Local extreme Value for each of the Following A) F(x)=x^² - 4x² +5​

The return on the investment is 3%

The given parameters are:

Buying rate = 7%

Selling rate = 10%

The return on the investment is

ROI = Selling - Buying

So, we have:

ROI = 10% - 7%

Evaluate

ROI = 3%

Hence, the return on the investment is 3%

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Answer:

(0, -2) and (2, 0)

Step-by-step explanation:

The solution to a systems of equations is when the x and y values are equal for two equations. This can also been seen as when the two equations intersect. So by looking at the graph you see the line and the circle intersect at the point (2, 0) and (0, -2) which are going to be the two solutions to the systems of equations.

Applying the Pythagorean theorem, the missing side of the triangle is: C. √193 km.

To find the missing side (x) in the right triangle, based on the Pythagorean theorem, we would have the following equation:

x = √(12² + 7²)

x = √(144 + 49)

x = √193

The missing side of the triangle is: C. √193 km

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Answer:

C.)  193√ km

Step-by-step explanation:

I got it right on founders edtell

the probability of getting heads on a two-face coin is simply 1/2.

now, what is the probability of getting 1/2 AND 1/2 AND 1/2 AND 1/2 AND 1/2?   well, AND means "times", namely

[tex]\cfrac{1}{2}\stackrel{and}{\cdot }\cfrac{1}{2}\stackrel{and}{\cdot }\cfrac{1}{2}\stackrel{and}{\cdot }\cfrac{1}{2}\stackrel{and}{\cdot }\cfrac{1}{2}\implies \cfrac{1}{32}[/tex]

well, and since it's a two-face coin, the probability for each face is equal, 1/2, so Heads has a chance of 1/2 each time, or we can also say that Tails has a chance of 1/2 each time, so if Tails has the same probability over 5 times as Head does.

Answer: c. the mean is greater than the median

Explanation:

To find out the correct answer, we first must know the true meanings and the method of calculation of the terms, "mean", "mode" and "median".

Mean: The mean is a type of average. It is the sum of all the values in a set of data, such as numbers of measurements, divided by the numbers of values on the list.

[tex]\bar{x} = \dfrac{\sum x}{n}[/tex]                                      where, [tex]\bar{x}=[/tex] sample mean
                                                               [tex]\sum x =[/tex] sum of each value in sample
                                                               [tex]n =[/tex] number of values in the sample

Example: in {6, 3, 9, 6, 6, 5, 9, 3} the mean is 5.875 (6+3+9+6+6+5+9+3/8).
                           
                                         

Mode: The mode is the number which appears most often in a set of numbers.
Example: in {6, 3, 9, 6, 6, 5, 9, 3} the Mode is 6.

Median: The median is the "middle" of a sorted list of numbers in ascending order (small to big). To find the Median, place the numbers in value order and find the middle.
Example: in {6, 3, 9, 6, 6, 5, 9, 3} the median is 6. (in 3,3,5,6,6,9,9, the middle number is 6 )

with an even amount of numbers things are slightly different.
In that case we find the middle pair of numbers, and then find the value that is half way between them. This is easily done by adding them together and dividing by two. (basically averaging the middle two numbers incase there is an even set of numbers)
Example: 3, 13, 7, 5, 21, 23, 23, 40, 23, 14, 12, 56, 23, 29

When we put those numbers in order we have:

3, 5, 7, 12, 13, 14, 21, 23, 23, 23, 23, 29, 40, 56

There are now fourteen numbers and so we don't have just one middle number, we have a pair of middle numbers.

3, 5, 7, 12, 13, 14, 21, 23, 23, 23, 23, 29, 40, 56

In this example the middle numbers are 21 and 23.

To find the value halfway between them, add them together and divide by 2: 21 + 23 = 44, then 44 ÷ 2 = 22

So the Median in this example is 22.
(Note that 22 was not in the list of numbers ... but that is OK because half the numbers in the list are less, and half the numbers are greater.)

Now that you understand the terms clearly, let's find out the mean, mode and median from your given set of numbers.
                                           5, 15, 25, 30, 3

Mean: (5+15+25+30+3)/5  is, 15.6
Mode: None since none of the numbers repeated more than once.
Median: 3,5,15,25,30  , so the middle number is 15 .

Since there is no mode, option d. can never be the answer. And clearly, 15.6 is greater than 15 so the answer should be c. the mean is greater than the median.

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Answer: 14.8

Step-by-step explanation: If the number in the hundredths place is less than 5, you must round down. On the contrary, if that number is 5 or greater, you must round up. This applies for rounding to any place not just the tenths place. For example, if you were to round it to the ones place, the answer would be 15.

Answer:

14.8

Step-by-step explanation:

The hundredth is smaller than 5, therefore you have to round down.

hope it helps

Considering the given rectangle, the coordinates of p are (6,7).

For x, there are two vertices at x = 3 and one at x = 6, hence the x-coordinate of p is x = 6.

For y, there are two vertices at y = 9 and one at y = 7, hence the y-coordinate of p is y = 7.

Then, the coordinates of p are (6,7).

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Answer: Point of intersection (0, -2)

Step-by-step explanation:

Answer:

S =  (0, -2)

Step-by-step explanation:

Convert both standard form equations to slope-intercept form.

-5x+2y=-4 ⇒ y = 5/2(Decimal form: 2.5)x - 2

2x-y=2 ⇒ y = 2x - 2

Given:

⇒ L1 = y = 5/2x - 2

⇒ L2 = y = 2x - 2

The intersection is point:

⇒ S = (0, -2)

Steps:

To find intersection point we need to solve the following system of equations.

STEP 1: Solve for x

5/2x - 2 = 2x - 2

5/2x - 2x = -2 + 2

1/2x = 0

x = 0

STEP 2:  Solve for y by substituting x = 0 into  first equation.

y = 5/2 * 0 - 2 = 0 - 2 = -2

Answer:

24 F

Step-by-step explanation:

Temp increases by 4F per hour.

-8F - 6F = 12F / 3hours

Answer:  

- 2/3

Step-by-step explanation:

Answer:

Any equation that has the same slope as the line y = -2/3x + 1 but a different y-intercept will be parallel because the lines will never intersect. For example, y = -2/3x + 2 or y = -2/3x + 3.

Brainliest, please :)

Answer:

a=10%, b=25/100, c=1/2

Step-by-step explanation:

a: If the denominator is exactly 100, then the numerator represents a percentage.

b: when you change a fraction to have a greater denominator, an easy way to figure out how to change the numerator to match it and make the value of the rewritten fraction equal to the old version, is to divide the new value of the denominator by the old value (in this case being 100/4=25), and put the answer where the numerator goes.

c: When simplifying a fraction with a lesser numerator than denominator, find the greatest common factor (a factor is a whole number a number can be divided by without resulting in a negative or a decimal number) and divide both the numerator and denominator by it.

The limit of

[tex]$\lim _{x \rightarrow 0}\left(\frac{x \cos (\theta)-\theta \cos (x)}{x-\theta}\right)=1$$[/tex].

In Mathematics, a limit exists described as a value that a function approaches the output for the provided input values. Limits exist necessary in calculus and mathematical analysis and exist utilized to determine integrals, derivatives, and continuity.

Given:

[tex]$\lim _{x \rightarrow 0}\left(\frac{x \cos (\theta)-\theta \cos (x)}{x-\theta}\right)$$[/tex]

Substitute the value x = 0, then we get

[tex]$=\frac{0 \cdot \cos (\theta)-\theta \cos (0)}{0-\theta}$$[/tex]

Simplify the above equation, we get

[tex]$\frac{0 \cdot \cos (\theta)-\theta \cos (0)}{0-\theta}= 1$[/tex]

Therefore, the limit of

[tex]$\lim _{x \rightarrow 0}\left(\frac{x \cos (\theta)-\theta \cos (x)}{x-\theta}\right)=1$$[/tex]

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The lateral area of the cone is calculated as: B. 47 in.².

Lateral area = πrl

Given the following:

Slant height (l) = 5 inches

Radius (r) = 3 inches.

π = 3.14

Plug in the values

Lateral area = (3.14)(3)(5)

Lateral area ≈ 47 in.²

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The radius of the cylinder should be approximately 2.040 inches long.

The volume required to store the powder is the sum of the volumes of the cylinder and the cone, whose expression is in this case:

204 in³ = (π/3) · r² · (4 in) + π · r² · h

204 in³ = (4/3 + h) · π · r²

204 in³ = (4/3 + 7 · r) · π · r²

204 = (4π/3) · r² + 7π · r³

7π · r³ + (4π/3) · r² - 204 = 0

The positive roots of the cubic equation are:  

r ≈ 2.040 in

The radius of the cylinder should be approximately 2.040 inches long.

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See below for the missing terms of the sequences

The given parameters are:

T4 = 30

T5 = 49

Calculate the third term as follows:

T3 = T5 - T4

T3 = 49 - 30

T3 = 19

Calculate the second term as follows:

T2 = T4 - T3

T2 = 30 - 19

T2 = 11

Calculate the first term as follows:

T1 = T3 - T2

T1 = 19 - 11

T1 = 8

Hence, the first term of the sequence is 8

The given parameters are:

T2 = x

T3 = y

Calculate the first term as follows:

T1 = T3 - T2

T1 = y - x

Calculate the fourth term as follows:

T4 = T2 + T3

T4 = x + y

Calculate the fifth term as follows:

T5 = T3 + T4

T5 = y + x + y

T5 = x + 2y

Hence, the missing terms of the sequence are y - x, x + y and x + 2y

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Answer:

1.6 < x < 9.6

Step-by-step explanation:

given 2 sides of a triangle then the third side x is in the range

difference of 2 sides < x < sum of 2 sides , that is

5.6 - 4 < x < 5.6 + 4

1.6 < x < 9.6

Induced pluripotent stem cells can be a valuable tool in science and medicine because: A. induced pluripotent stem cells can become any cell type in the body, but are from adults, avoiding the controversies associated with embryonic stem cells.

A cell can be defined as the fundamental functional, structural and smallest unit of life, which is typically found in all living organisms.  

In Science, all living organisms are broadly grouped into two (2) main categories according to cell type and these include the following;

Basically, the reason why induced pluripotent stem cells can be a valuable tool in science and medicine is simply because they can become any cell type within the body of a living organism, but are usually derived from adults that are avoiding the controversies associated with embryonic stem cells.

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Complete Question:

Induced pluripotent stem cells are cells from adults that have been reprogrammed to imitate embryonic stem cells. Why might induced pluripotent stem cells be a valuable tool in science and medicine?

A. Induced pluripotent stem cells can become any cell type in the body, but are from adults, avoiding the controversies associated with embryonic stem cells

B. Induced pluripotent stem cells are the only type of stem cell that's truly pluripotent.

C. Induced pluripotent stem cells may become any cell type in the body, but are fraught with ethical questions over their use.

D. Induced pluripotent stem cells are derived from adult cells and therefore may have DNA abnormalities, allowing scientists to understand the effects of sun exposure or toxins on DNA

The vertices of the feasible region are as follows,

(-14, -11), (9, -11) and (6, 4)

What is a Feasible Region?

The area of the graph where all constraints are satisfied is the feasible solution zone or feasible region. It might also be thought of as the point where each constraint line's valid regions intersect. Any decision in this region would lead to a workable resolution for our objective function.

Vertices of the Feasible Region

As it can be seen in the graph, the vertices of the feasible region surrounded by the given constraints are:

(-14, -11), (9, -11) and (6, 4)

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The equation that shows the proportional relationship between his defense and offense cards is y = 2x

An equation is an expression that shows the relationship between two or more numbers and variables.

Let y represent the defense cards and x represent the offense cards.

For every 2 offense cards, he owns 4 defense cards. Hence:

4 = 2m

m = 2

y = 2x

The equation that shows the proportional relationship between his defense and offense cards is y = 2x

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5pi/12 radians

The arc measure is 75, so theta must also be the same. if theta is 75, and 75 in radians is 5pi/12 radians, then the answer is that.

Using translation concepts, it is found that g(x) is positive on the following interval:

(3, ∞)

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

Function [tex]g(x) = \sqrt[3]{x - 3}[/tex] is a shift right of 3 units of [tex]f(x) = \sqrt[3]{x}[/tex], which is positive on the interval (0, ∞), hence g(x) is positive on the interval (3, ∞).

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Answer:

[tex]\frac{\sqrt{41}}{4}[/tex]

Step-by-step explanation:

sec(theta) is defined as: [tex]sec(\theta)=\frac{1}{cos(\theta)} = \frac{hypotenuse}{adjacent}[/tex]

In the diagram you provided the hypotenuse of the triangle is sqrt(41) and the opposite side is 5, using these two sides, we can solve for the adjacent side by using the Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex]

So this gives us the equation where a=adjacent side:

[tex]a^2+5^2=\sqrt{41}^2[/tex]

[tex]a^2+25=41[/tex]

Subtract 25 from both sides

[tex]a^2=16[/tex]

Take the square root of both sides

[tex]a=4[/tex]

So now plug this into the definition of sec(theta) and you get: [tex]\frac{\sqrt{41}}{4}[/tex]. This is in most simplified form since 41, has no factors besides 41 and 1.

Answer:

obtuse

Step-by-step explanation:

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

In the above problem, it's given that one of the angles of the triangle exceeds 90° [ that is : 97° ]

[tex] \qquad \large \sf {Conclusion} : [/tex]

hence, it's an obtuse angled triangle

Answer:

ok

this called f to do

Step-by-step explanation:

1. take a _____

73 division 84, 649 would give 8. 64 × 10^-4

In order to determine the value of the division, we have

= [tex]\frac{73}{84649}[/tex]

Using the calculator, put the values in

We would have

= 8. 64 × 10^-4

Thus, 73 division 84, 649 would give 8. 64 × 10^-4

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Let [tex]x[/tex] and [tex]y[/tex] be the amounts of available alloy (AA) and pure magic steel that are used, so we also have

[tex]x + y = 2.7[/tex]

DA13 is supposed to contain 7% gold, 3% silver, and 90% steel, so that 2.7 kg of it is made up of

[tex]0.07 \times 2.7 \,\mathrm{kg} = 0.189 \,\mathrm{kg} \text{ gold}[/tex]

[tex]0.03 \times 2.7 \,\mathrm{kg} = 0.081 \,\mathrm{kg} \text{ silver}[/tex]

[tex]0.90 \times 2.7 \,\mathrm{kg} = 2.43 \,\mathrm{kg} \text{ magic steel}[/tex]

For each kg of the available alloy (AA), there is a contribution of 0.21 kg of gold, 0.09 kg of silver, and therefore 0.70 kg of steel; [tex]x[/tex] kg of it will contain [tex]0.21x[/tex] kg of gold, [tex]0.09x[/tex] kg of silver, and [tex]0.70x[/tex] kg of steel. Each kg of magic steel of course contributes 1 kg of steel; [tex]y[/tex] kg of it will contribute [tex]y[/tex] kg of steel.

Then the dwarves need

• total gold: [tex]0.21x = 0.189[/tex]

• total silver: [tex]0.09x = 0.081[/tex]

• total steel: [tex]0.70x + y = 2.43[/tex]

Solve for [tex]x[/tex] and [tex]y[/tex]. The first two equations are consistent and give [tex]x = 0.90[/tex], and substituting this into the third we find [tex]y = 1.80[/tex]. So the dwarves must combine 0.90 kg of AA and 1.80 kg of magic steel.

Answer:

A minimum of 21250 packets per day.

Step-by-step explanation:

If Monday produced 15,000 packets, and Tuesday was closed they produced 15,000 packets in 2 days.

The factory is open 6 days a week.

They need 100,000 packets.

They have 15,000 packets.

6 subtract 2 is 4.

100,000 subtract 15,000 is 85,000.

They need 85,000 packets in 4 days.

That is a minimum of 21250 packets per day.

Using derivatives, the equation of the tangent line is: y + 2= -(x + 2)

The equation is:

[tex]y - y_0 = m(x - x_0)[/tex]

In which m is the derivative at point [tex](x_0, y_0)[/tex].

The function is:

[tex]x^2 + y^2 = 8[/tex].

Applying implicit differentiation, the derivative is:

[tex]2x\frac{dx}{dx} + 2y\frac{dy}{dx} = 0[/tex]

[tex]2ym = -2x[/tex]

[tex]m = -\frac{x}{y}[/tex]

We have that x = y = -2, hence m = -1 and the equation is:

y + 2= -(x + 2)

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Debido a restricciones de longitud invitamos cordialmente a leer la explicación de esta pregunta para aprender sobre las cuestiones de las ecuaciones cónicas.

Según la geometría analítica, existen cinco tipos de secciones cónicas: recta, circunferencia, elipse, parábola e hipérbola. Aquí se presentan problemas que emplean este tipo de ecuaciones.

1) La trayectoria de la rana describe la forma de una parábola. Asumimos que el punto máximo de la trayectoria de la rana es de la forma (h, k) = (0, k), entonces tenemos que la ecuación de la parábola es:

y - k = C · x²       (1)

Donde C es la constante del vértice.

Si sabemos que (h, k) = (0, 3) y (x, y) = (9, 0), entonces la ecuación de la parábola es:

C = (0 - 3) / 9²

C = - 1 / 27

La ecuación de la parábola es y - 3 = (- 1 / 27) · x².

2) Se determina el tipo de categoría de cada ecuación:

a) 3 · x - 2 · y + 4 = 0: Recta (a · x + b · y + c = 0)

b) 4 · x + y² - 7 = 0: Parábola ((y² - k) = 4 · p · (x - h))

c) x² + y² = 16: Circunferencia ((x - h)² + (y - k)² = r²)

d) y = x³ - 3 · x + 1: Ecuación cúbica

e) x² + 4 · y² = 4: Elipse (b² · (x - h)² + a² · (y - k)² = a² · b²)

3) Se debe hallar el valor C de la función lineal tal que S = 0.35 por medios algebraicos:

0.35 = 0.03 + 1.805 · C

0.32 = 1.805 · C

C = 0.32 / 1.805

C = 0.177

4) El arco semielíptico tiene una longitud de semieje mayor de 25 pies (paralelo al eje x) y una longitud de semieje menor de 15 pies (paralelo al eje y). Si consideramos que el centro de la elipse está en el origen, entonces tenemos que la ecuación es:

x² / 25² + y² / 15² = 1

y = 15 · √(1 - x² / 25²)

y = 15 · √(1 - 12² / 25²)

y = 13.159 pies

5) a) y b) Ahora graficamos la hipérbola y presentamos las ubicaciones de los focos y las asíntotas correspondientes. a) Las ecuaciones de las asíntotas son y = ± (3 / 2) · x, b) Las ecuaciones de las asíntotas son y = ± (√ 2 / 2) · x.

c) Se puede determinar la naturaleza de cada ecuación por métodos algebraicos:

9 · x² - 4 · y² - 54 · x - 16 · y + 29 = 0

[9 · x² - 2 · 9 · (3 · x) + 81] - [4 · y² - 2 · 8 · (2 · y) + 64] = 116

(3 · x - 9)² - (2 · y - 8)² = 116

9 · (x - 9)² - 4 · (y - 4)² = 116

(x - 9)² /12.889 - (y - 4)² / 29 = 1  - Hipérbola

4 · x² + 2 · y² - 7 · x + y - 5 = 0

[4 · x² - 2 · (7 / 4) · (2 · x) + 49 / 16] + [2 · y² + 2 · (√2 / 2) · (√2 · y) + 1 / 2] = 5

(2 · x - 7 / 4)² + (√2 · y + √2 / 2)² = 5

4 · (x - 7 / 8)² + 2 · (y + 1 / 2)² = 5

(x - 7 / 8)² / 1.25 + (y + 1 / 2)² / 2.5 = 1  - Elipse  

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The value of the circumference (C) of a circle, having a radius (r) = 0.8695 mm, using the formula C = 2πr, is calculated to be 5.4632296245926504416865368435231‬ mm.

A circle is a shape formed by all points in a plane that are at a particular distance from the center.

The linear distance around a circle is defined as its circumference. In other words, if a circle is opened to produce a straight line, the length of that line equals the circumference of the circle.

The formula for the circumference of a circle is given:

C = 2πr,

where C is the circumference of the circle, r is its radius, and π is a constant.

We are asked to find the circumference of the circle (C), given its radius (r) = 0.8695 mm.

Using the formula of the circumference C = 2πr, we can find the circumference as:

C = 2*π*(0.8695) mm,

or, C = 5.4632296245926504416865368435231‬ mm.

Thus, the value of the circumference (C) of a circle, having a radius (r) = 0.8695 mm, using the formula C = 2πr, is calculated to be 5.4632296245926504416865368435231‬ mm.

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