Name the quadrant or axis where each point lies.

Answer:

d = 17

Step-by-step explanation:

The given arithmetic sequence is :

31, 48, 65, 82, ...

We need to find the common difference for this sequence.

First term, a₁ = 31

Second term, a₂ = 48

Common difference = a₂-a₁

= 48-31

= 17

So, the common difference for this arithmetic sequence is equal to 17.

Answer:

x_<2

Step-by-step explanation:

its shaded in so you have to flip it

Answer:

The answer is

x_<2

The circle is shaded and the arrow is going to the left hand side

Answer:

15 meters per second

Step-by-step explanation:

60/4 = 15

Answer:

15 meters per second

Answer:

Buying Groceries, paying for a house, maybe in your job, doing schoolwork of course, and counting money.

Step-by-step explanation:

Answer:

1. you use it to calculate time (managing your day)

2. you use it while driving (use in angles and degrees)

3. you use it while drawing (again, use in angles and degrees)

4. you use it while cooking

5. you use it while banking (financial help)

Step-by-step explanation:

hope this helps:) please mark brainliest

Answer:

<BAC=1/2 <BOC=1/2 X=X/2(INSCRIBED ANGLE IS HALF OF CENTRAL ANGLE)

Answer:

j

Step-by-step explanation:

J is your answer to the question

Answer:

2

Step-by-step explanation:

hope this helps

please give brainliest. Thanks! :)

0.87 mushroom soup per can

Answer: $0.67

Explanation: if the tomato soup can cost 79 cents then you divide that by 8 and you will get $6.32. Now if you subtract that by 9 your answer will be $2.68 so once you get that number, divide it by 4 and the answer will be $0.67

Following order of operations:

3^2 = 9

(10-2) = 8

Now you have :

9 + 8 x 5 -4

Multiplication is next:

9 + 40 -4

Now just add and subtract from left to right:

9 + 40 = 49

49-4 = 45

The answer is 45

Step-by-step explanation:

So first you solve whats inside of the parenthesis 10 -2 aand get 8 then you figure 3^2 which is 9 then multiplie 8 times 5 and get 40. 9 + 40 - 4 is what it is so far then add 9 to 40 which is 49 then subtract 4 and get 45!

Answer: all i can read is number 2 and the answer is 5ft

Step-by-step explanation:

Answer:

B) [tex]\sqrt{225-81}[/tex]H) 5Triangle DG) 18 yards

Step-by-step explanation:

To solve question 1, you use the Pythagorean Theorem to solve. Option B uses this correctly.

Question 2 also uses the Pythagorean Theorem to solve. The answer is a decimal, but rounded to the nearest whole number, the answer is 5.

Question 3 uses the Pythagorean Theorem to see which triangles have the correct measurements of a right triangle. The triangle D is the only incorrect one.

Number 4 uses the Pythagorean Theorem to find the distance it would take to walk in a straight line. The answer to this is 51. Then subtract (24 + 45) - 51 to get 18 yards.

Hope it helps!

Answer:

3000

Step-by-step explanation:

100%-> 5000

60%->3000

Answer:

300

Step-by-step explanation:

if you mean, 245.320

Answer:37.5

Step-by-step explanation:

Answer:

37.5

Step-by-step explanation:

(3/5)^3 x (3/5)^-2
= (3/5)^1
= 3/5

Answer:

73

Step-by-step explanation:

Probably

Sure it good I have this question on my test

Answer:

[tex]P(B') = 0.77[/tex]

Step-by-step explanation:

Given

[tex]P(A) = 0.23[/tex]

[tex]P(A\ n\ B) = 0.12[/tex]

[tex]P(A\ u\ B) = 0.34[/tex]

Required

Find P(B')

First, we calculate P(B).

We have:

[tex]P(A\ n\ B) = P(A) + P(B) - P(A\ u\ B)[/tex]

Substitute values

[tex]0.12 = 0.23 + P(B) - 0.34[/tex]

[tex]0.12 = 0.23 - 0.34 + P(B)[/tex]

Collect like terms

[tex]P(B) = 0.12 - 0.23 + 0.34[/tex]

[tex]P(B) = 0.23[/tex]

P(B') is then calculated as:

[tex]P(B') = 1 - P(B)[/tex]

[tex]P(B') = 1 -0.23[/tex]

[tex]P(B') = 0.77[/tex]

Step-by-step explanation:

$9 because 1 third of 3 third would be $3

Answer:

low

Step-by-step explanation:

Answer:

8(34a-1)

Step-by-step explanation:

Hope this helps :)

Answer:

8(34a-1)

Step-by-step explanation:

Sorry don’t know
Joking so i will round to 1 sig fig
So 60 and 10 product is times
60x10=600
when estimating say what you are rounding to

Answer:

b) 200

Step-by-step explanation:

The correct answer is b) 200

1) El IVA del balón es de $ 20.

2) El precio final del balón es $ 145.

1) El Impuesto al Valor Agregado (IVA) es un impuesto indirecto que se aplica sobre el precio de compra del artículo comprado, es decir, se trata de un impuesto indirecto al consumo.

El porcentaje por concepto del impuesto varía de país en país. No obstante, el valor más común en países hispanoparlantes se ubica en torno al 16 % del precio de compra del artículo.

El IVA del balón se determina mediante la siguiente operación aritmética:

[tex]\Delta C = 0.16\cdot (125)[/tex]

[tex]\Delta C = 20[/tex]

El IVA del balón es de $ 20.

2) El precio final del producto es la suma del precio de compra y el IVA, es decir:

[tex]C = 125 + 20[/tex]

[tex]C = 145[/tex]

El precio final del balón es $ 145.  

Para aprender más sobre impuestos, invitamos cordialmente a ver esta pregunta verificada: https://brainly.com/question/24907444

Nota - El enunciado reporta numerosos errores tipográficos y está incompleto, el enunciado correcto y completo es el siguiente:

Un balón de fútbol tiene un precio de $ 125 + IVA.

1) ¿Cuánto es el IVA del balón? a) 20, b) 145, c) 325

2) ¿Cuál es el precio final con IVA del balón? a) 125, b) 200, c) 145

y=x^2
substitute the values into the original equation
0=4^2
0=16
No it does not satisfy the equation because 0 does not equal to 16

Answer:

[tex]\displaystyle \frac{1}{144}arctan(\frac{9x}{2}) + \frac{x}{8(81x^2 + 4)} + C[/tex]

General Formulas and Concepts:

Alg I

Terms/CoefficientsFactorExponential Rule [Dividing]: [tex]\displaystyle \frac{b^m}{b^n} = b^{m - n}[/tex]

Pre-Calc

[Right Triangle Only] Pythagorean Theorem: a² + b² = c²

a is a legb is a legc is hypotenuse

Trigonometric Ratio: [tex]\displaystyle sec(\theta) = \frac{1}{cos(\theta)}[/tex]

Trigonometric Identity: [tex]\displaystyle tan^2\theta + 1 = sec^2\theta[/tex]

TI: [tex]\displaystyle sin(2x) = 2sin(x)cos(x)[/tex]

TI: [tex]\displaystyle cos^2(\theta) = \frac{cos(2x) + 1}{2}[/tex]

Calc

Integration Rule [Reverse Power Rule]:                                                                [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

IP [Addition/Subtraction]:                                                             [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

U-Substitution

U-Trig Substitution: x² + a² → x = atanθ

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \int {\frac{dx}{(81x^2 + 4)^2}}[/tex]

Step 2: Identify Sub Variables Pt.1

Rewrite integral [factor expression]:

[tex]\displaystyle \int {\frac{dx}{[(9x)^2 + 4]^2}}[/tex]

Identify u-trig sub:

[tex]\displaystyle x = atan\theta\\9x = 2tan\theta \rightarrow x = \frac{2}{9}tan\theta\\dx = \frac{2}{9}sec^2\theta d\theta[/tex]

Later, back-sub θ (integrate w/ respect to x):

[tex]\displaystyle tan\theta = \frac{9x}{2} \rightarrow \theta = arctan(\frac{9x}{2})[/tex]

Step 3: Integrate Pt.1

[Int] Sub u-trig variables:                                                                                 [tex]\displaystyle \int {\frac{\frac{2}{9}sec^2\theta}{[(2tan\theta)^2 + 4]^2}} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                           [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[(2tan\theta)^2 + 4]^2}} \ d\theta[/tex][Int] Evaluate exponents:                                                                                [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4tan^2\theta + 4]^2}} \ d\theta[/tex][Int] Factor:                                                                                                      [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4(tan^2\theta + 1)]^2}} \ d\theta[/tex][Int] Rewrite [TI]:                                                                                              [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4sec^2\theta]^2}} \ d\theta[/tex][Int] Evaluate exponents:                                                                                [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{16sec^4\theta} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                          [tex]\displaystyle \frac{1}{72} \int {\frac{sec^2\theta}{sec^4\theta} \ d\theta[/tex][Int] Divide [ER - D]:                                                                                         [tex]\displaystyle \frac{1}{72} \int {\frac{1}{sec^2\theta} \ d\theta[/tex][Int] Rewrite [TR]:                                                                                            [tex]\displaystyle \frac{1}{72} \int {cos^2\theta} \ d\theta[/tex][Int] Rewrite [TI]:                                                                                              [tex]\displaystyle \frac{1}{72} \int {\frac{cos(2\theta) + 1}{2}} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                          [tex]\displaystyle \frac{1}{144} \int {cos(2\theta) + 1} \ d\theta[/tex][Int] Rewrite [Int Prop - A/S]:                                                                          [tex]\displaystyle \frac{1}{144} [\int {cos(2\theta) \ d\theta + \int {1} \ d\theta][/tex]  

Step 4: Identify Sub Variables Pt.2

Determine u-sub for trig int:

u = 2θ

du = 2dθ

Step 5: Integrate Pt.2

[Ints] Rewrite [Int Prop - MC]:                                                                       [tex]\displaystyle \frac{1}{144} [\frac{1}{2} \int {2cos(2\theta) \ d\theta + \int {1 \theta ^0} \ d\theta][/tex][Int] U-Sub:                                                                                                     [tex]\displaystyle \frac{1}{144} [\frac{1}{2} \int {cos(u) \ du + \int {1 \theta ^0} \ d\theta][/tex][Ints] Integrate [Trig/Int Rule - RPR]:                                                             [tex]\displaystyle \frac{1}{144} [\frac{1}{2} sin(u) + \theta + C][/tex][Expression] Back Sub:                                                                                 [tex]\displaystyle \frac{1}{144} [\frac{1}{2} sin(2 \theta) + arctan(\frac{9x}{2}) + C][/tex][Exp] Rewrite [TI]:                                                                                           [tex]\displaystyle \frac{1}{144} [\frac{1}{2}(2sin(\theta)cos(\theta)) + arctan(\frac{9x}{2}) + C][/tex][Exp] Multiply:                                                                                                 [tex]\displaystyle \frac{1}{144} [sin(\theta)cos(\theta) + arctan(\frac{9x}{2}) + C][/tex][Exp] Back Sub:                                                                                             [tex]\displaystyle \frac{1}{144} [sin(arctan(\frac{9x}{2}))cos(arctan(\frac{9x}{2})) + arctan(\frac{9x}{2}) + C][/tex]

Step 6: Triangle

Find trig values:

[tex]\displaystyle tan\theta = \frac{9x}{2}[/tex]

[tex]\displaystyle \theta = arctan(\frac{9x}{2})[/tex]

tanθ = opposite / adjacent; solve hypotenuse of right triangle, determine trig ratios:

sinθ = opposite / hypotenuse

cosθ = adjacent / hypotenuse

Leg a = 2

Leg b = 9x

Leg c = ?

Sub variables [PT]:                                                                                         [tex]\displaystyle 2^2 + (9x)^2 = c^2[/tex]Evaluate exponents:                                                                                      [tex]\displaystyle 4 + 81x^2 = c^2[/tex][Equality Property] Square root both sides:                                                  [tex]\displaystyle \sqrt{4 + 81x^2} = c[/tex]Rewrite:                                                                                                           [tex]c = \sqrt{81x^2 + 4}[/tex]

Substitute into trig ratios:

[tex]\displaystyle sin\theta = \frac{9x}{\sqrt{81x^2 + 4}}[/tex]

[tex]\displaystyle cos\theta = \frac{2}{\sqrt{81x^2 + 4}}[/tex]

Step 7: Integrate Pt.3

[Exp] Sub variables [TR]:                                                                               [tex]\displaystyle \frac{1}{144} [\frac{9x}{\sqrt{81x^2 + 4}} \cdot \frac{2}{\sqrt{81x^2 + 4}} + arctan(\frac{9x}{2}) + C][/tex][Exp] Multiply:                                                                                                 [tex]\displaystyle \frac{1}{144} [\frac{18x}{81x^2 + 4} + arctan(\frac{9x}{2}) + C][/tex][Exp] Distribute:                                                                                             [tex]\displaystyle \frac{1}{144}arctan(\frac{9x}{2}) + \frac{x}{8(81x^2 + 4)} + C[/tex]

Answer:

45 dollar's ezzzzzzzzzzzzz

Answer:

-26, -29, -32

Have a great day!

Step-by-step explanation:

Step-by-step explanation:

whatever amount her bank account balance is at the same time frame when paying off her loan as only her bank knows

Answer:

red

Step-by-step explanation:

1/2 is larger than 1/4, 1/6, and 1/12 meaning the chance of pulling red is greater than getting blue, green, or yellow.

hope i helped you!

Answer:

The bullet reaches a height of 4000 feet after 6.49 seconds, and then, coming back down, after 38.5 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]\bigtriangleup = b^{2} - 4ac[/tex]

The height of the bullet after t seconds is given by:

[tex]h(t) = -16t^2 + 720t[/tex]

When does the bullet reach a height of 4,000 feet?

This is t for which [tex]h(t) = 4000[/tex]. So

[tex]4000 = -16t^2 + 720t[/tex]

[tex]16t^2 - 720t + 4000 = 0[/tex]

Dividing by 16

[tex]t^2 - 45t + 250 = 0[/tex]

So [tex]a = 1, b = -45, c = 250[/tex]

[tex]\bigtriangleup = b^{2} - 4ac = (-45)^2 - 4(1)(250) = 1025[/tex]

[tex]t_{1} = \frac{-(-45) + \sqrt{1025}}{2} = 38.5[/tex]

[tex]t_{2} = \frac{-(-45) - \sqrt{1025}}{2} = 6.49[/tex]

The bullet reaches a height of 4000 feet after 6.49 seconds, and then, coming back down, after 38.5 seconds.

Answer: Your answer is (C) 6/14

Step-by-step explanation: Have a brilliant day mate - Lily ^-^

Answer:

True

Step-by-step explanation:

1.45 the 5 is equal/above it so it is true

yes if it's 5 or more your round it up 4 or less you don't