Lana's class is studying the various kinds of energy found on a playground
Which of the following would be the BEST way to test for an equal transformation of energy on a playground?
СА
Using the slide, Lana could measure her kinetic energy when she was climbing up the ladder, measure her potential energy before she slid down, and her total energy used at the bottom of the slide. If the amount of potential
energy and kinetic energy added up to equal the total amount of energy used, it would show an equal transformation of energy
OB
Using the slido, Lana could measure her potential and kinetic energy sitting at the top of the slide, and then she could measure her kinetic and potential energy at various points while sliding to the bottom of the total value of
her potential energy and her kinetic energy were equal at every measuremont, it would show that there had been an equal transformation
C
Using the swing, Lana could measure her potential energy when she was sitting still on the swing, and she could measure her kinetic energy when the swing was in motion. If the kinetic energy was twice the amount of her
potential energy, it would show there had boon an equal transformation of potential energy to kinetic energy
D
Using the soesaw, Lana could measure her potential energy when she was in motion, and she could measure her kinetic energy when she was resting. If her kinetic and potential energy were equal, it would show that there
had been an equal transformation

Answer:

The acceleration of the woman is 0.44 m/s²

Explanation:

Given;

mass of the woman, m₁ = 90 kg

mass of the boy, m₂ = 60 kg

The force applied by the boy, f₂ = 40 N

The net horizontal force on the woman = 40 N

Apply Newton's second law of motion to determine the acceleration of the woman;

f = ma

a = f / m

a = 40 / 90

a = 0.44 m/s²

Therefore, the acceleration of the woman is 0.44 m/s²

Answer:

2m/s

Explanation:

The formula for acceleration can be found by [ a = f/m ]

We are given the force [ 100N ] and the mass [ 50g ].

We can use these values to solve for the acceleration.

a = 100/50

a = 2m/s

Best of Luck!

Answer:

30.81°

Explanation:

Angle of refraction= sin⁻¹ 0.5122 = 30.81°.

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Explanation:

the acceleration will be unchanged according to newton second law of motion

A locomotive engine pulls a train with a constant force then its acceleration will increase if more coaches are added to the train because the mass of the system would increase

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

Force = mass ×acceleration

As given in the problem if a locomotive engine pulls a train with a constant force

As given the force is constant but if the number of coaches increases the mass of the train increase to balance the constant force acceleration will decrease.

Thus, if a locomotive engine pulls a train with a constant force then its acceleration will increase if more coaches are added to the train because the mass of the system would increase.

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Answer:

voltage

Explanation:

the current in a circuit, the voltage can be increased.

According to Ohm's law, when all other physical parameters, including temperature, are held constant, the voltage across a conductor is directly proportional to the current flowing through it.

From ohm's law, we can state that voltage is directly proportional to current.

Looking at the following formula:

I = V/R

Where V is voltage,

I is current, and

R is resistance

In the above equation, Current and Voltage are in a direct relationship such that if I is increased, V is also increased, and vice versa.

Therefore, To increase the current, the voltage should be increased.

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Answer:

the equipotential lines or surface are perpendicular to the electric field

Explanation:

In this exercise you are asked to explain the relationship between the direction of the equipotential lines and the electric field.

Electric field lines go from a positive charge to a negative charge, the specific shape of these lines depends on the charge distribution, let's look at two specific cases:

* in the case of point charge the lines are radial

* In the case of electric plates, they are lines perpendicular to the plates.

Equipotential surfaces are related to the elective field by

            Ex = - dV / dx

            Ey = -dV / dy

            Ez = -dV / dz

             E = Exi ^ + Ey j ^ + Ezk ^

remember electric potential is a scalar and the electric field is a vector quantity, therefore the equipotential lines or surface are perpendicular to the electric field. Specifically for

* point charge the equipotential surfaces are concentric with the charge

* For electrical plates equipotential lines are parallel to the plates.

Answer:

true

Explanation:

A easy dude please mark me as brainlyst

Answer:

Direction from A to B divided by time(30s)

Explanation:

Let [tex]u[/tex] be the initial velocity of the soccer ball at an angle of inclination of [tex]\theta_0[/tex] with the positive x-axis.

Given that:

[tex]\theta_0=45^{\circ}[/tex]

The horizontal distance covered by the projectile=20 m

Time of flight, [tex]t_f=2[/tex] seconds

Acceleration due to gravity, [tex]g= 10 m/s^2[/tex] downward.

As "north" and "up" as the positive x ‑ and y ‑directions, respectively.

So, [tex]g= -10 m/s^2[/tex]

As the acceleration due to gravity is in the vertical direction, so the horizontal component of the initial velocity remains unchanged.

The x-component of the initial velocity, [tex]u_x=u\cos\theta_0[/tex].

The horizontal distance covered by the projectile [tex]= u_x\times t_f[/tex]

[tex]\Rightarrow u_x\times t_f=20[/tex]

[tex]\Rightarrow u_x\times 2=20[/tex]

[tex]\Rightarrow u_x=10[/tex] m/s

So, the horizontal component of the velocity is 10 m/s which is constant and the graph has been shown in the figure (i).

Now,  [tex]u\cos(45^{\circ})=10[/tex] [as [tex]u_x=u\cos\theta_0[/tex]]

[tex]\Rightarrow u=10\sqrt{2}[/tex] m/s.

The vertical component of the initial velocity,

[tex]u_y= u\sin\theta_0[/tex]

[tex]\Rightarrow u_y=10\sqrt{2}\sin(45^{\circ})[/tex]

[tex]\Rightarrow u_y=10[/tex] m/s

Let v be the vertical component of the velocity at any time instant t.

From the equation of motion,

[tex]v=u+at[/tex]

where u: initial velocity, v: final velocity, a: constant acceleration, and t: time taken to change the velocity from u to v.

In this case, we have [tex]u=u_y, a= -10 m/s^2[/tex].

So at any time instant, t.

[tex]v=u_y+(-10)t[/tex]

[tex]\Rightarrow v=10-10t[/tex]

The vertical component of the velocity, v, is the function of time and related as [tex]v=10-10t[/tex].

This is a linear equation.

At 2 second, the vertical component of the velocity

v=10-10x2=-10 m/s.

The graph has been shown in figure (ii).

Answer:

The total force on the cart is:  

F = F(applied) - F(friction) = (18 N) - (15 N) = 3.0 N  

The acceleration of the cart is:  

a = (change in velocity)/(time) = (1.0 m/s)/(5.0 s) = 0.20 m/s^2  

Using F = ma, the mass of the cart is:  

m = F/a = (3.0 N)/(0.20 m/s^2) = 15 kg

Explanation:

Chimpanzees are genetically closest to humans, and in fact, chimpanzees share about 98.6% of our DNA. We share more of our DNA with chimpanzees than with monkeys or other groups, or even with other great apes! We also both play, have complex emotions and intelligence, and a very similar physical makeup.

(I hope that's good) :)

Answer:

(a) E = 3.6 x 10³ N/C = 3.6 KN/C

(b) ΔV = 1044 Volts

(c) K.E = 1.67 x 10⁻¹⁶ J

(d) Vf = 4.47 x 10⁵ m/s

(e) a = 3.45 x 10¹¹ m/s²

(f) F = 5.76 x 10⁻¹⁶ N

(g) E = 3.6 x 10³ N/C = 3.6 KN/C  

(h)  Both values are same in part (h) and (a)

Explanation:

(a)

Electric field between oppositely charged plates is given as follows:

E = σ/ε₀

where,

E = Electric Field Intensity = ?

σ = surface charge density = 32 nC/m² = 3.2 x 10⁻⁸ C/m²

ε₀ = Permittivity of free space = 8.85 x 10⁻¹² C²/N.m²

Therefore,

E = (3.2 x 10⁻⁸ C/m²)/(8.85 x 10⁻¹² C²/N.m²)

E = 3.6 x 10³ N/C = 3.6 KN/C

(b)

E = ΔV/r

ΔV = Er

where,

r = distance between plates = 29 cm = 0.29 m

ΔV = Potential Difference = ?

ΔV = (3.6 x 10³)(0.29)

V = 1044 Volts

(c)

Kinetic Energy of Proton = Work done on Proton

K.E = F r

but,  F = E q

K.E = E q r

where,

q = charge on proton = 1.6 x 10⁻¹⁹ C

Therefore,

K.E = (3600 N/C)(1.6 x 10⁻¹⁹ C)(0.29 m)

K.E = 1.67 x 10⁻¹⁶ J

(d)

K.E = (1/2)m(Vf² - Vi²)

where,

m = mass of proton = 1.67 x 10⁻²⁷ kg

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

Therefore,

1.67 x 10⁻¹⁶ J = (1/2)(1.67 x 10⁻²⁷ kg)(Vf² - (0 m/s)²]

Vf² = (1.67 x 10⁻¹⁶ J)(2)/(1.67 x 10⁻²⁷ kg)

Vf = √(20 x 10¹⁰ m²/s²)

Vf = 4.47 x 10⁵ m/s

(e)

2as = Vf² - Vi²

2(a)(0.29 m) = (4.47 x 10⁵ m/s)² - (0 m/s)²

a = (20 x 10¹⁰ m²/s²)/0.58 m

a = 3.45 x 10¹¹ m/s²

(f)

F = ma

F = (1.67 x 10⁻²⁷ kg)(3.45 x 10¹¹ m/s²)

F = 5.76 x 10⁻¹⁶ N

(g)

E = F/q

E = (5.76 x 10⁻¹⁶ N)/(1.6 x 10⁻¹⁹ C)

E = 3.6 x 10³ N/C = 3.6 KN/C

(h)

Both values are same in part (h) and (a)

Answer:

The magnitude of vector B is 13.7

Explanation:

Given that,

Component of vector B is

[tex]x=7.1[/tex]

[tex]y=8.2[/tex]

[tex]z=8.4[/tex]

We need to calculate the magnitude of vector B

Using given data

[tex]B=\sqrt{x^2+y^2+z^2}[/tex]

Put the value into the formula

[tex]B=\sqrt{(7.1)^2+(8.2)^2+(8.4)^2}[/tex]

[tex]B=13.7[/tex]

Hence, The magnitude of vector B is 13.7

Answer:

Number one is C.Both

Number two is A. throw upwards

Number three is B. react his grapple... shooting upward

Answer:

Gravitational

Electrostatic

magnetic

Frictional

gravitational

electrostatic

magnetic

frictional

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Answer:

137.2J

Explanation:

Ep= mgh

Given,

and we know, g = 9.81 N/kg

Ep= 2 × 9.81 × 7

Ep= 137.2J

Answer: STOP LOOKING FOR ANSWERS OMG:(((((9

Explanation:

Answer:

8

Explanation:

Finding time= t=change in velocity or distance/acceleration

so 32/9.5-5.5

32/4

8

Answer:

The cart starts out in position A with high potential energy, low kinetic energy, and some thermal energy. As the cart progresses into position B, the kinetic energy begins to increase and the potential energy begins to decrease; as the thermal energy increases as thermal energy from the track is transferred to the cart through friction. Once the cart reaches position C, it has high kinetic energy, low potential energy, and some thermal energy. At position D, the cart has high potential energy, low kinetic energy, and some thermal energy. The potential energy throughout is correlated to gravity, the kinetic energy is correlated to momentum, and the thermal energy is correlated to friction. The potential energy is at its maximum during position A, and its minimum at position C; the kinetic energy is at its maximum during position C, and its minimum at position A; the thermal energy is at its maximum during position B, and its minimum at position A.

Explanation:

Answer:

Cart A starts out on the top of the hill, it has great potential energy, low kinetic energy, and some thermal energy. Cart B is going down the hill which increased the kinetic energy and the thermal energy while the potential energy is decreasing. Cart C is at the bottom of the hill, having high kinetic energy, low potential energy and some thermal energy. Cart D is at the top of a smaller hill, giving it high potential energy, low kinetic energy and little thermal energy.

These changes occur because when an object is at a high place, it will have high potential energy, and low kinetic energy, and as the height goes down, the kinetic energy increases and the potential energy will decrease.  

Explanation:

here's my version of answer

Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 25 N

distance = 3 m

We have

work done = 25 × 3

We have the final answer as

Hope this helps you

Answer:

Because water is polar and oil is nonpolar, their molecules are not attracted to each other. polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.

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use your brain :)

Substances that can dissolve both polar and nonpolar substances are called amphiphilic or amphipathic. This unique property arises due to their molecular structure, which contains both polar and nonpolar regions.

Amphiphilic molecules typically have a hydrophilic (water-attracting) or polar end and a hydrophobic (water-repelling) or nonpolar end. This dual nature allows them to interact with and dissolve in both polar and nonpolar solvents. Let's explore the reasons behind this ability:

Polar interactions: The hydrophilic end of the amphiphilic molecule can form hydrogen bonds and electrostatic interactions with polar solvents (like water) due to the presence of charged or partially charged atoms (such as oxygen or nitrogen). This makes them soluble in polar substances.

Nonpolar interactions: The hydrophobic end of the amphiphilic molecule is typically a long hydrocarbon chain or a nonpolar group. These nonpolar regions can interact with other nonpolar substances (like oils, fats, or hydrophobic portions of biomolecules) through van der Waals forces and London dispersion forces.

Emulsification: The presence of both polar and nonpolar parts in an amphiphilic molecule allows it to act as an emulsifier. It can stabilize the interface between polar and nonpolar substances, preventing them from separating. For example, in the formation of an oil-in-water or water-in-oil emulsion, amphiphilic molecules form a barrier between the two immiscible substances, keeping them dispersed and forming a stable mixture.

Examples of amphiphilic molecules include surfactants (detergents), phospholipids (essential components of cell membranes), and lipoproteins (transporters of lipids in the bloodstream). These substances play vital roles in various biological processes and industrial applications due to their ability to interact with both polar and nonpolar substances.

Hence, Substances that can dissolve both polar and nonpolar substances are called amphiphilic or amphipathic. This unique property arises due to their molecular structure, which contains both polar and nonpolar regions.

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Answer: Force of magnitude 20.22lbf to the right at angle 8.5°

Explanation: The image named "Untitled" below shows the forces acting on the cart.

The second image, "Untitled2", demonstrate the vector diagram of the forces acting on the kart, in which:

f is force forward

f(left) is pull to the left

f(R) is the resulting force necessary for the kart to move

The drag force is not draw on the vector diagram because its value is already part of the force forward.

As we can see, the diagram forms a right triangle with f(R) as hypotenuse.

Using Pytagorean Theorem:

[tex][f(R)]^{2}=f^{2}+[f(left)]^{2}[/tex]

[tex][f(R)]^{2}=20^{2}+3^{2}[/tex]

[tex][f(R)]^{2}=409[/tex]

[tex]f(R)=\sqrt{409}[/tex]

f(R) = 20.22

Force forward equals 20.22lbf to the right.

The angle formed form the forward direction and the resulting force is

[tex]cos\theta=\frac{20}{20.22}[/tex]

cosθ = 0.989

θ = cos⁻¹(0.989)

θ = 8.5°

The forward force is to the right at angle 8.5° and magnitude 20.22lbf.

Answer:

To the extent that Stellar spectra look like blackbodies, the temperature of a star can also be measured amazingly accurately by recording the brightness in two different filters. To get a stellar temperature: Measure the brightness of a star through two filters and compare the ratio of red to blue light.

Explanation:

Answer:

Dang bro what school you in?

Answer:

nice app is brainly heheh........

Answer:

The acceleration is 100m

Explanation:

Answer:

  P_a = 3P₀ ,  P_b = 2 P₀ ,       P_c = 3 P₀

P_c> P_b> P_a

Explanation:

To determine which circuit consumes more energy than is given by the expression

           P = V I

           V = I R

           I = V / R

           P = V² / R

As all circuits have the same battery, the value of the resistance to which the battery is connected determines the consumption

Circuit A

In this circuit the three bulbs are in series so the total resistance is

         R_total = 3 R

the power dissipated is

         P_a = V² / 3R

if we call

         P₀ = V² / R

we substitute

         P_a = P₀/3

Circuit B

Two bulbs are connected in series

           R_total = 2 R

power is

        P_b = V2 / 2R

        P_b =  P₀/2

Circuit C

The 3 bulbs are connected, but in parallel, the resistance is

        1 / R_totak = 1 / R + 1 / R + 1 / R

        R_total = R / 3

        P _c = V2 3 / R

        P_c = 3 Po

By reviewing these results, we can sort the circuits

        P_c> P_b> P_a