Answer:
10 hours
Step-by-step explanation:
multiply b 2 then divided the miles and time and add to the total to get the time and miles you need
A rock is dropped from a height of 100 feet. Calculate the time between when the rock was dropped and when it landed. If we choose "down" as positive and ignore air friction, the
function is h(t) = 16t^2 – 100.
A)t = 2.5 seconds
B)t = 6.25 seconds
C)t = 10 seconds
D)t = 12.5
Answer:
A
Step-by-step explanation:
the rock lands when it reaches height 0.
so, for what t is h(t) = 0 ?
16t² - 100 = 0
16t² = 100
now we pull the square root on both sides (we can ignore the negative solutions, as negative seconds don't make any sense in our scenario)
4t = 10
t = 10/4 = 5/2 = 2.5 seconds
so, A is correct.
Please Help! will Give Brainlest!
Answer:
tan ¤ = opp/adj
tan ¤ = 20/50
since opposite of the angle is 20, height of the tree is 20 feet.
Ans : D
Answer:
height : 20distance : 50Explanation:
[tex]\sf tan(x)= \dfrac{opposite}{adjacent}[/tex]
[tex]\hookrightarrow \sf tan(x)= \dfrac{20}{50}[/tex]
using the equation, we can identify that ↓opposite ( the height of the tree ) is 20adjacent ( the distance ) is 50Can I have help on this?
Answer:
25°
Step-by-step explanation:
51+x+14=90°
x+65=90°
x=90-65
x=25°
Answer: 25°
Step-by-step explanation:
51+x+14=90°
x+65=90°
x=90-65
x=25°
Fill in the table using this function rule.
-
y=6x-1
х
у
1
4
5
10
0
Answer:
Below
Step-by-step explanation:
According to a website, ebra
Solve for
N
by cross multiplying.
N
=
5
Tap to view steps...
Solve for s
Isolate the variable by dividing each side by factors that don't contain the variable.
s
=
8
r
−
5
t
Tap to view steps...
Solve for x
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
x
>
−
6
Interval Notation:
(
−
6
,
∞
)
Tap to view steps...
Solve by Substitution
Move all terms that don't contain
x
to the right side and solve.
x
=
9
2
−
y
2
Tap to view steps...
3/31/2022 4:07 PM
How can I help you?
Tap to view tutorial...
Find the Function
Find the function by taking the integral of the derivative.
G
(
x
)
=
5
2
x
2
−
x
+
C
Tap to view steps...
How was this solution?
Tap to rate...
Find the Function
I am unable to solve this problem.
Tap for examples...
Tired of typing? Download the app to take a picture of your problems!
Find the Function Rule
The chosen topic is not meant for use with this type of problem. Try the examples below.
x
q
(
x
)
1
1
2
2
3
3
4
4
x
q
(
x
)
1
3
2
6
3
11
4
18
x
q
(
x
)
1
2
9
162
2
8
8
128
3
18
If the point (x,square root 3/2) is on the unit circle, what. is x?
Answer:
[tex]x=\pm\frac{1}{2}[/tex]
Step-by-step explanation:
On a unit circle, [tex](x,y)=(\cos\theta,\sin\theta)[/tex], so [tex]\sin\theta=\frac{\sqrt{3}}{2}[/tex] in this case. If you look at the attached circle, the only time that the y-coordinate is [tex]\frac{\sqrt{3}}{2}[/tex] is when [tex]x=-\frac{1}{2}[/tex] and [tex]x=\frac{1}{2}[/tex], which correspond to angles of [tex]\theta=\frac{2\pi}{3}[/tex] and [tex]\theta=\frac{\pi}{3}[/tex] respectively
The points 4,0 and 7,6 lie on a particular line, what is its equation in slope - intercept form?
[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{4}}}\implies \cfrac{6}{3}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{2}(x-\stackrel{x_1}{4})\implies y = 2x-8[/tex]
a locker requires a three-digit code to open the lock. the code must contain one letter and two numbers, and no letter or number can be repeated. you can choose from among four letters, a,b,c and d and two numbers, 5 and 6
Answer:
4 ways
Step-by-step explanation:
Given
Code consists of 3 digits1 letter and 2 numbersNo number/letter should be repeatedPossible combinations
a56b56c56d56⇒ 4 waysThe number of goldfish in a tank is 12, and the volume of the tank is 45 cubic feet. What is the density of the tank?
Answer: 0.27
Population density of the species in water:
Population density of a species in the water is given by the expression,
Density =Given in the question,
Number of goldfish in the tank = 12
Volume of the tank = 45 cubic feet
Substitute these values in the expression,
Density =
= 0.267
≈ 0.27 goldfish per cubic feet
Therefore, density of the tank will be 0.27 goldfish per cubic feet.
Which graph represents the function f(x) = - |x - 2| - 1?
Answer:
nsgs6
68÷9
02_3
73929
Step-by-step explanation:
8282×627=628373
Answer:
i hope this helps you!
Step-by-step explanation:
Will give Brainly Fivue starts and a tThanks
Answer:
y = x + 9
Step-by-step explanation:
Since each x input can be added by 9 to get the y outputs, the equation is y=x+9
Hope this helps :)
The numbers in the triangles below go together following the
4
9
8
7
3
2
6
Find the missing number.
A 1
B 3
Answer:
1
by looking only 1 is missing
The half-life of sr-85, which may be used in bone scans, is 64. 8 days. How many milligrams of a 7 mg sample will be left after 127 days? round to the hundredths place
[tex]\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &7\\ t=\textit{elapsed time}\dotfill &127\\ h=\textit{half-life}\dotfill &64.8 \end{cases} \\\\\\ A=7\left( \frac{1}{2} \right)^{\frac{127}{64.8}}\implies A=7\left( \frac{1}{2} \right)^{\frac{635}{324}}\implies A\approx 1.80[/tex]
The half-life of sr-85, which may be used in bone scans, is 64.8 days. 1.80 milligrams of a 7 mg sample will be left after 127 days.
What is half-life?Half-life is defined as the time required for a quantity to reduce to half of its initial value.
The half-life of sr-85, which may be used in bone scans, is 64. 8 days.
We need to find how many milligrams of a 7 mg sample will be left after 127 days.
[tex]\rm A = P\frac{1}{2} ^{t/h}[/tex]
here A = current amount
P = inital amount
t = time
h = half life
So,
[tex]\rm A = 7\frac{1}{2} ^{127/64.8}[/tex]
[tex]\rm A = 7\frac{1}{2} ^{635/324}\\A = 1.80[/tex]
Learn more about half-life;
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On Monday, Payton rode 7 miles on a bike. On Tuesday, she rode 23
miles. On Wednesday, she rode 3 times as much as she did Monday
and Tuesday combined. What equation could you use to find how
many miles Payton rode on Wednesday, r?
Answer:
483
Step-by-step explanation:
I really really pray and hope this helpss.
Answer:
X=3(7+23)
Step-by-step explanation:
Please help!
Find the value of x. Round to the nearest tenth for numbers #19.
Find the value of x. Round to the nearest degree # 23 & #27.
-Answer the last question :)
LAST QUESTION: The lengths of the diagonals of a rhombus are 2in. and 5in. Find the measures of the angles of the rhombus to the nearest degree.
The values of x in the triangles and the angles in the rhombus are illustrations of tangent ratios
The values of x in the triangles are 21.4 units, 58 degrees and 66 degreesThe angles in the rhombus are 44 and 46 degrees, respectivelyHow to determine the values of x?Triangle 1
The value of x is calculated using the following tangent ratio
tan(25) = 10/x
Make x the subject
x = 10/tan(25)
Evaluate
x = 21.4
Triangle 2
The value of x is calculated using the following tangent ratio
tan(x) = 8/5
Evaluate the quotient
tan(x) = 1.6
Take the arc tan of both sides
x = arctan(1.6)
Evaluate
x = 58
Triangle 3
The value of x is calculated using the following tangent ratio
tan(x) = 0.34/0.15
Evaluate the quotient
tan(x) = 2.27
Take the arc tan of both sides
x = arctan(2.27)
Evaluate
x = 66
How to calculate the angles of the rhombus?The lengths of the diagonals are:
L1 = 2 in
L2 = 5 in
Represent the angles with x and y.
The measures of the angles are calculated using the following tangent ratios
tan(0.5x) = 2/5 and y = 90 - x
Evaluate the quotient
tan(0.5x) = 0.4
Take the arc tan of both sides
0.5x = arctan(0.4)
Evaluate
0.5x = 22
Divide by 0.5
x = 44
Recall that:
y = 90 - x
This gives
y = 90 - 44
Evaluate
y = 46
Hence, the angles in the rhombus are 44 and 46 degrees, respectively
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If VZ=p–7 and WY=p–21, what is the value of p?
Using the midline property;
[tex]2wy = vz[/tex]
[tex]2(p - 21) = p - 7[/tex]
[tex]2p - 42 = p - 7[/tex]
[tex]2p - p = - 7 + 42[/tex]
[tex]p = 35[/tex]
pls help me thank you
Write the equation for the cosine function for the ferris wheel ride, with where h, is the height in meters, and t, is the time in minutes.
The cosine function for the ferris wheel ride is an illustration of a sinusoidial function
The equation of the Ferris wheel is y = -190cos(π / 120 t) + 195
How to determine the cosine function?A cosine function is represented as:
y = Acos(Bt - C) + D
From the complete question, the diameter of the ferris wheel is 380 feet.
The amplitude represents the radius, and this is calculated as:
A = 380/2
A = 190
The function becomes:
y = 190cos(Bt - C) + D
The period of the function is:
T = 2π / B
From the complete question, one full rotation is completed in 4 minutes.
Convert the time to seconds
T = 4 * 60
T = 240.
So, we have:
240 = 2π / B
Divide both sides by 2
120 = π / B
Make B the subject
B = π / 120
The function becomes
y = 190cos(π / 120 t - C) + D
From the question, the ferris wheel is 195 feet above the ground.
This represents the vertical shift.
So, we have:
D = 195
The function becomes
y = 190cos(π / 120 t - C) + 195
Also, we have:
The lowest point is at t = 0 and the function is a negative cosine function
So, we have:
C = 0
The function becomes
y = -190cos(π / 120 t) + 195
Hence, the cosine function is y = -190cos(π / 120 t) + 195
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can someone explain how to do "interquartile range"
What is it?
The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
How do you find IQR?
Step 1: Put the numbers in order. ...
Step 2: Find the median. ...
Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...
Step 4: Find Q1 and Q3. ...
Step 5: Subtract Q1 from Q3 to find the interquartile range.
Answer:
The answer to this quesion is a measure of statistical dispersion, the spread of data or observations, first you need to get the data find the median calculate the median from both lower and upper half of the data and the iqr is the diffrence between the lower and upper.
Step-by-step explanation:
I Hope This Helps You!
-Justin:)
Suppose that 18 inches of wire costs 72 cents.
At the same rate, how many inches of wire can be bought for 44 cents
A university class has had 8 graduate students enroll so far, as well as 8 other students. Considering this data, how many of the next 12 students to enroll should you expect to be graduate students?
Which of the following statements is equivalent to P (z greater-than-or-equal-to 1. 7)? P (z greater-than-or-equal-to negative 1. 7) 1 minus P (z greater-than-or-equal-to negative 1. 7) P (z less-than-or-equal-to 1. 7) 1 minus P (z less-than-or-equal-to 1. 7).
This [tex]\rm P(Z\geq 1.7)[/tex] is equivalent to [tex]\rm 1-P(Z\leq 1.7)[/tex]
It is given that the [tex]\rm P(Z\geq 1.7)[/tex]
It is required to find which statement is equivalent to [tex]\rm P(Z\geq 1.7)[/tex]
The statements are:
[tex]a) \ \rm P(Z\geq -1.7)\\b) \ \rm 1-P(Z\geq -1.7)\\c) \ \rm P(Z\leq 1.7)\\d) \ \rm 1-P(Z\leq 1.7)[/tex]
What is a normal distribution?It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.
We have the [tex]\rm P(Z\geq 1.7)[/tex]
We know that:
[tex]\rm P(Z\leq a)=P(Z\geq -a)\\\rm P(Z\geq a)=P(Z\leq -a)[/tex]
If we compare statement (a) and statement (c), we will see these options are not equivalent to [tex]\rm P(Z\geq 1.7)[/tex]
For statement (b) if we plot the graph for the given statement we will get the negative area of the bell curve hence it is also incorrect.
For statement (d) if we plot the graph for the given statement we will get the positive area which is equivalent to the [tex]\rm P(Z\geq 1.7)[/tex]
Thus, the [tex]\rm P(Z\geq 1.7)[/tex] is equivalent to [tex]\rm 1-P(Z\leq 1.7)[/tex]
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i need help with problem 1
solve pls brainliest
Answer:
2/5 > 1/4
Step-by-step explanation:
First convert the denominators to the LCM which will be 20
2/5 will convert to 8/20 because 5 x 4 = 20 so 2 x 4 = 8 and 1/4 will convert to 5/20 because 4 x 5 = 20 so 1 x 5 = 5
What is the volume of the square pyramid?
Answer:
v = 118.333333333
Step-by-step explanation:
formula: V=a^2h/3
The area is the base edge (so 5)
The height is the line going up the triangle (14.2)
Fill in:
v = 5^2(14.2/3)
Solve:
exponent first: 5^2 = 25
v = 25 (14.2/3)
divide/find out fraction: 14.2/3 = 4.73333333333
v = 23 x 4.73333333333
multiply: 23 x 4.73333333333 = 118.333333333
v = 118.333333333
you can also write as v = 118.3 with a line like “-“ over 3 to show the 3 is repeating:)
A robot vacuum cleans a dirty floor using multiple passes. During each pass, 24% of the dirt is removed. If the floor initially has 550 ml of dirt, write a function to find out how much dirt will remail after 10 passes?
please include function and value.
The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml
How to solve an exponential function?
Let y represent the amount of dirt on the floor after x passes.
The floor initially has 550 ml of dirt, hence a = 550.
During each pass, 24% of the dirt is removed. Hence b = 100% - 24% = 76% = 0.76
The equation is given by:
y = 550(0.76)ˣ
After 10 passes:
y = 550(0.76)¹⁰ = 35.36 ml
The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml
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find the value of (0.81÷0.09)+(0.81÷9)
Answer:
9.09
Step-by-step explanation:
[tex]\frac{0.81}{0.09} + \frac{0.81}{9}[/tex]
= 9 + [tex]\frac{0.81}{9}[/tex]
= 9+ 0.09
= 9.09
I hope this helped!! If so please rate and mark brainliest <3!!
PLS HELP ME I WILL MARK THE BRAINLIEST
#1
First the rectangle
L=18mB=7mArea
18(7)126m^2.For semicircle
d=7m=>r=3.5mArea
=πr^2/2=12.25π/2Total area
126+2(12.25π/2)126+12.25πm^2#2
r=15fttheta=332°=332×π/180=0.92πArea:-
r^2\theta15^2(0.92)207ft^2what is 60 divided by 4?
Answer:
The answer is 15
Step-by-step explanation:
3 kitchen assistants can prepare 10 kg of vegetables in 60 minutes. How long would it take 25 assistants to prepare the same amount?
Answer:
App. 83.33 kg
Step-by-step explanation:
10/60=0.167 kg/minute
0.167/3=0.056 kg/minute/person
0.056 x 25 x 60= 83.33...6
13. What is the equation in standard form of the circle
represented by
x2 + y2 - 10x - 6y = 23?
A (x+5)2+(y + 3)2 = 23
B. (x + 5)2+(y + 3)2 = 57
C. (x-5)+(y - 3)2 = 23
D. (x - 5)2+(y - 3)2 = 57
The standard form of a circle shows the center and the radius
The equation of the circle in standard form is (x + 5)^2 + (y - 4)^2 = 57
How to determine the equation?The standard equation of a circle is:
(x - a)^2 + (y - b)^2 = r^2
Where:
Center= (a,b)
Radius = r
Assume that:
(a,b) = (-5,3)
r = [tex]\sqrt{[/tex]57
The equation of the circle would be:
(x + 5)^2 + (y - 4)^2 = ([tex]\sqrt{57[/tex])^2
Evaluate the exponent
(x + 5)^2 + (y - 4)^2 = 57
Hence, the equation of the circle in standard form is (x + 5)^2 + (y - 4)^2 = 57
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