On a coordinate plane, quadrilateral J K L M with diagonals is shown. Point J is at (4, 5), point K is at (5, 1), point L is at (1, 2), and point M is at (1, 5). Which statement proves that quadrilateral JKLM is a kite?

Answers

Answer 1

Answer:

[tex]LM = MJ = 3[/tex]

[tex]JK = KL = \sqrt{17[/tex]

Step-by-step explanation:

Given

[tex]J = (4,5)[/tex]

[tex]K = (5,1)[/tex]

[tex]L = (1,2)[/tex]

[tex]M = (1,5)[/tex]

Required

Prove it's a kite

Start by calculating the length of the sides of the kite using:

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 -y_2)^2}[/tex]

[tex]JK = \sqrt{(4 - 5)^2 + (5 -1)^2} = \sqrt{17}[/tex]

[tex]KL = \sqrt{(5 - 1)^2 + (1 -2)^2} = \sqrt{17}[/tex]

[tex]LM = \sqrt{(1 - 1)^2 + (2 -5)^2} = \sqrt{9} =3[/tex]

[tex]MJ = \sqrt{(1 - 4)^2 + (5 -5)^2} =\sqrt{9} = 3[/tex]

Hence:

[tex]LM = MJ = 3[/tex]

[tex]JK = KL = \sqrt{17[/tex]

proves that it is a kite

Answer 2

Answer:

B)  LM = JM = 3 and JK = LK = [tex]\sqrt{17}[/tex]

Step-by-step explanation:

Edge 2021

Good Luck :)


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Answers

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Step-by-step explanation:

edge 2021

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*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

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Answers

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Step-by-step explanation:

Your answer is A.
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Answers

Answer:

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Step-by-step explanation:

Put problem in Desmos

Write the expression as StartFraction a Over 90 EndFraction. Write the expression as 90 – a. Write the expression as a – 90. Substitute 102 in for the variable, a. Simplify by subtracting 90 from 102. Simplify by dividing 102 by 90. The answer is 1.13. The answer is 12.

Answers

Answer:

Write the expression as a – 90

Simplify by subtracting 90 from 102.

The answer is 12.

Step-by-step explanation:

Write and evaluate the expression. Then, check all that

apply

the difference of a number and ninety;

o Write the expression as

90

when a = 102

Subtraction Words

Write the expression as 90-a.

Write the expression as a -90,

O Substitute 102 in for the variable, a.

Simplify by subtracting 90 from 102.

Simplify by dividing 102 by 90.

decreased by

difference

fewer

The answer is 1.13.

less than

The answer is 12.

subtract

Let

The unknown number = a

The expression is

a - 90

Substitute a = 102

a - 90

= 102 - 90

= 12

The answer is - /C, D, E, H/

                        - /3, 4, 5, 8/

                        - "Write the expression as a – 90.",

                         "Substitute 102 in for the variable, a.",

                         "Simplify by subtracting 90 from 102.",

                         "The answer is 12."

                           I hope it makes sense, you're welcome!

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Answers

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Answers

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0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?

Answers

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So,  4# · 3# · 2# · 1#? =  6912 · 24 · 2 · 1? = 331776

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Answer:

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