In a lab experiment, 830 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 28 hours. How many bacteria would there be after 13 years, to the nearest whole number?​

Answers

Answer 1

Answer:

1145

Step-by-step explanation:

830(2) 28/13

​   ^ do that ok??????? plug it in!!!!!!!!

then do u know what u will get? u will get this !!!!!! y = 1145.09631989

round 2 da whole numba and den boom shakalaka B ) i got my question wrong so that i could put the right answer here. bye yall

Answer 2

The number of bacteria doubling every 28 hours will be 1145 after 13 hours.

What is the formula for exponential growth and exponential decaying function?

The formula for exponential growth is y = y₀.e^(kt).

The formula for exponential decay is y = y₀.e^(-kt).

In the case of doubling the growth of bacteria, we can use the formula,

[tex]y_f = y_0\times2^{\frac{t_r}{t}[/tex], where [tex]y_f[/tex] represents the final population, [tex]y_0[/tex] is the initial population, [tex]t_r[/tex] is the time we are required to determine, and [tex]t[/tex] represents the time rate growth.

Therefore from the given information, the number of bacteria after 13 hours will be,

[tex]y_f = 830\times2^{\frac{13}{28}[/tex].

[tex]y_f = 830\times1.38[/tex].

[tex]y_f = 1144.86[/tex] or 1145 bacterias.

Q. In a lab experiment, 830 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to double every 28 hours. How many bacteria would there be after 13 hours, to the nearest whole number?​

learn more about bacteria growth problems here :

https://brainly.com/question/14106525

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