ostulate
Point D is on segment BC. Segment BC measures 8x units in length.

A line has points C, D, B. The length of line C D is 3 x + 8. The length of line D B is 4 x + 10.
What is the length of segment BC?

Answer:

0.27

0.1111111

Step-by-step explanation:

Given that:

X :

L1 = 40% = 0.4

L2 = 30% = 0.3

L3 = 20% = 0.2

L4 = 30% = 0.3

P(x) :

L1 = 0.2

L2 = 0.1

L3 = 0.5

L4 = 0.2

A.)

Σ(X * p(x))

(0.4 * 0.2) + (0.3*0.1) + (0.2*0.5) + (0.3 * 0.2) = 0.27

B.) Radartrap located at L2:

P(L2) = (L(x2) * p(L2)) / Σ(X * p(x))

= (0.1 * 0.3) / 0.27

= 0.1111111

Answer:

200 pounds per crate

Step-by-step explanation:

because if you divide 1600 by 8 than you get 200 pounds. then that is you unit rate

Answer:

250

2000 divided by 8

Step-by-step explanation:

Answer:

subtract 2-6 and the just put a - in front of 4 so -4

Step-by-step explanation:

Answer:

-2 will be 2 times to the left of zero and -6 would be 6 spaces to the left of zero.

7 inches = 17.78 cm

Step-by-step explanation:

I looked it up

Answer:

17.78

Step-by-step explanation:

Each inch is 2.54cm.

We will first multiply 2.54 into 7 inches, since it is asking us for the centimeters, then our work should now look like this: 2.54 x 7 = 17.78

We can check our work by dividing the sum by the number in our equation.

17.78/7= 2.54

Answer:

Step-by-step explanation:

Given sequence:  

The first term is -1 and the common difference is -3

19th term is:

Answer:

45

Step-by-step explanation:

Let the three quantities be x, y and z.

[tex] \because \: average = \frac{sum \: of \: quantities}{no \: of \: quantities} \\ \\ \therefore \: 15 = \frac{x + y + z}{3} \\ \\ 15 \times 3 = x + y + z \\ \\ \huge \purple{ 45 = x + y + z}[/tex]

answer is 10

if not then im srry

Answer:

a+2b-d=1, 3, 5, 7

Step-by-step explanation:

(ax^2+bx+3)(x+d)

ax^3+bx^2+3x+adx^2+bdx+3d

ax^3+bx^2+adx^2+3x+bdx+3d=x^3+6x^2+11x+12

ax^3=x^3, a=1

bx^2+adx^2=6x^2

x^2(b+ad)=6x^2

b+ad=6

b+(1)d=6

b+d=6

------------

3x+bdx=11x

x(3+bd)=11x

3+bd=11

-----------------

b=6-d

3+(6-d)d=11

3+6d-d^2=11

3-11+6d-d^2=0

-8+6d-d^2=0

d^2-6d+8=0

factor out,

(d-4)(d-2)=0

zero property,

d-4=0, d-2=0

d=0+4=4,

d=0+2=2

b=6-4=2,

b=6-2=4.

------------------

a+2b-d=1+2(2)-2=1+4-2=5-2=3

-------------------

a+2(4)-4=1+8-4=9-4=5

-----------------------

a+2(2)-4=1+4-4=5-4=1

-----------------------

a+2(4)-2=1+8-2=9-2=7

Answer:

[tex]a+2b-d=1[/tex]

Step-by-step explanation:

We are given that:

[tex](ax^2+bx+3)(x+d)=x^3+6x^2+11x+12[/tex]

And we want to determine:

[tex]a+2b-d[/tex]

So, we will determine our unknowns first.

We can distribute our expression:

[tex]=(ax^2+bx+3)x+(ax^2+bx+3)d[/tex]

Distribute:

[tex]=ax^3+bx^2+3x+adx^2+bdx+3d[/tex]

Rearranging gives:

[tex]=(ax^3)+(bx^2+adx^2)+(bdx+3x)+3d[/tex]

Factoring out the variable yields:

[tex]=(a)x^3+(b+ad)x^2+(bd+3)x+d(3)[/tex]

Since we know that our expression equals:

[tex]x^3+6x^2+11x+12[/tex]

This means that each of the unknown terms in front of each variable corresponds with the coefficient of the resulting equation. Therefore:

[tex]\begin{aligned} a&=1\\ b+ad&=6\\bd+3&=11\\3d&=12\end{aligned}[/tex]

Solving the first and fourth equation yields that:

[tex]a=1\text{ and } d=4[/tex]

Then the second and third equations become:

[tex]b+(1)(4)=6\text{ and } b(4)+3=11[/tex]

And solving for b now yields that:

[tex]b=2\stackrel{\checkmark}{=}2[/tex]

Therefore, we know that:

[tex]a=1, b=2\text{ and } d=4[/tex]

For the equation:

[tex](x^2+2x+3)(x+4)=x^3+6x^2+11x+ 12[/tex]

Then the expression:

[tex]a+2b-d[/tex]

Can be evaluated as:

[tex]=(1)+2(2)-4[/tex]

Evaluate:

[tex]=1+4-4=1[/tex]

Hence, our final answer is 1.

Answer:

A image was not attached

Step-by-step explanation:

Answer:

1360.78 mg

Step-by-step explanation:

3 pounds in grams is 1360.78 grams.

so, 1 mg per gram would mean the baby should recieve 1360.78 mg of the drug.

Answer:

secondary

Step-by-step explanation:

Answer:

Step-by-step explanation: i got it right :) hopefully you get it in time!

How do you calculate run time and speed?

32 min * 8 min per mi = 4 miles How to calculate run time. Multiply your pace by your distance; If the pace is 9.5 minutes per mile and you run 3 miles: 9.5 min per mi × 3 mi = 28.5 minutes = 28 minutes, 30 seconds How to calculate running speed. Divide your run distance by your run time.

What do you do to calculate average speed?

Learn more about average speed here https://brainly.com/question/5147964

#SPJ2

Answer:

Step-by-step explanation: 0.15 and 0.2 are the slope of the line on the graph. The graph of the equation reading y = 0.20x + 25 would show a steeper line bc the bigger the slope the steeper the line.

Step-by-step explanation:

multiply all the fractions together in your calculator :)

Answer:

The polynomial simplifies to a quadratic with a degree of 2

Step-by-step explanation:

Expand and simplify everything

-5x²-2x+4+8x²-x-1-x²+5x-2x+10

-5x²+8x²-x²-2x-x+5x-2x+4-1+10

2x²+13

Answer:

98

Step-by-step explanation:

Average is the sum of all data points divided the number of data points.

In this specific situation, the average test score, 91, is equal to the sum of Molly's four individual test scores divided by the number of test Molly had, 4.

(( 86 + 87  + 93  + x) / 4) = 91

86 + 87 + 93 + x = 91/4

86 + 87 + 93 + x = 364

x = 364 - 93 - 87 - 86 = 98

Hello there!

85 is composite.

There are 3 ways of determining whether a number is prime or composite.

Hope this helps!

[tex]GraceRosalia[/tex]

Answer:

10

Step-by-step explanation:

lol

...its 10

Step-by-step explanation:

1+1+1+1+1= 5

1+1+1+1+1= 5

5+5=10

Answer:

56.7

Step-by-step explanation:

Just Add all numbers

Answer:

13

Step-by-step explanation:

The term is in an arithmetic progression.

That means there is 6 between each term and the next one.

Givens

a = -30

d = 6

last term an = 42

Formula

L = a + (n - 1)*d

Solution

42 = -30 + (n -1 )*6               Add 30 to both sides

42+30 = (n - 1) * 6                Combine the terms on the left.

72 = (n - 1)*6                        Divide both sides by 6

72/6 = n - 1

12     = n - 1                          Add 1 to both sides

12 + 1 = n

n = 13

Answer:

0.057

0.6140

0.3158

0.0701

Step-by-step explanation:

Given that:

Let :

P(L) = Number transported by land = half = 50% = 0.5

P(S) = number transported by sea = 30% = 0.3

P(A) = Number transported by air = (100 - (50 + 30))% = 20% = 0.2

P(H) = highway transport = 40% of land transport = 0.4 * 0.5 = 0.2

P(R) = Rail shipment =(100- 40)% = 60% of land transport = 0.6 * 0.5 = 0.3

Percentage of damaged cargo :

Let probability of damage = P(d)

P(d | H) = 0.1

P(d | R) = 0.05

P(d | S) = 0.06

P(d | A) = 0.02

1) What percentage of all cargoes may be expected to be damaged

[P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

(0.1*0.2) + (0.05*0.3) + (0.06*0.3) + (0.02*0.2) = 0.057

(2) If a damaged cargo is received, what is the probability that it was shipped by ;

land?

([P(d | H)*p(H)] + [P(d | R)*p(R)]) / [P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

((0.1*0.2) + (0.05*0.3)) / (0.1*0.2) + (0.05*0.3) + (0.06*0.3) + (0.02*0.2)

= 0.035 / 0.057

= 0.6140

By sea?

[P(d | S)*p(S)] / [P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

(0.06 * 0.3) / 0.057

= 0.3158

By air?

[P(d | A)*p(A)] / [P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

(0.02 * 0.2) / 0.057

= 0.0701

Answer:B; 4.35 • 10/4

Step-by-step explanation:

Answer:

The equation of the line is y = 3x - 11.

Step-by-step explanation:

We are given the equation of a line:

[tex]\bullet \ \ \ y = 3x -2[/tex]

We are also given a point at which the line passes through.

[tex]\bullet \ \ \ (4, 1)[/tex]

With parallel lines, it is important to note:

We can use the point-slope equation to find the equation of the line:

[tex]\displaystyle y-y_1 =m(x-x_1)\\\\y - 1 = 3(x - 4)\\\\y - 1 = 3x - 12\\\\y - 1 + 1 = 3x - 12 + 1\\\\y = 3x - 11[/tex]

Therefore, the line that is parallel to y = 3x - 2 and passes through the point (4, 1) is y = 3x - 11.

Answer: 19

Step-by-step explanation: