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The acceleration of the 20 N force is 6.67 m/s^2. The acceleration of the 4N force is 1.33 m/s^2.

We define the force that acts on a body as that which is able to cause an acceleration or that which is able  to change the direction of an object. Recall that from the Newton first law, an object would continue in its state of rest or uniform motion unless the object is acted upon by an external force.

Now the frictional force is the force that tends to resist the motion of two surfaces that are in contact. Owing to the fact that it is a resistive force its direction is always opposite the force that seeks to move the object forward.

Now;

F = ma

a = F/m

a = 20 N/3Kg

a = 6.67 m/s^2

If the force is 4N;

a = F/m

a = 4N/3Kg

a = 1.33 m/s^2

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Missing parts;

How would you calculate the acceleration if you push with a 20 N horizontal force on a 3 kg block on a horizontal friction-free air table? What is the acceleration if the friction force is 4 N?

Answer: 80.5 miles

Explanation:

3.5 x 23 = 80.5

Answer:

A. a total solar eclipse

Explanation:

During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth

Answer:

30600kg

Explanation:

density=m/v make v subject of the formula

Answer:

The depth of focus achievable with those lenses is small.

Explanation:

A larger aperture makes it much harder to focus on more than one object. When using a telephoto lens (the ones the question is referring to), the depth of focus is very small. For example, using a telephoto lens to take a photo of a runner might get the runner in focus, but certainly not the track, or the audience behind them. If you look at photos, especially older photos, of Olympians in almost any sport you can see this.

Hope this helps!

Answer:

C. unbalanced force

Explanation:

it is called unbalanced force because it has changed direction of the moving object

Answer:

(a) 6,000,000J      

(b)  3,000,000J

(c)  For A 20,000W

But for B 10,000W

The work done in getting  the car to the top is equal to 6 ×10⁶ J. If the vertical speed is 2.5 m/s then, the work done will be  3 ×10⁶ J. The power exerted on the car is in 5 minutes is 20000 J/s.

In physics, work done is the dot  product of force and displacement. Let w be the work done and F and ds be the force and displacement. Then

W = F.ds

It is given that the, the force of the cable is 4 × 10³ N. The velocity is 5 m/s and time is 5 minutes or 300 seconds. Now, the displacement is the product of time and velocity.

ds = velocity ×  time

    =  300 s ×  5 m/s

    = 1500 m.

Thus the work done = F × ds

                                  = 4 × 10³ N ×  1500 m

                                  = 6 ×10⁶ J .

If the velocity is reduced to half 2.5 m/s , then work done will be reduced to half as 3 ×10⁶ J.

Power is the rate of work done. Thus it is the ratio of work done to time. The power exerted on the car in 5 minutes = 6 ×10⁶ J /300s

                                                                        = 20000 J/s

Hence, the power exerted on the cable car in 5 minutes is 20000 J/s.

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The wave height is equal to twice the amplitude of the wave.

The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.

The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.

Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.

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Explanation:

F=m×a

m=2kg

a=4m/s^2

F=2kg×4m/s^2

F=8N

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is body with some mass than there is force.

Given in the question mass and acceleration of balloon, force is given as

F = m*a

m = 2 kg

a = 4 m/s²

F = 2 kg×4 m/s²

F = 8 N

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

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Answer:

c

Explanation:

The changing of color of a substance is not necessarily an indicator of a chemical change. For example, changing the color of a metal does not change its physical properties. However, in a chemical reaction, a color change is usually an indicator that a reaction is occurring.

Answer:

Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:

Explanation:

Answer:

24mm

Explanation:

3 N to g is 305.9 g

50g ---- 4 mm

305.9 ----- 4×305.9/50 = 24 mm

Answer:

unfortunately we have not received a reply to the park yet but

Explanation:

mohamedz and he had killed him

[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]

[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]

[tex] \sf \huge \red {\dag} Given[/tex]

[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]

[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]

We know that the formula of Pressure is

[tex]\sf \longmapsto \: Force/Area[/tex]

Let's start.

[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]

[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]

[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]

Answer:

Where is the picture send again please

Explanation:

Answer:

Explanation:

Newton's law of universal gravitation is that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder   is mathematically given as

[tex]dl=\frac{Flo}{yA}[/tex]

[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=1.19064778*10^-^4[/tex]

Generally the equation for brass cylinder   is mathematically given as

[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=2.43*10^{-4}[/tex]

Therefore Total change in length

[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]

[tex]dl'=3.621*10^{-4}m[/tex]

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Answer:

Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Explanation:

The conservation of momentum, Newton's second law and kinematics allows to find the result for the initial speed of the car is:

Given parameters

To find

The momentum is defined by the product of the mass and the velocity of the body, so it is a vector quantity. In the case of an isolated system the momentum is conserved.

In the attachment we see a diagram of the vehicle crash, let's write the moment for each axis.

y-axis

Initial instant. Before the shock.

          [tex]p_{oy}[/tex]  = M v₀₁

Final moment. After the crash

          [tex]p_{fy}[/tex] = (M + m) [tex]v_{fy}[/tex]

The system is formed by the two vehicles for which during the crash it is isolated and the momentum is conserved.

          [tex]p_{oy} = p_{fy} \\\\M v_{o1} = (M+m) v_{fy} \\v_{fy} = \frac{M}{M+m} \ v_{o1}[/tex]          

Calculate us

           [tex]v_{fy} = \frac{1200}{1200+750} \ 15[/tex]  

           vfx = 9.23 m / s

x-axis

Initial instant. Before the crash.

           p₀ₓ = m v₀₂

Final moment. After the crash.

           [tex]p_{fx}[/tex] = ​​(M + m) [tex]v_{fx}[/tex]  

The momentum is preserved.

          [tex]p_{ox}= p_{fx} \\m v_{o2) = (M+m) \ v_{fx}[/tex]  

Let's find the velocity just after the collision, let's use Newton's second law,

y-axis

        N-W = 0

        N = W = (M + m) g

x-axis

       fr = (M + m) a

The friction force is the macroscopic manifestation of the interactions between the two bodies.

       fr = μ N

We substitute.

       μ  g = a

Now we can use kinematics.

        v² = v₀² - 2a d

When the vehicles stop their speed is zero.

        v₀² = 2 a x

        v₀ = [tex]\sqrt{2\ \mu \ g \ d}[/tex]

Let's calculate.

       v₀ = [tex]\sqrt{2 \ 0.40 \ 9.8 25 }[/tex]  

       v₀ = 14 m / s

This is the speed of the two vehicles just after the collision, that is, let's use trigonometry to find their components.

          cos 25 = [tex]\frac{v_{ox}}{v_o}[/tex]  

          v₀ₓ = v₀ cos 25

          v₀ₓ = 14 cos 25

          v₀ₓ = 12.69 m / s

We substitute in the expression of the conservation of the momentum in the x-axis.

           m v₀₂ = (M + m) [tex]v_{fx}[/tex]  

           [tex]v_{o2} = \frac{M+m}{m} v_{fx}[/tex]  

Let's calculate.

           [tex]v_{o2} = \frac{1200+750}{750} \ 12.69[/tex]  

           vfy = 32.99 m / s = 40 m / s

In conclusion using the conservation of momentum, Newton's second law and kinematics we can find the result for the initial speed of the car is:

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Answer:

b.fabric

Explanation:

Nowadays, when people talk about space-time, they often describe it as resembling a sheet of rubber. This, too, comes from Einstein, who realized as he developed his theory of general relativity that the force of gravity was due to curves in the fabric of space-time.

Answer:

B. fabric

Explanation:

Answer:

a=v/t (searched)

Explanation:

a=acceleration

v=change in velocity

t=time

(searched)

Answer:

Resolve the vectors:

F1 = 30 cos 30 i + 30 sin 30 j = 26 i + 15 j

F2 = 80 cos 135 i + 80 sin 135 j = -56.6 i + 56,6 j

F1 + F2 = (26 - 56.6) i + (15 + 56.6) j = -30.6 i + 71.6 j

The offsetting force would be

F3 = 30.6 i - 71.6 j

The magnitude of this vector is (30.6^2 + 71.6^2)^1/2 = 77.9

cos theta 3 = 30.6 / 77.9 = 66.9 deg

Check:

77.9 * sin 66.9 = 71.6  agreeing in magnitude with F3

Now we need the quadrant of the offsetting vector

sin theta 3 = -         cos theta 3 = +

This occurs in the fourth quadrant and theta 3 = 360 - 66.9 = 293.1 deg

A milliliter, abbreviated as ml or mL, is a unit of volume in the metric system. One milliliter is equal to one thousandth of a liter, or 1 cubic centimeter. In the imperial system, that's a small amount: . 004 of a cup

Answer:

The graph for 7a is shown in the attachment. For question 7b she walks a distance of 16 meters. (m)

Explanation:

Valid results are only obtained if each tube is identical because; effective comparison of the tested blood each time can only be achieved if the testing model is constant in which case each tube is identical.

Discussion:

During scientific tests such as that described in the question; it is important to keep all parameters of testing constant.

This is so because, the utmost motive of the testing model is to draw comparison. It is on this note that valid results are only obtained if each tube is identical.

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Answer:

I'm no expert, but multitasking is a no bueno. Because multitasking reduces your efficiency and performance because your brain can only focus on one thing at a time. When you try to do two things at once, your brain lacks the capacity to perform both tasks successfully.

Therefore I would choose A, considering he could easily workout another time, whilst the test is a one time thing. He can't redo the test, but he can workout again. So my answer is A.

If he HAS to workout and study at the same time, then C would be appropriate.

I hope this helps!

Answer: i think its a bullfrog forgive me if im wrong i dont exactly know

Explanation:

Answer:

that is an African bullfrog