May you please help me?

Answer:

They conduct thermal energy from inside the house and release it outside the house.

Explanation:

An air conditioner works to by conducting thermal energy or heat from inside the house and releasing this heat energy outside the house, thus making inside of the house cooler than the outside.

Warm air from inside the house is circulated around the evaporator fins. The refrigerant liquid is made to pass through the evaporator coil made of aluminum ,where the coils exchanges the heat it absorbs from the air surrounding it with the refrigerant. Aluminum metal is used in making the evaporator coils because it is a good conductor of heat. The heat absorbed by the refrigerant coverts it to vapor, which is then reconverted into liquid by the condenser removing the heat absorbed from inside the outside by means of a fan. As the heat is removed from the air, the air is cooled and blown back inside the house. This process is repeated several times until the desired temperature is attained inside the house.

Answer:

B is the answer

Explanation:

pls give me brainliest

Answer:

no im in a rehab program so we eat the sam shi every day

Explanation:

brainlest?

Explanation:

During lockdown, I ate LOADS OF JUNK FOOD. TRUST ME!!

I gained 14 kg of weight and became 68 kg

just due to junk food.I am 13 btw and at that time I was 5 feet 4 so definitely fat. all those pizzas and burgers and all.then I realised that I have gained weight. I have to REDUCE MY WEIGHT. I am quite determined on what I say. it took me 3 months or so and I finally got back to my original weight. How? just by going for a stroll everyday, eating healthy and constantly working out. eating less is not the solution,eating less calories is the solution.Also, by eating healthy food,I grew taller. I am 5 feet 6 now. So yes, definitely it helps put alot and keep eating healthy food and you will definitely be healthy.

Thank You.

Answer:

CALCIUM IDENINE ADEININE AND PHOSPHATE

Explanation:

Answer:

Vibrations are sent through the air to your ears.

Explanation:

Sound is a form of energy that is transmitted in compression and rare factions. Sound is a mechanical wave. All mechanical waves require a material medium for propagation.

The material medium for the propagation of sound is air. When the sound is produced by the speakers, the molecules of air are set into vibration and this vibration carries the sound from the speaker to your ears.

Answer:

When the string moves, it creates a very small change in the distance to the next point, th

Explanation:

When the string moves, it creates a very small change in the distance to the next point, this generates a restoring force that tends to push the string back, this small disturbance propagates along the string and is what creates the pulse.

This is similar to what happens when a spring is stretched and a restoring force is generated shaved by the law of shortening.

            F = k Dx

Answer:

As the first particle travels upward, it pulls on the next particle, which follows the first particle upward. Then next in line is pulled up in turn, and so on. The motion of each particle follows the one before it, either up or down, with a slight lag in time. This succession of particles moving up or down travels along the string as a wave. Eventually, it pulls every particle along the string up and down in series.

Explanation:

Answer:

What is the half-life of isotope X?  25 seconds

How many radioactive atoms of isotope X are left after 3 half-lives? 13

How many half-lives must have occurred if only 7 atoms of isotope X are left? 4

Explanation:

The half-life of isotope X is 25 seconds

The radioactive atoms of isotope X left after 3 half-lives are 13

Number of half-lives must have occurred if only 7 atoms of isotope X  left are 4.

Half life is the time taken by a radioactive material for the radioactivity of to reduce by half its original value.

The half life equation is:

A = A₀ (½)^(t / T)

where A is the final amount, A₀ is the initial amount, t is the amount of time, and T is the half life.

The half-life of isotope X is 25 seconds

The radioactive atoms of isotope X left after 3 half-lives are 13

Number of half-lives must have occurred if only 7 atoms of isotope X  left are 4.

Thus, the questions are answered.

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187.92 years

8*10^-2= .08

1.88*10^2= 188

188-.08=187.92

Answer:

306 m/s

Explanation:

Law of conservation of momentum

m1v1 + m2v2 = (m1+m2)vf

m1 is the bullet's mass so it is 0.1 kg

v1 is what we're trying to solve

m2 is the target's mass so it is 5.0 kg

v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

(0.1)(v1) + 0 = 30.6

(0.1)(v1) = 30.6

v1 = 306 m/s

The initial velocity of the bullet can be determined from the total momentum of the system. The velocity of the bullet was 306 m/s.

Momentum of a body is the product of its mass and velocity. For a collision, the momentum before and after collision will be the same for the colliding system.

Let m1 and m2 be the masses and u be the initial velocity and v is the final velocity.

then,  m1 u1  + m2 u2 = m1 v1  + m2 v2.

Given m1 = 5 kg

m2 =  0.1 kg

The velocity of the combined mass v = 6 m/s.

The momentum of the target is zero since it was stationary.

(0.1 × u1) = (0.1 + 5)6 m/s

(0.1 × u1) = 30.6 m/s

then u1 = 30.6/0.1 = 306 m/s

Therefore, the velocity of the bullet before hitting was 306 m/s.

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Explanation:

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.

Answer:

There are 2 definitions chose the suitable one for ur question

Explanation:

1. strength or energy as an attribute of physical action or movement.

2. coercion or compulsion, especially with the use or threat of violence.

HOPE THIS HELPS

Answer:

D: 2π/√k0

Explanation:

I got it right

The slope of the line of best fit is the quantity 2π/√ko.

The line of best fits is used to show the relationship between two variables. The nature of the graph shows the relationship between the variables.

We can see that this is a graph of the period of oscillation against the square root of the mass of the body. The slope of the line of best fit is the quantity 2π/√ko.

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Answer:

The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom. During the fusion process, radiant energy is released. :D

Answer:

Wavelength = 5.77 * 10^-5 meters.

Explanation:

Given the following data:

Frequency of light = 5.2 *10^12 Hz

We know that the Speed of light = 3.0 * 10^8 m/s

To find the wavelength of light;

Mathematically, wavelength is calculated using this formula;

[tex] Wavelength = \frac {speed}{frequency} [/tex]

Substituting into the equation, we have;

[tex] Wavelength = \frac {3*10^{8}}{5.2 *10^{12}} [/tex]

Wavelength = 5.77 * 10^-5 meters.

Answer:

I'm pretty sure it's half

Answer:

half

Explanation:

.................................

Answer:

Chemical weathering

Explanation:

This changes the molecular structure of rocks and soil. For instance, carbon dioxide from the air or soil sometimes combines with water in a process called carbonation. This produces a weak acid, called carbonic acid, that can dissolve rock.

Answer: if the door knob is metal the static electricity will exit your body, but shock you in the process

Explanation:

An unmanned spacecraft leaves for Venus. The statements, The weight of the spacecraft keeps changing and The mass of the spacecraft remains the same. This 2 statements A and D are true.

A spaceship is a machine or vehicle built to travel through space. Spacecraft are a form of artificial satellite utilised for a wide range of tasks, such as communications, Earth observation, meteorology, navigation, space colonisation, planetary exploration, and freight and person transfer. All spacecraft, with the exception of single-stage-to-orbit vehicles, need a launch vehicle (carrier rocket) to get into space.

A spacecraft that is performing a sub-orbital spaceflight launches into space and then lands without gaining enough momentum or energy to complete a full orbit of the Earth. Spacecraft enter confined orbits around the Earth or other celestial bodies for orbital spaceflights. Only humans are carried on human spacecraft either as crew or guests from launch or while in orbit (space stations).

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Answer:

96.3%

Explanation:

Efficiency = Work input/Work output * 100%

Work done = Force * distance\

Work done by the engine is the work output = 700 * 0.55

Work output = 423.5Nm

Work done by you is the work input = 35.7*11.43

Work input = 408.051Nm

Efficiency = 408.051/423.5 * 100

Efficiency = 0.963 * 100

Efficiency = 96.3%

Hence the efficiency of the pulley system is 96.3%

Answer:

RT = 35 Ohms

Explanation:

Let the three resistors be R1, R2 and R3 respectively.

Given the following data;

R1 = 14 Ohms

R2 = 12 Ohms

R3 = 9 Ohms

To find the total resistance, RT;

Since all the resistors are connected in series, the total resistance is equal to the sum of all three resistance of the resistors.

RT = R1 + R2 + R3

Substituting into the equation, we have

RT = 14 + 12 + 9

RT = 35 Ohms.

Therefore, the total resistance of the circuit is 35 Ohms.

Answer:

0.5 second

Explanation:

We are given that

Force, F=20 N

Mass, m=5 kg

Change in velocity,=2m/s

We have to find the time taken to change the velocity .

We know that

Force, F=ma

Where

Acceleration, a=Change in velocity/time

[tex]a=\frac{2}{t}[/tex]

Substitute the values

[tex]20=5\times \frac{2}{t}[/tex]

[tex]t=\frac{5\times 2}{20}[/tex]

[tex]t=0.5 s[/tex]

Answer:

The tangential acceleration is 0 m/s².

Explanation:

Answer:

The tangential acceleration is 0 m/s².

Explanation:

Answer:

The force applied to the spring is 35,780 N

Explanation:

Given;

extension of the spring, x = 200 mm = 0.2 m

energy stored in the spring, E = 3578 J

The force applied to the spring is calculated as;

E = ¹/₂Fx

where;

F is the applied force

F = 2E/x

F = ( 2 x 3578) / 0.2

F = 35,780 N

Therefore, the force applied to the spring is 35,780 N

The time taken for Planet Mercury to orbit around the sun is determined as 1.21 x 10⁶ s.

The time of motion of the planet around the sun is calculated as follows;

[tex]T = 2\pi \sqrt{\frac{a^3}{Gm} } \\\\[/tex]

where;

[tex]T = 2\pi \sqrt{\frac{(5.8 \times 10^{10})^3}{(6.67 \times 10^{-11})(1.99\times 10^{30})} } \\\\T = 1.21 \times 10^6 \ s[/tex]

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Answer:

a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s

b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m

c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s

d) La altura que alcanza el bloque es de 5 metros.

e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción

Explanation:

a) Los parámetros dados del bloque son;

La masa del bloque, m = 3 kg

La altura a la que se coloca el bloque, h = 5 m

La constante de resorte, k = 400 N / m

La aceleración debida a la gravedad, g = 9,8 m / s²

La energía potencial de un cuerpo, P.E. = m · g · h

Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;

P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios

P.E. = 147 julios

La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²

Dónde;

v = La velocidad del bloque cuando llega al resorte

Por lo tanto, para el bloque dado tenemos;

K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²

Por el principio de conservación de la energía, tenemos;

El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.

∴ P.E. = K.E.

147 J = 1/2 × 3 kg × v²

v² = 147 J / (1/2 × 3 kg) = 98 m² / s²

v = √ (98 m² / s²) = 7 · √2 m / s

v = 7 · √2 m / s ≈ 9,9 m / s

b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²

Dónde;

k = La constante del resorte = 400 N / m

x = La distancia a la que se comprime el resorte

Por el principio de conservación de la energía, tenemos;

La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.

∴ E = 1/2 · k · x² = P.E.

De lo que tenemos;

E = 1/2 × 400 N / m × x² = 147 julios

x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²

x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m

La distancia a la que se comprime el resorte = x ≈ 0.86 m

c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;

La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²

∴ 1/2 · k · x² = 1/2 · m · v²

∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s

La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s

d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;

P.E. = K.E.

∴ m · g · h = 1/2 · m · v²

v = 7 · √2 m / s

De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros

e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción

a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.

b) El resorte se deforma 0.858 metros.

c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.

d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).

a) Conforme a la situación de este problema, la energía cinética traslacional final ([tex]K[/tex]), en joules, es igual a la energía potencial gravitacional inicial ([tex]U[/tex]), en joules.

[tex]U = K[/tex] (1)

Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:

[tex]m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)

Ahora despejamos la velocidad de esa ecuación:

[tex]v = \sqrt{2\cdot g\cdot h}[/tex]

Donde:

Si sabemos que [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]h = 5\,m[/tex], entonces la velocidad final del bloque es:

[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]

[tex]v\approx 9.903\,\frac{m}{s}[/tex]

La velocidad final del bloque es aproximadamente 9.903 metros por segundo.

b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:

[tex]\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (2)

Where:

Ahora despejamos la deformación del resorte:

[tex]x = \sqrt{\frac{m}{k} }\cdot v[/tex] (3)

Si sabemos con [tex]k = 400\,\frac{N}{m}[/tex], [tex]m = 3\,kg[/tex] y [tex]v \approx 9.903\,\frac{m}{s}[/tex], entonces la deformación del resorte es:

[tex]x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)[/tex]

[tex]x \approx 0.858\,m[/tex]

El resorte se deforma 0.858 metros.

c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.

d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).

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Answer:

.5(3120kg)(22.1m/s)^2 = 7.62x10^5 J

Explanation:

The work done on the truck to achieve given speed is [tex]7.62*10^{6}[/tex] Joules.

The work done on the truck is equivalent to the kinetic energy.

   Work done = Kinetic energy = [tex]\frac{1}{2} mv^{2}[/tex]

Where m is mass of truck and v is final velocity of truck.

Given that, [tex]m=3120Kg,v=22.1m/s[/tex]

Substitute values in above equation

                 [tex]Workdone=\frac{1}{2}*3120*(22.1)^{2} \\\\Workdone=0.5*3120*488.41=7.62*10^{6} KJ[/tex]

Thus,  The work done on the truck to achieve given speed is [tex]7.62*10^{6}[/tex] Joules.

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Answer:

D

Explanation:

Answer:

HELLO THERE

Explanation:

D