in circle T with m angle STU=50 and ST=3 units, find the length of arc SU. Round to the nearest hundredth.

Answer:

40

Step-by-step explanation:

If you take 15, and divide it by the 3 out of the 3/8 left, you get 5. You then multiply 5 by 8 to get the full amount of candies she had before sharing, 40.

I hope this helped!

Thanks!

Your friend in answering,

~Steve

Answer:

40.

Step-by-step explanation:

If 15 candies are the rest of 3/8, then the total candies were 40.

[tex]\Huge \bf \over \rightarrow\mid\mathcal {\underline{ \orange{12 \: : \: 00}}} \mid[/tex]

Answer:

I think 10:45 is the nearest quarter hour.

[tex] \frac{b}{3} \geq - 1 \\ = 3 \times \frac{b}{3} \geq \times ( -1 ) \\ = b \geq3 \times ( - 1) \\ = b \geq - 3 \times 1 \\ \\ = b \geq - 3[/tex]

Step By Step Explanation:

#CarryOnLearning

Answer:

2.5 miles

Step-by-step explanation:

Answer:10,666,66 [tex]\pi[/tex]m^3

Step-by-step explanation:

V=[tex]\frac{4}{3} \pi r^{3}[/tex]

[tex]\frac{4}{3} \pi 20^{3} \\ V=10,666.66 \pi[/tex]

9514 1404 393

Answer:

  36 9/16 cubic feet

Step-by-step explanation:

Volume formula

  V = LWH

  V = (3 3/4 ft)(3 ft)(3 1/4 ft) = (15/4)(3)(13/4) ft³ = 585/16 ft³

  V = 36 9/16 ft³ . . . the volume of the shipping box

__

Packing cubes

Each cube measures 1/4 ft on a side. In terms of cubes, the dimensions of the box are ...

  3 3/4 ft = 15/4 ft = 15×(1/4 ft)   ⇒   15 cubes

  3 ft = 12/4 ft = 12×(1/4 ft)   ⇒   12 cubes

  3 1/4 ft = 13/4 ft = 13×(1/4 ft)   ⇒   13 cubes

This means 15 cubes can be lined up along the bottom front of the box. 12 such lines can make one layer of cubes covering the bottom of the box, and 13 such layers will fill the box.

The total number of cubes in the box is ...

  15 × 12× 13 = 2340 . . . . fish food cubes

Each cube has a volume of (1/4 ft)³ = 1/64 ft³, so the volume of the shipping box is ...

  (2340 cubes)×(1/64 ft³/cube) = 2340/64 ft³

  = 36 9/16 ft³ . . . shipping box volume

__

Using the volume formula, the volume is 36 9/16 ft³

Using the packing cubes method, the volume is 36 9/16 ft³

__

If you consider the math used in the packing cubes method, you see it looks like ...

  V = (15)(12)(13) × (1/64 ft³)

  = (15)(12)(13)×(1/4 ft)³ = (15×1/4 ft)(12×1/4 ft)(13×1/4 ft)

  = (3 3/4 ft)(3 ft)(3 1/4 ft)

  = LWH

That is, the "packing cubes method" is simply a rearrangement of the volume formula product using the commutative and associative properties of multiplication. The same numbers are used to compute the product, but in a different order. Hence the result must be the same.

Answer:

b.    [tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]

Step-by-step explanation:

[tex] l = 14j + 3k [/tex]

Switch sides.

[tex] 14j + 3k = l [/tex]

Subtract 14j from both sides.

[tex] 3k = l - 14j [/tex]

Divide both sides by 3.

[tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]

Answer:

x + 25 is an expression, not an inequality.

Jordan has more than 25 coins, so this means that the > symbol will be used.

The answer with this symbol is B. x>25.

Step-by-step explanation:

Answer:

x+3y =6

2x+8y=-12​

The solutions to your equations are:

x= 42 and y= -12

lets check this

42+-36 =6

84+-96=-12​

Hope This Helps!!!

Answer:

42 teaspoons of vinegar

Step-by-step explanation:

Given

[tex]x \to vegertable[/tex]

[tex]y \to vinegar[/tex]

[tex]x : y = 4 :12[/tex]

Required

Find y when [tex]x = 14[/tex]

[tex]x : y = 4 :12[/tex] implies that:

[tex]14 : y = 4 : 12[/tex]

Express as fraction

[tex]\frac{y}{14} = \frac{12}{4}[/tex]

[tex]\frac{y}{14} = 3[/tex]

Multiply by 3

[tex]y = 14* 3[/tex]

[tex]y = 42[/tex]

Answer:

Step-by-step explanation:

Law of sines says that the length of sides are proportional to the sine of the opposing angle.

Using the sine rule,

sin(x)/2.5 = sin(28)/3

therefore

sin(x) = 2.5 * sin(28) / 3

or

here we have

x = asin (2.5*sin(28) / 3)

so

box 1 = 2.5

box 2 = 28°

box 3 = 3

Answer:

The median weight for shelter A is greater than that for shelter B.

The data for shelter B are a symmetric data set.

The interquartile range of shelter A is greater than the interquartile range of shelter B.

Step-by-step explanation:

The median weight for shelter A is greater than that for shelter B.

The median of A = 21 and the median of B = 18  true

The median weight for shelter B is greater than that for shelter A.

The median of A = 21 and the median of B = 18   false

The data for shelter A are a symmetric data set.

False, looking at the box it is not symmetric

The data for shelter B are a symmetric data set.

true, looking at the box it is  symmetric

The interquartile range of shelter A is greater than the interquartile range of shelter B.

IQR = 28 - 17 = 11 for A

IQR for B = 20 -16 = 4  True

Answer:

the awnser is 2,0

Step-by-step explanation:

Answer:

(1,-2) is the correct answer

Answer:

3:7

Step-by-step explanation:

We know that there are 4 girls and 3 boys and 4+3=7.

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is mean amount of inches of rain and [tex]\sigma[/tex] is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean [tex]\mu[/tex], standard deviation [tex]\sigma[/tex]

n days:

This means that [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

Applying the Central Limit Theorem to the z-score formula.

[tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is mean amount of inches of rain and [tex]\sigma[/tex] is the standard deviation.

9514 1404 393

Answer:

  $163,002

Step-by-step explanation:

If you're working problems of this sort, you have been shown formulas and examples. Use the appropriate formula with the numbers of this problem.

For the formula below, you have d=3000, r=0.045, k=4, N=11

  P = (3000)(1 -(1 +0.045/4)^(-11·4))/(0.045/4) ≈ 163,002

The account needs to hold about $163,002 to make this possible.

Answer:

2B+5C

Step-by-step explanation:

Multiply them out....

2B=2*(4i-j) = 8i-2j

5C=5*(2i+3j) = 10i+15j

2B+5C= 8i-2j+10i+15j =18i+13j = A

9514 1404 393

Answer:

  a)  2B +5C

Step-by-step explanation:

It is probably easiest to simply try the answer choices. You find the first one works, which means it is the one you want.

  2B +5C = 2(4i -j) +5(2i +3j) . . . . choice (a)

  = 8i -2j +10i +15j

  = 18i +13j = A

__

In general, you can solve for the coefficients p and q that make ...

  pB +qC = A

  p(4i -j) +q(2i +3j) = 18i +13j

  (4p+2q)i +(-p +3q)j = 18i +13j

Equating the coefficients of i and j gives us 2 equations in p and q.

  4p +2q = 18

  -p +3q = 13

Adding 2 times the second equation to 1/2 the first, we get ...

  1/2(4p +2q) +2(-p +3q) = 1/2(18) +2(13)

 7q = 35

 q = 5

Using the second equation to find p, we get ...

  p = 3q -13 = 3(5) -13 = 2

These coefficients tell us ...

  A = 2B +5C . . . . . . . matches choice (a)

Answer:

someone else tell me to thank you

Answer:

[tex]\textbf{HELLO!!}[/tex]

[tex]21\left(2-y\right)+12y=44[/tex]

[tex]42-21y+12y=44[/tex]

[tex]~add ~similar\:elements[/tex]

[tex]42-9y=44[/tex]

[tex]Subtract~42~from~both~sides[/tex]

[tex]42-9y-42=44-42[/tex]

[tex]-9y=2[/tex]

[tex]Divide\:both\:sides\:by\:}-9[/tex]

[tex]\frac{-9y}{-9}=\frac{2}{-9}[/tex]

[tex]y=-\frac{2}{9}[/tex]

----------------------

hope it helps...

have a great day!

Answer:

20

Step-by-step explanation:

15+(-2)+7=13+7=20

[tex]\longrightarrow{\blue{20}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex]\:15 + ( - 2) + 7[/tex]

➺ [tex] \: 15 - 2 + 7[/tex]

➺ [tex] \: 22 - 2[/tex]

➺ [tex] \: 20[/tex]

[tex]\sf\pink{PEMDAS\: rule.}[/tex]

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]

9514 1404 393

Answer:

Step-by-step explanation:

Add or subtract multiples of 360° to find coterminal angles.

Positive

  75° +360° = 435°

  75° +2×360° = 795°

Negative

  75° -360° = -285°

  75° -2×360° = -645°

Answer:

v = 15 mph

Step-by-step explanation:

Given that,

A cyclist travels 3 miles in 15 minutes and then a further 7 miles in 25 minutes without stopping.

Total distance, d = 3 + 7 = 10 miles

Total time, t = 15 + 25 = 40 minutes = 0.6667 hours

Average speed,

[tex]v=\dfrac{d}{t}[/tex]

Put all the value,

[tex]v=\dfrac{10}{0.6667}\\\\= $$14.99\ mph[/tex]

or

v = 15 mph

So, the required average speed is equal to 15 mph.

Answer:

3sqaure root 100/5

Step-by-step explanation:

It would look like this picture Below

Answer:

h = [tex]\frac{V}{\pi r^2}[/tex]

Step-by-step explanation:

Given

V = πr²h ( isolate h by dividing both sides by πr² )

[tex]\frac{V}{\pi r^2}[/tex] = h

Answer:

option A

Step-by-step explanation:

since the given triangle is an isosceles triangle it's two remaining sides are equal

let the length of missing side be x

using pythagoras theorem

a^2 + b^2 = c^2

x^2 + x^2 = 22^2

2x^2 = 484

x^2 = 484/2

x = [tex]\sqrt{242}[/tex]

x = [tex]11\sqrt{2}[/tex]

the answer is in the picture

Answer:

option C

Step-by-step explanation:

Total number of items = 5

Number of items to choose = 2

Therefore, the number of combinations is

                                                       [tex]5C_2 = \frac{5 \times 4}{1 \times 2} = 10[/tex]

Answer:

a) 0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b) 0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c) 0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 8.1 minutes and a standard deviation of 2.0 minutes.

This means that [tex]\mu = 8.1, \sigma = 2[/tex]

a. between 5 and 10 min

This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5.

X = 10

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{10 - 8.1}{2}[/tex]

[tex]Z = 0.95[/tex]

[tex]Z = 0.95[/tex] has a p-value of 0.8289

X = 5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{5 - 8.1}{2}[/tex]

[tex]Z = -1.55[/tex]

[tex]Z = -1.55[/tex] has a p-value of  0.0606

0.8289 - 0.0606 = 0.7683

0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b. less than 5 min

p-value of Z when X = 5, which, found from item a, is of 0.0606

0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c. more than 10 min

1 subtracted by the p-value of Z when X = 10, which, from item a, is of 0.8289

1 - 0.8289 = 0.1711

0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

Answer:

x = 82.1º

Step-by-step explanation:

tan = opp/adj

tan75 = x/22

multiply both sides by 22

22 * tan75 = x

use calculator

82.1051177665153 = x

Rounded

x = 82.1º