i'll promise to give the brainliest ! so, can someone help me with this one please

Answer:

h=8ft

Step-by-step explanation:

[tex]v = l \times w \times h[/tex]

[tex]h = \frac{v}{l \times v} = \frac{200}{5 \times 5} = 8[/tex]

Answer:

3

Step-by-step explanation:

+2

Answer:

125 as a fraction is 1/8.

0.125 = 125/1000. We can reduce this to lowest terms by dividing the numerator and denominator by 125 to get the equivalent fraction 1/8.

Step-by-step explanation:

hey mate hope it cleared your problem!!

Answer:

18

Step-by-step explanation:

just type the thing in the calculator

The measure of x for the given similar triangle will be 18 units.

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices.

In a triangle, the sum of all three angles is 180°

The triangle is a highly common shape that we deal with on a daily basis. For instance, the right-angle triangle is frequently used to estimate the height of towers.

By similar triangle rule ;

If two triangles are similar then the ratio of the corresponding side will be the same.

So,

x/12 = 24/(12+4)

x/12 = 1.5

x = 18 units.

Hence the measure of x will be 18 units.

For more information about triangle

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Answer: 3/14

Step-by-step explanation:

Number of red marbles = 4

Number of green marbles = 6

Number of white marbles = 1

Number of blue marbles = 3

Total number of marbles = 14

Therefore, the probability of drawing one blue marble will be:

= Number of blue marbles / Total number of marbles

= 3/14

Answer:

total of it is Nu.24

Step-by-step explanation:

just add all up into

9 + 15 = 24

Answer:

4033

Step-by-step explanation:

An easy way to solve this problem is to notice the numerator, 2017^4-2016^4 resembles the special product a^2 - b^2. In this case, 2017^4 is a^2 and 2016^4 is b^2. We can set up equations to solve for a and b:

a^2 = 2017^4

a = 2017^2

b^2 = 2016^4

b = 2016^2

Now, the special product a^2 - b^2 factors to (a + b)(a - b), so we can substitute that for the numerator:

We can notice that both the numerator and denominator contain 2017^2 + 2016^2, so we can divide by [tex]\frac{2017^2+2016^2}{2017^2+2016^2}[/tex] which is just one, and will simplify the fraction to just:

2017^2 - 2016^2

This again is just the special product a^2 - b^2, but in this case a is 2017 and b is 2016. Using this we can factor it:

(2017 + 2016)(2017 - 2016)

And, without using a calculator, this is easy to simplify:

(4033)(1)

4033

Answer: 110

Step-by-step explanation:

I did it it’s correct :)

Answer:

on like term

Step-by-step explanation:

x+2)=(y-5)=2+5=7

x-y{x-y]=7x-y

by Emmanuel okorie

Answer:

3/1

Step-by-step explanation:

Answer:

[tex]-3[/tex]

Step-by-step explanation:

The slope of the line is -3 because to get to one point from another point, you would need to go down 3 and right 1 which is -3/1, and that is also just -3

Hope this helps

the addition sign thus 2+1÷3=2

Answer:

56

Step-by-step explanation:

Answer: 0.0062

Step-by-step explanation:

Answer:

Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.

Step-by-step explanation:

Let 10-oz, 14-oz, and 20-oz coffees be represented by the variables a, b, and c, respectively.

Since a total of 14 cups of coffee was served:

[tex]a+b+c=14[/tex]

A total of 204 ounces of coffee was served. Therefore:

[tex]10a+14b+20c=204[/tex]

A total of $16.70 was collected. Hence:

[tex]0.95a+1.15b+1.5c=16.7[/tex]

This yields a triple system of equations. In order to solve a triple system, we should isolate the system to only two variables first.

From the first equation, let's subtract a and b from both sides:

[tex]c=14-a-b[/tex]

Substitute this into both the second and third equations:

[tex]10a+14b+20(14-a-b)=204[/tex]

And:

[tex]0.95a+1.15b+1.5(14-a-b)=16.7[/tex]

In this way, we've successfully created a system of two equations, which can be more easily solved. Distribute:

For the Second Equation:

[tex]\displaystyle \begin{aligned} 10a+14b+280-20a-20b&=204\\ -10a-6b&=-76\\5a+3b&=38\end{aligned}[/tex]

And for the Third:

[tex]\displaystyle \begin{aligned} 0.95a+1.15b+21-1.5a-1.5b&=16.7\\ -0.55a-0.35b&=-4.3\end{aligned}[/tex]

We can solve this using substitution. From the second equation, isolate a:

[tex]\displaystyle a=\frac{1}{5}(38-3b)=7.6-0.6b[/tex]

Substitute into the third:

[tex]-0.55(7.6-0.6b)-0.35b=-4.3[/tex]

Distribute and simplify:

[tex]-4.18+0.33b-0.35b=-4.3[/tex]

Therefore:

[tex]-0.02b=-0.12\Rightarrow b=6[/tex]

Using the equation for a:

[tex]a=7.6-0.6(6)=4[/tex]

And using the equation for c:

[tex]c=14-(4)-(6)=14-10=4[/tex]

Therefore, Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.

Answer:

0.3233

0.09

Step-by-step explanation:

Given that :

Mean, λ = 0.25 for a 100,000 per week

For a population of 800,000 :

λ = 800,000 / 100,000 * 0.25 = 8 * 0.25 = 2 orders per week

Probability that technician is required after one week ;

After one week, order is beyond 2 ; hence, order, x ≥ 3

P(x ≥ 3) = 1 - [p(x=0) + p(x= 1) + p(x =2)]

P(x ≥ 3) = 1 - e^-λ(1 + 2¹/1! + 2²/2!)

P(x ≥ 3) = 1 - e^-2(1+2+2) = 1 - e^-2*5 = 1 - e^-10

P(x ≥ 3) = 1 - e^-2 * 10

P(x ≥ 3) = 1 - 0.6766764

P(x ≥ 3) = 0.3233

B.)

Mean, λ for more than 2 weeks = 2 * 2 = 4

P(x < 2) = p(x = 0) + p(x = 1)

P(x < 2) = e^-4(0 + 4^1/1!)

P(x < 2) = e^-4(0 + 4) = e^-4(5)

P(x < 2) = e^-4(5) = 0.0183156 * 5 = 0.0915

P(x < 2) = 0.09

Answer:

82

Step-by-step explanation:

Answer:

X = 5

Step-by-step explanation:

Hope it's help you !!!!!!!!!

Answer:

X=5

Step-by-step explanation:

X=5

The other side is the same as X so it is 5. Also it the same as the bottom that = 5.

Answer:

base = 21.2

Step-by-step explanation:

Let the base be 2x

Drawing a perpendicular bisector divides the bases into 2 equal parts.

Then using trigonometric ratio :

[tex]cos \theta = \frac{adjacent}{hypotenuse}[/tex]   , [tex][ \ where \ \theta = 28^{ \circ} , \ adjacent = x,\ hypotenuse = 12 \ ][/tex]

The trigonometric function gives the ratio of different sides of a right-angle triangle. The length of the base of the isosceles triangle is 21.19 units.

The trigonometric function gives the ratio of different sides of a right-angle triangle.

[tex]\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}[/tex]

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

In order to solve the problem, we will draw a line between the triangle such that it will bisect the angle at the top(∠A) and the base(BC). As shown in the image below.

Now, as we know that the line(AD) is perpendicular to the base(BC) of the isosceles triangle, therefore, using the function of trigonometry in the Δ ABD we can write,

[tex]Cos \theta=\dfrac{BD}{AB}\\\\\\Cos (\angle B)=\dfrac{BD}{12}\\\\\\Cos 28^o \times 12={BD}\\\\BD = 10.5953[/tex]

Now, we know that the line BD divides the base BC into two equal parts, therefore, BD=BC.

BC = BD + DC

BC = 10.5953 +10.5953

BC = 21.19 units

Hence, the length of the base of the isosceles triangle is21.19 units.

Learn more about Trigonometric functions:

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Answer:

No solution is possible from the provided information

Step-by-step explanation:

Answer:

Breadth = 15 cm

Step-by-step explanation:

Area = length x breadth

315 = 21 x breadth

[tex]\frac{315}{21} = \frac{21}{21} \times breadth[/tex]                 [ dividing both sides by 21 ]

[tex]15 = 1 \times breadth\\\\breadth = 15 \ cm[/tex]

___________________________________

[tex]\quad\quad\quad\quad\tt{A = A rea}[/tex]

[tex]\quad\quad\quad\quad\tt{ l = length} [/tex]

[tex]\quad\quad\quad\quad\tt{ b \: = breadth} [/tex]

[tex]\quad\quad\quad\quad\tt{A = 315 {cm}^{2} }[/tex]

[tex]\quad\quad\quad\quad\tt{l = 21cm}[/tex]

[tex]\quad\quad\quad\quad\tt{b = \: ? }[/tex]

[tex]\quad\quad\quad\quad\tt{breadth = \frac{Area}{length} }[/tex]

[tex]\quad\quad\quad\quad\tt{b = \frac{315 {cm}^{2} }{21cm} }[/tex]

[tex]\quad\quad\quad\quad\tt \boxed{ \boxed{ \color{magenta}{b = 15cm }}}[/tex]

___________________________________

#CarryOnLearning

✍︎ C.Rose❀

Answer:

The event is mutually exclusive.

Step-by-step explanation:

Mutually exclusive events are events that cannot exist simultaneously.

Thus, events that are not mutually exclusive can exist simultaneously.

Since each student only has one major, a single student cannot be both a mathematics major and a business major.

So, the event is mutually exclusive.

Answer:

so if 8x10 is 80 and 4x6 is 24 then take 24 of 80 you get 56

Answer:

there are about 36 students in each grade.

Step-by-step explanation:

divide the total amount of students by the amount of grades. 108/3 = 36

Answer:

pie times radius square is equal to 147

when pie is 3, radius square is 49

radius is equal to 7

actual pie r square is 22/7 times 7 times 7 is 154

Step-by-step explanation:

ans is 154

Answer:

y = 8/5x

Step-by-step explanation:

I'm assuming that they're asking for the equation in point-slope form.

The formula is y=mx+b where:

m = slope

b = y intercept

However, the y intercept is just (0,0) so b = 0

To find the slope we already have 2 given points: (0,0) and (5,8)

To find slope you do rise/run and you get 8/5

Substitute the slope & y intercept in the formula:

y = 8/5x

Let me know if I'm wrong!!

Answer:

y=8/5x

Step-by-step explanation:

Hi there!

We need to find the equation of the line that passes through (5,8) and the origin (the point (0,0)).

There are 3 ways to write the equation of the line, although the most common way is slope-intercept form, or y=mx+b where m is the slope and b is the y intercept

first, let's find m (slope)

The formula for the slope calculated from two points is [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex], where ([tex]x_{1}[/tex],[tex]y_{1}[/tex]) and ([tex]x_{2}[/tex], [tex]y_{2}[/tex]) are points

we have two points, but let's label their values to avoid any confusion

[tex]x_{1}[/tex]=5

[tex]y_{1}[/tex]=8

[tex]x_{2}[/tex]=0

[tex]y_{2}[/tex]=0

now substitute into the formula

m=[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

m=[tex]\frac{0-8}{0-5}[/tex]

multiply

m=[tex]\frac{-8}{-5}[/tex]

divide

m=8/5

The slope of the line is 8/5

here's the equation so far

y=8/5x+b

now we need to find b

as the point will pass through both (5,8) and (0,0) we can use either one of them to solve for b

let's take (0,0) as an example

substitute 0 as x and 0 as y

0=8/5(0)+b

multiply

0=0+b

add

0=b

substitute 0 as b into the equation

Therefore the equation of the line is:

y=8/5x (the 0 is not necessary)

Hope this helps! :)

Given:

The data values are:

164, 148, 137, 157, 173, 156, 177, 172, 169, 165, 145, 168, 163, 162, 174, 152, 156, 168, 154, 151, 174, 146, 134, 140, and 171.

To find;

a. Lower quartile.

b. Upper quartile.

c. Interquartile range.

Solution:

We have,

164, 148, 137, 157, 173, 156, 177, 172, 169, 165, 145, 168, 163, 162, 174, 152, 156, 168, 154, 151, 174, 146, 134, 140, 171.

Arrange the data values in ascending order.

134, 137, 140, 145, 146, 148, 151, 152, 154, 156, 156, 157, 162, 163, 164, 165, 168, 168, 169, 171, 172, 173, 174, 174, 177.

Divide the data values in two equal parts.

(134, 137, 140, 145, 146, 148, 151, 152, 154, 156, 156, 157), 162, (163, 164, 165, 168, 168, 169, 171, 172, 173, 174, 174, 177)

Divide each parentheses in two equal parts.

(134, 137, 140, 145, 146, 148), (151, 152, 154, 156, 156, 157), 162, (163, 164, 165, 168, 168, 169), (171, 172, 173, 174, 174, 177)

a. Location of lower quartile is:

[tex]Q_1=\dfrac{1}{4}(n+1)\text{th term}[/tex]

[tex]Q_1=\dfrac{1}{4}(25+1)\text{th term}[/tex]

[tex]Q_1=\dfrac{26}{4}\text{th term}[/tex]

[tex]Q_1=6.5\text{th term}[/tex]

The lower quartile of the weights is:

[tex]Q_1=\dfrac{148+151}{2}[/tex]

[tex]Q_1=\dfrac{299}{2}[/tex]

[tex]Q_1=149.5[/tex]

Therefore, the location of the lower quartile of the weights is between 6th term and the 7th term. The value of the lower quartile is 149.5.

b. Location of upper quartile is:

[tex]Q_3=\dfrac{3}{4}(n+1)\text{th term}[/tex]

[tex]Q_3=\dfrac{3}{4}(25+1)\text{th term}[/tex]

[tex]Q_3=\dfrac{3\cdot 26}{4}\text{th term}[/tex]

[tex]Q_3=19.5\text{th term}[/tex]

The upper quartile of the weights is:

[tex]Q_3=\dfrac{169+171}{2}[/tex]

[tex]Q_3=\dfrac{340}{2}[/tex]

[tex]Q_3=170[/tex]

Therefore, the location of the upper quartile of the weights is between 19th term and the 20th term. The value of the upper quartile is 170.

c. The interquartile range of the given data set is:

[tex]IQR=Q_3-Q_1[/tex]

[tex]IQR=170-149.5[/tex]

[tex]IQR=20.5[/tex]

Therefore, the interquartile range of the weights is 20.5.