John is a quarterback. This year, he completed 350 passes, which is 70, percent of all the passes he's attempted this year.
How many passes has John attempted this year?

Answers

Answer 1

Answer:

John attempted 500 passes this year

Step-by-step explanation:

To sum up the question, it is basically asking what number has 350 as 70% of it.

We know that:

350 is 70% of some number.

Convert 70% to fraction:

70% = 7/10

Divide:

350 ÷ 7/10 = 500

So 350 is 70% of 500

CHECK THE ANSWER:

10% of 500 is 50

To find 70% of 500, multiply:

50 x 7 = 350

I really hope this helps! Please ask me in case you’re confused.


Related Questions

The ice cream man just ended his shift for the day. Let 1/2x^2 6/11x + 8 represent the amount of chocolate ice cream bars he sold. Let 5/9x^2 + 2/3 represent the amount of vanilla ice cream bars he sold. Finally let 1/3x^2 + 4x + 4/3 represent the amount of strawberry ice cream bars he sold. Select all the statements that are true

a. The total amount of ice cream bars sold can be represented by the expression 25/18x^2+ 50/11x +10
b. The total amount of ice cream bars sold can be represented by the expression 25/18x^2 + 172/33x +28/3
c. He sold 1/6x^2 + 50/11x + 28/3 more chocolate than strawberry ice cream bars.
d. He sold 1/6x^2 - 38/11x + 20/3 more chocolate than strawberry ice cream bars.

Answers

Answer:

A and D

Step-by-step explanation:

Total ice cream bars sold = sum of chocolate sold , vanilla and strawberry ice-creams sold.

=(1/2)x2 + (6/11)x + 8 + (5/9)x2 + (2/3) +(1/3)x2 + 4x +(4/3) (Given in the question)

=(25/18)x2 + (50/11)x + 10 (Adding terms corresponding to x2,x ,constant respectively)

Difference in chocolate and strawberry bars =[ (1/2)x2 + (6/11)x + 8] - [(1/3)x2 + 4x +(4/3)]

= (1/6)x2 - (38/11)x +(20/3)

So, the correct options are A and D

Question 1 of 10
The number √3 goes on forever with no repeating pattern; therefore, it is
rational.
A. True
B. False
SUBMIT

Answers

the answer should be true

Answer:

False

Step-by-step explanation:

Rational number :

A rational number is a number which can be represent as p/q of two integers where q is not equal to zero

Example: 2/3

[tex]\sqrt{3}[/tex] = 17320508075........ and it keeps extending. Since it does not terminate or repeated after the decimal point.

Therefore [tex]\sqrt{3}[/tex] is an irritational number,

Hence given statement is FALSE

What is the volume in cubic centimeters of the figure below?

Answers

Answer:

so that you will multiply 15 * 4.

Step-by-step explanation:

15*4 = 60 now you divide 60 by 4 and the answer will be 15.

After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only four women among the last 19 new employees. She also learns that the pool of applicants is very large, with an approximately equal number of qualified men as qualified women.
Help her address the charge of gender discrimination by finding the probability of getting four or fewer women when 19 people are hired, assuming that there is no discrimination based on gender.
(Report answer accurate to 8 decimal places).
P(at most four) =

Answers

Answer:

P(at most four) = 0.00960541

Step-by-step explanation:

For each employee hired, there are only two possible outcomes. Either it is a women, or it is not. The probability of an employee being a women is independent of any other employee, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

19 new employees.

This means that [tex]n = 19[/tex]

Approximately equal number of qualified men as qualified women.

This means that [tex]p = 0.5[/tex]

Probability of getting four or fewer women when 19 people are hired

This is:

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{19,0}.(0.5)^{0}.(0.5)^{19} = 0.00000191[/tex]

[tex]P(X = 1) = C_{19,1}.(0.5)^{1}.(0.5)^{18} = 0.00003624[/tex]

[tex]P(X = 2) = C_{19,2}.(0.5)^{2}.(0.5)^{17} = 0.00032616[/tex]

[tex]P(X = 3) = C_{19,3}.(0.5)^{3}.(0.5)^{16} = 0.00184822[/tex]

[tex]P(X = 4) = C_{19,4}.(0.5)^{4}.(0.5)^{15} = 0.00739288[/tex]

Then

[tex]P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.00000191 + 0.00003624 + 0.00032616 + 0.00184822 + 0.00739288 = 0.00960541[/tex]

So

P(at most four) = 0.00960541

Diana is going to roll a 6-sided die. What's the probability she will role a 4 or
a 5? *

Answers

The probability of rolling any one number on a 6 sided die is 1/6

The probability of rolling a 4 is 1/6

The probability of rolling a 5 is 1/6

The probability of rolling a 4 or a 5 is the probability of rolling a 4 plus the probability of rolling a 5:

1/6 + 1/6 = 2/6 = 1/3

The answer is 1/3

Classify each differential equation as separable, exact, linear, homogeneous, or Bernoulli. Some equations may be more than one kind. Do not solve.
a) dy/dx = (x − y)/x
b) (x + 1)dy/dx = −y + 20
c) dy/dx = 1/(x(x − y2))
d) dy/dx =(y^2 + y)/(x^2 + x)
e) dy/dx = 5y + y^2
f) y dx = (y − xy^2) dy
g) x dy/dx = ye^(xy) − x
h) 2xyy' + y^2 = 2x^2
i) y dx + x dy = 0
k) (x^2 + 2y/x) dx = (3 − ln x^2) dy
l) (y/x^2) dy/dx + e^(2x^3) + y^2 = 0

Answers

a) dy/dx = (x − y)/x=> This is a separable differential equation.b) (x + 1)dy/dx = −y + 20=> This is a linear first-order differential equation.c) [tex]dy/dx = 1/(x(x - y^2))[/tex]=> This is a separable differential equation.d) [tex]dy/dx = (y^2 + y)/(x^2 + x)[/tex]=> This is a separable differential equation.e)[tex]dy/dx = 5y + y^2[/tex]=> This is a Bernoulli differential equation.f) [tex]y dx = (y - xy^2) dy[/tex]=> This is a separable differential equation.g) [tex]x dy/dx = ye^{(xy)} - x[/tex] => This is a linear first-order differential equation.h) [tex]2xyy' + y^2 = 2x^2[/tex]=> This is a linear first-order differential equation.i) y dx + x dy = 0 => This is a separable differential equation.k) [tex](x^2 + 2y/x) dx = (3 - \text ln x^2) dy[/tex] => This is a linear first-order differential equation.l) [tex](y/x^2) dy/dx + e^{(2x^3)} + y^2 = 0[/tex] => This is a linear first-order differential equation.

Here, we have to classify each differential equation based on their characteristics:

a) dy/dx = (x − y)/x

This is a separable differential equation because the variables can be separated on different sides of the equation.

It's of the form dy/dx = g(x) - f(y)/h(y), where g(x) = x/x and h(y) = 1.

b) (x + 1)dy/dx = −y + 20

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), where P(x) = -1/(x + 1) and Q(x) = 20/(x + 1).

c) [tex]dy/dx = 1/(x(x - y^2))[/tex]

This is a separable differential equation because the variables x and y can be separated on different sides of the equation.

d) [tex]dy/dx = (y^2 + y)/(x^2 + x)[/tex]

This is a separable differential equation because the variables x and y can be separated on different sides of the equation.

e)[tex]dy/dx = 5y + y^2[/tex]

This is a Bernoulli differential equation because it is of the form [tex]dy/dx = p(x)y + q(x)y^n[/tex], where p(x) = 0 and q(x) = 5x, n = 2.

f) [tex]y dx = (y - xy^2) dy[/tex]

This is a separable differential equation because the variables x and y can be separated on different sides of the equation.

g) [tex]x dy/dx = ye^{(xy)} - x[/tex]

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), where P(x) = -1/x and [tex]Q(x) = e^{(xy)} - x^{(-1)[/tex].

h) [tex]2xyy' + y^2 = 2x^2[/tex]

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), where P(x) = -2/x and Q(x) = 2x.

i) y dx + x dy = 0

This is a separable differential equation because the variables x and y can be separated on different sides of the equation.

k) [tex](x^2 + 2y/x) dx = (3 - \text ln x^2) dy[/tex]

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), although it's not immediately obvious what P(x) and Q(x) are.

l) [tex](y/x^2) dy/dx + e^{(2x^3)} + y^2 = 0[/tex]

This is a linear first-order differential equation because it can be rearranged to the form y' + P(x)y = Q(x), where [tex]P(x) = -1/x^2[/tex] and [tex]Q(x) = -e^{(2x^3)} - y^2[/tex].

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Simplify
x×x×x×у×у and
2×x×x×3×y×y×y​

Answers

Step-by-step explanation:

1.x³y²

2. 6x²y³

hope it helps

I need help with this!

Answers

Answer:

1.  y=5   x=1

2.  y=4   x=4/5

3.  y=2   x=2/5

Step-by-step explanation:

Plug the y-values in for y:

1. 5=5x

2. 4=5x

3. 2=5x

Then solve for x:

1. x=1

2. x=4/5

3. x= 2/5

Hope this helps!

Expand, and simplify the following expressions a. (2x+y)(x+y) + (2x-y)(x+y)​

Answers

Step-by-step explanation:

2x²+2xy+yx+y²+2x²+2xy-yx+y²

2x²+2x²+2xy+2xy+yx-yx+y²+y²

2x²+2x²+2xy+2xy

4x²+4xy

Your Answer is in the above image.

Hope this solution may help you

A crew clears brush from 1/3 acre of land in 2 days. How long will it take the same crew to clear the entire plot of 2 1/ 2 acres?

Answers

Answer:

15 days

Step-by-step explanation:

Given that :

Time taken to clear 1/3 acre = 2 days

This means that, they will be able to clear ;

1/3 ÷ 2 = 1/3 * 2 /1 = 1/6 acre in one day

1/6 acres per day :

Hence, the number of days it will take to clear 2 1/2 acres will be :

2 1/2 acres ÷ 1/6

5 / 2 ÷ 1/ 6

5/2 * 6 /1 = (5*6) / (2*1) = 30/2 = 15

Hence, it will take 15 days to clear 2 1/2 acres

A man, 1.5m tall, is on top of a building. He observes a car on the road at an angle of 75°. If the building is 30m, how far is the car from the building?​

Answers

Answer:

The answer to this question is 8.44 m.

Step-by-step explanation:

This problem is best illustrated in the photo below.

First, we must know that the angle stated in the problem is the angle of depression. Angle of depression is the angle between the horizontal and the line of sight of the observer. On the other hand, if the observer is looking upward, then the angle between the horizontal and his line of sight is called the angle of elevation.

Since we have the given angle of depression, we must use its complementary angle to solve for the distance of the car from the building.

Let x = complementary angle of 75°

y = distance of the car from the building

To solve for x,

To solve for y, we need to use a trigonometric function that will relate the adjacent of 15° and the opposite of 15°. Let us look at the mnemonics

SOH: Sine =  

CAH: Cosine =  

TOA: Tangent =  

Therefore we must use the tangent function to solve for y.

 

Find the length of side x

Answers

no no no no no no no no no no

Answer:

Step-by-step explanation:

tan(30) = x/1

sqrt(3) / 3 = x/1

x= sqrt(3) / 2

Which of the following represents the factorization of the trinomial below?
x2 - 14x + 49
O A. (x-7)
O B. (x-7)(x+7)
O C. (x+7)
O D. (x+2)(x+7)
ANSWER ASAP!!

Answers

the answer should be B!

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: ( {x - 7})^{2} }}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] {x}^{2} - 14x + 49[/tex]

[tex] = {x}^{2} - 7x - 7x + 49[/tex]

Taking "[tex]x[/tex]" as common from first two terms and "7" from last two terms, we have

[tex] = x \: ( \: x - 7 \: ) - 7 \: ( \: x - 7 \: )[/tex]

Taking the factor [tex](x-7)[/tex] as common,

[tex] = ( \: x - 7\:) \: (\: x - 7\: )[/tex]

[tex] =( {x - 7})^{2} [/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

There is a bag filled with 3 blue and 4 red marbles.
A marble is taken at random from the bag, the colour is noted and then it is replaced.
Another marble is taken at random.
What is the probability of getting exactly 1 blue?

Answers

Answer:

its a three in seven chance, since there are seven total outcomes and there is only one favorable outcome. Hope that helps.

Step-by-step explanation:

Find Length of x line OR

Answers

ATQ:-

Both figures r similar (given )

so :-

[tex] \frac{5}{2.5} = \frac{3}{1.5} = \frac{2}{1} = \frac{4}{x} \\ \frac{2}{1} = \frac{4}{x} \\ \frac{ \cancel{2}}{1} = \frac{ \cancel{4}^ { \tiny{2}}}{x} \\ x = 2 \: \: ans[/tex]

subtract

a2-b2 from a2 +b2

Answers

Answer:

2b^2

Step-by-step explanation:

according to the question equation is

(a^2 + b^2 ) - (a^2 - b^2)

a^2 + b^2 - a^2 + b^2

plus a square and minus a square gets cancel

b^2 + b^2

since they are like terms they can be added

2b^2

Answer:

2b^2

Step-by-step explanation:

according to the question equation is

(a^2 + b^2 ) - (a^2 - b^2)

a^2 + b^2 - a^2 + b^2

= b^2 + b^2

like terms can be added

+2b^2

Consider a species of bird that can be split into three age groupings: those aged 0-1 years, those aged 1-2 years, and those aged 2-3 years. The population is observed once a year. Given that the Leslie matrix is equal to

Answers

Answer: hello your question lacks some information attached below is the complete question

answer :

a) attached below

b) 65 students aged 1-2 years

Step-by-step explanation:

For a Leslie matrix ; there is a relation

Pn = L^n Po  where ; Pn = population vector after n years , Po = initial population vector .

a) Initial population vector

attached below

[tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

b) Number of birds aged 1-2 years are available after 10 years

i.e. P10 = L^10 Po

note : Po = Xo

∴ P10 = [tex]\left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right][/tex]   [tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

we will apply  MATLAB to resolve the above matrix

P10  = [tex]\left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]

∴ Number of children between 1-2 years left after 10 years  = 65.24 ≈ 65

The total number of birds aged between 1-2 years which are available after 10 years is 65 and this can be determined by using the Leslie matrix relation.

Given :

Consider a species of bird that can be split into three age groupings: those aged 0-1 years, those aged 1-2 years, and those aged 2-3 years. [tex]\rm L = \left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right][/tex]

According to the given data, the initial population vector is given by:

[tex]x_0 = \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

Now, the total number of birds aged between 1-2 years which are available after 10 years is:

[tex]\rm P_{10} = \left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right] \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]

Now, solve the above matrices in order to determine the value of [tex]\rm P_{10}[/tex].

[tex]\rm P_{10} = \left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]

Therefore, the total number of birds aged between 1-2 years which are available after 10 years is 65.

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what is 1+1+3+4+6+2+6+3+5=+8+2+5

Answers

Answer:

16

Step-by-step explanation:

baámmáy tính  

What is 15 5/7 - 6 4/5

Answers

Answer:

8.9

Step-by-step explanation:

15.71428571-6.8=8.914285714

We round of to one significant figure because its addition n the lowest is 6.8

Answer:

[tex]8\frac{32}{35}[/tex]

Step-by-step explanation:

Write the phrase as an algebraic expression and simplify if possible. Let x represent the unknown number

Three times a number, decreased by five

(Simplify your answer.)

Answers

EZ,
3x-5
(3x) = 3 times a number.
Decrease means subtract.

To express the phrase "Three times a number, decreased by five" as an algebraic expression, we can use the variable x to represent the unknown number: 3x - 5

Now, let's simplify this expression: Given that the unknown number is represented by x, we can substitute it into the expression above. Substituting x into the expression, we have: [tex]3(x) - 5 3x - 5[/tex] Therefore, the algebraic expression representing "Three times a number, decreased by five" is [tex]3x - 5.[/tex] At this point, there is no further simplification possible since the expression is already in its simplest form.

For example, let's assume the unknown number x is 7. We can plug in this value to evaluate the expression: [tex]3(7) - 5 = 21 - 5 = 16[/tex] Similarly, if x is -2, the calculation would be: [tex]3(-2) - 5 = -6 - 5 = -11[/tex] In conclusion, the algebraic expression 3x - 5 represents the phrase "Three times a number, decreased by five."

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I need help please anyone

Answers

The answer is a or d u choose

Answer:

20

Step-by-step explanation:

l*w*h

4*5*1= 20

WILL GIVE BRAINLIEST Solve for x

Answers

Answer:

Step-by-step explanation:

sin x° = [tex]\frac{17}{19}[/tex]

x° = [tex]sin^{-1}[/tex] [tex]\frac{17}{19}[/tex]

x° ≈ 63°

DO THIS FAST PLEASE I WILL GIVE BRAINLY CROWN



Use a model to divide. 5 ÷ 1/2 10 4 2 20

Answers

5 ÷ 1/2 => 5 x 2/1 => 10/1 => 10

Answer:

10

Step-by-step explanation:

In the pic, it shows ten half squares.  

look at attachment below

Answers

I think it’s 8/55=4/x
So it’s 8x=4(55)
8x=220
x=220/8
x=27.5

PLS HELP

the simplest form of this product has a numerator of

x + 2
x - 2
( x - 2 ) ( x - 2 )
( x + 2 ) ( x - 2 )

and a denominator of

x - 5
( x - 5 ) ( x - 1 )
x - 1
( x + 5 ) ( x + 1 )

the expression has an excluded value of x

- 5
2
-1
5

Answers

(x+2)(x-2) / (x-1)(x-5) this is the simplified form of the expression.

What is fraction?

A fraction is a mathematical term that represents a part of a whole or a ratio between two quantities. It is a way of expressing a number as a quotient of two integers, where the top number is called the numerator, and the bottom number is called the denominator.

x²-3x-10/x²-6x+5 • x-2/x-5

We can factor the numerator and denominator of the first fraction as follows: (x-5)(x+2) / (x-5)(x-1)

Notice that there's a common factor of x-5 in both the numerator and denominator. We can cancel them out, leaving: (x+2) / (x-1)

Now let's simplify the second fraction:

x-2 / x-5

We can't simplify this fraction any further, so we leave it as is.

Putting it all together, we get:

(x+2) / (x-1) * (x-2) / (x-5)

Multiplying the two fractions, we get:

(x+2)(x-2) / (x-1)(x-5)

This is the simplified form of the expression.

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An educational psychologist wondered whether there was a relationship between the amount of academic pressure a high school student felt and their plans for college. They surveyed a random sample of 300 high school students throughout the country about their college plans and whether they felt academic pressure. Here are the responses and partial results of a chi-square test (expected counts appear below observed counts):
Chi-square test:
Planned years of college vs. feeling academic pressure now
O years Up to 4 years Up to 4 years More than 4 years Total
Yes 31 48 161 240
31.2 48 160.8
No 8 12 40 60
7.8 12 40.2
Total 39 60 201 300
They want to use these results to carry out a xạ test of independence. Assume that all conditions for inference were met. What are the values of the test statistic and P-value for their test?
What are the values of the test statistic and P-value for their test?
A. x² = 0.002;
0.001 < P-value < 0.0025
B. x² = 0.002;
P-value > 0.25
C. x² = 0.007;
0.005 < P-value < 0.01
D. x² = 0.007;
P-value > 0.25

Answers

Answer:

D. x² = 0.007;

P-value > 0.25

Step-by-step explanation:

The observed and expected values are given below :

Yes____31 48 161 ____240

______31.2 48 160.8

No ____ 8 12 40_____ 60

______7.8 12 40.2

Total __ 39 60 201 ___300

The Chisquare statistic, χ²:

Σ(Observed - Expected)²/ Expected

Chi-Squared Values:

0.00128205 __ 0 __ 0.000248756

0.00512821 __ 0 __ 0.000995025

(0.00128205 + 0 + 0.000248756 + 0.00512821 + 0 + 0.000995025 )

= 0.007654041

The degree of freedom = (row - 1) * (column - 1)

Degree of freedom = (2-1)*(3-1) = 1*2= 2

The Pvalue = 0.9962

Pvalue > 0.25

Có 7 cây hãy trồng thành 6 hàng, mỗi hàng 3 cây?

Answers

Answer:

Step-by-step explanation:

Bạn vẽ 1 tức giác ABCD lồi sau đó nối AB và CD cắt nhau tại E, AD và BC cắt nhau tại F, AC và BC cắt nhau tại G. Trồng 7 cây vào các điểm ABCDEFG  l. Ta có sáu hàng là ABE, DCE, BCF, ADF, ACG, BDG

The interarrival time of nuclear particles in a Monte Carlo simulation of a reaction is designed to have a uniform distribution over an interval from 0 to 0.5 milliseconds. Determine the probability that the interarrival time between two particles will be:

Answers

Answer:

Incomplete question, but you can use the formulas given to solve it.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

[tex]P(X < x) = \frac{x - a}{b - a}[/tex]

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

Uniform distribution over an interval from 0 to 0.5 milliseconds

This means that [tex]a = 0, b = 0.5[/tex]

Determine the probability that the interarrival time between two particles will be:

Considering [tex]a = 0, b = 0.5[/tex], and the question asked, you choose one of the three formulas above.

Construct a frequency polygon that represents the following data regarding the selling prices of houses sold in 2006 for a particular neighborhood find the midpoint

Class Frequency
78787 – 98786 9
98787 – 118786 8
18787 – 138786 9
138787 – 158786 4
158787 – 178786 8

Answers

Answer:

See attachment for polygon

Step-by-step explanation:

Given

[tex]\begin{array}{cc}{Class} & {Frequency} & 78787 - 98786 & 9 &98787 - 118786 & 8 & 118787 - 138786 & 9 & 138787 - 158786 & 4 & 158787 - 178786 & 8 \ \end{array}[/tex]

Required

The frequency polygon

First, we calculate the midpoint of each class.

This is the average of the class limits

So, we have:

[tex]x_1 = \frac{78787 + 98786}{2} = \frac{177573}{2} = 88786.5[/tex]

[tex]x_2 = \frac{98787 + 118786}{2} = \frac{217573}{2} = 108786.5[/tex]

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[tex]x_5 = \frac{158787 + 178786}{2} = \frac{337573}{2} = 168786.5[/tex]

(138787 + 158786)/2

So, the table becomes:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {x} &78787 - 98786 & 9 & 88786.5 & 98787 - 118786 & 8 & 108786.5 & 118787 - 138786 & 9 & 128786.5 & 138787 - 158786 & 4 & 148787.5 & 158787 - 178786 & 8 & 168786.5\ \end{array}[/tex]

See attachment for frequency polygon

Is 69 square routed a even number

Answers

No it is not, the square root is 8.3
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