Name the following aromatic hydrocarbon:

Name The Following Aromatic Hydrocarbon:

Answers

Answer 1

Explanation:

I think option 3..............


Related Questions

Which best describes an alpha particle that is emitted during nuclear decay?

A. A helium nucleus
B. A hydrogen nucleus
C. An electron
D. A positron

Answers

Answer:

A helium nucleus

Thre types of radiation

Alpha: Helium nucleus

Beta: Electron

Gamma: Gamma rays

Select the correct answer. What is the hydronium (H3O+) concentration of a solution with a pH of 3.60?

Answers

Answer: The hydronium [tex](H_{3}O^{+})[/tex] concentration of a solution with a pH of 3.60 is 0.56 M.

Explanation:

pH of a substance is the negative logarithm of concentration of hydrogen ions present in it.

It's formula is; pH = - log [tex][H^{+}][/tex]

When pH of a solution is 3.60 then its hydronium or hydrogen ion concentration is calculated as follows.

[tex]pH = - log [H^{+}]\\3.6 = - log [H^{+}]\\concentration of H^{+} = antilog (-3.6)\\= 0.56[/tex]

Thus, we can conclude that the hydronium [tex](H_{3}O^{+})[/tex] concentration of a solution with a pH of 3.60 is 0.56 M.

Give the full fome of PET​

Answers

Answer:

The full form of PET is Polyethylene Terephthalate.

sulfur and oxygen can react to form both sulfur dioxide and sulfur trioxide in sulfur dioxide there are 32.06 grams of sulfur and 32 grams of oxygen in sulfur dioxide there are 32.06 grams of sulfur are combined with 48 grams of oxygen

a. what is the ratio of the weights of oxygen that combine with 32.06 g of sulfur ?
b. How do these data illustrate the law of multiple proportions? ​

Answers

Answer:

Explanation:

In sulfur dioxide there are 32.06 grams of sulfur and 32 grams of oxygen .

In sulfur trioxide there are 32.06 grams of sulfur are combined with 48 grams of oxygen.

The ratio of oxygen which reacts with 32.06 gram of sulfur is 32: 48 .

This ratio is equal to 2 : 3.

This is in accordance with law of multiple proportion because , the ratio of mass of oxygen which reacts with constant mass of sulfur is integral ratio . Hence they are in accordance with law of multiple proportions.

Answer:

sulfur and oxygen can react to form both sulfur dioxide and sulfur trioxide in sulfur dioxide there are 32.06 grams of sulfur and 32 grams of oxygen in sulfur dioxide there are 32.06 grams of sulfur are combined with 48 grams of oxygen

a. what is the ratio of the weights of oxygen that combine with 32.06 g of sulfur?

b. How do these data illustrate the law of multiple proportions? ​

Explanation:

In sulfur dioxide ([tex]SO_2[/tex])

32.06 g of sulfur reacts with 32.0 g of oxygen.

In sulfur trioxide ([tex](SO_3)[/tex] 32.0 g of sulfur reacts with 48.0 g of oxygen.

So, both th ecom[pounds are made from sulfur and oxygen,

But the amount of oxygen reacts with fixed amount of sulfur that is 32.06 g and it is in proportions that is:

32.0 g : 48.0 g

=2:3.

Hence, the ratio of oxygen combines with sulfur is in the ratio of 2:3.

b.

This data illustrates the law of multiple proportions.

Because the oxygen which is combining with fixed amount of sulfur is in proportions.

Please I need an explanation on the relationship between concentration and volume of reacting substances​

Answers

Answer:

when d volume of a substance is high, the concentration is gonna b low...

Jus lyk putting much water in just a cube of sugar

Explanation:

So lower volume, higher concentration

which of the following metal is a p-block element ?a.gold b.iron c.copper d.aluminium​

Answers

The answer is D)Aluminium

A 2.0 M solution of LiF had 4.00 moles of LiF added to a solvent to make it.


What is the volume of this solution?


A. 2 L


B. 3 L


C. 6 L


D. 8 L



Its 2L Btw

Answers

Answer:

2 L

Explanation:

From the question given above, the following data were obtained:

Molarity of LiF = 2 M

Mole of LiF = 4 moles

Volume =?

Molarity of a solution is simply defined as the mole per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole / Volume

With the above formula, we can obtain the volume of the solution as shown below:

Molarity of LiF = 2 M

Mole of LiF = 4 moles

Volume =?

Molarity = mole / Volume

2 = 4 / volume

Cross multiply

2 × volume = 4

Divide both side by 2

Volume = 4/2

Volume = 2 L

Therefore, the volume of the solution is 2 L.

Discuss the phenomena of sunrise and sunset seen on Earth and describe how they will be different from the perspective of outer space. PLS REPLY ASAP AND EXPLAIN IM DESPEPERATE

Answers

Answer:

IM TO LATE SORRY

Explanation:

What are the limitations of bohr's model of atom​

Answers

Answer:

The Bohr Model is very limited in terms of size. Poor spectral predictions are obtained when larger atoms are in question. It cannot predict the relative intensities of spectral lines. It does not explain the Zeeman Effect, when the spectral line is split into several components in the presence of a magnetic field.

Explanation:

Answer:

espero que te ayude ........

why is dilute tetraoxosulphate(VI) acid not suitable for preparing carbon monooxide​

Answers

Answer: Because this does not dissolve in water - it forms a barrier on the surface of the unreacted CaCO3 which prevents any further reaction. A small volume of CO2 is produced , but this stops after a short time . Conclusion: H2SO4 cannot be used with CaCO3 to produce CO2 gas .

Explanation:

All samples of a specific substanice have the same chemical
composition
TRUE
FALSE

Answers

Answer:

true

Explanation:

what is the lewis dot structure for AgBr? PLS HELP ME

Answers

of what lol. dndkdmsldksmsnsjdjdbdh

How many mL of 0.013 M potassium hydroxide are required to reach the equivalence point in the titration of 75 mL 0.166 M hydrocyanic acid?

Answers

Answer:

957.7mL

Explanation:

Using the formula below;

CaVa = CbVb

Where;

Ca = concentration of acid (M)

Va = volume of acid (mL)

Cb = concentration of base (M)

Vb = volume of base (mL)

According to the information provided in this question:

Ca = 0.166 M

Cb = 0.013 M

Va = 75mL

Vb = ?

Using CaVa = CbVb

0.166 × 75 = 0.013 × Vb

12.45 = 0.013Vb

Vb =12.45/0.013

Vb = 957.7mL

You have 5000 atoms of gold and 5000 atoms of silver. Which statement is true.
You have the same mass of each.
You have the same number of moles of each.
Both are true.
Neither are true.

Answers

"You have the same number of moles of each." is the true statement.

The mass of Gold and Silver differ, so that first statement can't be true because the quantities are the same. Because a mole measures solely amounts, like a dozen does, you will have the same amount of moles if the quantities are the same.

what is the formula for potassium sulfate

Answers

What is the formula for potassium sulfate?

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { K_{2} SO_{4} }}}}}}[/tex]

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

E. Give reasons
1. Oxygen is a diatomic element.
3. The valency of sodium is one.
F. Differentiate between
1. electrovalent bond and covalent bond
2. acidic radical and basic radical​

Answers

Answer:

the valency of sodium is one because sodium loses 1 electron to become stable

How much energy is needed to heat enough water to make a cup of tea (250 ml), if the water is initially at 20.0°C and you want to increase the temperature to 85.0°C? (1.00 mL of water has a mass of 1.00 g.)

As the tea in the previous question steeps, it cools from 85.0°C to 75.0°C. How much energy is lost by the tea as it steeps?

Answers

Answer:

Heat Energy needed (Q) = 68250 J

Energy lost (Q') = 10500 J

Explanation:

Applying,

Q = cm(t₂-t₁)............. Equation 1

Where Q = heat  energy needed, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature.

From the question,

Given: m = 250 g = 0.25 kg, t₁ = 20.0°C, t₂ = 85.0°C

Constant: c = 4200 J/kg°C

Substitute these values into equation 1

Q = 0.25(4200)(85-20)

Q = 68250 J.

Similarly, heat lost

Q' = cm(t₁-t₂)................. Equation 2

Where Q = heat lost

Given: t₁ = 85°C, t₂ = 75°C

Substitute into equation 2

Q' = 4200(0.25)(85-75)

Q' = 10500 J

In the chemical reaction between aqueous magnesium chloride and sodium metal, what chemical amount (mol) of magnesium metal can be precipitated (produced) with 12.6 mol of sodium metal?

Answers

Answer:

6.3moles

Explanation:

The balanced equation of the reaction described above between aqueous magnesium chloride and sodium metal is as follows:

MgCl2(aq) + 2Na(s) → 2NaCl(aq) + Mg(s)

From the above equation, 2 moles of sodium metal (Na) produces 1 mole of Magnesium metal (Mg)

Hence, 12.6 mol of Na will produce (12.6/2) mol of Mg.

12.6/2 = 6.3moles of Mg metal.

Boyle's Law Problems
Charles' Law Problems ​

Answers

Answer:

here are the answers babe. Feel free to ask for more

what is the balanced equation of magnesium carbonate decomposes on heating to form magnesium oxide and carbon dioxide​

Answers

Answer:

ExplaAt high temperatures MgCO3 decomposes to magnesium oxide and carbon dioxide. This process is important in the production of magnesium oxide. This process is called calcining: MgCO3 → MgO + CO2 (ΔH = +118 kJ/mol)

nation:

PLEASE HELP!!!!!
Q1: Give the letter of a substance that is a solid at 20 °C
Q2: Give the letter of a substance that is a liquid at 50 °C

Answers

Answer:

A1: Z

A2: Y

Explanation:

Q1: Z is the only one with a melting point high than 20 °C.

Q2: Y is the only substance with both a melting point lower than 50 °C and a boiling point higher than 50°C

What are substance made of

Answers

Answer:

Lesson Summary. A substance is simply a pure form of matter. In other words, a substance is matter than contains only one type of atom or molecule. Pure substances can be further divided into two sub-categories: elements and compounds.

Explanation:

Radhe Radhe

Write the four quantum numbers of the outermost two electrons in the atom of calcium

Answers

Answer:

Its electron configuration is: 2 electrons in the K shell (principal quantum number 1), 8 in the L shell (principal quantum number 2), 8 in the M shell (principal quantum number 3), and 2 in the N shell (principal quantum number 4).

Explanation:

Hope this helped!!! xoxo

t!kt0k: preppydreams

Write a letter to someone who had bullied you in the past,

Answers

Answer:

frick u beotch

Explanation:

What type of reaction is shown below?
H202 + H2O + O2
Single replacement
Combustion
Synthesis
Decomposition

Answers

Answer:

Decomposition Reaction

NO2 + H2O =
SO2 + H2O =
H2S + H2O=

Answers

SO2+ H2O=H2SO3

H2S+ H2O=H2SO4 +H2

NO2+  H2O= HNO3+NO

State the method you will use to separate the following substances. (a) calcium carbonate from table salt (b) iodine from sodium chloride (c) table salt from seawater (d) sugar from sugar solution (e) pure water from sewage water (f) ethanol from beer (g) yellow dye from durian ice cream

Answers

Answer:

https://www.meritnation.com :)

I HOPE IT'S HELP

Answer: There are many forms of table salt: coarse salt, refined salt, iodized salt. It is a crystalline solid, white to very pale pink or gray in color, obtained from seawater or salt deposits. Salt obtained from seawater has crystals that are smaller or larger than rock salt. In nature, table salt consists mainly of sodium chloride (NaCl), but also a few other minerals (trace minerals). Table salt obtained from rock salt may appear more gray because of traces of trace minerals. Table salt is necessary for the survival of all living organisms, including humans. Table salt is involved in regulating the body's water content (liquid balance).

Which of the following is true of a reaction with a negative enthalpy?
O A. The enthalpy of the reactants is greater than that of the products.
B. The reaction has a negative activation energy.
C. The enthalpies of the products and reactants are both negative.
D. The enthalpy of the reactants is less than that of the products.

Answers

Answer: The statement enthalpy of the reactants is greater than that of the products is true of a reaction with a negative enthalpy.

Explanation:

A chemical reaction where energy is being released is called an exothermic reaction.

In an exothermic reaction, the value of enthalpy of reaction is negative in nature.

Also, heat is being released which means the reactants has more energy than the products due to which the value of enthalpy is negative.  

Thus, we can conclude that the statement enthalpy of the reactants is greater than that of the products is true of a reaction with a negative enthalpy.

Answer:

A

Explanation:

trust

calculate the volume of 150 kg of chlorine gas.

Answers

as+at+room+temperature+and+pressure

Calculate the volume of 150kg of chlorine gas at room ... Calculate the volume of 150kg of chlorine gas at room temperature and pressure. The volume of one mole of gas at room temperature and pressure is 24.0dm^3. Relative formula mass

Answer:

[tex]{ \tt{at \: \: s.t.p : }} \\ { \bf{0.0355 \: kg \: of \: chlorine \: occupies \: 22.4 \: {dm}^{3} }} \\ { \bf{150 \: kg \: will \: occupy \: ( \frac{150 \times 22.4}{0.0355} )}} \: dm {}^{3} \\ \\ { \tt{ volume = 94647.88 \: {dm}^{3} }}[/tex]

The number of molecules in 17.9 g of CO is

Answers

Answer:

3.85 × 10²³ molecules CO

General Formulas and Concepts:

Atomic Structure

Reading a Periodic TableCompoundsMolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[Given] 17.9 g CO

[Solve] molecules CO

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of C: 12.01 g/mol

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of CO: 12.01 + 16.00 = 28.01 g/mol

Step 3: Convert

[DA] Set up:                                                                                                       [tex]\displaystyle 17.9 \ g \ CO(\frac{1 \ mol \ CO}{28.01 \ g \ CO})(\frac{6.022 \cdot 10^{23} \ molecules \ CO}{1 \ mol \ CO})[/tex][DA] Divide/Multiply [Cancel out units]:                                                           [tex]\displaystyle 3.8484 \cdot 10^{23} \ molecules \ CO[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.8484 × 10²³ molecules CO ≈ 3.85 × 10²³ molecules CO

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