PLEASE HELP ITS RLLY IMPORTANT.

Consider the model of Ammonia to the right. Which terms would be used to describe this model? Element, molecule, and/or compound? Explain your reasoning.

Answer:

The answer to the question is true.

Answer:

Explanation:

Kandndkjwnww

Answer:

C

Explanation:

is this one ok? XD

Answer:

1.239 * 10^8 Kg

Explanation:

Since all the electricity consumed comes from natural gas;

amount of electricity consumed = 700 * 300,000 = 2.1 * 10^8 kWh

So, amount of CO2 consumed is given by;

amount of electricity consumed * amount of CO2 per kWh

Hence,

Amount of CO2 = 2.1 * 10^8 kWh * 0.59 = 1.239 * 10^8 Kg

Answer:

A molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms.

Explanation:

Answer:

A molecule is the smallest part of an element, sorry if im incorrect

Answer:

A. 0.027 M

B. 0.0054 M

C. 31 cm³

Explanation:

A. Determination of the final concentration (Molarity)

Initial Volume (V₁) = 27 cm³

Initial concentration (C₁) = 0.150 M

Final volume (V₂) = 150 cm³

Final congratulation (C₂) =?

C₁V₁ = C₂V₂

0.150 × 27 = C₂ × 150

4.05 = C₂ × 150

Divide both side by 150

C₂ = 4.05 / 150

C₂ = 0.027 M

Thus, the final concentration of the solution is 0.027 M

B. Determination of the final concentration (Molarity)

Initial Volume (V₁) = 35.71 cm³

Initial concentration (C₁) = 0.0756 M

Final volume (V₂) = 500 cm³

Final congratulation (C₂) =?

C₁V₁ = C₂V₂

0.0756 × 35.71 = C₂ × 500

Divide both side by 500

C₂ = (0.0756 × 35.71) / 500

C₂ = 0.0054 M

Thus, the final concentration of the solution is 0.0054 M

C. Determination of the final volume.

Initial Volume (V₁) = 10 cm³

Initial concentration (C₁) = 0.155 M

Final congratulation (C₂) = 0.05 M

Final volume (V₂) =?

C₁V₁ = C₂V₂

0.155 × 10 = 0.05 × V₂

1.55 = 0.05 × V₂

Divide both side by 0.05

V₂ = 1.55 / 0.05

V₂ = 31 cm³

Thus, the final volume of the solution is 31 cm³

Answer:

No

Explanation:

No, but the total mass of reactants must equal the total mass of products to be a balanced equation.

Example: Consider the following reaction ...

3H₂ + N₂ => 2NH₃ and 'amu' is atomic mass units (formula weights from periodic table)

In terms of molecules, there are 4 molecules on the left (3 molecular hydrogens (H₂) and 1 molecular nitrogen (N₂) and 2 molecules of ammonia on the right side of equation arrow. ∑reactant molecules ≠ ∑product molecules.

In terms of mass of reactants & mass of products, the 3H₂ + N₂ => 6amu + 28amu = 34amu & mass of products (2NH₃) => 2(14amu) + 6(1amu) = 34amu for sum of product masses.

∑mass reactants = ∑mass products <=> 34amu = 34amu.

The expression '∑mass reactants = ∑mass products' as applied to chemical equations is generally known as 'The Law of Mass Balance'.

Answer:

its the last one

Explanation:

Answer:

2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

I've checked this multiple times this should be it

Answer:

Decarboxylation is a chemical reaction that removes a carboxyl group and releases carbon dioxide (CO2). Usually, decarboxylation refers to a reaction of carboxylic acids, removing a carbon atom from a carbon chain.

Explanation:

Please give me brainlist

Answer:

T₁ = P₁V₁T₂ / P₂V₂

Explanation:

The combine gas equation is given by:

P₁V₁ / T₁ = P₂V₂ / T₂

Where:

P₁ => is the initial pressure

V₁ => is the initial volume

T₁ => is the initial temperature

P₂ => is the final pressure

V₂ => is the final volume

T₂ => is the final temperature

Finally, we shall make T₁ the subject of the above expression. This can be obtained as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

Cross multiply

T₁P₂V₂ = P₁V₁T₂

Divide both side by P₂V₂

T₁ = P₁V₁T₂ / P₂V₂

Thus, the formula for T₁ is:

T₁ = P₁V₁T₂ / P₂V₂

Answer:

71.1%. , is a fertilizer.

The total mass of the compound guanidine is 59 g/mo. It contains 3 nitrogen atoms. Hence, the percent composition of nitrogen in this fertilizer is 71.18 %.

The mass percent or percent composition of an element in a compound is the measure of amount of that element in 100 g of the compound. Thus, it is the ratio of mass of that element in the compound to the total mass multiplied by 100.

mass percent = mass of the element in the sample/ total mass × 100

The given compound is guanidine with the formula, HNC(NH2)₂ .

atomic mass of N = 14 g/mol

mass of carbon = 12 g/mol

hydrogen = 1 g/mol.

Then total mass of guanidine = 14 + 12 + 1 + 2(2 + 14) = 59 g/mol.

there are 3 nitrogen.

mass of three nitrogen = 42 g.

Then mass percent of N in guanidine = 42 g/ 59 g × 100= 71.1%.

Therefore, the percent by mass of nitrogen in guanidine is 71.18%.

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Answer: i think its the thired one

Explanation:

Answer:

The answer is A

Explanation:

I got it right on the test

Answer:

should be D. Hope this helpsss!

Answer:

D group

................

Answer:

It can be verified since the information came from a government article. Or you could trust the magzine/general article if its from a well known article. Explanation:

you get the point, you can add on to this. I can't make it the best since im not in your class learning. Good luck

Answer:

x=2.

Explanation:

Hello there!

In this case, since we have a mole ratio of moles of Cl to moles of Cu as 2.39, it is possible to write the following:

[tex]\frac{2.39molCl}{1molCu}[/tex]

Thus, since the two possible copper chlorides are CuCl and CuCl₂, we can therefore infer that x=2 since it is close but not as close as it should to the whole number 2.

Best regards!

Answer:

Explanation:

Lithium is in group 1 so there's 1 outermost shell electron.

Oxygen is in group 6 so there's 6 outermost shell electron.

To react lithium with oxygen, we need 2 lithium and 1 oxygen

Each lithium transfer 1 electron to the oxygen and oxygen gain 2 electrons.

[tex]Li_{2}O\\[/tex] formed.

If there's 4 lithium oxide, 4 molecules will be there.

If you mean how many ATOMS are there, there will be 3×4=12 atoms.

Answer:

176 grams of sugar

explanation is down

Explanation:

250 / 22 = 2000 / x250 ml to 22 grams = 2000 ml to x grams

cross multiply

(250)(x) = (2000)(22)

250x = 44,000

x = 44,000/250

x = 176 grams of sugar 

Answer:

1.  H₂SO₄  +  Na₂CO₃  ⇒  Na₂SO₄  +  H₂O  +  CO₂

sulfuric acid + sodium carbonate ⇒ sodium sulfate + water + carbon dioxide

2.  2 HCl  +  Mg(HCO₃)₂  ⇒  MgCl₂  +  2 H₂O  +  2 CO₂

hydrochloric acid + magnesium hydrogencarbonate ⇒ magnesium chloride + water + carbon dioxide

Explanation:

1.  Sulfuric acid is H₂SO₄.  Sodium carbonate is Na₂CO₃.

H₂SO₄  +  Na₂CO₃  ⇒  Na₂SO₄  +  H₂O  +  CO₂

sulfuric acid + sodium carbonate ⇒ sodium sulfate + water + carbon dioxide

2.  Hydrochloric acid is HCl.  Magnesium hydrogencarbonate is Mg(HCO₃)₂.

2 HCl  +  Mg(HCO₃)₂  ⇒  MgCl₂  +  2 H₂O  +  2 CO₂

hydrochloric acid + magnesium hydrogencarbonate ⇒ magnesium chloride + water + carbon dioxide

Answer:

an object is a rest upon a table

Answer:

62.02 g/mol

62.03 g/mol

Explanation:

62.03 g/mol

The molar mass of H2CO3 is 62.02 g/mol

The molar mass of the compound is the sum of molar mass of indivitual atom multiple by number of that atom.

Calculation of molar mass of H2CO3 ,

Molar mass of H2CO3 =  Molar mass of H*2 +  Molar mass of C + Molar mass of O*3

Molar mass of H2CO3 = 1.0079*2 + 12.010 + 15.999*3

Molar mass of H2CO3 = 2.0158 + 12.010 + 47.997

Molar mass of H2CO3 = 62.02 g/mol

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Answer:

2.44 g S

Explanation:

One mole of Na2SO4 contains 1 mol of S.

Step 1: Find out the moles of Na2SO4:

10.8 g Na2SO4/MM Na2SO4

Step2: Find out the moles of S:

moles S = moles Na2SO4

Step 3: Find out the mass of S.

mass S = moles S x MM S

Dimensional analysis:

? g S = 10.8 g Na2SO4 x (1mol Na2SO4/MM Na2SO4) x (1mol S/1mol Na2SO4) x (MM S/ 1 mol S) = (10.8/142.04)x32.1 = 2.44 g S

Answer:

It would be exactly 5.3586262014272155. But if you were to round it up it would be 5.35.

Answer:

N2O.

Explanation:

Hello there!

In this case, according to the Avogadro's number, we can compute the number of atoms, taking into account that CO2 has three moles of atoms, N2O has three moles of atoms, He one mole of atoms and CO two moles of atoms:

[tex]atoms_{CO_2}=1molCO_2*\frac{3*6.022x10^{23}atoms}{1molCO_2}=1.81x10^{24}atoms\\\\atoms_{N_2O}=3molN_2O*\frac{3*6.022x10^{23}atoms}{1molN_2O}=5.4x10^{24}atoms\\\\atoms_{He}=2molHe*\frac{1*6.022x10^{23}atoms}{1molHe}=1.2x10^{24}atoms\\\\atoms_{CO}=4molCO*\frac{2*6.022x10^{23}atoms}{1molCO}=4.82x10^{24}atoms[/tex]

Thus, we infer that 3 moles of N2O have the greatest number of atoms.

Answer:

It is possible not all of the water was evaporated from the sand, causing the recovered mass to be higher.

Explanation:

If not all the water is evaporated from the sand so the recovered mass to be higher than the sand from which more water is evaporated because evaporation of little amount of water causes less decrease in the recovered mass as compared to that sand from which more water is evaporated so more decrease occur in the recovered mass.