On a coordinate plane, 2 quadrilaterals are shown. The first figure has points A (negative 2, 1), B (negative 4, 1), C (negative 4, 5), and D (negative 2, 4). Figure 2 has points A prime (2, 1), B prime (4, 1), C prime (4, 5), and D prime (2, 4).
What is the rule for the reflection?

A. rx-axis(x, y) → (–x, y)

B. ry-axis(x, y) → (–x, y)

C. rx-axis(x, y) → (x, –y)

D. ry-axis(x, y) → (x, –y)

Answer:

x less than or equal to -2

Answer:

5/6

Step-by-step explanation:

Answer:

5/6

Step-by-step explanation:

All of the answers either increase or reduce to 8/10 except 5/6

Hope this helps! Please mark as brainliest answer if correct.

Stay safe, God bless, and happy studying!

Answer:3500

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Answer:

Uh how to use segmant tool

Step-by-step explanation:

not there

Answer:

12

Step-by-step explanation:

Given :-

Two numbers => 48 and 60

To Find :-

HCF of 48 and 60

Solving :-

Prime factorize the numbers.

48 = 2⁴ x 3

60 = 2² x 3 x 5

Solution :-

HCF (48, 60) = 2² x 3 = 12

Answer:

x=40

Step-by-step explanation:

The angles of both expressions (4x-28) and (3x+12) are congruent (alternating exterior angles). So, you can set up the equation 4x-28 = 3x+12 because both expressions are equivalent, so it makes sense. Then solve for x.

4x - 28 = 3x + 12

x - 28 = 12

x = 40

Answer:

4/5

Step-by-step explanation:

There are 10 tiles total, and E and I are vowels. This makes 2/10 of the tiles tiles. The other 8/10 are not vowels.

8/10 can be simplified down to 4/5.

There is a 4/5 probability of picking a letter that is not a vowel.

Answer:

x+y=12

Step-by-step explanation:

Standard form is ax+by=c

Given, y-8 = -(x-4)

y-8=-x+4

x+y=4+8

x+y=12

Answer:

x + y = 12

Step-by-step explanation:

Standard form is Ax+By=C

so the goal is to get the y and the x on the same side without and negatives or fractions on that side.

y - 8 = - (x - 4)  first, start by simplifying

y - 8 = -x +4  next, because it is negative, we are going to add x to -x on the right side to get it to cancel out and we'll add x to y on the left side

x + y - 8 = 4  now we need to get rid of that eight so we'll add 8 to -8 so it cancels out and we'll add 8 to 4

x + y = 12 now it is in standard form

The profit that Jude made during the party was £3700.

Profit is the difference between revenue and cost. It is given by:

Profit = Revenue - Cost

From the question:

The total cost = 300 + 2500 + 500 + (1 * 400 people) = £3700

Revenue = 400 ticket * £16 = £6400

Profit = Revenue - Cost = £6400 - £3700

The profit that Jude made during the party was £3700.

Find out more on profit at: https://brainly.com/question/23103804

A function is a relation in which there is only one y-value for every x-value.

If we given an input of 3 for x, for example, we would only get one output for y, like 1, for example.

If we look at the table, we can see that the x-value of 3 gives us two outputs: 7 and 9.

Therefore, this relation is not a function.

9514 1404 393

Answer:

  congruent

Step-by-step explanation:

Angles supplementary to the same angle are congruent.

__

Here, angles 1 and 3 are both supplementary to angle 2, so ...

  angle 1 and angle 3 are congruent

Step-by-step explanation:

320 = 80 × 4

80 = 8 × 10

4 = 2 × 2

10 = 5 × 2

bold one's are answer.

hope this helps you.

========================================================

Explanation:

Going from the first term to the second, we add on -2

Then going from the second term to the third, we add on +2

This inconsistency (-2 vs +2) means we don't have a common difference, and therefore the sequence is not arithmetic.

------------

Now let's divide each term by their previous term

term2/term1 = 0/2 = 0

term3/term2 = 2/0 = undefined

We can stop here and conclude that we don't have a common ratio either, so this sequence is not geometric.

------------

Side note: The subsequence 0,2,4,6,... is arithmetic with common difference d = 2 because we add 2 to each term. It's that first 2 in the original sequence that breaks everything.

9514 1404 393

Answer:

Step-by-step explanation:

The point-slope form of the equation for a line with slope m through point (h, k) is ...

  y -k = m(x -h)

Comparing this to the equation you have, you see that you have a "point-slope form" equation with m=7 and (h, k) = (4, 2).

__

The standard form of an equation for a line is ...

  ax +by = c

where a, b, c are mutually prime integers and a > 0.

Putting your equation into standard form would make it look like ...

  7x - y = 26

Your equation is not in correct standard form.

_____

see https://brainly.com/question/18537811 for more information

Answer: The correct equation should be 0.2+5.8=6

Step-by-step explanation: First of all let's look at the equation without the decimal ".8". So, it would be 2+5 which equals 7. Since the sum is greater, adding a decimal will make the sum larger than 6. 2+5.8=7.8, therefore the correct equation being 0.2+5.8=6. Hopes this makes sense and helps!

Answer:

down

Step-by-step explanation:

c) 6 and 8

a) 7 and 1

b) 5 and 4

Answer:

(b) NO

Step-by-step explanation:

It must have the square to to be a right angle

Answer:

A: It is obtuse

B: It is a right angle

Step-by-step explanation:

A: Angle RST equals 110*, if it is greater than 90*, it is obtuse

B: Right Angles are 90*, so this is simple, you subtract RST by UST, so 110-20=90

Answer:

x = 31 1/2

Step-by-step explanation:

If y = 42, that means the original y = 28 was multiplied by 1.5, so we have to multiply x = 21 by 1.5 to find the answer.

21 * 1.5 = 31.5 A.K.A 31 1/2

Divide both systems:

y=4(4)^x

y=4^x+1

Answer:

[tex]x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}[/tex]

Step-by-step explanation:

[tex]\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}[/tex]

[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]\mathrm{For\:}\quad a=2,\:b=-10,\:c=5[/tex]

[tex]x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:2\cdot \:5}}{2\cdot \:2}[/tex]

[tex]\sqrt{\left(-10\right)^2-4\cdot \:2\cdot \:5}[/tex]

Apply exponent rule: (-a)^n=a^n, if n is even

[tex]\left(-10\right)^2=10^2[/tex]

[tex]=\sqrt{10^2-4\cdot \:2\cdot \:5}[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:4\cdot \:2\cdot \:5=40[/tex]

[tex]=\sqrt{10^2-40}[/tex]

[tex]10^2=100[/tex]

[tex]=\sqrt{100-40}[/tex]

[tex]\mathrm{Subtract\:the\:numbers:}\:100-40=60[/tex]

[tex]=\sqrt{60}[/tex]

[tex]60\:\mathrm{divides\:by}\:2\quad \:60=30\cdot \:2[/tex]

[tex]=2\cdot \:30[/tex]

[tex]30\:\mathrm{divides\:by}\:2\quad \:30=15\cdot \:2[/tex]

[tex]=2\cdot \:2\cdot \:15[/tex]

[tex]15\:\mathrm{divides\:by}\:3\quad \:15=5\cdot \:3[/tex]

[tex]=2\cdot \:2\cdot \:3\cdot \:5[/tex]

[tex]2,\:3,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}[/tex]

[tex]=2\cdot \:2\cdot \:3\cdot \:5[/tex]

[tex]=2^2\cdot \:3\cdot \:5[/tex]

[tex]=\sqrt{2^2\cdot \:3\cdot \:5}[/tex]

Apply Radical Rule:

[tex]=\sqrt{2^2}\sqrt{3\cdot \:5}[/tex]

Apply Radical Rule:

[tex]\sqrt{2^2}=2[/tex]

[tex]=2\sqrt{3\cdot \:5}[/tex]

[tex]\mathrm{Refine}[/tex]

[tex]=2\sqrt{15}[/tex]

[tex]x_{1,\:2}=\frac{-\left(-10\right)\pm \:2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]\mathrm{Separate\:the\:solutions}[/tex]

[tex]x_1=\frac{-\left(-10\right)+2\sqrt{15}}{2\cdot \:2},\:x_2=\frac{-\left(-10\right)-2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]\frac{-\left(-10\right)+2\sqrt{15}}{2\cdot \:2}[/tex]

Apply Rule -(-a)=a

[tex]=\frac{10+2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4[/tex]

[tex]=\frac{10+2\sqrt{15}}{4}[/tex]

[tex]=\frac{2\left(5+\sqrt{15}\right)}{4}[/tex]

[tex]\mathrm{Cancel\:the\:common\:factor:}\:2[/tex]

[tex]=\frac{5+\sqrt{15}}{2}[/tex]

[tex]\frac{-\left(-10\right)-2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]=\frac{10-2\sqrt{15}}{2\cdot \:2}[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4[/tex]

[tex]=\frac{10-2\sqrt{15}}{4}[/tex]

[tex]=\frac{2\left(5-\sqrt{15}\right)}{4}[/tex]

[tex]\mathrm{Cancel\:the\:common\:factor:}\:2[/tex]

[tex]=\frac{5-\sqrt{15}}{2}[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}[/tex]

[tex]x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}[/tex]

Answer:

It's multiply both by thesame number

Step-by-step explanation:

For example:

If we want to change this fraction to a simplest form:

5/25

We simply multiply both sides by 5,which will give us:

5/5

And if you want simplify it further, the answer will be 1

Thanks.

Answer:

alternate angled

Step-by-step explanation:

add up to 180

Let

[tex]I(a) = \displaystyle \int_0^\infty \frac{\sqrt x \arctan(ax)}{1+x^2} \, dx[/tex]

Differentiate with respect to a :

[tex]I'(a) = \displaystyle a \int_0^\infty \frac{x^{\frac32}}{(1+x^2)(1+a^2x^2)} \, dx[/tex]

Substitute y = √x :

[tex]I'(a) = \displaystyle 2a \int_0^\infty \frac{y^4}{(1+y)(1+a^2y)} \, dy[/tex]

Polynomial division yields

[tex]\dfrac{y^4}{(1+y)(1+a^2y)} \\\\ = \dfrac1{a^2}y^2 - \left(\dfrac1{a^2} + \dfrac1{a^4}\right)y + \dfrac1{a^2} + \dfrac1{a^4} + \dfrac1{a^6} - \dfrac{\left(1+\frac1{a^2} + \frac1{a^4} + \frac1{a^6}\right)y + \frac1{a^2} + \frac1{a^4} + \frac1{a^6}}{(1+y)(1+a^2y)}[/tex]

Computing I'(a) isn't so difficult from here. You'd find (assuming a ≥ 0)

[tex]I'(a) = \displaystyle \frac\pi{\sqrt2\left(\sqrt a + a + a^{\frac32} + a^2\right)}[/tex]

Integrate both sides with respect to a. On the right side, substituting b = √a yields

[tex]\displaystyle \int \frac{da}{\sqrt a + a + a^{\frac32} + a^2} = \int \frac{2b}{b + b^2 + b^3 + b^4} \, db \\\\ = 2 \int \frac{db}{1 + b + b^2 + b^3} \\\\ = 2 \int \frac{db}{(1+b)(1+b^2)} \\\\ = \int \left(\frac1{1+b} + \frac{1-b}{(1+b^2)}\right) \, db \\\\ = \frac14 \left(2 \arctan(b) + 2 \ln(1 + b) - \ln(1 + b^2)\right) + C \\\\ = \frac14 \left(2 \arctan(\sqrt a) + 2 \ln(1 + \sqrt a) - \ln(1 + a)\right) + C[/tex]

Noting that a = 0 makes the integral I(a) vanish, we have

[tex]0 = \dfrac14 \left(2 \arctan(\sqrt0) + 2\ln(1 + \sqrt0) - \ln(1 + 0)\right) + C \implies C = 0[/tex]

and so

[tex]\displaystyle I(a) = \frac\pi{4\sqrt2} \left(2 \arctan(\sqrt a) + 2 \ln(1 + \sqrt a) - \ln(1 + a)\right)[/tex]

We recover the integral we want with a = 1, which gives a value of

[tex]\displaystyle \int_0^\infty \frac{\sqrt x \arctan(x)}{1 + x^2} \, dx = \boxed{\frac{\pi^2 + 2\pi\ln(2)}{4\sqrt2}}[/tex]

Answer:

what are you trying to solve?

Answer:

Step-by-step explanation:

Answer:

The answer is True.

Step-by-step explanation:

The earliest civilizations developed between 4000 and 3000 BCE, when the rise of agriculture and trade allowed people to have surplus food and economic stability.

Hope this helps you!