In need your help please

Mrs. Phillips is making room in a closet for hoarding toilet paper. Using the Fermi process, she wants to estimate the number of rolls of toilet paper she can fit into a rectangular section of a closet with dimensions of (length 48 inches) (by width 84 imches) the toilet paper has the diameter 5 inches, height 4 inches.


(1)What us the volume of closet space


(2)what is the volume of one roll of toilet paper [use 3.4 for pie and round to the nearest while number]


(3) How many rolls of toilet paper can fit into the closet space

Answers

Answer 1

(1) The volume of closet space = 161,280

(2) The volume of one roll of toilet paper =  265 cubic inches

(3) The number of rolls of toilet paper can fit into the closet space = 608 rolls.

Given that,

The  length of rectangular section = 48 inches

The  width of rectangular section   = 84 inches

The diameter of toilet paper           = 5 inches

Height of toilet paper = 4 inches

The volume of the wardrobe space can be calculated by multiplying the rectangular section's length, breadth, and height.

As a result,

The closet's volume is roughly 161,280 cubic inches (48 x 84 x height).

The volume of one roll of toilet paper can be calculated using the volume of a cylinder formula (V = πr²h) with a diameter of 5 inches and a height of 4 inches.

Therefore,

One roll of toilet paper has a volume of around 265 cubic inches, rounded to 3.4.

To get the maximum number of rolls that can fit in the closet, divide the closet volume by the volume of one roll of toilet paper.

As a result, approximately 608 rolls of toilet paper can fit in the closet's rectangular part.

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

The value of "p" will be "0.002".

Equation:

According to the question,

[tex]100+0.05p=0.25p[/tex]

By subtracting "0.25p" from both sides, we get

→ [tex]100+0.05p-0.25p=0.25p-0.25p[/tex]

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Answer:

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Step-by-step explanation:

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37 monedas de $5 y 15 monedas de $10

Step-by-step explanation:

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The coordinates of the vertices of △UVW are U(−2,−1), V(2,−1), and W(2,−8). Find the side lengths to the nearest hundredth and the angle measures to the nearest degree.

Answers

Answer:

UV = 4; VW = 7, UW ≈ 8.06

m∠V = 90°, m∠U ≈ 60°, m∠W ≈ 30°

Step-by-step explanation:

Using the distance formula, find the length of UW⎯⎯⎯⎯⎯⎯⎯.

UW=(2−(−2))2+(−8−(−1))2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√

Simplify.

UW=(4)2+(−7)2‾‾‾‾‾‾‾‾‾‾‾‾√

Square.

UW=16+49‾‾‾‾‾‾‾√

Simplify.

UW=65‾‾‾√

Use a calculator to approximate.

UW≈8.06

Therefore, UW≈8.06.

Using the distance formula, find the length of UV⎯⎯⎯⎯⎯⎯.

UV=(2−(−2))2+(−1−(−1))2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√

Simplify.

UV=(4)2+(0)2‾‾‾‾‾‾‾‾‾‾√

Square.

UV=16+0‾‾‾‾‾‾√

Simplify.

UV=16‾‾‾√

Simplify.

UV=4

Therefore, UV=4.

Using the distance formula, find the length of VW⎯⎯⎯⎯⎯⎯.

VW=(2−2)2+(−8−(−1))2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√

Simplify.

VW=(0)2+(−7)2‾‾‾‾‾‾‾‾‾‾‾‾√

Square.

VW=0+49‾‾‾‾‾‾√

Simplify.

VW=49‾‾‾√

Simplify.

VW=7

Therefore, VW=7.

The figure shows the same triangle U V W on a Cartesian plane as in the beginning of the task. The length of segment U V is 4 units. The length of segment V W is 7 units. The length of segment U W is 8.06 units.

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By the definition of tangent, tan∠U=VWUV.

Take the inverse tangent of both sides.

m∠U=tan−1(VWUV)

Substitute 7 for VW and 4 for UV.

m∠U=tan−1(74)

Use a calculator to calculate the inverse tangent.

The figure shows a calculator screen on which the inverse tangent of seven fourths is calculated. The result of the calculation is 60 point 2 5 5 1 1 8 7.

m∠U≈60°

Therefore, m∠U≈60°.

The figure shows the same triangle U V W on a Cartesian plane as in the beginning of the task. Angle V is a right angle. Angle U measures 60 degrees.

The acute angles of a right triangle are complementary by the corollary of the Triangle Sum Theorem.

So, m∠U+m∠W=90°.

Substitute 60° for m∠U.

60°+m∠W≈90°

Subtract 60° from both sides.

m∠W≈90°−60°

Simplify.

m∠W≈30°

Therefore, m∠W≈30°.

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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the length of a room is 2 m longer than its breadth .if the area of its floor is 63 sq.m.calculate the length and the breadth of the room​

Answers

Answer:

Given :-

the length of a room is 2 m longer than its breadth .if the area of its floor is 63 sq.m.calculate the length and the breadth of the room

To Find :-

Length and breadth

Answer :-

Let the length and breadth be l + 2 and l

Now,

[tex] \large \sf \: Area = l + 2 \times l [/tex]

[tex] \large \sf \: 63 = l + 2 \times \: l[/tex]

[tex] \large \sf \: 63 = 2l + {l}^{2} [/tex]

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[tex] \large \sf \: l = - 9[/tex]

or,

[tex] \large \sf \: l = 7[/tex]

Length can't be negative,

So,

L = 9

B = 7

Please mark as brainliest :)

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Step-by-step explanation:

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