The frequency of this wave will be 1 × 10¹¹ Hz. Option d is correct. Frequency is the inverse of the time period.
What is the frequency?Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.
The given data in the problem is;
v is the speed of light = 2 x 10⁸ m/s
[tex]\lambda[/tex] is the wavelength = 2 x 10⁻³ m,
f is the frequency of the wave is to be found;
Frequency is given by the formula as,
[tex]\rm v = \lambda \times f \\\\\ \rm f = \frac{v}{\lambda} \\\\ \rm f = \frac{2 \times 10^8}{2 \times 10^-3} \\\\ \rm f = 1 \times 10^{11} \ Hz[/tex]
Hence the frequency of this wave will be 1 × 10¹¹ Hz. Option d is correct.
To learn more about the frequency reference the link;
https://brainly.com/question/14926605
1. A buoyant force of 790 N lifts a 214 kg sinking boat.What is the boat's
net acceleration?
Choose Yes or No to tell if the number 9.81 will make each equation true.
12.47 – □ = 2.66
8.05 + □ = 17.96
14.08 – □ = 4.17
3.67 + □ = 13.48
Answer:
yes
no
no
yes
Explanation:
What type of force occurs when one object pushes or pulls a second object while they
are touching?
★・・・・・・★・・・・・・★・・・・・・★・・・・・・★・・・・・・
»Answer
【Contact forces involve push, pull and friction. A contact force is when two interacting objects are touching, for example: when you throw a ball you are using a contact force.】
hope it helps
can u give a thanks
thank you
★・・・・・・★・・・・・・★・・・・・・★・・・・・・★・・・・・・
A rock is thrown downward from the top of a cliff with an initial speed of -13m/s.If the rock hits the ground after 2.7 s, what is the height of the cliff
Answer:
0.62 m down.
Explanation:
Use the formula d= vi*t +1/2 at^2
So the initial speed or vi is -13 m/s and time is 2.7 s and a or acceleration is 9.8 m/s^2 down ( because it's the gravity). So you plugged all the values and you will get 0.62 m. We put the down because the acceleration is saying down. Because displacement is vector quantity you have to show the direction of it.
An 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds. What is the truck’s acceleration and how much momentum does it have after it has reached this final velocity?
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
a = (18.0 m/s − 0 m/s) / (6.00 s)
a = 3.00 m/s²
Momentum is mass time velocity.
p = mv
p = (8000 kg) (18.0 m/s)
p = 144,000 kg m/s
When an 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds then the truck’s acceleration would be 3 m/s² and the momentum after it has reached this final velocity would be 144000 kgm/s.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
Mathematically the formula of the momentum is
P = mv
where P is the momentum of the particle
m is the mass of the particle
v is the velocity by which the particle is moving
As given in the problem An 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds
By using the first equation is given as follows
v = u + at
18 =0 + a×6
a = 3 m/s²
As given in the problem the final velocity of An 8000.0 kg truck is 18 m/s
the momentum is given by the formula
P = mv
P= 8000×18
P = 144000 kgm/s
Thus, the truck’s acceleration would be 3 m/s², and the momentum after it has reached this final velocity would be 144000 kgm/s.
Learn more about momentum from here
brainly.com/question/17662202
#SPJ5
Which of the following statements are true
Answer:
none of them
Explanation:
Answer:
Did u forget to add a pic?
Explanation:
The driver of a car slams on the brakes, causing the car to slow down at a rate of
20.0ft/s as the car skids 295ft to a stop.
How long does the car take to stop?
What was the car’s initial speed?
Answer:
The time taken for the car to stop is 5.43 s.
The initial velocity of the car is 108.6 ft/s
Explanation:
The following data were obtained from the question:
Acceleration (a) = –20 ft/s² (since the car is coming to rest)
Distance travalled (s) = 295 ft
Final velocity (v) = 0 ft/s
Time taken (t) =?
Initial velocity (u) =?
Next, we shall determine the initial velocity of the car as shown below:
v² = u² + 2as
0² = u² + (2 × –20 × 295)
0 = u² + (–11800)
0 = u² – 11800
Collect like terms
0 + 11800 = u²
11800 = u²
Take the square root of both side
u = √11800
u = 108.6 ft/s
Therefore, the initial velocity of the car is 108.6 ft/s.
Finally, we shall determine the time taken for the car to stop as shown below:
Acceleration (a) = –20 ft/s² (since the car is coming to rest)
Final velocity (v) = 0 ft/s
Initial velocity (u) = 108.6 ft/s
Time taken (t) =?
v = u + at
0 = 108.6 + (–20 × t)
0 = 108.6 + (–20t)
0 = 108.6 – 20t
Collect like terms
0 – 108.6 = – 20t
– 108.6 = – 20t
Divide both side by –20
t = – 108.6 / –20
t = 5.43 s
Therefore, the time taken for the car to stop is 5.43 s.
pls awnser short i need awnsers
Answer:
4. 0.12mm
5:
a. screw gauge
b. caliper
Answer:
0.11 mm
vernier calipers
im not sure about the sure about B
Explanation: