Explanation:
Initial horizontal velocity
If a projectile is launched at an angle to the horizontal, then the initial velocity of the projectile has both a horizontal and a vertical component. The horizontal velocity component (vx) describes the influence of the velocity in displacing the projectile horizontally.
The initial horizontal velocity can also be determined by measuring the diameter d of the ball and dividing by the time t that it takes for the ball to move across the photogate. That is Vo = d/t.
Initial vertical velocity
Vertical velocity refers to the speed of an object's movement in a vertical direction.The initial vertical velocity is the vertical component of the initial velocity: v 0 y = v 0 sin θ 0 = ( 30.0 m / s ) sin 45 ° = 21.2 m / s .
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a 1200-kg pick-up truck traveling south at 15 m/s suddenly collides with a 750-kg car that is traveling east. the two vehicles stick together and slide along the road after colliding. a highway patrol officer investigating the accident determines that the final position of the wreckage after the collision is 25 m, at an angle of 50° south of east, from the point of impact. she also determines that the coefficient of kinetic friction between the tires and the road at that location was 0.40. what was the speed of the car just before the collision?
The conservation of momentum, Newton's second law and kinematics allows to find the result for the initial speed of the car is:
The speed of the car is 40 m/s at the East direction.
Given parameters
Mass of the truck M = 1200 kg. Truck speed v₀₁ = 15 m / s towards the South. Mass of the car m = 750 kg. Travel east The two vehicles unite. The braking distance d = 25m at 50º SE The friction coefficient μ = 0.40To find
The initial speed of the car.
The momentum is defined by the product of the mass and the velocity of the body, so it is a vector quantity. In the case of an isolated system the momentum is conserved.
In the attachment we see a diagram of the vehicle crash, let's write the moment for each axis.
y-axis
Initial instant. Before the shock.
[tex]p_{oy}[/tex] = M v₀₁
Final moment. After the crash
[tex]p_{fy}[/tex] = (M + m) [tex]v_{fy}[/tex]
The system is formed by the two vehicles for which during the crash it is isolated and the momentum is conserved.
[tex]p_{oy} = p_{fy} \\\\M v_{o1} = (M+m) v_{fy} \\v_{fy} = \frac{M}{M+m} \ v_{o1}[/tex]
Calculate us
[tex]v_{fy} = \frac{1200}{1200+750} \ 15[/tex]
vfx = 9.23 m / s
x-axis
Initial instant. Before the crash.
p₀ₓ = m v₀₂
Final moment. After the crash.
[tex]p_{fx}[/tex] = (M + m) [tex]v_{fx}[/tex]
The momentum is preserved.
[tex]p_{ox}= p_{fx} \\m v_{o2) = (M+m) \ v_{fx}[/tex]
Let's find the velocity just after the collision, let's use Newton's second law,
y-axis
N-W = 0
N = W = (M + m) g
x-axis
fr = (M + m) a
The friction force is the macroscopic manifestation of the interactions between the two bodies.
fr = μ N
We substitute.
μ g = a
Now we can use kinematics.
v² = v₀² - 2a d
When the vehicles stop their speed is zero.
v₀² = 2 a x
v₀ = [tex]\sqrt{2\ \mu \ g \ d}[/tex]
Let's calculate.
v₀ = [tex]\sqrt{2 \ 0.40 \ 9.8 25 }[/tex]
v₀ = 14 m / s
This is the speed of the two vehicles just after the collision, that is, let's use trigonometry to find their components.
cos 25 = [tex]\frac{v_{ox}}{v_o}[/tex]
v₀ₓ = v₀ cos 25
v₀ₓ = 14 cos 25
v₀ₓ = 12.69 m / s
We substitute in the expression of the conservation of the momentum in the x-axis.
m v₀₂ = (M + m) [tex]v_{fx}[/tex]
[tex]v_{o2} = \frac{M+m}{m} v_{fx}[/tex]
Let's calculate.
[tex]v_{o2} = \frac{1200+750}{750} \ 12.69[/tex]
vfy = 32.99 m / s = 40 m / s
In conclusion using the conservation of momentum, Newton's second law and kinematics we can find the result for the initial speed of the car is:
The speed of the car is 40 m/s at the East direction.
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what metaphor most closely describes the nature of space-time?
a. chemistry formula
b.fabric
c. sine wave
d. moebius strip
Answer:
b.fabric
Explanation:
Nowadays, when people talk about space-time, they often describe it as resembling a sheet of rubber. This, too, comes from Einstein, who realized as he developed his theory of general relativity that the force of gravity was due to curves in the fabric of space-time.
Answer:
B. fabric
Explanation:
A new tube is used each time a blood sample is tested.Explain why valid results are only obtained if each tube is identical
Valid results are only obtained if each tube is identical because; effective comparison of the tested blood each time can only be achieved if the testing model is constant in which case each tube is identical.
Discussion:
During scientific tests such as that described in the question; it is important to keep all parameters of testing constant.
This is so because, the utmost motive of the testing model is to draw comparison. It is on this note that valid results are only obtained if each tube is identical.
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1. You walk along a long straight school corridor for 55
m, then you turn around and walk 30 m in the
opposite. Finally, you turn again and walk 39 m in
the original direction and stop. What is your
displacement from your starting point?
Explanation:
14 m is the displacement and towards the north
Omar rubs a balloon with wool, giving the balloon a
charge of -8.9x10-14 C. What is the force between
the balloon and a metal sphere that is charged to
25 C and is 2 km away?
Answer:
-8.9×10-14=-89-14=-103°C
25°C=2km
-103°C=? Less
=-103/25×2km
=-8.24km
These people load 10 items on the truck in 10 minutes. What are ways power can be increased?
The power can be increased by decreasing the time it takes to load 10 items into the truck it can be done by using leverage and putting more boxes in the truck at the same time.
What is power in physics?Power refers to the ability of doing work done per unit time, higher the power means more work has been done in less time. The SI unit of power is watt.
What is work done?Work done is a physical quantity that refers to measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
Given:
10 people are loading 10 items in a truck
According to the question we have to maximize the power output.
To do this we need to increase work done per unit time. This can be done in a number of ways which include:
Using leverage and pulley techniques to increase the loading capacity of the individual, so that more work is done in less time and therefore increasing the power output of the work to be done.
The second method would be decreasing the time it takes to load the boxes into the truck which can be done if multiple boxes are loaded into the truck at the same time.
Therefore, the power can be increased by decreasing the time it takes to load 10 items into the truck it can be done by using leverage and putting more boxes in the truck at the same time.
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What acceleration occurs if the friction force in #4 is now 4N?
The acceleration of the 20 N force is 6.67 m/s^2. The acceleration of the 4N force is 1.33 m/s^2.
What is force?We define the force that acts on a body as that which is able to cause an acceleration or that which is able to change the direction of an object. Recall that from the Newton first law, an object would continue in its state of rest or uniform motion unless the object is acted upon by an external force.
Now the frictional force is the force that tends to resist the motion of two surfaces that are in contact. Owing to the fact that it is a resistive force its direction is always opposite the force that seeks to move the object forward.
Now;
F = ma
a = F/m
a = 20 N/3Kg
a = 6.67 m/s^2
If the force is 4N;
a = F/m
a = 4N/3Kg
a = 1.33 m/s^2
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Missing parts;
How would you calculate the acceleration if you push with a 20 N horizontal force on a 3 kg block on a horizontal friction-free air table? What is the acceleration if the friction force is 4 N?
What is the acceleration of an elevator that weighs 5200 kg with a force of 35 N ?
Answer:
0.007 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{35}{5200} = 0.006730 \\ [/tex]
We have the final answer as
0.007 m/s²Hope this helps you
If 40 N force is exerted by a box covering 2 metre square area, calculate pressure.
[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]
[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]
[tex] \sf \huge \red {\dag} Given[/tex]
[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]
[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]
We know that the formula of Pressure is
[tex]\sf \longmapsto \: Force/Area[/tex]
Let's start.
Put the values[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]
[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]
[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]
Emma travels at a speed of 23 miles per hour for 3.5 hours. How far has she travelled?
Answer: 80.5 miles
Explanation:
3.5 x 23 = 80.5
Define displacement in your own word
Answer:
Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
Explanation:
URGENT! 40 POINTS! For each situation below, make a model of the situation and find the work done on the box using both energy and forces.
1. A 2 kg box with some initial velocity slides up a frictionless ramp, which is at a 15ᵒ
angle to the ground, until the box comes to rest 1 second later.
2. A 2 kg box initially at rest slides down a frictionless ramp (at 15ᵒ from the ground) for
1 second.
3. A 2 kg box is thrown upward with an initial speed of 3.5 m/s. Consider the box from
the time it was thrown until it reaches its maximum height.
4. A 2 kg box is dropped from an initial height of 10 m.
I have some physics, I just don't know what formulas to use or where to start. Help is much appreciated.
Answer:
i dont know but ask your mom for help
Explanation:
some brainly things dont work so ask your mom for some help or someone you know ok
3.2.1.3.2 Practice with Work and Forces …A_K_
What is occurring in the umbra?
A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse
Answer:
A. a total solar eclipse
Explanation:
During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth
A child sits on a rotating merry-go-round, 2.1 m from its center. If the speed of the child is 2.2 m/s, what is the minimum coefficient of static friction between the child and the merry-go-round that will prevent the child from slipping?
We have that the the minimum coefficient of static friction is mathematically given as
[tex]\mu= 0.235[/tex]
ForceGenerally the equation for the Force is mathematically given as
[tex]F=n\mu\\\\Where\\\\n = mg\\\\Given\\\\Fc = m(vt2/R)\\\\Therefore\\\\\mu = vt2/gR\\\\\mu = 2.22/(9.8(2.1)) \\\\[/tex]
[tex]\mu= 0.235[/tex]
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A girl pushes her little brother on his sled with a force of 300 N for 750 m.
How much work is this? _______________
How much energy is used?__________
How much power does she use if it takes her 25s?_________
How much power does she use if she runs and complete the 750m in 10s?________
Answer:
W = F× d
= 300×750
= 225000
E = 225000
P = 300×750/25 = 9000
P = 300× 750/10 = 22500
A scientist fills a container with sea water. The container has dimensions 30 cm x 30 cm x 40 cm The density of sea water is 1020 kg/mº. Calculate the mass of the sea water in the container.
Answer:
30600kg
Explanation:
density=m/v make v subject of the formula
What would be the acceleration of a block sliding down an inclined plane that makes an angle of 45° with the horizontal if the coefficient of sliding friction between two surfaces in 0.3? 141
Ans: 4.95 m/sec?
Answer:
unfortunately we have not received a reply to the park yet but
Explanation:
mohamedz and he had killed him
A student did 24 J of work on a chair. She applied a force of 12 N and moved the chair 2 m. What else do you need to know to determine the amount of power used?
Answer:
time
Explanation:
power = work done ÷ time
what is Secular Music's instrument's?
Answer:
Drums, harps, recorders, and bagpipes.
Explanation:
The wave height is equal to twice the _____.wave period wave height wave amplitude wave velocity wavelength
The wave height is equal to twice the amplitude of the wave.
The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.
The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.
Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.
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Describe the changes that occur inside a helium balloon as it rises from sea level
Answer:
The balloon expands in the number of particles per cubic centimeter decreases. This happens because as it expands there is a decrease in the density of area. The Dead Sea is a solution that is so dense that you easily float on it.
what is the radius of the event horizon of a 10 solar mass black hole?
Answer:
The number take for the "radius" is normally taken to be the radius from the center to the event horizon, since nothing inside that can be observed, and since it is a point of no return. This radius is directly proportional to the mass of the black hole. From the Wikipedia article on event horizon: "For the mass of the Sun this radius is approximately 3 kilometers and for the Earth it is about 9 millimeters. In practice, however, neither the Earth nor the Sun has the necessary mass and therefore the necessary gravitational force, to overcome electron and neutron degeneracy pressure." The last sentence means that it is unlikely for the Sun to become a black hole, since it has too little mass to become one.
Explanation:
CAN I GET BRAINLIEST
I'll give brainliest
Answer: figuratively speaking both the lines for the force Q and force P is equal.
c. How can you explain natural selection in evolution of insects from the time they evolved till our days now?
Se lanza un balón verticalmente hacia arriba con una velocidad de 72 km/h. ¿Qué altura recorrió dicho cuerpo después de 0.05 minutos? (g = 10m/s2)
Usando la información contenida en la pregunta, la distancia que recorre la bola hacia arriba es de 15 m.
Velocidad inicial = 20 m / s
Tiempo= 3 s
Aceleración por gravedad = 10 ms-2
Velocidad final = 0 m / s
Usando la ecuación;
h = u t - 1 / 2 g t 2
h = (20 × 3) - 1/2 × 10 × (3) ^ 2
h = 60 - 45
h = 15 m
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(50 POINTS!!) 3. Make a model that shows the forces acting on two blocks on a flat, frictionless surface:
a. A 1 N block at rest
b. A 1 N block with 2 N of force applied in one horizontal direction
Include arrows to represent the forces and labels to indicate the magnitude of each force. Use your model to compare and explain the motion of each block.
The change in position of an object is known as motion. Force is external that causes a body to change its position
For a body is to be at rest, the sum of all the forces acting on the object must be zeroFor a 1N block to be at rest, the normal force acting opposite to the weight must also be 1N.For 1 N block with 2 N of force applied in one horizontal direction, the image of the body is as shown in the attachmentLearn more about force here: https://brainly.com/question/20955770
Answer:
In short terms. the 1N block at rest will stay still and the 1N block with 2N applied will move forward.
State the universal law of gravitation.
Answer in detail
Answer:
Explanation:
Newton's law of universal gravitation is that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
A very light rod 40cm long is pivoted at the centre. A weight of 50N is placed at one end. Where is the place to put a weight of 200N in order that the rod is in equilibrium?
Hi there!
We can go about this problem using a summation of torques.
In order to ensure the rod is in equilibrium, we must satisfy the condition:
Στ = 0
Since the rod is "very light", we can disregard its mass.
The equation for torque is:
τ = rFsinθ
In this instance, the torques are the weights of the objects and their distance from the pivot.
As the rod is 40 cm, the pivot is at 20 cm. Also, the torques must sum up to 0, so:
0 = rF1 - rF2
r1F1 = r2F2
0.20(50) = r2(200)
Solve:
10 = r2(200)
r2 = 0.05 m = 5 cm
The 200N weight must be put at a distance of 5 cm from the OTHER SIDE of the pivot in order to balance the rod.
With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the bottom of this hill from its starting height. To do this start by setting the kinetic and potential energy equations equal to one another
The speed of the car at the bottom of the hill is obtained as, [tex]v = \sqrt{2gh}[/tex]
According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.
[tex]K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v= \sqrt{2gh}[/tex]
where;
v is the speed of the car at the bottom of the hillh is the height of the hillg is acceleration due to gravityThus, the speed of the car at the bottom of the hill is obtained as, [tex]v = \sqrt{2gh}[/tex]
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