

Answer:

x = 12

Step-by-step explanation:

g(x) - × + 4 =0

put g(x) = 8

so, 8 - x + 4 = 0

x = 12

Answer:

x = - 4

Step-by-step explanation:

Given g(x) = - x + 4 and g(x) = 8 , the equate the right sides, that is

- x + 4 = 8 ( subtract 4 from both sides )

- x = 4 ( multiply both sides by - 1 )

x = - 4

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Answer:

  C.  -2.00 m/sec

Step-by-step explanation:

The average velocity on the interval [a, b] is found by ...

  m = (s(b) -s(a))/(b -a)

One end of the interval remains constant here, so we can define 'd' so that the interval is [4, 4+d]. Then the average velocity is ...

  m = (s(4 +d) -s(4))/((4 +d) -4)

  m = (s(4+d) -s(4))/d

The attached table shows the average velocity values on the intervals required by the problem statement. Respectively, they are ...

  -1.5 m/s, -1.7 m/s, -1.9 m/s, -1.99 m/s, 2.01 m/s, 2.1 m/s, 2.3 m/s, 2.5 m/s

We expect the instantaneous velocity at d=0 to be the average of the values at d=-0.01 and d=+0.01. We estimate the instantaneous velocity at t=4 seconds to be -2.00 m/s.