Looking north, two skyscrapers are sighted from the viewing deck of the Empire State Building at 1250 feet up. One skyscraper is sighted at a 20° angle of depression and a second skyscraper is sighted at a 30° angle of depression. How far apart are the two skyscrapers to the nearest foot?

Answers

Answer 1

Answer:

Step-by-step explanation:

Looking North, Two Skyscrapers Are Sighted From The Viewing Deck Of The Empire State Building At 1250
Answer 2

The angle of depression is the angle between the line of sight and a vertical line.

The distance between the two skyscrapers is 1269ft

I've added as an attachment, a figure that illustrates the scenario

First, we calculate distance AB using the following tangent ratio

[tex]\mathbf{\tan(\theta) = \frac{Opposite}{Adjacent}}[/tex]

So, we have:

[tex]\mathbf{\tan(60) = \frac{AB}{1250}}[/tex]

Make AB the subject

[tex]\mathbf{AB = 1250 \times \tan(60)}[/tex]

Next, we calculate distance AC using the following tangent ratio

[tex]\mathbf{\tan(\theta) = \frac{Opposite}{Adjacent}}[/tex]

So, we have:

[tex]\mathbf{\tan(60+10) = \frac{AB + BC}{1250}}[/tex]

[tex]\mathbf{\tan(70) = \frac{AB + BC}{1250}}[/tex]

Make AB + BC, the subject

[tex]\mathbf{AB + BC = 1250 \times \tan(70)}[/tex]

Make BC the subject

[tex]\mathbf{BC = 1250 \times \tan(70) - AB}[/tex]

Substitute [tex]\mathbf{AB = 1250 \times \tan(60)}[/tex]

[tex]\mathbf{BC = 1250 \times \tan(70) - 1250 \times \tan(60)}[/tex]

[tex]\mathbf{BC = 1269}[/tex]

Hence, the distance between the two skyscrapers is 1269ft

Read more about angles of depression at:

https://brainly.com/question/13697260

Looking North, Two Skyscrapers Are Sighted From The Viewing Deck Of The Empire State Building At 1250

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