Is (2,1) a solution to this system of equations??
8x+7y=11
x+y=3

a) Yes
b) No​

Answer:

x²+1/x² = 51

Explanation:

Given x - 1/x = 7 ---(1)

We know the algebraic identity:

a²+b²-2ab = (a-b)²

Or

a²+b² = (a-b)²+2ab

Now,

x²+1/x²

= (x-1/x)²+2*x*(1/x)

= (x-1/x)²+2

:7²+2 [ from (1)] =

= 49+2

= 51

Therefore,

x²+1/x² = 51

[tex]\mathfrak{5x + 15 = 28} [/tex]

[tex]\mathfrak{5x = 28-15} [/tex]

[tex]\mathfrak{5x = 13} [/tex]

[tex]\boxed{\mathfrak{x = \dfrac{13}{5}}} [/tex] → option B.

[tex]\mathbb{MIREU} [/tex]

Answer:

B

Step-by-step explanation:

The first thing you need to do is,

28 - 15

which is 13.

Now look at the answer choices and multiply them by 5.

It cannot be C or D because it would not fit the equation.

If anyone of them equal 13 then it is the answer.

Now lets try it.

43/5 = 8.6

13/5 = 2.6

8.6 times 5 is way to big so A is not it.

2.6 times 5 is 13.

So it is B.

Answer:

Ariana can move 24 boxes. Hope this helps.

Pls give brainliest. :D

Answer:

1/28

Step-by-step explanation:

Answer:

try for an answer: 6ab • (18ab + a - 6b)

Answer:

ok first we round them both

386230 is rounded to 386k

59250 is rounded to 59 k

386+59=445

445,000

Hope This Helps!!!

Answer:

y = -6

Step-by-step explanation:

-2(y - 3) = y + 24

-2y + 6 = y +24

-18 = 3y

-6 = y

Answer:

$30.46

Step-by-step explanation:

Total payment = down payment + interest fee + 24 equal payments

980 = 200 + 49 + 24 equal payments

24 equal payments = 24 * p, as we add p 24 times

980 = 249 + 24p

subtract 249 from both sides to isolate p and its coefficient

731 = 24p

divide both sides by 24 to isolate p

p = 30.46

Answer:

2/7÷3/4=2/7×4/3=8/21

[tex] \rm \ \blue{ \overbrace{ \underbrace{ \tt \color{hotpink} \: \: \: \: \: \: \: \: \: \: answer \: \: \: \: \: \: \: \: \: }}}[/tex]

[tex]\large \color{pink} \frac{8}{21} [/tex]

Step-by-step explanation:

[tex] \huge \color{brown} \frac{2}{7} \div \frac{3}{4} [/tex]

[tex] \large \color{hotpink} \frac{2}{7} \div \frac{4}{3} [/tex]

[tex] \huge \color{darkblue} \frac{8}{21} [/tex]

Answer:

Slope=0.12   power is down by 28%

Step-by-step explanation:

:)

The inverse of an implication p ⇒ q is ¬p ⇒ ¬q.

The converse of p ⇒ q is q ⇒ p.

The contrapositive of p ⇒ q is ¬q ⇒ ¬p.

Then

• the inverse of the inverse of p ⇒ q is p ⇒ q

• the inverse of the the converse of p ⇒ q is ¬q ⇒ ¬p

• the inverse of the contrapositive of p ⇒ q is q ⇒ p

Answer:

x < - 1

Step-by-step explanation:

You have to treat it is a linear equation.

First, - 5 from both sides, resulting in -2x < 2.

Lastly, you need to find x on it's own so you have to divide by - 2.

Therefore, the answer would be x < -1.

Hope this helps :)

Answer:

7=4m +c( y intercept)

Step-by-step explanation:

use the formula y= mx +c

Answer:

x=17.333

Step-by-step explanation:

3x+8=60

3x=60-8

3x=52

x=52\3

x=17.333

Answer:

3 (B)

Step-by-step explanation:

rise/run

rise=3

run=1

3/1=3

Answer: B)1/4

Step-by-step explanation: If you divide a pizza into 4 pieces, each person will get a fourth of the pizza.

we know that $1290 is to be divided on a 7:8 ratio, so we'll start off by dividing 1290 by (7+8) and give each person accordingly

[tex]1290~~ at~~ 7:8\implies 7\cdot \cfrac{1290}{7+8}~~ :~~8\cdot \cfrac{1290}{7+8} \\\\\\ 7\cdot 86~~:~~8\cdot 86\implies 602~~ :~~688[/tex]

Answer:

A. sec =12/13×

B. COS =12/13×

C. tan =12/5✓

D. sin =12/13 ✓

Step-by-step explanation:

we know,

using Pythagoras formula,

p=12,h=13 ,b=?

h^2 =p^2 +b^2

b=5

so tan = p/b

=12/5

sin=p/h and cosec= h/p

D. sin =12/13

The amount Billy has at the end of the 15 years is $9,377.73.

It is the interest we earned on the interest.

The formula for the amount earned with compound interest after n years is given as:

A = P[tex](1 + r/n)^{nt}[/tex]

P = principal

r = rate

t = time in years

n = number of times compounded in a year.

We have,

P = $5000

r = 4.2%

t = 15 years

n = 12

A = P[tex](1 + r/n)^{nt}[/tex]

A = 5000 [tex](1 + 0.0035)^{180}[/tex]

A = 5000 x [tex]1.0035^{180}[/tex]

A = $9,377.73

Thus,

Billy has $9,377.73 at the end of the 15 years.

Learn more about compound interest here:

https://brainly.com/question/13155407

#SPJ2

Answer:

[tex]b=-a^2-c[/tex]

Step-by-step explanation:

Answer:

( 4 x − 7 ) ( 16 x 2 + 28 x + 49 )

Step-by-step explanation:

Answer:

(4x - 7) (16x^2 + 28x + 49)

Step-by-step explanation:

Since both terms are perfect cubes, factor using the difference of cubes formula, a^3 - b^3 = (a - b) (a^ 2  +  a b  +  b^ 2 )  where  a  =  4 x  and  b  =  7 .

Answer:

C=50.27mm

Step-by-step explanation:

C=2πr=2·π·8≈50.26548mm

Answer:

[tex]x > -3[/tex]

Step-by-step explanation:

Isolate the variable. Treat the < sign like an equal sign, in that what you do to one side, you do to the other.

Do the opposite of PEMDAS. PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Divisions

Additions

Subtractions

~

First, subtract 60 from both sides of the equation:

-15x + 60 (-60) < 105 (-60)

-15x < 45

Next, divide -15 from both sides of the equation. Note that when you multiply or divide a negative number, you must flip the sign:

(-15x)/-15 < (45)/-15

x < 45/(-15)

x > -3

[tex]x > -3[/tex] is your answer.

~

Answer:

x = 0

y = -1

Step-by-step explanation:

Multiply second equation with -1

(-1) * (-3x - 8y) = 8

3x + 8y = -8 now find its sum with the first equation

2x - 8y + 3x + 8y = 8 - 8 add like terms (note that minus 8y will eliminate +8y)

x = 0 to find the value  of y replace the x with 0 in the first equation

2*0 - 8y = 8

-8y = 8 divide both sides by -8

y = -1

Answer:

[tex]y'= \dfrac{2}{3}e^{2x + e^{2x}/3}[/tex]

Step-by-step explanation:

We have [tex]e^{2x} = \ln(y^3)[/tex] and we want the implicit differentiation [tex]\dfrac{dy}{dx}f(x) = y'[/tex]

Therefore, we want to separate the [tex]y[/tex] from the equation.

[tex]\ln(y^3) =e^{2x} \implies 3 \ln(y) = e^{2x} \implies \ln(y) = \dfrac{e^{2x} }{3}[/tex]

[tex]\implies e^{\ln(y)} = e^{e^{2x}/3} \implies \boxed{y = e^{e^{2x}/3}}[/tex]

Now we can calculate the derivative. By the chain rule,

[tex]y' = \dfrac{d}{dx}\left(e^{e^{2x}/3}\right) = e^{e^{2x}/3}\dfrac{d}{dx}\left(\dfrac{e^{2x}}{3}\right)[/tex]

Now

[tex]\dfrac{d}{dx}\left(\dfrac{e^{2x}}{3}\right) =\dfrac{1}{3}\dfrac{d}{dx}\left(e^{2x}\right) = \dfrac{2}{3}e^{2x}[/tex]

Therefore

[tex]y' = e^{e^{2x}/3}\cdot \dfrac{2}{3}e^{2x} = \dfrac{2}{3}e^{2x + e^{2x}/3}[/tex]