Answer:
i am!
Explanation:
PLease help i will give brainliest
Answer:
1. False
2. Fats
3. False
Explanation:
MyPlate is an initiative from the United States Department of Agriculture that is designed to help Americans improve their eating habits throughout their lifetimes. Every meal matters. The five food groups represented in My Plate include vegetables, grain, dairy, protein foods, and fruits.
Calories are a source of energy for the human body. So, the more active a person is, the more energy he would need to be supplied to him in form of calories. The less active a person is, the fewer calories he would need.
This is an apparatus for studying the photoelectric effect. The work function of the material being investigated is 3.5 × 10–19 J. The battery is set at 1.5 V. What is the longest wavelength of light needed to produce an electric current from the cathode (C) to the anode (A)?
Answer:
The longest wavelength of light needed to produce current is 567.9 nm.
Explanation:
Given;
minimum energy required to produce electric current from the cathode to anode = work function, E = 3.5 x 10⁻¹⁹ J
E = hf
[tex]E = \frac{hc}{\lambda}[/tex]
where;
c is speed of light = 3 x 10⁸ m/s
λ is the longest wavelength of light needed to produce current
[tex]E = \frac{hc}{\lambda} \\\\\lambda = \frac{hc}{E} \\\\\lambda = \frac{(6.626\times 10^{-34})(3\times 10^8)}{3.5\times 10^{-19}}\\\\\lambda = 5.679 \times 10^{-7} \ m\\\\\lambda = 567.9 \times 10^{-9} \ m\\\\\lambda = 567.9 \ nm[/tex]
Therefore, the longest wavelength of light needed to produce current is 567.9 nm.
it is difficult to walk on a smooth floor why
Answer:
because theres is not enough friction so it will be super slippery
Explanation:
What is the minimum force require to move a 5kg wooden crate on a wooden floor?
14.7 m/s^2
20.6N
20.6 m/s^2
14.7N
You need to know the coefficient of static friction between a wooden object and a wooden surface. I'll denote it with µ. If you're given a specific value you should obviously use that.
By Newton's second law, the horizontal and vertical net forces are
• net horizontal:
∑ F = p - f = 0
• net vertical:
∑ F = n - w = 0
where
p = magnitude of the pushing force
f = mag. of friction
n = mag. of the normal force
w = weight of the crate
The second equation gives
n = w = (5 kg) (9.8 m/s²) = 49 N
Friction is proportional to the normal force by a factor of µ, so
f = µ (49 N) = 49µ N
To overcome static friction, the push has to exceed this in magnitude, so that
p > 49µ N
For instance, if p = 0.25, then p would need to greater than 12.25 N. (This example isn't particularly helpful, though, since both possibly correct options are larger than 12.25 N...)
suppose a wireless charging system of an electric toothbrush. the charger has solenoid 1 with 800 turns and the toothbrush has solenoid 2 with 150 turns what is the mutual inductance
Complete Question
Suppose a wireless charging system of an electric toothbrush. The charger has Solenoid 1 with 800 turns and the toothbrush has Solenoid 2 with 150 turns. The current in the charger is 220 mA and the corresponding average magnetic flux through Solenoid 2 is 0.056 Wb. What is the mutual inductance of the pair of the solenoids?
Answer:
The value is [tex]M = 38.2 \ H[/tex]
Explanation:
From the question we are told that
The number of turns of solenoid 1 is [tex]N_1 = 800[/tex]
The number of turns for solenoid 2 is [tex]N_2 = 150 \ turns[/tex]
The current in the charger is [tex]I = 220 \ mA = 220 *10^{-3} \ A[/tex]
The magnetic flux through solenoid 2 is [tex]\phi = 0.056 \ Wb[/tex]
Generally mutual inductance is mathematically represented as
[tex]M = \frac{N_2 * \phi }{ I }[/tex]
=> [tex]M = \frac{150 * 0.056 }{ 220 *10^{-3} }[/tex]
=> [tex]M = 38.2 \ H[/tex]
help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 39 points and will give branlist asap!
Examine the diagram below and answer the following questions for 2 points each: Identify which graph shows an object that is not moving. Explain why. Identify which graph shows an object that is speeding up over time. Explain why. Identify which graph shows an object that is moving at a constant speed. Explain why. Question 15 options:
Answer:
Graph for object that is not moving: B
Graph for object that is speeding up: D
Explanation:
A.) In order to represent that an object is not moving, you must either show that there is no velocity (0 m/s) or show a position over time graph that is a horizontal line.
Because the position is the same as time increases, the graph shows that there the object must be at rest, as there is no change in position due to velocity. (Velocity must be 0m/s)
B.) In order to represent an object is speeding up, the position time graph must either be a positive exponential function, the velocity time graph must be a positive, linear line, or the acceleration over time graph must be a positive, horizontal line.
Why is D the correct answer? Because if an object is speeding up, you know that the value of its speed (velocity) is increasing at some rate. And since speeding up refers to positive change, the function of velocity over time graph must be a positive function.
9. A 15kg mass is lifted upward at a constant speed to a height of 22 m. Calculate the work done by the lifting
force.
Work done by lifting is 3,300 Newton.
Given that;
Mass of thing = 15 kg
Height lifted = 22 m
Find:
Work done by lifting
Computation:
Work done = mgh
Work done by lifting = (15)(10)(22)
Work done by lifting = 3,300 Newton
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Two equal forces act at the same time on the same motionless object, but in opposite directions. Which statement best describes the object’s resulting motion? A. The object will accelerate. B. The object will change direction. C. The object will move at a constant speed. D. The object will remain motionless.
Answer:
D
Explanation:
The object will remain motionless(i just need points)
if a person does not just do what you told what happens
Answer:
Of course we feel bad or angry.
Explanation:
that it what i know....
a 12-kg block is pulled by a string at a 30 degree angle. if the string exerts a 50 n force, the block accelerates at 4.13 m/s2. what is the frictional force and normal force exerted on the block?
Let, frictional force is f and normal force is N.
Balancing horizontal forces :
[tex]50cos \ 30^o - f = 12 \times 4.13\\\\f = 50cos \ 30^o - 49.56\\\\f = -6.26\ N[/tex]
Also, balancing vertical forces, we get :
[tex]N = mg + 50sin \ 30^o\\\\N =( 12\times 9.8 ) + (50\times sin \ 30^o)\\\\N = 142.6\ N[/tex]
Therefore, the frictional force and normal force is -6.26 N and 142.6 N.
Consider a box with the same mass and velocity instead sliding without friction toward the incline. How does this object's kinetic energy before the incline compare to the sphere
Answer:
Object's kinetic energy is high on frictionless medium.
Explanation:
There is a great difference in object's kinetic energy which is present between sliding with friction and sliding without friction because friction decreases the speed of an object so if an object moves on the frictionless medium, it moves and covers more distance and we can say that the object has more kinetic energy while on the other hand, if a body moves on the medium and experience friction so it moves with little speed so we can say that the body has low kinetic energy.
how much work is needed to move an object 20 meters with 40 newtons of force?
Answer: c I think is the answer
Explanation:
Which number is written using standard scientific notation?
O A. 40x10°
B. 10.29x10
C. 3.47x10-7
D. 0.02x102
Question 2: Start-Up
Now you will use another Tracker experiment to examine the displacement, velocity, and acceleration of a car in the x (horizontal) direction. To
begin your investigation, open the Tracker Car Start-up experiment.
Part A
Play () the video. At the end, rewind (H) and step forward (►) one frame ata time to observe the step-by-step changes in position. Based on
your observations, describe the car's displacement (distance and direction from the starting place) over time.
Answer:
The car starts moving in the positive direction at x = 0.2 seconds. Initially it moves very little, but it covers a greater distance with each time increment.
Explanation:
Answer: The car starts moving in the positive direction at x = 0.2 seconds. Initially it moves very little, but it covers a greater distance with each time increment.
Explanation: edmentum sample answer
A teammate starts taking an all-natural supplement to improve strength and body shape and recommends you take it, too. This is an example of
Answer:
Explanation:
online personal fittness
Which of the following statements about elements and atoms is true?
A. Atoms are the smallest unit of an element.
B. Atoms are made of particles called elements.
C. Elements are made of more than one type of atom.
D. Elements are changed into atoms by a chemical reaction.
hmu^^^^
Answer:
A. Atoms are the smallest unit of an element.
Explanation:
The correct statement from the given choices is that atoms are the smallest unit of an element.
Atoms are the smallest particles that takes part in chemical reactions and they are made up of protons, neutrons and electrons.
Elements are distinct substances that cannot be split up into simpler substances. They are made up of only one kind of atoms. Elements are not changed into atoms by chemical reactions. In chemical reactions, atoms simply recombine.Two forces with magnitudes of 6 pounds and 18 pounds are applied to an object. The magnitude of the resultant is 13 pounds. Find the measurement of the angle between the resultant vector and the vector of the 18 pound force to the nearest whole degree.
Answer: the angle between the resultant vector and the vector of the 18 pound is 28°
Explanation:
given that data in the question; as its interpreted in the diagram below;
from the cosine rule, we know that;
a² = b² + c² - 2bc
so
(13)² = (6)² + (18)² - (2 × 6 × 18 ) cos∅
169 = 36 + 324 - 216cos∅
169 = 360 - 216cos∅
216cos∅ = 360 - 169
216cos∅ = 191
cos∅ = 0.8842
∅ = cos⁻¹ ( 0.8842 )
∅ = 27.8° ≈ 28° {nearest whole number}
Therefore the angle between the resultant vector and the vector of the 18 pound is 28°
A proton is projected toward a fixed nucleus of charge Ze with velocity vo. Initially the two particles are very far apart. When the proton is a distance R from the nucleus its velocity has decreased to 1/2vo. How far from the nucleus will the proton be when its velocity has dropped to 1/4vo
Answer:
The value is [tex]R_f = \frac{4}{5} R[/tex]
Explanation:
From the question we are told that
The initial velocity of the proton is [tex]v_o[/tex]
At a distance R from the nucleus the velocity is [tex]v_1 = \frac{1}{2} v_o[/tex]
The velocity considered is [tex]v_2 = \frac{1}{4} v_o[/tex]
Generally considering from initial position to a position of distance R from the nucleus
Generally from the law of energy conservation we have that
[tex]\Delta K = \Delta P[/tex]
Here [tex]\Delta K[/tex] is the change in kinetic energy from initial position to a position of distance R from the nucleus , this is mathematically represented as
[tex]\Delta K = K__{R}} - K_i[/tex]
=> [tex]\Delta K = \frac{1}{2} * m * v_1^2 - \frac{1}{2} * m * v_o^2[/tex]
=> [tex]\Delta K = \frac{1}{2} * m * (\frac{1}{2} * v_o )^2 - \frac{1}{2} * m * v_o^2[/tex]
=> [tex]\Delta K = \frac{1}{2} * m * \frac{1}{4} * v_o ^2 - \frac{1}{2} * m * v_o^2[/tex]
And [tex]\Delta P[/tex] is the change in electric potential energy from initial position to a position of distance R from the nucleus , this is mathematically represented as
[tex]\Delta P = P_f - P_i[/tex]
Here [tex]P_i[/tex] is zero because the electric potential energy at the initial stage is zero so
[tex]\Delta P = k * \frac{q_1 * q_2 }{R} - 0[/tex]
So
[tex]\frac{1}{2} * m * \frac{1}{4} * v_o ^2 - \frac{1}{2} * m * v_o^2 = k * \frac{q_1 * q_2 }{R} - 0[/tex]
=> [tex]\frac{1}{2} * m *v_0^2 [ \frac{1}{4} -1 ] = k * \frac{q_1 * q_2 }{R}[/tex]
=> [tex]- \frac{3}{8} * m *v_0^2 = k * \frac{q_1 * q_2 }{R} ---(1 )[/tex]
Generally considering from initial position to a position of distance [tex]R_f[/tex] from the nucleus
Here [tex]R_f[/tex] represented the distance of the proton from the nucleus where the velocity is [tex]\frac{1}{4} v_o[/tex]
Generally from the law of energy conservation we have that
[tex]\Delta K_f = \Delta P_f[/tex]
Here [tex]\Delta K[/tex] is the change in kinetic energy from initial position to a position of distance R from the nucleus , this is mathematically represented as
[tex]\Delta K_f = K_f - K_i[/tex]
=> [tex]\Delta K_f = \frac{1}{2} * m * v_2^2 - \frac{1}{2} * m * v_o^2[/tex]
=> [tex]\Delta K_f = \frac{1}{2} * m * (\frac{1}{4} * v_o )^2 - \frac{1}{2} * m * v_o^2[/tex]
=> [tex]\Delta K_f = \frac{1}{2} * m * \frac{1}{16} * v_o ^2 - \frac{1}{2} * m * v_o^2[/tex]
And [tex]\Delta P[/tex] is the change in electric potential energy from initial position to a position of distance [tex]R_f[/tex] from the nucleus , this is mathematically represented as
[tex]\Delta P_f = P_f - P_i[/tex]
Here [tex]P_i[/tex] is zero because the electric potential energy at the initial stage is zero so
[tex]\Delta P_f = k * \frac{q_1 * q_2 }{R_f } - 0[/tex]
So
[tex]\frac{1}{2} * m * \frac{1}{8} * v_o ^2 - \frac{1}{2} * m * v_o^2 = k * \frac{q_1 * q_2 }{R_f }[/tex]
=> [tex]\frac{1}{2} * m *v_o^2 [-\frac{15}{16} ] = k * \frac{q_1 * q_2 }{R_f }[/tex]
=> [tex]- \frac{15}{32} * m *v_o^2 = k * \frac{q_1 * q_2 }{R_f } ---(2)[/tex]
Divide equation 2 by equation 1
[tex]\frac{- \frac{15}{32} * m *v_o^2 }{- \frac{3}{8} * m *v_0^2 } } = \frac{k * \frac{q_1 * q_2 }{R_f } }{k * \frac{q_1 * q_2 }{R } }}[/tex]
=> [tex]-\frac{15}{32 } * -\frac{8}{3} = \frac{R}{R_f}[/tex]
=> [tex]\frac{5}{4} = \frac{R}{R_f}[/tex]
=> [tex]R_f = \frac{4}{5} R[/tex]
10 POINTS BE FAST
Which statement illustrates how progress in engineering has affected the
natural environment?(please hurry)
A. Modern mining practices provide materials that can be used for
technological advances.
B. Modern mining equipment has improved
the health and safety of
workers.
C. Extracting mineral resources
with modern mining equipment
removes fertile topsoil.
D. Mining companies use modern equipment to extract mineral
resources more efficiently.
hurry please
Answer:
I think it's c or A hopes this help
A rugby players runs 10.0 m straight down the playing field in 2.00 s. The player is then hit and pushed 5.00 m straight backward in 1.50 s. The player breaks the tackle and runs straight forward another 17.2 m in 4.10 s. Calculate the velocity for the players entire motion.
Answer:
2.92 m/s
Explanation:
For the entire motion, the average velocity (V) can be calculated thus;
V = [tex]\frac{displacement}{time}[/tex]
Total displacement of the player = 10.0 + (-5) + 17.2
= 22.2 m
Total time = 2.00 + 1.50 + 4.10
= 7.60 s
V = 22.2/7.60
= 2.92 m/s
Hence, the velocity of the players for the entire motion is 2.92 m/s.
When using an open flame or hot plate,
which of the following should be used
as a safety precaution to avoid burns?
A. test tube
B. beaker
C. hot pad or mit
D. safety goggles
A force of 250 N is applied to a hydraulic jack piston that is 0.02 m in diameter. If the piston that supports the load has a diameter of 0.15 m, approximately how much mass can be lifted by the jack
Answer:
1400.38N
Explanation:
Step one
Given data
P1= 250N
D1= 0.02m
A1= πD1^2/4
substitute
[tex]A1= 3.142*0.02^2/4\\\\A1=3.142*10^-4[/tex]
D2= 0.15m
A1= πD2^2/4
[tex]A2= 3.142*0.15^2/4\\\\A2=1.76*10^-3[/tex]
Required
The load P2
Step two:
Applying the hydraulic expression for a non-compressible fluid
we know that
Pressure= force/are
P1/A1=P2/A2
[tex]250/3.142*10^-4= P2/1.76*10^-3[/tex]
cross multiply we have
P2= 1.76*10^-3*250/3.142*10^-4
P2=0.44/3.142*10^-4
P2=1400.38N
A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.9 rad/s in 3.10 s. (a) Find the magnitude of the angular acceleration of the wheel.
Answer:
The value is [tex]\alpha = 3.84 \ rad/s^2[/tex]
Explanation:
From the question we are told that
The constant angular speed is [tex]w = 11.9 \ rad/s[/tex]
The time taken is [tex]t = 3.10 \ s[/tex]
Generally the magnitude of the angular acceleration is mathematically represented as
[tex]\alpha = \frac{w}{t}[/tex]
=> [tex]\alpha = \frac{11.9}{ 3.10 }[/tex]
=> [tex]\alpha = 3.84 \ rad/s^2[/tex]
A runaway train car that has a mass of 15,000 kg travels at a speed of 5.4 m/s down a track. Compute the time required for a force of 1500 N to bring the car to rest.
The 1500 N force would need to act in the direction opposite the train car's movement, so if we take the current direction it's moving in to be positive, we have by Newton's second law
-1500 N = (15,000 kg) a → a = -0.10 m/s²
If t is the time it takes for the train to come to rest, then
-0.10 m/s² = (0 - 5.4 m/s) / t
t = (5.4 m/s) / (0.10 m/s²) → t = 54 s
calculate the number of molecules of hydrogen and carbon present in 4 g of methane
Answer:
Answer = 6.022×10²³ molecules of CH4 which consists of 1 mole of C atoms and 4 moles of H atoms.
A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds of its travel. What is
its average speed during the time from t 5 seconds to t - 10 seconds?
A. 2 meters/second
В. 3 meters/second
С. 4 meters/second
D. 5 meters/second
E. 6 meters/second
In order for convection to transfer heat, particles need to
Select one:
a.
absorb solar and fossil energy
b.
circulate and move within a liquid or gas
c.
make contact with the heat source
d.
transmit electromagnetic waves
Answer:
the answer is b mark me as the brqinlist
Which of the following is the best example of Newton’s third law? A. A person riding a bike at a constant speed B. A car accelerating C. Rowing a boat D. An orange rolling off a tray
Answer:
C; Rowing a boat
Explanation:
Hope this helps! :3
Plz mark as brainliest!
Determine the wavelength of a wave with a frequency of 100hz and a velocity of 5m/s.
We are given:
Frequency of the wave = 100 Hz
Velocity of the wave = 5 m/s
Finding the Wavelength:
We know the relation between the wavelength and frequency is:
u = νλ [where ν is the frequency, u is the speed and λ is the wavelength]
5 = 100*(λ)
λ = 5/100 [dividing both sides by 100]
λ = 1/20
λ = 0.05 m
Hence, the wavelength is 0.05 m
A 0.3 g mosquito is flying toward a girl with a speed of 4.5 mph. Just before landing on the girl, the fly is swatted straight back at a speed of 12 mph. If the fly swatter and the fly were in contact for 0.2 s, what is the force that was exerted on the fly
Answer:
1.1x10^-2N
Explanation:
We have the change in momentum as
P = 0.3(4.5+12)g.mph
= 0.3x0.447x(4.5+12)x10^-3
Then the force that is exerted will be
F = p/∆t
∆t = 0.2
= 0.3x0.447x(4.5+12)x10^-3/0.2
= 0.1341x16.5x10^-3/0.2
= 1.1x10^-2
Therefore the force that was exerted is equal to 1.1x10^-2
The required magnitude of the force exerted on the fly is of [tex]5.025 \times 10^{-3} \;\rm N[/tex].
Given data:
The mass of mosquito is, [tex]m =0.3 \;\rm g =3 \times 10^{-4} \;\rm kg[/tex]
The speed of flying is, u = 4.5 mph = 4.5 ( 0.447) = 2.01 m/s.
The swatting speed of mosquito is, v = 12 mph = 12 (0.447 ) = 5.36 m/s.
The time of contact is, t = 0.2 s.
In this problem, we will first calculate the change in momentum, and the change in momentum is given as,
p = m ( v - u)
Solving as,
[tex]p = 3 \times 10^{-4} (5.36 - 2.01)\\\\p = 1.005 \times 10^{-3} \;\rm kg.m/s[/tex]
Now as per the Newton's second law,
[tex]F = p/t\\\\F = 1.005 \times 10^{-3} / 0.2\\\\F= 5.025 \times 10^{-3} \;\rm N[/tex]
Thus, the required magnitude of the force exerted on the fly is of [tex]5.025 \times 10^{-3} \;\rm N[/tex].
Learn more about the Newton's second law here:
https://brainly.com/question/19860811