Please help it’s super hard

Answer:

[tex](a)[/tex] [tex]\frac{2}{cos\theta}/\frac{1}{sin\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

[tex](b)[/tex] [tex]\frac{2sin\theta}{cos\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

(c) Addition and Quotient identity

Step-by-step explanation:

Given

[tex]\frac{2sec\theta}{csc\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex] --- The expression missing from the question

Solving (a): Write the left hand side in terms of sin and cosine

In trigonometry:

[tex]sec\theta = \frac{1}{cos\theta}[/tex]

and

[tex]csc\theta = \frac{1}{sin\theta}[/tex]

So, the expression becomes:

[tex]\frac{2 * \frac{1}{cos\theta}}{\frac{1}{sin\theta}} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

[tex]\frac{\frac{2}{cos\theta}}{\frac{1}{sin\theta}} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Rewrite as:

[tex]\frac{2}{cos\theta}/\frac{1}{sin\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Solving (b): Simplify

[tex]\frac{2}{cos\theta}/\frac{1}{sin\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Change / to *

[tex]\frac{2}{cos\theta}*\frac{sin\theta}{1} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

[tex]\frac{2sin\theta}{cos\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Solving (c): The property used

To do this, we need to further simplify

[tex]\frac{2sin\theta}{cos\theta} + \frac{4sin\theta}{cos\theta} =6tan\theta[/tex]

Take LCM

[tex]\frac{2sin\theta+ 4sin\theta}{cos\theta} =6tan\theta[/tex]

Add the numerator

[tex]\frac{6sin\theta}{cos\theta} =6tan\theta[/tex]

Apply quotient identity

[tex]\frac{sin\theta}{cos\theta} = tan\theta[/tex]

This gives

[tex]\frac{6sin\theta}{cos\theta} = 6tan\theta[/tex]

Hence, the properties applied are:

Addition and Quotient identity

Answer:

what there is nothing, what can we help you

Answer:

I am ready to help you.ask question.

Answer:

30

Step-by-step explanation:

3 x 10 = 30

add the 0 from ten to 3 and you get 30

Answer:

a. x = 13m, b. x = 12cm

Step-by-step explanation:

a. x² = 12² + 5² (Pyth. theorem)

x = 13 m

b. 15² = 9² + x² (Pyth. theorem)

x = 12 cm

Answer:

2 units

Step-by-step explanation:

The x-coordinates are

School = 2

House = 5

Count the units (lines) between the two x-coordinates

There are 2 units between them

Answer:

The answer is the first one; x = 6 y =42

Answer:

C. any number greater than 5

Step-by-step explanation:

when rounding numbers. 5 or more up the score. the number will be rounded to the next whole number

Answer:

Step-by-step explanation:

D the digit does not metter

Answer:

12 cm (I don't understand bro):(

Answer: 72

Step-by-step explanation:

Answer:

C..00000451

Step-by-step explanation:

For each person in the jury, there are only two possible outcomes. Either they were minorities, or they were not. The probability of a person being a minority is independent of any other person. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Population in which 27% were minorities.

This means that [tex]p = 0.27[/tex]

90 people

This means that [tex]n = 90[/tex]

Find the probability of getting 7 or fewer minorities in a world where the jury pool selection pro- cess was supposed to be random.

This is

[tex]P(X \leq 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{90,0}.(0.27)^{0}.(0.73)^{90} \approx 0[/tex]

[tex]P(X = 1) = C_{90,1}.(0.27)^{1}.(0.73)^{89} \approx 0[/tex]

[tex]P(X = 2) = C_{90,2}.(0.27)^{2}.(0.73)^{88} \approx 0[/tex]

[tex]P(X = 3) = C_{90,3}.(0.27)^{3}.(0.73)^{87} = \approx 0[/tex]

[tex]P(X = 4) = C_{90,4}.(0.27)^{4}.(0.73)^{86} = 0.00000002[/tex]

[tex]P(X = 5) = C_{90,5}.(0.27)^{5}.(0.73)^{85} = 0.00000015[/tex]

[tex]P(X = 6) = C_{90,6}.(0.27)^{6}.(0.73)^{84} = 0.00000080[/tex]

[tex]P(X = 7) = C_{90,7}.(0.27)^{7}.(0.73)^{83} = 0.00000354[/tex]

So

[tex]P(X \leq 7) = 0.00000002 + 0.00000015 + 0.00000080 + 0.00000354 = 0.00000451[/tex]

So the correct answer is given by option C.

Answer:

slope of AB = -1/2

slope of CD = -2

No.

Step-by-step explanation:

slope of AB = (5-7)/(6-2) = -2/4=-1/2

slope of CD = (-6-2)/(4-0) = -8/4 =-2

for being two opposite sides of parallelogram, their slopes should be equal. But there slopes aren't equal

Answer:

We can correctly rewrite the equation: 4(5+3) = 2(22-6) by distributing each side.

4(5+3) = 2(22-6)

4(8) = 2(16)

32 = 32

Once you finish distributing each side, you can check to see if it is equal on both sides.

Step-by-step explanation:

Step-by-step explanation:

4(5 + 3) = 2(22 - 6)

4(8) = 2(16)

32 = 32

Answer:

oh

Step-by-step explanation:

Answer:

g(-3) = -4

Step-by-step explanation:

We are given the following function:

[tex]g(x) = -x^2 + 5x + 2[/tex]

Find and simplify g(-3)

We want to find the value of g when [tex]x = -3[/tex]. So

[tex]g(-3) = (-3)^2 + 5(-3) + 2 = 9 - 15 + 2 = -4[/tex]

g(-3) = -4

Answer:

[tex]2 \frac{4}{6} [/tex]

I think this is it?? very sorry if it's incorrect

Answer:

4/3 or 1 1/3

Step-by-step explanation:

2 * 4/6

= 8/6 (You multiply 2 by the numerator, 4)

= 4/3 (Cancel out the common factor in the numerator and denominator, 2)

Mixed number form: 1 1/3

Answer:

To find out how any inches are in a certain amount of feet you have to multiply it by 12. For example 4 feet is equal to 48 inches. (4x12)

Step-by-step explanation:

Answer:

t=1/2

Step-by-step explanation:

Answer:

∠C = 75°

Step-by-step explanation:

using the formula for the sum of interior mangles for a polygon:

total interior angles = (180° x 5 angles) - 360° = 540°

113° + 4x + 113° + 2x + 9° + 3x + 8° = 540°

combine like terms:

9x + 243° = 540°

9x = 297°

x = 33°

∠C = 2(33) + 9 = 75°

Answer:

horizontal asymptote at y = 0

Step-by-step explanation:

According to the definition of asymptotes, it is a line that the function gets closer and closer to as x goes to plus or minus infinity. The definition clearly does not mention anything about the finite value of x.

However, crossing of asymptotes does not happen in the case of vertical asymptotes because for a given x, the function has only one value but the same y can be obtained for different values of x.

It is a common misconception that graphs of functions can’t cross the asymptotes. This is true only for vertical asymptotes. In fact, there are several examples of functions whose graphs cross the horizontal asymptote. For example:

f(x) = (xe)^((-x)^2)

The horizontal asymptote of the above function is y=0 but it still crosses the x axis at x=0.

hope that helps, I really don't know thought. Quite tricky

Answer:

x ≤ 9 (Up to nine people)

Step-by-step explanation:

12 + x ≤ 21

x ≤ 9 (Subtracted both sides by 12)

Hope this helps! <3

Answer:

[tex]\boxed {\boxed {\sf A \approx 3.3 \ in^2}}[/tex]

Step-by-step explanation:

Since we are given the central angle in degrees, we should use the following formula for sector area.

[tex]A= \frac {\theta}{360}* \pi r^2[/tex]

The angle is 42 degrees and the radius is 3 inches. Therefore,

[tex]\theta= 42 \\r=3 \ in[/tex]

[tex]A=\frac {42}{360} * \pi (3 \ in)^2[/tex]

Solve the exponent.

[tex]A=\frac {42}{360} * \pi (9 \ in^2)[/tex]

Multiply all three numbers together.

[tex]A= 0.116666666667* 3.14159265359 * 9 \ in^2[/tex]

[tex]A=3.29867228627 \ in^2[/tex]

Let's round to the tenth place. The 9 in the hundredth place tells us to round the 2 up to a 3.

[tex]A \approx 3.3 \ in^2[/tex]

The area of the sector is approximately 3.3 square inches.

Answer:

5 x 8 = 40

5 x -70 = -350

40 - 350

29 x 4 = 116t

therefore it would be 40 - 350 + 116t

I think

Answer:

the total surface area of the prism is 245.67

Step-by-step explanation:

Given;

height of the triangular prism, h = 8

length of the triangular bases, = 7, 8, and 9

The total surface area of the prism is calculated as;

T.S.A = ph + 2B

Where;

p is the perimeter of the base

B is area of the base

P = 7 + 8 + 9 = 24

Area of the base can be calculated using Hero's formula;

[tex]S = \frac{7+8+9}{2} = 12\\\\Base \ area (B) = \sqrt{12(12-7)(12-8)(12-9)} = 26.833[/tex]

T.S.A = (24 x 8)   +  2 x 26.833

T.S.A = 192 +  53.666

T.S.A = 245.67

Therefore, the total surface area of the prism is 245.67

Answer:

C. 20 Ft.

Step-by-step explanation:

Using The Pythagorean Theorem, a²+b²=c² , insert the known variables into the equation.

18.7²+6²=c²

This gives you 385.69 + 36 = 385.69.

Next, square the result to find the missing side length.

[tex]\sqrt{385.69[/tex]

The answer comes out to around 19.6, which can be rounded up to 20ft.

Hope this helped!

Answer:

1 or 0.5

Step-by-step explanation:

Answer:

a) The null hypothesis, H₀; p = 0.1

The alternative hypothesis, Hₐ; p ≠ 0.1

b) The proportion of left handed undergrads in UW differs from the national proportion of 0.1

c) The p-value is larger than the level of significance therefore there is statistical evidence supporting the alternative hypothesis

Step-by-step explanation:

The given data are;

The number of students in the sample, n = 140

The number of left handed students in the sample = 12

The number of right handed students in the sample = 128

The proportion of left handed students in the sample, [tex]\hat p[/tex] = 12/140 = 0.08571429

The significance level = 5%

The national proportion, p₀ = 0.1

a) The null hypothesis, H₀; p = 0.1

The null hypothesis is the proportion of left handed students in the UW is the same as the national proportion of 0.1

The alternative hypothesis, Hₐ; p ≠ 0.1

The alternative hypothesis is the proportion of left handed students in the UW is not the same as the national proportion of 0.1

b) Given from the output values of the Confidence Interval at 95% confidence level, (0.04971124, 0.14384532) which are both positive values, and the p-value of 0.5731, we conclude that there is a difference between the proportion of left-handed UW undergraduate students and the national proportion of 0.1

c) Given that the p-value of 0.5731 is larger than the significance level of 0.05, we reject the null hypothesis and there is significant statistical evidence to suggest that the proportion of UW undergrads who are left handed differs from the national proportion of 0.10