Answer:
1.7ft
Step-by-step explanation:
Given data
Volume of tank= 300π 〖ft〗^3
Height of tank= 10ft
The expression for the volume of a cylinder is given as
Volume= πr^2h
Substitute
300π = π *r^2*10
300= r^2*100
3= r^2
r= √3
r= 1.7 ft
Hence the radius of the cylinder is 1.7ft
A² + b² = 7b and b² + (2b-a)² = 7² find (a - b)².
Answer:
(a - b)^2 = 49 - 4b^2 +2ab
Step-by-step explanation:
Given: a^2 + b^2 = 7b (assuming A is really “a”)
b^2 + (2b - a)^2 = 7^2
Find; (a - b)^2
Plan: Use Algebraic Manipulation
Start with b^2 + (2b - a)^2 = 7^2 =>
b^2 + 4b^2 - 4ab + a^2 = 49 by expanding the binomial.
a^2 + b^2 + 4b^2 - 4ab = 49 rearranging terms
a^2 + b^2 -2ab - 2ab + 4b^2 = 49 =>
a^2 - 2ab + b^2 = 49 - 4b^2 +2ab rearranging and subtracting 4b^2 and adding 2ab to both sides of the equation and by factoring a^2 - 2ab + b^2
(a - b)^2 = 49 - 4b^2 +2ab
Double Check: recalculated ✅ ✅
(a - b)^2 = 49 - 4b^2 +2ab
Help find x and angle BEC
Answer:
x = 32 and BEC = 43
Step-by-step explanation:
3X + 41 = 137
3X = 96
X = 32
FOR BEC:
137 + 137 = 274
360-274=86 ( ANGLES AROUND A POINT ADD UP TO 360)
86/2 = 43
BEC/AED = 43 ( VERTICALLY OPPOSITE ANGLES ARE EQUAL)
hope this helps good luck!
Find the area of the trapezoid. Leave your answer in simplest radical form.
Answer:
[tex]Area = 52\sqrt3 \ ft^2[/tex]
Step-by-step explanation:
Area of trapezoid
[tex](\frac{a+ b}{2}) \times h[/tex] -----------( 1 )
We will split the trapezoid into Triangle and rectangle. To find the height and full length of base.
[tex]sin 60 = \frac{opposite}{hypotenuse}[/tex] [tex][ opposite \ in \ the \ equation \ \ is \ the \ height \ of \ the \ trapezoid ][/tex]
[tex]\frac{\sqrt3}{2} = \frac{opposite }{ 8}\\\\\frac{\sqrt3}{2} \times 8 = opposite\\\\4\sqrt3 = opposite[/tex]
Therefore, h = 4√3 ft
[tex]cos 60 = \frac{adjacent}{hypotenuse}[/tex] [tex]adjacent \ in \ the\ equation \ is \ the\ base \ of \ the \ triangle ][/tex]
[tex]\frac{1}{2} = \frac{adjacent}{hypotenuse}\\\\\frac{1}{2} \times 8 = adjacent\\\\4 = adjacent[/tex]
Therefore, a = 11 feet, b = 11 + 4 = 15 feet
Substitute the values in the Area equation :
[tex]Area = \frac{11 + 15}{2} \times 4 \sqrt3 = \frac{26}{2} \times 4\sqrt3 = 13 \times 4\sqrt3=52\sqrt3 \ ft^2[/tex]
the equation cos(x)( cos(x)-tan(x)sin(x)) simplifies to
The probability that Andrew has heart disease The two events are independent, so you need to find
the product of their probabilities: 0.9 x 0.75 = 0.675. Enter the
correct answer The probability that Andrew has heart disease
Answer:
correct bayan HAHAHAHAHAHA
use these functions a(x) =4x +9 and b(x) =3x -5 to complete the function operations listed below
Consider that we need to find [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].
Given:
The functions are:
[tex]a(x)=4x+9[/tex]
[tex]b(x)=3x-5[/tex]
To find:
The function operations [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].
Solution:
We have,
[tex]a(x)=4x+9[/tex]
[tex]b(x)=3x-5[/tex]
Now,
[tex](a+b)(x)=a(x)+b(x)[/tex]
[tex](a+b)(x)=4x+9+3x-5[/tex]
[tex](a+b)(x)=7x+4[/tex]
Similarly,
[tex](a-b)(x)=a(x)-b(x)[/tex]
[tex](a-b)(x)=4x+9-(3x-5)[/tex]
[tex](a-b)(x)=4x+9-3x+5[/tex]
[tex](a-b)(x)=x+14[/tex]
And,
[tex](ab)(x)=a(x)b(x)[/tex]
[tex](ab)(x)=(4x+9)(3x-5)[/tex]
[tex](ab)(x)=12x^2-20x+27x-45[/tex]
[tex](ab)(x)=12x^2+7x-45[/tex]
And,
[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{a(x)}{b(x)}[/tex]
[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex]
Therefore, the required functions are [tex](a+b)(x)=7x+4[/tex], [tex](a-b)(x)=x+14[/tex], [tex](ab)(x)=12x^2+7x-45[/tex] and [tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex].
the taco truck sells tacos for $3 and burritos for $4. the number of items sold on a tuesday is 125 with a total income of $430. how many tacos were sold?
Answer:
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations:
3 T + 4 B =425
T + B = 125
Where T is the number of tacos sold, and B is the number of burritos sold.
Multiplying the second equation by 3, and subtracting it to the first equation:
3 T + 4 B =425
3T + 3B = 375
___________
B =50
Replacing B in any equation:
T + B = 125
T +50 =125
T =125-50
T = 75
Feel free to ask for more if needed or if you did not understand something.
Learning Activities
Solve the following problems. Choose
the letter of the correct answer
(Show your complete solutions)
1.) The sum of all the sides of a STOP sign is 104 inches. A STOP sign is an
with all sides equal. How many inches does each side measure?
B. 11 in
C. 13 in
D. 16 in
2.) In A ABC, LA and Beach measure 70% How many degrees are there in 202
A. 400
B. 50°
C. 60
D700
3.) The measures of the three angles of a quadrilateral are 49. 58, and 127. What
is the measure of the fourth angle?
A. 116
B. 126
C. 54
D. 64
A. 8 in
4.) Solve for the value of x in DEFG.
E
D
(x + 40)
130
A 400
B. 70°
C. 500
D. 90°
F
(2x-10)
G
5.) if the length of the two sides of an isosceles triangle are 3 cm and 7 cm, then
what must be the length of the third side?
Step-by-step explanation:
answers I the above photo
some of the questions are not clear
Answer:
1. C(13inches)
2. A(40°)
3. B(126°)
4. C(50°)
5. 7cm
Step-by-step explanation:
According To the Question,
1. Given, The sum of all the sides of a STOP sign is 104 inches. A STOP sign is Octagon with all sides equal.
Thus, Octagon has 8 equal side
So, Each Side Measure = 104/8 ⇔ 13inches
2. Given, In Triangle ABC, ∠A & ∠B each measure 70°
And, We Know Sum of all angles of a triangle is 180°.
Thus, ∠C = 180° - (∠A + ∠B) ⇔ 180°-140° ⇒ 40°
3. Given, The measures of the three angles of a quadrilateral are ∠A=49° ,∠B=58° & ∠C=127° .
And, We know sum of all angles of quadrilateral is 360°.
Thus, ∠D=360° - (∠A+∠B+∠C) ⇔ 360°-234° ⇒ 126°
4. Given, The measure of all the Four angles of a quadrilateral are ∠A=(x+40)°, ∠B=130°, ∠C=x° & ∠D=(2x-10)° .
And, We know sum of all the angles of quadrilateral is 360°.
Thus, ∠A+∠B+∠C+∠D = 360°
Put all the Values, we get
x+40+130+x+2x-10 = 360
4x+160 = 360
4x = 200 ⇔ 200/4 ⇒ 50°
5. Given, the length of the two sides of an isosceles triangle are 3cm and 7cm .
Now, in order to form a triangle the sum of any two side of a triangle is always greater than the third side of a triangle.
So, We have an isosceles triangle in which two sides is always equal & we have given two sides of 3cm & 7cm .
Assume, if third side be 3cm (First Side+Third side > Second side)
3+3 ⇒6cm which is not greater than 7cm(thus, the Triangle not possible if we assume 3cm as triangle's third side)
Hence, The other Side of Triangle Surely be 7 cm.
Ryder used front end estimation to estimate the product of -24.98 - 1.29 what is the zestimate
Answer:
20
Step-by-step explanation:
The numbers whose product are to be obtained :
(–24.98)(–1.29)
To use front end approximation, numbers are rounded to the greatest place value :
For :
(-24.98) is rounded to - 20 (4 is rounded here to 0)
(-1.29) is rounder to - 1 (2 is rounded to 0)
Then, the product of the two numbers will be :
-20 * - 1 = 20
In a bowl of fruit, there are green grapes and black grapes in the ratio 3:4 If there are 24 green grapes, how many black grapes are there?
answer is 32
ask me more questions any time
f(x) =-x²+16 and g(x) =x+4
f(x)/g(x) = (x2-16)/(x+4)
The domain is all real numbers except x = -4 (because the denominator is zero at x = -4 and division by zero is undefined.)
We can simplify by factoring the numerator:
(x2-16)/(x+4) = (x-4)(x+4)/(x+4) = (x-4)
The domain is the same as the original expression: all real numbers except x = -4
Segment Addition Postulate
Using the following image, solve for x.
Answer:
Here,
CD + DE = CD
x+10 + x+4 = 8
2x + 14 = 8
2x= -6
x= -3
Find missona value in the equation below
Answer:
[tex] \sqrt[5]{96x {}^{7} y {}^{11} } = 2xy {}^{2} \sqrt[5]{3x {}^{2}y } [/tex]
There are 75 students in classes A and B altogether. There are 61 students in classes A and C altogether. The ratio of the number of students in Class B to Class C is 5:3. How many students are there in Class A?
Answer:
40
Step-by-step explanation:
A + B=75
A + C = 61
B = 5/3 *C
A+C * 5/3 = 75 then we got the answer
Answer:
A = 40
Step-by-step explanation:
A+B = 75
A+C = 61
Subtract
A+B = 75
-A-C = -61
----------------------
B-C = 14
B:C
5:3
for every 5B there are 3C
Replace B with 5/3 C
5/3C-C = 14
2/3C = 14
C = 21
A+C = 61
A +21 = 61
A = 40
Determina la masa molar y el volumen que ocupa la siguiente sustancia CO2, si su masa es de 28 gr. *
Answer:
Para el CO₂ sabemos que:
densidad = 0,001976 g/cm³
Sabemos que:
densidad = masa/volumen
Entonces, si tenemos una masa de 28 g, podemos escribir:
volumen = masa/densidad
volumen = (28g)/(0,001976 g/cm³) = 14,170 cm^3
Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.
Carbono: tiene una masa molar de 12 g/mol
Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)
entonces la masa molar va a ser:
masa molar = 12g/mol + 2*16g/mol = 44 g/mol
Es decir, un mol de CO₂, pesa 44 gramos.
HURRY !!!!!! Which describes the correlation shown in the scatterplot?
Find the area of an equilateral triangle whose value is 18 cm
Answer:
[tex]18 + 18 + 18 = 18 \times 3 = 54[/tex]
Step-by-step explanation:
I ain't sure but it might help you out:D
Answer:
140.3 cm²
Step-by-step explanation:
area of an equilateral triangle
[tex] = \frac{\sqrt{3} }{4} {a}^{2} [/tex]
where a is the side of the triangle
[tex] = \frac{ \sqrt{3} }{4} \times {18}^{2} \\ = 140.3 \: cm {}^{2} [/tex]
help me pls due in 49 mins
Answer:
Step-by-step explanation:
cos(c)= x/ac
ac = cos32/9.4
ac =11.08
Answer:
Step-by-step explanation:
sin(58/9.4 = sin(90)/AC
AC= 11.08
Help me solve these 4 plssss ASAP
Step-by-step explanation:
[tex]1) \\ - 2 \leqslant x \leqslant 1 \\ 2) \\ - 3 > x \geqslant 2 \\ 3) \\ x> 0[/tex]
[tex]4) \\ x \leqslant - 3 \\ 5) \\ - 4 \leqslant x \geqslant 1[/tex]
[tex]6) \\ - 2< x \leqslant 0[/tex]
Pls answer both Pls pls
Answer:
bjkfkvdvdejij
Step-by-step explanation:
22333444 ijdcijsivjdivdvndk snciscicicnlvjavjadvj
Solve for y please and thank you
Answer:
c) y = 8[tex]\sqrt{3}[/tex]
Step-by-step explanation:
in a 30-60-90° Δ the ratio of the sides, respectively, is 1: [tex]\sqrt{3}[/tex] : 2
if the side opposite the 30°∡ is 8 then 'y' is 8[tex]\sqrt{3}[/tex] and 'x' is 16
Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.
r = 4 cos 5θ
Answer:
y-acis
Step-by-step explanation:
the function graph is symmetric about
- y-axis when it is an even function
-the origin ehen it is an even function
A symmetrical graph about the x-axis is not a function graph
f(×) is a even if and only if f(×) =f(×)
f(×) is a odd if and only f(×)=f(×)
We have the function r(0) = 4cos (50)
(only symmetry about the y-acis or about the origin)
Check r(-0)
r(-0) = 4cos (5-0) = 4cos (-50 = 4 cos (50)
Used cos (-× = cos ×
We have r(0). Therefore the graph of r(0) is symmectric about the y-axis.
solutia reala a ecuatiei 4x la a doua = 6 intregi si 1/4 (dau coroana)
Answer:
x = + 5/4 or x = - 5/4
Step-by-step explanation:
[tex]4 x^2 = 6\frac{1}{4}\\\\4 x^2 = \frac{25}{4}\\\\x^2 =\frac{25}{16}\\\\x = \pm \frac{5}{4}[/tex]
Find the quadratic equation whose parabola has vertex (3,-2) and y-intercept (0, 16). Give your
answer in vertex form.
Answer:
y = 2*(x - 3)^2 - 2
Step-by-step explanation:
Remember that a quadratic equation of vertex (h, k) is written as:
y = a*(x - h)^2 + k
Where a is the leading coefficient.
So, if we know that the vertex is at (3, - 2)
we have:
y = a*(x - 3)^2 + (-2)
And we want the y-intercept to be (0, 16)
This means that, when we take x = 0, we must have y = 16
if we replace these in the above equation we get:
16 = a*(0 - 3)^2 - 2
now we can solve this for a
16 = a*(-3)^2 - 2
16 = a*9 - 2
16 + 2 = a*9
18 = a*9
18/9 = a
2 = a
Then the quadratic equation is:
y = 2*(x - 3)^2 - 2
How many solutions exist for the system of equations in the graph?
Answer:
Two solutions
Step-by-step explanation:
The number of points of intersections represents the number of solutions to the system of equations. Since the parabola intersects the circle at two points, there are two solutions to the circle.
Furthermore, these two points of intersection are exactly the solutions to the system of equations. Finding the coordinates of the points of intersection will give you the solutions to the system of equations.
The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the spring stretches 9 centimeters. Which equation relates the mass of the object, m, and the length of the spring, s?
s = StartFraction 3 Over 10 EndFraction m
s = StartFraction 10 Over 3 EndFraction m
m = StartFraction 3 Over 10 EndFraction s
m = StartFraction 1 Over 30 EndFraction s
Answer:
it is b
Step-by-step explanation:
Answer:
it is b
Step-by-step explanation:
Hey, can anyone help me with this pls
Answer:
it's B
Step-by-step explanation:
I'm quite sure it is. Hope it helps u
10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.
Answer:
0.2992 = 29.92% probability of obtaining at least 8 failures.
Step-by-step explanation:
For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
A success is 5 or 6.
A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:
[tex]p = \frac{4}{6} = 0.6667[/tex]
10 normal six sided dice are thrown.
This means that [tex]n = 10[/tex]
Find the probability of obtaining at least 8 failures.
This is:
[tex]P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)[/tex]
So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951[/tex]
[tex]P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867[/tex]
[tex]P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174[/tex]
Then
[tex]P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992[/tex]
0.2992 = 29.92% probability of obtaining at least 8 failures.
if 1/a+1/b+1/c=1/a+b+c then prove that 1/a^9+1/b^9+1/c^9=1/a^9+1/b^9+1/c^9
Answer:
The given relation is presented as follows;
[tex]\dfrac{1}{a} + \dfrac{1}{b} +\dfrac{1}{c} = \dfrac{1}{a + b + c}[/tex]
Where 'a', 'b', and 'c' are member of real numbers, we have;
a⁹, b⁹, and c⁹ are also member of real numbers
When a⁹ = x, b⁹ = y, and c⁹ = z
By the above relationship, we have;
[tex]\dfrac{1}{x} + \dfrac{1}{y} +\dfrac{1}{z} = \dfrac{1}{x + y + z}[/tex]
Substituting x = a⁹, y = b⁹, and z = c⁹, we get;
[tex]\dfrac{1}{a^9} + \dfrac{1}{b^9} +\dfrac{1}{c^9} = \dfrac{1}{a^9 + b^9 + c^9}[/tex]
Step-by-step explanation:
Express as simply as possible with a rational denominator
7/√10
Answer:
7√10 / 10.
Step-by-step explanation:
7/√10
Multiply top and bottom by √10:
= 7√10 / 10