.Let S=∑n=1[infinity]an be an infinite series such that SN=7−(9/N^2).
(a) What are the values of\sum_{n=1}^{10}a_{n}and\sum_{n=4}^{16}a_{n}?
\sum_{n=1}^{10}a_{n}=_________________________
\sum_{n=4}^{16}a_{n}=_______________________
(b) What is the value of a3?
a3= ______________________
(c) Find a general formula for an.
an= _____________________
(d) Find the sum\sum_{n=1}^{\infty}a_{n}.
\sum_{n=1}^{\infty}a_{n}=______________________

Answers

Answer 1

The sum of the series is ∑n=1^∞ an = S∞ = 7.

(a) We have the formula for the partial sums:

Sn = ∑n=1[infinity]an

And we know that:

SN = 7 - (9 / N^2)

So we can find the value of a1 by taking N to infinity:

S∞ = lim(N→∞) SN = lim(N→∞) (7 - (9 / N^2)) = 7

a1 = S1 - S0 = S1 = 7 - S∞ = 0

Now we can use the formula for partial sums to find the other two sums:

∑n=1^{10}an = S10 - S0 = (7 - (9 / 10^2)) - 0 = 6.91

∑n=4^{16}an = S16 - S3 = (7 - (9 / 16^2)) - (7 - (9 / 3^2)) = 6.977

Therefore, ∑n=1^{10}an = 6.91 and ∑n=4^{16}an = 6.977.

(b) We can find a3 using the formula for partial sums:

S3 = a1 + a2 + a3

We know that a1 = 0 and we can find S3 from the formula for partial sums:

S3 = 7 - (9 / 3^2) = 6

So we have:

a3 = S3 - a1 - a2 = 6 - 0 - a2 = 6 - a2

We don't have enough information to determine a2, so we cannot determine the exact value of a3.

(c) We can find a general formula for an by looking at the difference between consecutive partial sums:

Sn - Sn-1 = an

So we have:

a1 = S1 - S0 = 7 - S∞ = 0

a2 = S2 - S1 = (7 - (9 / 2^2)) - 7 = -1/4

a3 = S3 - S2 = (7 - (9 / 3^2)) - (7 - (9 / 2^2)) = 1/9 - 1/4 = -7/36

We can see that the denominators of the fractions are perfect squares, so we can make a guess that the general formula for an involves a square in the denominator. We can then use the difference between consecutive terms to determine the numerator. We get:

an = -9 / (n^2 (n+1)^2)

(d) To find the sum of the series, we can take the limit of the partial sums as n goes to infinity:

S∞ = lim(n→∞) Sn

We can use the formula for the partial sums to simplify this expression:

Sn = 7 - (9 / n^2)

So we have:

S∞ = lim(n→∞) (7 - (9 / n^2)) = 7 - lim(n→∞) (9 / n^2) = 7

Therefore, the sum of the series is ∑n=1^∞ an = S∞ = 7.

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