In ΔBCD, the measure of ∠D=90°, the measure of ∠B=71°, and DB = 67 feet. Find the length of BC to the nearest tenth of a foot.

In BCD, The Measure Of D=90, The Measure Of B=71, And DB = 67 Feet. Find The Length Of BC To The Nearest

Answers

Answer 1

Answer:

in triangle BCD

relationship between base and hypotenuse is given by cos angle

cos 71=b/h

cos71=BD/BC

cos71=67/x

x=67/cos71=205.8ft.

the length of BC to the nearest tenth of a foot is 206ft.


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