it takes 32 pounds of seed to completely plant a 5 -acre field. How many acres can be planted per pound of seed?

Answer:

60 because their a 2 induivedinal in 1 sock.

Step-by-step explanation:

30 x 2 = 60

The distance and bearing of the boat from its original location are about 183.33 miles, N71.97°E

A bearing is a description of the amount by which a north or south headed line is deflected in the eastern or western direction.

The initial direction in which the boat is traveling = Due east

The distance the boat travels in the direction due east = 130 miles

The distance the boat travels in the direction N38°E = 72 miles

Therefore;

The distance the boat has traveled from its original location is found using the law of cosines as follows;

The included angle between the 130 miles distance the boat travels east and the 72 miles distance the boat travels N38°E = 90° + 38° = 128°

Let d represent the distance of the boat from its original location, we get;

d² = 130² + 72² - 2 × 130 × 72 × cos(128°) ≈ 33609.1828181

d ≈ √(33609.1828181) ≈ 183.33

The distance of the boat from its original location is about 183.33 miles

Let the angle formed by the direction of the boat to its destination and the path the boat travels east, according to the law of sines, we get;

183.33/(sin(128°) ≈ 72/(sin(B))

(sin(B)) ≈ 72 × (sin(128°))/183.33

m∠B ≈ arcsin(72 × (sin(128°))/183.33) ≈ 18.03°

The bearing of the boat from its original location is; N(90° - 18.03°)E = N71.97°E

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Answer:

52 bags and 2 extra

Step-by-step explanation:

Simply divide the no. of rolls by no. of rolls per bag

Answer:

12 bags

Step-by-step explanation:

158 rolls ÷ 13 rolls/bag = 12.15 bags

You will have 12 full bags plus about 2 extra rolls left over, which you can try to sell separately or as a "pack" of 2.  Or, you can sell one overstuffed bag with 2 extra rolls in it (for a total of 15 rolls) for a little extra on the price.

Answer:

cant answer sorry i didnt realize it was an equation

Step-by-step explanation:

The general two steps to solve the two-step equations are:

Step 1: Addition and subtraction to isolate the variable.

Step 2: Multiplication or division to determine the value of the variable.

Now, According to the question:

Solving Two Step Equations:

Two step equations are very easy to solve. It includes just one extra step as compared to one-step equations to solve. We can solve a two-step equation by isolating the variable (usually represented by an alphabet or letter) on one side of the equation and all other values on the other side. The general two steps to solve the two-step equations are:

Step 1: Addition and subtraction to isolate the variable.

Step 2: Multiplication or division to determine the value of the variable.

Generally, two step equations are of the form ax + b = c, where a, b, c are real numbers. A few examples of two step equations are:

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The inequality to discover the values of x for which the rectangle's perimeter is under 112 is x<  26.

An inequality in mathematics is a relationship between two expressions or values that is not equal. Thus, imbalance leads to inequality. An inequality creates the link between two values that are not equal in mathematics. Egality is distinct from inequality. When two values are not equal, most commonly use the not equal symbol (). Different inequalities are used to contrast values, no matter how small or large. Many simple inequalities can be resolved by modifying the two sides until the variables are all that remain. But a number of things contribute to inequality: Negative values on both sides are divided or added. Trade off the left and right.

given

perimeter of a rectangle = length + length + width + width

length + length + width + width = perimeter of a rectangle

(x +4) + (x+4) + x + x < 112

x + 4 + x + 4 + x + x < 112

4x + 8 < 112

4x < 104

x < 26

So ,The inequality to discover the values of x for which the rectangle's perimeter is under 112 is x<  26.

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The radius of a sphere whose surface area is  324*pi cm² is:

R = 9 cm.

We know that the surface of a sphere of radius R is given by:

S = 4*pi*R^2

Where pi = 3.14

Here we know that a sphere has a surface of 324*pi cm², then we can write the equation:

S =  324*pi cm² = 4*pi*R^2

We can divide both sides by pi, so we get:

324 cm^2 = 4*R^2

Now we can solve that equation for R, we will get:

R^2=  (324 cm^2)/4 = 81cm^2

R = √(81 cm^2)

R = 9cm

The radius of the sphere is 9cm.

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Answer:

18b^6

Step-by-step explanation:

3b⁴ x 6b²

After solving the algebraic equation, Miguel has 4 quarters, 12 dimes and 16 nickels.

What is algebra?

One of the earliest areas of mathematics that deals with number theory, geometry, and analysis is algebra. Algebra is also defined as the study of mathematical rules and symbols through the manipulation of those mathematical symbols.

The number of quarters is taken to be x, then the number of dimes will be 3x, and the number of nickels will be 3x + x = 4x

$3.00 when converted to cents is 300 cents.

The value of nickels is 5 x 4x=20x.

The value of dimes is 10 x 3x=30x.

The value of quarters is 25x.

As the total value of money Miguel has is 300 cents, then the algebraic equation will be -

20x + 30x + 25x = 300

Solve to get the value of x -

75x = 300

x = 4

Therefore, the amount of quarters is x = 4 quarters.

The amount of dimes is x = 3x = 3 x 4 = 12 dimes.

The amount of nickels is 4x = 4 x 4 = 16 nickels.

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A solution set is the set of all variables or numbers that makes the equation true.

If solving a linear equation leads to a true statement is equal to 0 = 0 the equation is an identity. Its solution set is all real numbers.A solution set is the set of values that satisfy a given set of equations or inequalities. The feasible region of a constrained optimization problem is the solution set of the constraints.

There are three possibilities for the number of real solutions of a quadratic equation, and those are that a quadratic equation can have no real solutions, exactly one real solution, or exactly two real solutions.Zero is considered to be both a real and an imaginary number.

Now we can find solution set by solving the equation.

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Answer: $120

Step-by-step explanation:

So you find 1/3 of 180, basically, you multiply them which is 60.

So if he has a third of the money, he has $60, but he needs 180. So we subtract $180 (how much money he needs) from $60 (the money he has). Which is 120 dollars, so the boy needs $120.

Or 2/3 more.

The completed blanks in the statement are underlined as follows

From the question, we have the following parameters that can be used in our computation:

A mathematical expression

The mathematical expression is given as

2x⁴ + 53x⁵ - 2 + x⁶

The standard form

To do this, we rearrange the expression from the highest power to the least

So, we have the following representation

x⁶ + 53x⁵ + 2x⁴  - 2

The degree

This is the highest power in the expression

So, the degree is 6

The leading coefficient

This is the coefficient of the term that has highest power of x

So, the leading coefficient is 1

The name of the expression

The expression has 4 terms

So, the name is a polynomial

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The coefficient of x² in 2 x² x³ is 2 n with number.

2 x² x³

= 2 x² (x³)

= 2 x² (x  x  x)

= 2 x² x  x  x

The coefficient of x² is 2.The expression 2 x² x³ can be written as 2 x² (x³). This can be further simplified to 2 x² (x  x  x). The coefficient of x² is 2, which means that the coefficient of x² in 2 x² x³ is 2. The coefficient of a term is the numerical factor of the term, or the number that is multiplied with the term. In this case, the coefficient of x² is 2, as it is the number multiplied with x².

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The domain and range of the logarithmic function is given by:

Domain= [ 0 , ∞ ) and Range = { y ∈ R }.

As given in the question,

Let y = logₐ x be the given logarithmic function.

Logarithmic function is defined for all the positive values.

Domain of the logarithmic function is given by x∈ R , x > 0.

Range of the logarithmic function is inverse of the domain of the exponential function.

x = e^y

Here y is set of all the real numbers.

Range of logarithmic function is set of all the real numbers.

Therefore, domain of the logarithmic function is set of all real number greater than zero and range of the logarithmic function is the set of all the real numbers.

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Answer:128 cm^2

Step-by-step explanation:

35% in each package is red.

that means nothing else than for every M&M you pick, the probability is 35% (or 0.35) that is is red.

it also means the probability to get anything but red is 1 - 0.35 = 0.65 (65%).

if I understand you correctly, the question is for the probability that there are no more than 18 red M&Ms in a package of 52.

in other words, the probabilty that there are exactly 18, or exactly 17, or exactly 16 ... or exactly 1, or no red M&Ms.

the probability to get exactly 18 red out of 52 is

0.35¹⁸ × 0.65³⁴

for one of the combinations.

and we have C(52, 18) possible combinations :

52! / (18! × (52-18)!) = 52! / (18! × 34!)

18 red = 0.35¹⁸ × 0.65³⁴ × C(52, 18) = 0.115457378...

17 red = 0.35¹⁷ × 0.65³⁵ × C(52, 17) = 0.110273578...

16 red = 0.35¹⁶ × 0.65³⁶ × C(52, 16) = 0.096708177...

15 red = 0.35¹⁵ × 0.65³⁷ × C(52, 15) = 0.077665254...

14 red = 0.35¹⁴ × 0.65³⁸ × C(52, 14) = 0.056935055...

13 red = 0.35¹³ × 0.65³⁹ × C(52, 13) = 0.037956703...

12 red = 0.35¹² × 0.65⁴⁰ × C(52, 12) = 0.022909582...

11 red = 0.35¹¹ × 0.65⁴¹ × C(52, 11) = 0.012452595...

10 red = 0.35¹⁰ × 0.65⁴² × C(52, 10) = 0.006056874...

9 red = 0.35⁹ × 0.65⁴³ × C(52, 9) = 0.002615926...

8 red = 0.35⁸ × 0.65⁴⁴ × C(52, 8) = 0.000993712...

7 red = 0.35⁷ × 0.65⁴⁵ × C(52, 7) = 0.000328083..

6 red = 0.35⁶ × 0.65⁴⁶ × C(52, 6) = 9.271902896e-005

5 red = 0.35⁵ × 0.65⁴⁷ × C(52, 5) = 2.198201902e-005

4 red = 0.35⁴ × 0.65⁴⁸ × C(52, 4) = 4.252473918e-006

3 red = 0.35³ × 0.65⁴⁹ × C(52, 3) = 6.446899235e-007

2 red = 0.35² × 0.65⁵⁰ × C(52, 2) = 7.183687719e-008

1 red = 0.35 × 0.65⁵¹ × C (52, 1) = 5.231817386e-009

0 red = 0.35⁰ × 0.65⁵² × C(52, 0) =

= 0.65⁵² = 1.868506209e-010

the probability to have no more than 18 reds is the sum of all that :

0.540472593...

Answer:

-33

Step-by-step explanation:

Plug 9 in for c, then simplify the resulting expression.

5c - 9c + 3

5(9) - 9(9) + 3

↓ execute multiplication

45 - 81 + 3

↓ simplify by adding 81 and 3

45 - 84

↓ execute subtraction

-33

Answer:

[tex] \sf \: - 33 \: (if \: c = 9)[/tex]

Step-by-step explanation:

Given expression,

→ 5c - 9c + 3

Now we have to use,

→ c = 9

Simplifying the given expression,

→ 5c - 9c + 3

→ 5(9) - 9(9) + 3

→ 45 - 81 + 3

→ -36 + 3

→ -33 => (answer)

Hence, required answer is -33.

The evaluation of the expression 2(b + 4) when b = 4 is 18

From the question, we have the following parameters that can be used in our computation:

Expression: 2(b + 4)

Values: b = 5

Substitute the known values in the above equation, so, we have the following representation

2(b + 4) = 2 * (5 + 4)

Evaluate the products

This gives

2(b + 4) = 10 + 8

Evaluate the like terms in the equation

So, we have the following representation

2(b + 4) = 18

Using the above as a guide, we have the following:

The solution is 18

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1)correct option is b) true

2)Which of the following expressions always evaluates to true?

 correct option is d)(x > 0) && (x == 0)

given that

An expression, often known as a mathematical expression, is a finite collection of symbols that are well-formed in accordance with context-dependent principles. Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Many authors make a distinction between an expression and a formula, with the former designating a mathematical object and the latter a claim about such objects.

x = 5 and y = 7

Choose the value of the following expression: (x != 7) && (x <= y)

a. false

b. true

c. 0

d. null

(5! = 7) && (5<=7)

5 ≠ 7

correct option is b) true

Suppose that x is an int variable.

Which of the following expressions always evaluates to true?

a. (x > 0) || ( x <= 0)

b. (x > 0) && ( x <= 0)

c. (x >= 0) 11 (x == 0)

d. (x > 0) && (x == 0)

a) x = 1,2,3.... || x =0,-1,-2,-3......

b)x = 1,2,3.... && x = 0,-1,-2,-3,.....

c) x = 0,1,2,3..... 11 x = 0

d) x = 1,2,3.... && x = 0

correct option is d)(x > 0) && (x == 0)

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Answer:

It appears that the solution set of the inequality 5n + 1.5 ≥ 4 is the set of all real numbers greater than or equal to -0.3. This can be determined by looking at the graph and noting that the region to the right of the vertical line x = -0.3 is shaded, which indicates that all values of x in that region are included in the solution set.

To verify this, we can substitute -0.3 into the inequality in place of n to see if the inequality is satisfied:

5(-0.3) + 1.5 ≥ 4

This simplifies to:

-1.5 + 1.5 ≥ 4

Which further simplifies to:

0 ≥ 4

Since this is not true, -0.3 is not a solution of the inequality. However, all values of x that are greater than or equal to -0.3 are solutions, as indicated by the shaded region on the graph.

Step-by-step explanation:

Answer:

C. 2%

Step-by-step explanation:

(6500-5000) / 15 / 5000 x 100% = 1500 / 15 / 5000 x 100% = 100 / 5000 x 100% = 0.02 x 100% = 2%

to get the equation of any straight line, we simply need two points off of it, let's use those from the picture below.

[tex](\stackrel{x_1}{-10}~,~\stackrel{y_1}{-100})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{140}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{140}-\stackrel{y1}{(-100)}}}{\underset{\textit{\large run}} {\underset{x_2}{30}-\underset{x_1}{(-10)}}} \implies \cfrac{140 +100}{30 +10} \implies \cfrac{ 240 }{ 40 } \implies 6[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-100)}=\stackrel{m}{ 6}(x-\stackrel{x_1}{(-10)}) \\\\\\ y +100 = 6 ( x +10)\implies y+100=6x+60\implies {\Large \begin{array}{llll} y=6x-40 \end{array}}[/tex]

The function that describes the depth of the soil is h(x) = -(1/2)x + 8.

Where x is the number of bags of soil.

A function is a relationship between inputs where each input is related to exactly one output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

Depth of the soil = 8 inches

One bag of soil increases by 1/2 of an inch.

Now,

The function denotes the depth of the soil.

h(x) = -(1/2)x + 8

Where x is the number of bags of soil

Thus,

The function is h(x) = -(1/2)x + 8.

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FG stands for Function Generator, which is a device that produces electrical signals with a function of frequencies and amplitudes. It is commonly used in scientific laboratories to generate signals for testing and research purposes.

A function generator is an electrical device used to generate electrical signals with a range of frequencies and amplitudes. It is commonly used in scientific laboratories to generate test signals for testing and research purposes. Function generators typically consist of an oscillator, amplifier, and waveform selector. The oscillator generates a signal of a given frequency and amplitude, while the amplifier adjusts the output voltage. The waveform selector allows the user to choose from a variety of waveforms, such as sine, square, triangle, and sawtooth. Function generators can be used to simulate various types of electrical signals, such as AC and DC signals, as well as a variety of noise signals. They are also used to test various types of electronic components, such as transistors and capacitors, and to conduct research in fields such as telecommunications and signal processing. The acronym FG stands for Function Generator.

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[tex]sin(A)+cos(A)=\sqrt{2}\hspace{10em}tan(A)+cot(A)=2 \\\\[-0.35em] ~\dotfill\\\\ tan(A)+cot(A)=2\implies \cfrac{sin(A)}{cos(A)}+\cfrac{cos(A)}{sin(A)}=2 \\\\\\ \cfrac{sin^2(A)+cos^2(A)}{cos(A)sin(A)}=2\implies \boxed{\cfrac{1}{cos(A)sin(A)}=2} \\\\[-0.35em] ~\dotfill[/tex]

[tex]sin(A)+cos(A)=\sqrt{2}\implies (~~sin(A)+cos(A)~~)^2=(\sqrt{2})^2 \\\\\\ sin^2(A)+2sin(A)cos(A)+cos^2(A)=2 \\\\\\ 2sin(A)cos(A)+sin^2(A)+cos^2(A)=2\implies 2sin(A)+1=2 \\\\\\ 2sin(A)cos(A)=1\implies \boxed{2=\cfrac{1}{cos(A)sin(A)}}[/tex]

now, another way to look at this identity will  be as a unified system of equations

[tex]\begin{cases} (~~sin(A)+cos(A)~~)^2=2\\\\ ~~ ~tan(A)+cot(A)=2 \end{cases}\implies (~~sin(A)+cos(A)~~)^2=tan(A)+cot(A)[/tex]

and we'd end up with the same rigamarole.

Answer: For all three functions, the direction of fastest increase at the point (1, 1, 1) is the direction of the gradient vector of the function at that point.

For function (a), the gradient vector at (1, 1, 1) is given by the partial derivatives of the function at that point:

[2/x³, 2y, 22] = [2, 2, 22].

The direction of this gradient vector is given by the direction in which each of its components is increasing the most rapidly. In this case, all three components are increasing at the same rate, so the gradient vector points in the direction of the positive x, y, and z axes.

For function (b), the gradient vector at (1, 1, 1) is given by the partial derivatives of the function at that point:

[4y + 4z, 4x + 4z, 4x + 4y] = [4, 4, 4].

Again, all three components are increasing at the same rate, so the gradient vector points in the direction of the positive x, y, and z axes.

For function (c), the gradient vector at (1, 1, 1) is given by the partial derivatives of the function at that point:

[2x, 2y, 2z] = [2, 2, 2].

As before, all three components are increasing at the same rate, so the gradient vector points in the direction of the positive x, y, and z axes.

Therefore, for all three functions, the direction of fastest increase at (1, 1, 1) is the direction of the positive x, y, and z axes.

Step-by-step explanation:

Answer:

Use the following denomination (Ghana cedis 200,100,50 and 20)to find the quantities of notes

1.3584655000

2.85760000

3.146737000

4.5555627000

5.7777000

please help

Step-by-step explanation:

1. Eliminate any constant that is on the same side as the variable.

2. Use inverse operations to isolate the variable by itself.

3. Whatever you do to one side you do to the other.

Answer:

Step-by-step explanation:

To find the number Katherine should multiply the prices on the tags by to find the price she would have to pay before tax, we need to calculate the inverse of the discount percentage, which is 1 - (discount percentage / 100).

Given that the discount is 3% and we want to find the price after the discount, that means:

1 - (3/100) = 1 - 0.03 = 0.97

So, the number Katherine should multiply the prices on the tags by to find the price she would have to pay, before tax, in one step, is 0.97. Multiplying the price of an item by 0.97 is equivalent to subtracting 3% from the original price, which is the same as finding the final price after the discount.

For example, if an item is priced at $10, Katherine can multiply this by 0.97 to find that the final price she would have to pay before tax is $9.7

10*0.97 = 9.7

solution of the linear equation is x = (2a - 16)/ 3 and y = - (a+16)/ 9

An algebraic expression that shows a relationship between two variables   that have only first order term. One of the main criteria for linear equation is that we get a straight line when plot this equation in a coordinate system.

.

we are given, two linear equations x - a -3y = 0

and a - 2x -3y - 16 =0

from the first equation, x = a + 3y

we put the value of x in the second equation, a - 2(a +3y) - 3y -16= 0

                                                                     a - 2a - 6y - 3y -16 = 0

                                                          - a - 9y -16 =0

                                                   - (a + 16) = 9y

                                              y = - (a+16) / 9

now we put the value of y in the equation, x = a + 3y

                                    get, x = a+ 3 [ - (a+16)] / 9

                                      x = a + [ - (a+16)] / 3

                                          x = (3a - a -16) / 3

                              x = (2a - 16)/ 3

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You ran 1/8 of miles more today than yesterday.

Subtraction can be done for any numbers or algebraic expressions. It is the process of taking out certain value from a given amount of number.

Miles you ran yesterday is three fourths of a mile.

Let 1 mile be M.

Miles you ran yesterday = 3/4 M

Today you ran seven-eighths of a mile.

Miles you ran today = 7/8 M

Difference of miles = 7/8 M - 3/4 M

3/4 is same as 6/8.

Difference of miles = 7/8 M - 6/8M

                                = 1/8 M

Hence you ran 1/8 of miles more than yesterday.

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