Answer:
Explanation:
C₆H₁₂O₆ + 60₂ = 6H₂0 + 6CO₂.
1 mole 6 mole
molecular weight of C₆H₁₂O₆ = 180 g
molecular weight of oxygen = 32 g
1 gram of glucose = 1 / 180 = 5.55 x 10⁻³ moles
1 gram of oxygen = 1 / 32 = 31.25 x 10⁻³ moles
1 mole of glucose reacts with 6 moles of oxygen
5.55 x 10⁻³ moles of glucose will react with 6 x 5.55 x 10⁻³ moles of oxygen
= 33.30 x 10⁻³ moles of oxygen .
But oxygen available = 31.25 x 10⁻³ moles
So available oxygen is less than required .
Hence oxygen is the limiting reagent .
b ) is the right option .
. Carbamide (CH4N2O), can be synthesized by the reaction of ammonia (NH3) with carbon
dioxide (CO2):
2 NH3 (aq) + CO2 (aq) CH4N2O (aq) + H2O (l)
An industrial synthesis of urea obtains 87.5 kg of urea upon reaction of 68.2 kg of ammonia
with 105 kg of carbon dioxide. Determine the limiting reactant, theoretical yield of urea and percent yeild for the reaction
Answer:
NH₃ is the limiting reactant.Theoretical yield = 120 kg% yield = 72.9 %Explanation:
2NH₃ (aq) + CO₂ (aq) → CH₄N₂O (aq) + H₂O (l)First we convert the given masses of reactants to moles, using their respective molar masses:
68.2 kg NH₃ ÷ 17 kg/kmol = 4.01 kmol NH₃105 kg CO₂ ÷ 44 kg/kmol = 2.39 kmol CO₂2.39 kmol of CO₂ would react completely with (2.39 * 2) 4.78 kmol of NH₃. There are not as many NH₃ kmoles so NH₃ is the limiting reactant.
We calculate how much urea would form with a 100% yield, using the moles of limiting reactant:
4.01 kmol NH₃ * [tex]\frac{1kmolCH_4N_2O}{2kmolNH_3}[/tex] = 2.00 kmol CH₄N₂OWe convert that amount to kg:
2.00 kmol CH₄N₂O * 60 kg/kmol = 120 kg CH₄N₂OFinally we calculate the percent yield:
87.5 kg / 120 kg * 100% = 72.9 %Do you agree / disagree - Light is always the same, even when it is emitted by different light sources (like the sun and a light bulb).
Answer:
She's right that there's a difference, and you are right that it's all just electromagnetic waves!
The key to this is that there is no such thing as "white light" when you really get down to it. Each light emits a range of wavelengths of light. If they have a sufficiently even distribution of wavelengths, we tend to call that light "white," but we can only use that term informally.
Both the sun and the light bulb emit so-called "Blackbody radiation." This is the particular spectrum of light that's associated with the random thermal emissions of a hot object. Cool objects tend to emit more of their energy in the longer wavelengths like reds and IRs, while hotter objects emit more energy in the shorter wavelengths like blues and UV.
Blackbody graphic
(Note, there are other possible emission spectra, but those are associated with different materials doing the emissions and, for the purposes of this discussion, they aren't too important. We can just claim the emissions are all blackbody)
If you notice, as you get hotter, a larger portion of the energy is emitted in the blue, violet, and ultraviolet. That's how you get a sunburn from the sun. It's harder to get a sunburn from an artificial light, not because it's artificial, but because those lights are almost always cooler than the sun. They don't have as much UV content. Instead, they have more red and yellow, which incidentally is why pictures taken indoors look very yellow. If you use a strobe, however, all those yellow hues go away because a strobe light is very warm, with lots of blues.
You can get a sunburn from artificial light, of course. Tanning beds are the obvious example, but there are other interesting ones. When you're a jeweler working in platinum, for instance, you need to wear UV protective gear (like glasses or even sunscreen). Platinum's melting point is so hot that it actually emits quite a lot of UV light and can give you a sunburn!
Other than these spectra, there is nothing different between light from an artificial source and light from the sun. Photons are photons.
Explanation:
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During electrolysis, where do reduction reactions occur?
A. in the anode of an electrolytic cell
B. in the cathode of an electrolytic cell
C. in the power source of an electrolytic cell
D. in the salt bridge of an electrolytic cell
Answer:
B)
Explanation:
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Answer:
( : The correct option is, (a) anode
Explanation:
A mixture of gaseous reactants is put into a cylinder, where a chemical reaction tums them into gaseous products. The cylinder has a piston that moves in or out, as necessary, to keep a constant pressure on the mixture of 1 atm. The cylinder is also submerged in a large insulated water bath. 1 atm pressure piston cylinder The temperature of the water bath is monitored, and it is determined from this data that 300.1J of heat flows out of the system during the reaction. The position of the piston is also monitored, and it is determined from this data that the system does 316.kJ of work on the piston during the reaction water bath gases exothermic.
Required:
a. Is the reaction exothermic or endothermic?
b. Does the temperature of the water bath go up or down?
Answer:
The reaction is exothermic
The temperature of the water bath goes up
Explanation:
An exothermic reaction is one in which energy flows out of the reaction system.
In this case, the system is the reaction vessel while the surrounding is the water bath. We see in the question that 300.1J of heat flows out of the system during the reaction. This is heat lost to the surroundings showing that the reaction is exothermic.
As energy is lost to the surroundings, the temperature of the water bath rises accordingly.
What happens to a solute?
Answer:
A
Explanation:
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help me plss it’s kinda easy but i’m not sure
Answer:
Sexual Reproduction
Explanation:
In Asexual Reproduction offsprings are know as ramets and many ramets are known as clowns. So, when two parents are involved genetic variations occur in offspring. Pollen possess male gamete (antherozoid/sperm) and ovule possess egg.
A part
A fly hits a windshield of a truck. The truck exerts a force on the fly, and
the fly exerts an equal and opposite force back on the windshield.
A. Newton’s first law
B. Newton’s second law
C. Newton’s third law
Answer:
A fly hits a windshield of a truck.
Explanation:
newton's first law
A major textile dye manufacturer developed a new yellow dye. The dye has a percent composition of 75.95% C, 17.72% N, and 6.33% H by mass with a molar mass of about 240 g/mol. Determine the molecular formula of the dye.
Answer:
C₁₅N₃H₁₅
Explanation:
Follow the sequence ...
%/100wt => grams/100wt => moles => mole ratio => reduce mole ratio (divide by smaller mole value) => empirical ratio.
Note: If the above calculation comes out with a fraction (for most textbook problems) do the following:
--.25 => multiply empirical ratio by 4
--.50 => multiply empirical ratio by 2
--.75 => multiply empirical ratio by 4
Or, if initial data is given in grams, convert to %/100wt. (example at end of problem)
This Problem:
%/100wt. grams moles =mass/formula wt.
%C = 75.95% => 75.95g => 75.95g/12.0107g·mol⁻¹ = 6.325 mole OS
%N = 17.72% => 17.72g => 17.72g/14.0067g·mol⁻¹ = 1.2651 mole N
%H = 6.33% => 6.33g => 6.33g/1.00794g·mol⁻¹ = 6.28 mol H
(∑ = 100% | assume 100g cpd => ( grams => 100g compound would contain 75.95g C, 17.72g N & 6.33g H )
=> mole ratio => C : N : H => 6.3235 : 1.2651 : 6.28
=> reduce mole ratio ( divide by smaller mole value ) ...
=> 6.3235/1.2651 : 1.2651/1.2651 : 6.28/1.2651 => empirical ratio is => 5:1:5
empirical formula => C₅NH₅
empirical formula wt. = 5C + 1N + 5H = 5(12) + 1(14) + 5(1) = 79
=> molecular ratio (n) => molecular wt (given) = N · empirical formula wt
=> N = molecular wt / empirical wt = 240/79 = 3
∴ Molecular Formula is => C₅NH₅ X 3 => C₁₅N₃H₁₅
________________________________________
EXAMPLE: Empirical Formula Problem with initial data in grams:
Assume an oxide of Osmium (compd wt) = 2.89 grams contains 2.16 gram Osmium, what is the empirical formula?
Use given mass values to calculate %/100wt then use the sequence
% => grams => moles => reduce => emp. ratio => emp. formula
%Os = 2.16g/2.89g x 100% = 74.74%
%Oxy = [(2.89g -2.16g)/2.89] x 100% = 25.26% or use 100% - 74.74% = 25.26%
% => g => moles => reduce => emp formula
%Os = 74.74% => 74.74g => 74.74g/190.23g·mol⁻¹ = 0.3929 mol Os
%Oxy = 25.26% => 25.26g => 25.26g/16g·mol⁻¹ = 1.5788 mole Oxy
Reduce mole ratio (divide by smaller mole value) => empirical ratioo
=> Os:Oxy => 0.3929/0.3929 : 1.5788/0.3929 = 1 : 4
=> Empirical Formula => OsO₄
Describe the patterns and atomic mass is an ion charges in the periodic table
Answer:
The atomic number increases across a period and down the group or family. The atomic mass generally increases with atomic number with a few exceptions.
The density of pentanol, C3H20, is 0.8110 g/mL. Calculate the volume occupied by 7.455 moles of pentanol. What is the volume occupied by 7.455 moles of pentanol?
The volume occupied by 7.455 moles of pentanol is 553.5 mL or 0.5535 L.
What does molar mass of a compound signify?The molar mass of a given compound is the mass of one mole of that compound. It is expressed in unit as grams per mole (g/mol).
To calculate the volume of pentanol occupied by 7.455 moles of the substance, we can use the following formula:
Volume = (number of moles x molar mass) / density
The molar mass of pentanol (C3H8O) can be calculated as:
3 x atomic mass of carbon (12.01 g/mol) = 36.03 g/mol 8 x atomic mass of hydrogen (1.01 g/mol) = 8.08 g/mol 1 x atomic mass of oxygen (16.00 g/mol) = 16.00 g/mol Total molar mass = 60.11 g/mol
Placing the given values into the formula, we get:
Volume = (7.455 mol x 60.11 g/mol) / 0.8110 g/mL Volume = 553.5 mL or 0.5535 L
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Where does an air mass gets its characteristics? A. From the air close to the sun and then it moves down to earth
B. From where it forms over the Earth and then it rises
C. From the air in the stratosphere
Answer:
C. From the air in the stratosphere
Explanation:
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In humans, normal color perception (N) dominates the expression of color blindness (n), and both of these genes are carried on the X chromosome (XN or Xn). A woman with normal color vision has a color-blind father. Her husband is also color-blind.
a. What is the genotype of the colorblind man? ____
b. What is the genotype of the woman? ______
c. What is the probability of her daughter to be colorblind? __________%
d. What is the probability of her sons to be colorblind? _________%
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Answer:
a: Nn or XN
b: Nn or Xn
c: 75%
d: 50%
Explanation:
what is the molarity of ethanol c2h5oh in an aqueous solution that is 36.4% ethanol by mass
Answer:
the answer is A
Explanation:
Name the following alkene compound
Sodium chloride (NaCl) is commonly used to melt ice on roads during the winter. Calcium chloride (CaCl2) is sometimes used for this purpose too. Let us compare the effectiveness of equal masses of these two compounds in lowering the freezing point of water by calculating the freezing point depression of solutions containing 220. g of each salt in 1.00 kg of water. (An advantage of is that it acts more quickly because it is hygroscopic, that is, it absorbs moisture from the air to create a solution and begin the process. A disadvantage is that this compound is more costly.) Assume full dissociation of ionic compounds. Kfp(H2O)= -1.86 °C/m.
ΔTfp= _________°C for NaCl
ΔTfp=_________ °C for CaCl2
Answer:
[tex]\Delta Tfp_{NaCl}= -14.0\°C\\\\\Delta Tfp_{CaCl_2}=-11.1\°C[/tex]
Explanation:
Hello!
In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:
[tex]\Delta Tfp= i*m*Kfp[/tex]
Thus, we first need to compute the molality of each solute, as shown below:
[tex]m_{NaCl}=\frac{220.g/(58.44g/mol)}{1.00kg} =3.76m\\\\m_{CaCl_2}=\frac{220.g/(110.98g/mol)}{1.00kg} =1.98m[/tex]
Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:
[tex]\Delta Tfp_{NaCl}= 2*3.76m*-1.86\°C/m=-14.0\°C\\\\\Delta Tfp_{CaCl_2}= 3*1.98m*-1.86\°C/m=-11.1\°C[/tex]
It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.
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For case 1, what happens when an electron jumps from energy level 1 to energy level 3 in an atom?
Answer:
Case 1 (energy level): In an atom, an electron jumps from energy level 1 to energy level 3. ... The energy will increase.
Explanation:
What is the formula for Triphosphorous nonaoxide
What is the atomic weight of Mercury?
Answer:
Not sure if I'm correct, but I think it's 200.59 u
Answer:
The answer is 200.59 u
Explanation:
Mercury has a mass of 3.3 x 1023kilograms. This mass is contained in a volume of 14.6 billion cubic miles (60.8 billion cubic km). The mass and volume of Mercury is only about 0.055 times that of Earth
What are the main parts of a simple electrie motor, like the one found inside a remote control car? O a generator, wires, and turbine magnets and coils of wire O electromagnets only
Answer:
A DC power supply, commutator, rotor armature, axle, and a field magnet.
If someone is building a scale model of our solar system which characteristic would be the most difficult to build into the model?
1#The relative sizes of the objects
2#The colors of the objects
3#The distances between objects
4#The composition of the objects
Answer:
The composition of the objects because not all the planets have been explored
Pl help it’s for a grade
15 g NiO is dissolved into enough water to make 800. mL of solution. What is the molar concentration of the solution? Report your answer with the correct number of significant figures.
Answer: 0.25
Explanation: M = moles of solute / volume of solution (L)
First, you need to calculate the number of moles using the given mass and the molar mass.
15 g74.692 g/mol≈0.20 mol
Then, you can solve for molarity using the molarity equation. The answer should be reported to two significant figures.
M=0.20 mol/ 0.800 L = 0.25 M
The molar concentration of NiO solution is 0.251 M.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.Considering the given example, molar concentration of NiO is found out as follows,
molar concentration=15/74.69 ×1/0.8= 0.251 M.
where 74.69 is molar mass of NiO.
Thus, the molar concentration of NiO is 0.251 M.
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need help answering this, Aleks is very picky, and I have been struggling with these questions
Answer:
No
No
Yes 25cm
Explanation:
1) mass can't be divided by distance.
2) the measurements are completely different but under the same category of distance. you can only divide it if meters was cm and squared
3) measurements the same and you can multiply it
For the following reaction, 14.3 grams of phosphorus (P4) are allowed to react with 32.1 grams of chlorine gas. phosphorus (P4) (s) + chlorine (g) phosphorus trichloride (l) What is the maximum amount of phosphorus trichloride that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams
Answer:
Limiting reactant: Cl2.
Max mass of PCl3 = 41.44 g.
P4 leftover = 5.51 g.
Explanation:
Hello!
In this case, since the undergoing chemical reaction is:
[tex]P_4+6Cl_2\rightarrow 4PCl_3[/tex]
In order to compute the maximum amount of PCl3, it is necessary to compute the grams of this product produced by each reactant, just as shown below, whereas molar masses and mole ratios are used:
[tex]m_{PCl_3}^{by\ P_4}=14.3gP_4*\frac{1molP_4}{123.89gP_4} *\frac{4molPCl_3}{1molP_4} *\frac{137.33gPCl_3}{1molPCl_3} =63.41gPCl_3\\\\m_{PCl_3}^{by\ Cl_2}=32.1gCl_2*\frac{1molCl_2}{70.91gCl_2} *\frac{4molPCl_3}{6molCl_2} *\frac{137.33gPCl_3}{1molPCl_3} =41.44gPCl_3[/tex]
Thus, since chlorine gas yields fewer grams of PCl3 than P4 we infer Cl2 is the limiting reactant and 63.41 grams of PCl3 product are yielded.
Finally, for the excess reactant, we see a difference of 63.41-41.44=21.97g, so we can compute of the leftover of P4 as follows:
[tex]m_{P_4}^{leftover}=21.97gPCl_3*\frac{1molPCl_3}{137gPCl_3} *\frac{1molP_4}{4molPCl_3} *\frac{137.33gP_4}{1molP_4} =5.5gP_4[/tex]
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Which two notations represent isotopes of the same element?
1.
N and EN
2.
N and Ne
3
N and Ne
4.
N and Ne
Submit Answer
Answer:
No.2, No.3 and No.4 answers are same. Give the options properly.
What is the difference between Claire’s test of the collision scene where Vehicle 2 fell off the cliff and the film, Iceworld Revenge, where it did not?*
Which claim is more convincing?
Claim 1: The vehicles in Iceworld Revenge had different masses; in Claire’s test, the vehicles had the same mass.
Claim 2: The friction of the surface that was used in Iceworld Revenge was different from the friction of the surface in Claire’s test.
Did the Science Seminar cause your thinking about the claims to change? Explain.
Complete Question:
Check the file attached to get the complete question
Answer:
In the film Ice word Revenge, vehicle 2 did not fall of the cliff because, but in Claire's test, vehicle 2 off the cliff because
Explanation:
In Claire's test, the weight of vehicle 1 is either equal to or greater than the weight of vehicle 2, so it was sufficient to push it down the cliff. In the film Ice word revenge, the weight of vehicle 1 is less than the weight of vehicle 2, it is not sufficient to make it fall off the cliff ( Note: Looking exactly the same in the movie, as Claire claimed, does not mean they have the same mass). Therefore if Claire wants a collision that will not make the vehicle 2 fall off the cliff, he should collide it with a vehicle of lesser mass/weight.
Farsighted people have trouble seeing objects that are close to their eyes.
True
False
If plant a, the parent plant, died from a new disease, what might happen to plant B?
Which of the following methods is least likely to help Alisha determine the age of sedimentary rock layers in her backyard?
A. Apply radiometric dating to determine the amount of radioactive isotopes in each rock layer.
B.Identify index fossils in sedimentary rock that have lived in a particular time in Earth’s history.
C. Analyze seismic diagrams to determine how radioactive elements break down into stable elements.
D. Use relative dating techniques to determine how individual fossil groups are related to specific rock layers.
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Answer:
i put c
Explanation:
Rocks' ages are determined through radiometric dating, which takes into account the ratio of two different isotopes in a sample. Geologists can use tools like these to assess the age of a material,Mass spectrometer for thermal ionization Thus, option C is correct.
What determine the age of sedimentary rock layers?How rocks are structured in strata and how they fit into the larger geological history are the main topics of stratigraphic study. This approach is best suited for studying sedimentary rocks. Cross dating is a method for using fossils to determine a rock's relative age.
Therefore, Index fossils are sought after by geologists in geological strata. Index fossils are useful because they show the relative dates of the rock layers in which they are discovered. Since radioactive isotopes deteriorate with known time intervals.
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In the benzene molecule, carbon atoms form a ring with alternating single and double bonds in between each of them. Each carbon atom forms one σ bond with one carbon atom and one σ and one π bond with another. The π bonding electrons are delocalized over the entire molecule. Thus, benzene is a resonance hybrid of two equivalent structures, and the single and double bonds oscillate from one position to the other.
Required:
Calculate the bond order for one carbon-carbon bond in the benzene molecule, taking σ and π bonding into consideration.
Answer:
1.5
Explanation:
From;
BO = ½(B – A)
BO= Bond order
B= Number of bonding electrons
A = Number of antibonding electrons
For the sigma bonds, there are 2 bonding electrons and 0 nonbonding electrons.
σ BO = ½(B – A) = ½(2 – 0) = 1
π bond order for 6 C-C bonds;
π BO = ½(B – A) = ½(6 – 0) = 3
For each π bond, BO = 3/6 = 0.5.
Hence, for a single C-C bond in benzene, the total Bond order = σ + π = 1 + 0.5 = 1.5.