Name the following straight-chain
alkane.
CH3CH2CH2CH3

Answer:

Transports Dissolved gases and Controls pH The pH of blood must remain in the range 6.8 to 7.4, otherwise it begins to damage cells.

Explanation:

main functions tho Transportation. Nutrients from the foods you eat are absorbed in the digestive tract. ...

Defense. Many types of WBCs protect the body from external threats, such as disease-causing bacteria that have entered the bloodstream in a wound.

Maintenance of Homeostasis. Recall that body temperature is regulated via a negative-feedback loop.

Answer: The changes are the mL of methanol ingestion (30mL) and the proof of the whiskey (40% ethanol; 80 proof), and the percentage of reduction (1%). I applied the formulas from the last post in reference to this question but am completely lost. The formulas used last time were: 2. Formulas Applied alpha=1 + ([etOH]/KetOH) (V[meOH]/V[etOH])= (Vmax*[meOH]/KmeOH+[meOH])/(Vmax*[meOH]/alpha*KmeOH+[meOH]) which reduces to (V[meOH]/V[etOH])=(alpha*KmeOH+[meOH])/(KmeOH+[meOH]) 3. My attempt Molarity of methanol: 30mL; which equates to 23.7g of methanol; in 40L that is equal to 0.5925 g/L Dividing the molecular weight by 32.04g/mol I get 0.0184925 which is approximately 0.02M; Km is 0.01M Since the molar mass of methanol and ethanol are two fold, I can multiply the g/l by 4. However, unlike the previous problem, I cannot multiply by 2 because I do not have 50% EtOH, so because 40 is less than 50 I assume to multiply by 2.5 yielding: (30mL)(4)(2.5)=300mL 300mL of EtOH to effectively reduce the Methanol to 1%.

Answer: 44.8 L

Explination:

44.8 liters of carbon dioxide gas at STP are produced by the combustion of 64.0 g of methanol. Therefore, option A is correct.

Combustion is a chemical reaction between two or more substances, usually involving oxygen, that produces heat and light in the form of a flame.

Combustion is a high-temperature exothermic redox chemical reaction that occurs between a fuel and an oxidant, frequently atmospheric oxygen, to produce oxidized, often gaseous products in a mixture known as smoke.

The flash point of methanol is extremely low. This means that even trace amounts of ignition material can start a fire. 44.8 liters of carbon dioxide gas at STP are produced by the combustion of 64.0 g of methanol.

Thus, option A is correct.

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Answer:

HCl is the limiting reactant

Explanation:

To find the limiting reactant of a reaction we must find the moles of each one as follows:

Moles Mg (Molar mass: 24.305g/mol)

4.8g Mg * (qmol / 24.305g) = 0.20 moles Mg

Moles HCl (Molar mass: 36.46g/mol)

6.00g HCl* (1mol / 36.46g) = 0.165 moles HCl

Based on the chemical reaction, for a complete reaction of 0.20 moles of Mg are necessaries:

0.20 moles Mg * (2mol HCl / 1mol Mg) = 0.40 moles HCl

As there are just 0.165 moles of HCl:

Answer:

mushroom are a type of fungi

Explanation:

Answer:

Cl⁻ was oxidized.

Explanation:

Oxidation can be defined as the process in which the oxidation number of a substance increases.

On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.

Thus, Cl⁻ was oxidized.

I uploaded the answer to a file hosting. Here's link:

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Answer: increase

Explanation: when Mg is powder it has greater surface area and

Reaction occurs faster

In all living organisms, in substances like carbohydrate, starch, urea etc. To prove sugar contains carbon, take a little amount of sugar in spoon and heat it gently till it melts and turned into yellowish color. On further heating it changes into brown colored mass and then black, which is charcoal.

Answer: sugar treated with strong sulphur acid turns to black

Explanation: sulphur acid removes water from sugars and carbon is left in residue.

This should not to try at home. Water boils when high temperature is achieved.

Also smell of burned sugar occurs

Answer:

Explanation:

[tex]\text{From the list of the options given; we are to identify the suitable techniques} \\ \\ \text{for the characterization of benzoic acid.}[/tex]

[tex]\text{The analytical method used to confirm the structure and functional groups}\\ \\ \text{present in the product is} \ \ \mathbf{IR \ spectroscopy.}[/tex]

[tex]\text{The technique used to separate pure products from any excess reagents,} \\ \\ \text{impurities, and byproducts is}\ \ \mathbf{Recrystallization.}[/tex]

[tex]\text{The quick, numeric analysis done to characterize the product and assess the purity is}[/tex][tex]\mathbf{melting \ point.}[/tex]

Answer:

oop I'm thinking hmmmmm

Answer:

a form of energy resulting from the existence of charged particles (such as electrons or protons), either statically as an accumulation of charge or dynamically as a current.

Explanation:

Answer: The equilibrium constant is [tex]3.3\times 10^{-4}[/tex]

Explanation:

Initial concentration of [tex]I_2[/tex] = 0.095 M  

The given balanced equilibrium reaction is,

                            [tex]I_2(g)\rightleftharpoons 2I(g)[/tex]

Initial conc.          0.095 M       0 M

At eqm. conc.     (0.095-x) M   (2x) M

Given : 2x = 0.0055

x = 0.00275

The expression for equilibrium constant for this reaction will be,

[tex]K_c=\frac{[l]^2}{[I_2]}[/tex]  

Now put all the given values in this expression, we get :

[tex]K_c=\frac{(0.0055)^2}{(0.095-0.00275)}[/tex]

[tex]K_c=\frac{(0.0055)^2}{0.09225}=0.00033[/tex]

Thus the equilibrium constant is [tex]3.3\times 10^{-4}[/tex]

Answer:

Transform = the third one

convergent = the first one

divergent = the second one

Explanation:

Answer:

B, B and C

Explanation:

The two components (AA, hydrocarbons and BB, nitrogen oxide) are most likely released from automobile exhaust.

This is referred to a type of air pollution which could be from carbon emission etc and reduces the visibility.

(AA, hydrocarbons and BB, nitrogen oxide peaked midmorning when traffic is highest which means they were most likely released from automobile exhaust?.

Read more about Smog here  https://brainly.com/question/14029972

Answer:

I think the dish contracts and shrinks

Answer:

The dish cracks or breaks.

Explanation:

When glass changes temperature rapidly, it may undergo thermal shock. This is stress that is produced by a sudden change in temperature.

Answer:

The heat of reaction is basically the energy that is being released and or absorbed when chemicals are transformed in a type of chemical reaction. However, the heat of reaction or also called reaction enthalpy is mostly or typically expressed as a molar enthalpy in kJ/mol and or as just a specific enthalpy in kJ/kg or kJ/L.

Answer:

NaCl

Explanation:

If you follow traditional rounding, Na atomic mass is 23 and Cl atomic mass 35, 23 +35 = 58.

I was taught that Cl is one of the elements you round to 35.5, but this works if you’re not in an advanced chem class.

Answer:

True

Explanation:

Benzene is formed as a result when benzoic acid is generated by Grignard reaction. We must therefore isolate it from the desired benzoic acid compound, as the rest is not dismissed after dissolution in aqueous NAOH solution. Therefore, it a good idea to outline a separation scheme for such cases.

This implies that the given statement is true.

Answer: Dynamic equilibrium

Explanation:

Answer:

Explanation:

From the information given:

oxidation of oxidized solution takes place at 950° C

For wet oxidation:

The linear and parabolic coefficient can be computed as:

[tex]\dfrac{B}{B/A} = D_o \ exp \Big [\dfrac{-\varepsilon a}{k_BT} \Big][/tex]

Using [tex]D_o[/tex] and [tex]E_a[/tex] values obtained from the graph:

Thus;

[tex]\dfrac{B}{A} = 1.63 \times 10^8 exp \Big [ \dfrac{-2.05}{8.617 \times 10^{_-5}\times 1173}\Big] \\ \\ = 0.2535 \ \ \mu m/hr[/tex]

[tex]B= 386 \ exp \Big [-\dfrac{0.78}{8.617 \times 10^{-3} \times 1173} \Big] \\ \\ = 0.1719 \ \mu m^2/hr[/tex]

So, the initial time required to grow oxidation is expressed as:

[tex]t_{ox} = \dfrac{x}{B/A}+ \dfrac{x^2}{B} - t_o (initial)[/tex]

[tex]where; \\ \\ t_{ox} = 2 \ hrs;\\ \\ x = 0.5 \\ \\ B/A = 0.2535 \\ \\ B = 0.1719[/tex]

∴

[tex]2= \dfrac{0.5}{0.2535}+ \dfrac{0.5^2}{0.1719} - t_o (initial)[/tex]

[tex]2 = 3.4267 - t_o (initial) \\ \\ t_o(initial) = 3.4267 - 2 \\ \\ t_o(initial) = 1.4267 \ hr[/tex]

NOW;

[tex]1.4267 = \dfrac{d_o}{0.2535} + \dfrac{d_o^2}{0.1719} \\ \\ 1.4267 = 3.9448 \ d_o + 5.8173 \ d_o^2 \\ \\ d_o^2 + 0.6781 \ d_o = 0.2453[/tex]

[tex]d_o = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]d_o = \dfrac{-(0.6781) \pm \sqrt{(0.6781)^2-4(1)(-0.245)}}{2(10)}[/tex]

[tex]d_o = \dfrac{-(0.6781) \pm \sqrt{0.45981961+0.98}}{20}[/tex]

[tex]d_o = \dfrac{-(0.6781) \pm \sqrt{1.43981961}}{20}[/tex]

[tex]d_o = \dfrac{-(0.6781) + \sqrt{1.43981961}}{20} \ OR \ \dfrac{-(0.6781) - \sqrt{1.43981961}}{20}[/tex]

[tex]d_o =0.02609 \ OR \ -0.0939[/tex]

Thus; since we will consider the positive sign, the initial thickness [tex]d_o[/tex] is ;

≅ 0.261 μm

Answer:

The answer is definitely D

Explanation:

Answer:

Explanation:

The left electrode will be positive on the grounds that focus on the concentration that the cell electron moves from a lower concentration fixation to a higher concentration. Thus right electrode will go about and act as an anode and will be negative.  Also, the left electrode will be the cathode and will be positive.

The concentration cell [tex]E_{Cell} = \dfrac{-0.0591}{1} log \dfrac{0.02}{4}[/tex]

[tex]E_{Cell} =0.136 V[/tex]

         = 136 mV

Answer: compressibility

Explanation:

The ratio of the measured molar volume of a real gas to the measured molar volume  of an ideal gas is known as​ compressibility.

Compressibility is defined by the symbol Z and is calculated by the formula :

[tex]Z=\frac{PV}{nRT}[/tex]

For a gas with ideal behavior, molar volume of an ideal gas is equal to the molar volume of a real gas so Z= 1.

Answer:

Their sleek shape makes them more aerodynamic which reduces the contact force.

Answer: The are formed in a way so they create less friction against the air and water. Helping the jet stream create less traction so it moves faster. Like how a bullet is designed. The pointed front and narrow body helps it move faster through the air. Less things sticking of these object so friction is avoided, and they can easily move speedily. The same thing goes for cars, the more narrow they are as well as pointed makes it easier to push through the air making the wind resistance extremely low.

Hope this helps :)