The answer of m^2 is 30 modulo 59.
Since we know that N = 12 = 2^2 + 2^3, we can use the Chinese Remainder Theorem (CRT) to break down the problem into two simpler congruences.
First, we need to find the values of MP^2 and MP^3 modulo 2 and 3. Since 51 is odd, we have:
MP^2 ≡ 1^2 ≡ 1 (mod 2)
MP^3 ≡ 1^3 ≡ 1 (mod 3)
Next, we need to find the values of MP^2 and MP^3 modulo 59. We can use Fermat's Little Theorem to simplify these expressions:
MP^(58) ≡ 1 (mod 59)
Since 59 is a prime, we have:
MP^(56) ≡ 1 (mod 59) [since 2^56 ≡ 1 (mod 59) by FLT]
MP^(57) ≡ MP^(56) * MP ≡ MP (mod 59)
MP^(58) ≡ MP^(57) * MP ≡ 1 * MP ≡ MP (mod 59)
Therefore, we have:
MP^2 ≡ MP^(2 mod 56) ≡ MP^2 ≡ 51^2 ≡ 2601 ≡ 30 (mod 59)
MP^3 ≡ MP^(3 mod 56) ≡ MP^3 ≡ 51^3 ≡ 132651 ≡ 36 (mod 59)
Now, we can apply the CRT to find m^2 modulo 59:
m^2 ≡ x (mod 2)
m^2 ≡ y (mod 3)
where x ≡ 1 (mod 2) and y ≡ 1 (mod 3).
Using the CRT, we get:
m^2 ≡ a * 3 * t + b * 2 * s (mod 6)
where a and b are integers such that 3a + 2b = 1, and t and s are integers such that 2t ≡ 1 (mod 3) and 3s ≡ 1 (mod 2).
Solving for a and b, we get a = 1 and b = -1.
Solving for t and s, we get t = 2 and s = 2.
Substituting these values, we get:
m^2 ≡ 1 * 3 * 2 - 1 * 2 * 2 (mod 6)
m^2 ≡ 2 (mod 6)
Therefore, m^2 is congruent to 2 modulo 6, which is equivalent to 30 modulo 59.
Thus, m^2 is 30 modulo 59.
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the height of a can of coke is in 11 cm and the radius is 6 cm calculate the total surface area of the can in cm^3 assuming that the can is a closed cylinder
The total surface area of the can of coke is 641.143 cm².
What is the total surface area of the can?A can of coke has the shape of a cylinder. A cylinder is a three-dimensional object that is made up of a prism and two circular bases. The total surface area of a closed cylinder can be determined by adding the area of all its faces.
Total surface area of the closed cylinder = 2πr(r + h)
Where:
r = radius = 6cm h = height = 11 cm r = pi = 22 / 7Total surface area of the closed cylinder = (2 x 22/7 x 6) x (6 + 11)
(264 / 7) x (17)
37.714 x 17 = 641.143 cm²
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Can someone help me on these problems and show work please !
Answer:
1. 3 terms; degree 5
2. 2 terms; degree 3
3. 9mn³ + 14mn²
4. 9a^4b^3
Step-by-step explanation:
Problems 1 - 2:
Each product of a number and variables is a term. The number may be 1, so it is not written. Also, a term may not have a variable.
The degree of a term is the sum of the exponents of all the variables of the term. A plain variable, such as x has an exponent of 1 which is not written but must be added to determine the degree.
The degree of the polynomial is the same as the degree of the term with the highest degree.
1.
3 terms
degree 5
2.
2 terms
degree 3
Problems 3 - 4:
Combine like terms. Like terms have the same variables and exponents.
3.
6mn³ - mn² + 3mn³ + 15mn² =
= 6mn³ + 3mn³ - mn² + 15mn²
= 9mn³ + 14mn²
4.
a^4b^3 + 8a^4b^3 =
= 1a^4b^3 + 8a^4b^3
= 9a^4b^3
Which of the following functions has a vertical asymptote at x=2, a horizontal asymptote at f(x)=1, and a root at x=−1?
A. f(x)=3x+2+1
B. f(x)=−3x−2+1
C. f(x)=3x+2−1
D. f(x)=3x−2+1
what is the temperature in Celsius? (LOOK AT PIC)
Answer:
21
Step-by-step explanation:
(69.8-32)×(5/9)=21
Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning. After 10 hours of burning, a candle has a height of 25 centimeters. After 26 hours of burning, its height is 17 centimeters. What is the height of the candle after 21 hours
If the height of candle after 10 and 26 hours are 25 cm and 17 cm then the height of candle after 21 hours is 19.5 cm.
Given height of candle after 10 hours is 25 cm , height of candle after 26 hours is 17 cm.
We have to find the height of candle after 21 hours.
We have been given two points of linear function (10,25),(26,17).
We have to first form an equation which shows the height of candle after x hours.
let the hours be x and the height be y.
Equation from two points will be as under:
[tex](y-y_{1} )=(y_{2} -y_{1} )/(x_{2} -x_{1} )*(x- x_{1} )[/tex]
(y-25)=(17-25)/(26-10)* (x-10)
y-25=-8/16 *(x-10)
16(y-25)=-8(x-10)
16y-400=-8x+80
8x+16y=480
Now we have to put x=21 to find the height of candle after 21 years.
8*21+16y=480
168+16y=480
16y=480-168
16y=312
y=312/16
y=19.5
Hence the height of candle after 21 hours is 19.5 cm.
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How could the relationship of the data be classified? (1 point)
(see photo)
A fairly strong positive correlation
A fairly weak positive correlation
A fairly strong negative correlation
A fairly weak negative correlation
The relationship of the data can be classified as a fairly strong positive correlation.
What is positive correlation?
Correlation is a statistical measure used to measure the relationship that exists between two variables.
Positive correlation is when two variables move in the same direction. If one variable increases, the other variable also increases. When there is a positive correlation, the graph of the variables is upward sloping
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On a monday a friend says he will meet you again in 34 days. What day of the week will that be?
Answer:
On a Sunday?
Step-by-step explanation:
One day, eleven babies are born at a hospital. assuming each baby has an equal chance of being a boy or girl, what is the probability that at most nine of the eleven babies are girls?
The probability of having, at most, 9 girls, is 0.9515
How to get the probability?The probability that a random baby is a girl is:
p = 0.5
And the probability that a random baby is a boy is:
q = 0.5
Then the probability that, at most, 9 out of 11 babys are girls, is given by:
1 - p(10) - p(11)
Where P(10) is the probability that 10 of the babies are girls and p(11) is the probability that the 11 babies are girls.
p(10) = C(11, 10)*(0.5)^10*(0.5)^1 = C(11, 9)*(0.5)^11
Where C(11, 10) is the combinations of 10 elements that we can make with a set of 11 elements, such that:
C(11, 10)= 11!/(11 - 10)!*10! = 11
Replacing that, we get:
P = 11*(0.5)^11 = 0.0054
p(11) = C(11, 11)*0.5^11 = 1*0.5^11 = 0.0005
Then the probability is:
P = 1 - 0.0054 - 0.0005 = 0.9515
The probability of having, at most, 9 girls, is 0.9515
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PLEASE HELP ME I NEED HELP I'LL GIVE YOU BRAINLEST PLEASE I BEG YOU NICELY.
Can some one help me with this. This isn't school work this is math that I am doing at home on prodigy the app. I will mark you brainlest if you get this correct. Also look at both of the pictures one of them has a hint for you.
The perimeter of a rectangle is the sum of its side lengths.
A rectangle is special in that sides opposite one another have equal length. So if [tex]x[/tex] is the length of the horizontal sides, the total perimeter of the rectangle is
[tex]4\,\mathrm{cm} + 4\,\mathrm{cm} + x\,\mathrm{cm} + x\,\mathrm{cm} = (8+2x)\,\mathrm{cm}[/tex]
We're given the perimeter is actually 18 cm, so
[tex]8+2x = 18[/tex]
Solve for [tex]x[/tex].
[tex](8 + 2x) - 8 = 18 - 8[/tex]
[tex]2x = 10[/tex]
[tex]\dfrac12 \cdot 2x = \dfrac12 \cdot 10[/tex]
[tex]\boxed{x = 5}[/tex]
l=10m,b=8m,h=5m
Please answer
Step-by-step explanation:
we have given
l=10m
b=8m
h=5m
volume =?
area=?
volume =l*b*h
= 10*8*5
=400
area=2(lb+lh+bh)
=2(10*8+10*5+8*5)
=2(80+50+40)
=2(170)
=340
hope this is helpful please make me brainliest
David has kept track of his family’s grocery bills for the past 10 weeks, as shown in the table.
Week 1 2 3 4 5 6 7 8 9 10
Bill ($) 92 106 129 115 100 84 110 156 98 87
Would you choose to use a histogram, a circle graph, or a line graph to display the data? Explain your choice. Then make a display.
The best option that would be used to show the data would be the line graph.
Why the line graph is the bestThe reason I chose the line graph is that it would show us the trend in the data. This is in a way that we would see the periods there was a high bills.
Also the line graph is very simple to understand. The relationship and the changes in the data is easily seen.
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To find the 95% confidence interval for the population standard deviation using the bootstrap method. You repeatedly sample with replacement from the sample, tens of thousands of times. For each sample, you compute the sample standard deviation. What is the next step?.
The next line after computing the sample standard deviation is to; determine the 2.5th and 97.5th percentiles of the values.
How can the 95% confidence interval be determined?It follows from the task content that the 95% confidence interval for the population standard deviation using the bootstrap method in which case, after numerous sampling, the 2.5th and 97.5th percentiles of the standard deviations are determined.
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There are 3 pieces of glass that are cracked. if a rock is thrown by a lawn mower hits the window, what is the probability, that the rock hits a piece of glass that is cracked?
The chance or chance that the lawn mower will hit a chunk of glass that is already cracked is calculated with the aid of dividing the variety of glasses that are cracked by way of the full quantity of glasses. on this item, the unknown may be calculated through . The solution is, therefore, 0.20.
Opportunity is a measure of the chance of an event to arise. Many occasions cannot be predicted with overall reality. We are able to are expecting only the danger of an event to arise i.e. how likely they're to manifest, using it.
The possibility is the branch of arithmetic regarding numerical descriptions of how in all likelihood an occasion is to arise, or how possibly it's miles that a proposition is actual. The possibility of an occasion various between 0 and 1, where, roughly talking, 0 indicates the impossibility of the event and 1 shows reality.
The probability of an event can be calculated by possibility components via surely dividing the favorable range of effects through the full range of possible outcomes.
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Given: Quadrilateral PAST, TX = AX; TP || AS
Prove: Quadrilateral PAST is a parallelogram.
1) Quadrilateral PAST, TX=AX, [tex]\overline{TP} \parallel\overline{AS}[/tex] (given)
2) [tex]\angle XPT \cong \angle XSA[/tex] and [tex]\angle XTP \cong \angle XAS[/tex] (alternate interior angles theorem)
3) [tex]\triangle TXP \cong \triangle AXS[/tex] (AAS)
4) [tex]\overline{TP} \cong \overline{AS}[/tex] (CPCTC)
5) PAST is a parallelogram (a quadrilateral with two pairs of opposite congruent sides is a parallelogram)
(Adding to the other person's answer)
For the 5th step reason, put this: A quadrilateral is a parallelogram if a pair of opposite sides are parallel and congruent.
It won't work to just say something like the def. of parallelograms.
Solve for x when [tex]x^{yz} =y^{2}[/tex]
The value of x in x^yz = y^2 is [tex]x = \sqrt[yz]{y^2}[/tex]
How to solve for x?The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows
[tex]x^{yz} = y^2[/tex]
Take the yz root of both sides
[tex]\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}[/tex]
Apply the law of indices
[tex]x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}[/tex]
Divide yz by yz
[tex]x = \sqrt[yz]{y^2}[/tex]
Hence, the value of x in x^yz = y^2 is [tex]x = \sqrt[yz]{y^2}[/tex]
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Answer:
e
Step-by-step explanation:
Using euler's identity we can see that e^ipi=-1 and considering that i=y and i^2=-1 we can conclude that x=e
The perimeter of square JKLM is 48 units.
Square J K L M is shown. The length of J K is x + 3.
What is the value of x?
6
9
12
15
Answer:
9
(Correct On Edgen)
Please help with the bonus! Thank you:)
a. The function that models the situation is F(t) = 48(1.08)ˣ
b. The price of the stock 6 years from now is $76.17
c. Find the graph in the attachment
d. I receive a dividend of $0.026.
a. Write a function f(t) that models the situation.Since the stock price increases at a rate of 8% every year, and is initially $48, it follows exponential growth.
So, the current price [tex]F(t) = A(1 + r)^{t}[/tex] where
A = price at current moment = $48, r = rate of growth = 8% = 0.08 and t = number of yearsSo, [tex]F(t) = A(1 + r)^{t}[/tex]
[tex]F(t) = 48(1 + 0.08)^{t} \\= 48(1.08)^{t}[/tex]
So, the function that models the situation is F(t) = 48(1.08)ˣ
b. Determine the price of the stock 6 years from now?The price of the stock 6 years from now is gotten when t = 6.
So,
[tex]F(t) = 48(1.08)^{t} \\= 48(1.08)^{6} \\= 48(1.5869)\\= 76.17[/tex]
So, the price of the stock 6 years from now is $76.17
c. Sketch a graph of the price of the function vs time in yearsFind the graph in the attachment
d. BonusSince every quarter, the company pays a dividend of 1.5 %, the rate per year would be r = 1.5 % ÷ 1/4 year = 1.5 % × 4 = 6 % per year.
Since they pay at a rate, r = 6 % = 0.06 of the stock price, F(t) as dividend.
After n years, the dividend is D = (r)ⁿF(t)
= (0.06)ⁿF(t)
So, [tex]D = (0.06)^{t}F(t) \\= (0.06)^{t}[4.8(1.08)^{t}][/tex]
So, after 3 years when t = 3,
[tex]D = (0.06)^{t}[4.8(1.08)^{t}]\\D = (0.06)^{3}[4.8(1.08)^{3}]\\D = 0.000216 \times 48 \times 1.2597\\D = 0.013[/tex]
Since there are 3 shares, the total dividend would be D' = 3D
= 3 × 0.013
= 0.026
So, i receive a dividend of $0.026
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Which monomials are perfect squares? Select three options.
6x2
9x8
17x9
25x12
36x16
Answer: B, D, E
Step-by-step explanation:
Select the correct answer.
The variable b varies directly as the square root of c. If b= 100 when c=4, which equation can be used to find other combinations of b and c?
A b= 25c
B.
b = 50√e
OC. b = 200c
OD. b√e 50
-
Reset
Next
The equation in which b varies directly as the square root of c is b = 50 · √c. (Correct choice: B)
What is the equation of the direct variation between two variables?
In this problem we have a case of direct variation between two variables, which is mathematically described by a direct proportionality model, whose form and characteristics are shown below:
b ∝ √c
b = k · √c (1)
Where k is the proportionality constant.
First, we determine the value of the constant of proportionality by substituting on b and c and clearing the variable: (b = 100, c = 4)
k = b / √c
k = 100 / √4
k = 100 / 2
k = 50
Then, the equation in which b varies directly as the square root of c is b = 50 · √c. (Correct choice: B)
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A triangular face of the roof of the garage has two sides
that are √93 feet in length each and a base of length
186 feet. Is the roof a right triangle? Explain the steps
to take to determine whether the roof forms a right
triangle.
Answer:
The roof does form a right triangle.
Step-by-step explanation:
If it is a right triangle then it will obey the Pythagoras Theorem.
Now (√186)^2 = (√93)^2 + (√93)^2
186 = 93 + 93 = 186
So it obeys the theorem and is therefore a right triangle.
TRUE OR FALSE: No matter the population distribution from which a sample of size n is taken, we can use the normal distribution to approximate the distribution of the sample mean as long as n is large enough.
Answer:
true
Step-by-step explanation:
mean we show up the distribution
x + x/3 = 4/9
solve for x!!
Answer:
x=1/3
Step-by-step explanation:
A roll of aluminum for you measure 76.2 m long by 304 m wide what is the length in millimeters
Answer:
76,200 mm
Step-by-step explanation:
1 meter = 1000 mm, by definition. Make that a conversion factor:
(1 meter)/(1000 mm), or (1000 mm)/(1 meter). Both are equal to 1, since 1 meter = 1000 mm. We can multiply anything by 1, so take the original measurement of length of 76.2 meters, and multiply it by (1000 mm)/(1 meter).
(76.2 meters)*((1000 mm)/(1 meter)) = 76,200 mm. The meters cancels, leaving just mm, the desired unit.
A coffee shop gives the customer a free cup of coffee after the purchase of 5 cups: a.) industrial marketing program b.) loyalty marketing program c.) product sampling program d.) cooperative marketing program
Two fishing boats leave the same dock at the same time. One boat heads northeast and is travelling at a speed of 15 km/h while the other is travelling northwest at 18 km/h. After 45 minutes, the boats are 14.0 km apart. Assuming that both boats are travelling in straight paths, what is the angle between their paths to the nearest degree?
The angle between their paths to the nearest degree is 68⁰.
Displacement of each boats after 45 minutes
first displacement, a = 15 km/h x (45/60)
first displacement, a = 11.25 km
second displacement, b = 18 km/h x (45/60)
b = 13.5 km
Angle between their paths to the nearest degreec² = a² + b² - 2ab(cosθ)
2ab(cosθ) = a² + b² - c²
cosθ = (a² + b² - c²)/(2ab)
cosθ = (11.25² + 13.5² - 14²) / (2 x 11.25 x 13.5)
cosθ = 0.371
θ = arc cos(0.371)
θ = 68.22 ⁰
Thus, the angle between their paths to the nearest degree is 68⁰.
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help me I need help now!!
what help? how can i help you?
While traveling to Europe, Phelan exchanged 250 US dollars for euros. He spent 150 euros on his trip. After returning to the United States he converts his money back to US dollars. How much of the original 250 US dollars does Phelan now have? Round to the nearest cent.
The computation shows that the amount will be 44.70 Dollars.
How to illustrate the information?The options are missing: Here are the missing options:
A. 44.70 US dollars
B. 73.06 US dollars
C. 136.87 US dollars
D. 140.41 US dollars
For solving this question first we will convert the USD to euros.
The conversion rate we have is:
1 euro = 1.3687 USD
250/1.3687 = 182.655 euros
Now we will subtract it from what he has spent:
= 182.655 - 150
= 32.655 euros
Now we will again convert it back to USD. This will be:
32.655 euros * 1.3687 = 44,695 us dollars
Therefore, the answer is 44.70.
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The graph of f(x)= |x| is transformed to g(x) = x + 11-7. On which interval is the function decreasing?
O (-∞, -7)
O (-00,-1)
O (-00, 1)
O (-∞0,7)
Answer:
The interval of the decreasing function is (-∞ , -1) ⇒ g(x)
The interval of the decreasing function is (-∞ , 0) ⇒ f(x)
Step-by-step explanation:
* Lets explain how to solve it
- Decreasing function means a function with a graph that moves
downward as it is followed from left to right.
- For example, any line with a negative slope is decreasing function
- Lets look to the attached graph to understand the meaning of the
decreasing function
∵ f(x) = IxI ⇒ green graph
∵ g(x) = Ix + 1I - 7 ⇒ purple graph
- From the graph f(x) translated 1 unit to the left and 7 units down to
form g(x)
- The domains of f(x) and g(x) are all real numbers {x : x ∈ R}
- The range of f(x) is {y : y ≥ 0}
- The range of g(x) is {y : y ≥ -7}
# For f(x)
- The slope of the green line from (-∞ , 0) is negative
- The slope of the green line from (0 , ∞) is positive
# For g(x)
- The slope of the purple line from (-∞ , -1) is negative
- The slope of the purple line from (-1 , ∞) is positive
∵ The line with negative slope represent decreasing function
∴ The interval of the decreasing function is (-∞ , -1) ⇒ g(x)
∴ The interval of the decreasing function is (-∞ , 0) ⇒ f(x)
Two fishing boats leave the same dock at the same time. One boat heads northeast and is travelling at a speed of 15 km/h while the other is travelling northwest at 18 km/h. After 45 minutes, the boats are 14.0 km apart. Assuming that both boats are travelling in straight paths, what is the angle between their paths to the nearest degree?
The boat speeds of 15 km/h and 18 km/h, directions, and the time of travel of 45 minutes gives the angle between their paths as approximately 68°.
How can the angle between the paths of the boats be found?The given parameters are;
Direction of the first boat = Northeast
Speed of the first boat = 15 km/h
Direction of the second boat = Northwest
Speed of the second boat = 18 km/h
Distance between the boats after 45 minutes = 14.0 km.
45 minutes = 0.75 × 1 hour
Distance traveled by the first boat in 45 minutes, d1, is therefore;
d1 = 15 km/h × 0.75 hr = 11.25 km
For the second boat, we have;
d2 = 18 km/h × 0.75 hr = 13.5 km
Using cosine rule, we have;
14² = 11.25² + 13.5² - 2 × 11.25 × 13.5 × cos(A)
Where A is the angle between the paths of the two boats.
Which gives;
[tex]cos(A) = \frac{361}{972} [/tex]
[tex] A= \mathbf{ arccos\left(\frac{361}{972} \right) }\approx 68^\circ [/tex]
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If a = √3-√11 and b = 1 /a, then find a² - b²
If [tex]b=\frac1a[/tex], then by rationalizing the denominator we can rewrite
[tex]b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8[/tex]
Now,
[tex]a^2 - b^2 = (a-b) (a+b)[/tex]
and
[tex]a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8[/tex]
[tex]a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8[/tex]
[tex]\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}[/tex]