Please someone help me plz I don’t understand 1 or 2 plz help me plz plz plz

Answer:

Given,

A 5 kg mass is at the origin. A 7 kg mass is located at x = 0.6 m and a 4 kg mass is at x = 0.9 m.

To find,

the net gravitational force on the 5 kg mass.

we know, from Newton's gravitational law, two massive bodies attract each other by a force , F = Gm₁m₂/r²

so, 7 kg mass attracts 5kg mass by the force, F₁ = G(7kg)(5kg)/(0.6)²

= 35G/0.36 = 97.22G

similarly, 4kg mass attracts 5kg mass by the force, F₂ = G(4kg)(5kg)/(0.9)²

= 20G/0.81 = 24.69G

net gravitational force = F₁ + F₂

= 97.22G + 24.69G

= 121.91G

we know, G = 6.67 × 10¯¹¹ Nm²/Kg²

F = 121.91 × 6.67 × 10¯¹¹

= 813.1397 × 10¯¹¹ N

= 8.131397 × 10^-9 N ≈ 8.13 × 10^-9 N

Therefore net gravitational force acting on mass 5kg is 8.13 × 10^-9 N

Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.

[tex]\rm F= K\frac{q_2q_3}{r^2}[/tex]

[tex]\rm F= 9\times 10^9 \times \frac{1.6 \times 10^{-13}\times 1.6\times10^{-13}}{(0.5)^2}[/tex]

[tex]\rm F= - 1. 1 \times 10^{11 }N[/tex]

Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.

To learn more about the electric force refer to the link;

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Answer:

Your answer is MASS.

Explanation:

Volume measures how much space an item takes up.

Temperature measures how hot or cold something is.

Density is the degree of compactness of a substance.

Mass measures the amount of matter in an object.

Answer:

The moon and sun cause tidal bulges to move around the planet in perfect sync and unison.

Explanation:

However, do not consider these to be large oceans of water moving in relation to continents. Only the fluctuations in water level—the water's surface profile—follow the moon's and sun's positions in the sky.

Answer:

cohesion and adhesion property of water

Explanation:

Water - the universal solvent with many unique properties. According to the given question, one of the unique properties of water that can be the best answer to the question is the property of cohesion and adhesion of water.

Therefore, the long distance water movement, from roots up to leaves, of the water transport in large plants depends on one unique property of water. Water's unique property of  cohesion and adhesion  allows water molecules to stick together so they can be pulled upward by the force of transpiration.

Answer:

181276.802 m

Explanation:

The computation of the horizontal range of the shell is shown below:

As we know that

range = u × usin2θ ÷ g

where,

u = 1600 m/s

θ = 68

g=9.81

Put these values to the above formula

So, the value of the horizontal range of the shell is

R = 181276.802 m

=  181276.802 m

We simply applied the above formula and the same is to be considered

Answer:

Microwaves (D

Explanation:

I'm not sure! But I think it's Microwaves!

Answer:

Explanation:

The total surface area of the room is expressed as;

TSA = 2(LW+LH+WH)

L is the length

W is the width.

H is the height

Given

L = 4m

W = 3m

H = 2.5m

.TSA = 2{4(3)+3(2.5)+4(2.5)}

TSA = 2(12+7.5+10)

TSA = 2(29.5

TSA = 59m²

TSA (without the floor) = 2(3(2.5)+4(2.5))

TSA = 2(7.5+10)

TSA = 2(17.5)

TSA = 35m²

If a certain part covers 25 square meters per gallon, the amount of gallon needed will be 35m²/25m²

= 1.4gallons

P = F/A

P = 50/5

P = 10 Pa

Hope it helps :)

change in momentum = 37,500kg.m/s in the opposite direction

time it takes = 12.5s

u=25m/s

v=0m/s

F=ma

-3000=(1500)(a)

-3000÷1500=a

a= -2m/s^2

Change in momentum=mv-mu

(1500)(0)-(1500)(25)

= -37,500kg.m/s

relax the( - ) represents direction

v=u-at

0=25-2t

2t=25

t= 12.5s

Answer: a) 36 m/s

B) 64 m

Explanation:

A) d= ½ (Vi+Vf)t

d= ½ (0+12)6

d= 36 m/s

B) 100 – 36 = 64

Answer:

I'm From Philippines

I hope we can be friends.

Answer:

t = 0.3 seconds

Explanation:

Given that,

Initial velocity of a ball, u = 3 m/s

Final velocity of the ball, v = 6 m/s

We need to find the time for which the ball is in the air. As the ball was directed upwards, it would mean that the acceleration of the ball is -g or -9.8 m/s².

Using the first equation of motion to find the time. So,

v=u+at

or

v=u-gt

[tex]t=\dfrac{v-u}{-g}\\\\t=\dfrac{6-3}{-9.8}\\\\t=-0.3\ s[/tex]

or

t = 0.3 seconds

So, the ball is in the air for 0.3 seconds.

Answer: t= 0.92 s

Explanation: the formula you use it’s v=vinitial + at and you rearrange it to make (t= vfinal - vinitial /a) using this you get 0.92s

Answer:

[tex]\rainbow{\rule{10000pt}{900000pt}}[/tex]

Answer:

The time of the second observer at the end of the car motion is 27 s

Explanation:

Initial time of the first observer, t₁ = 262 s

final time of the first observer, t₂ = 375 s

The time of the car motion, t = t₂ - t₁

t = 375 s - 262 s

t = 113 s

Initial time of the second observer, t₁ = -86 s

final time of the second observer, t₂ = ?

The time of the car motion, t = t₂ - t₁

113 = t₂ - t₁

113 = t₂ - (-86)

113 = t₂ + 86

t₂ = 113 - 86

t₂ = 27 s

Therefore, the time of the second observer at the end of the car motion is 27 s

Answer: The answer is C. 58,000

Explanation:

We can confirm that the primary reason that killer whales cause deforestation of the seabed is due to a domino effect caused by one of their food sources.

Killer whales are carnivorous organisms. Among their prey are sea otters. This new source of food for killer whales began to cause a domino effect in that the decline in sea otter population caused the primary meal of the otters, that being sea urchins, to increase greatly in population. Given that the sea urchins feed on kelp, this contributes to the deforestation of the sea bed and the lack of kelp.

Therefore, we can confirm that killer whales cause deforestation of the seabed in an indirect manner by contributing to the increase in sea urchin populations that leads to deforestation of the seabed.

To learn more about ecosystems visit:

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Answer:

??? this makes no sense give more info

Explanation:

Answer:

The answer should be 0.825

Explanation:

I took like 20 mins to figure this out lol

Answer:

Density is the degree of compactness in an object.

Explanation:

S.I unit is kg/m3

Answer:

The mass of the paraffin is 70g

Explanation:

You have to subtract the mass of the empty beaker from that of the empty beaker and paraffin oil to get the mass of the paraffin oil

Explanation:

Well, it depends...

Explanation:

Weight is given by the formula,

W

=

m

g

W

is the weight of the object in newtons

m

is the mass of the object in kilograms

g

is the gravitational acceleration

On Earth,

g

=

9.8

m/s

2

. So, the object's weight on Earth will be:

W

=

50

kg

⋅

9.8

m/s

2

=

490

N

Can you tell what the object's weight will be on another planet, such as Mars?

Answer: 34 kilograms (approximate)

==================================

Work Shown:

F = m*g

330 newtons = (m kg)*(9.8 m/s^2)

330 = m*9.8

330/9.8 = m

m = 33.673469387755

m = 34 kilograms

I'm rounding to 2 significant figures because 330 has 2 sig figs and 9.8 has 2 sig figs. When dividing we pick the smaller of the sig fig count to determine how many sig figs to round to.

Answer:

3.6×10⁶ m

Explanation:

g = GM / R²

4 m/s² = (6.67×10⁻¹¹ m³/kg/s²) (6×10²⁴ kg) / (6.4×10⁶ m + h)²

(6.4×10⁶ m + h)² = 1.00×10¹⁴ m²

6.4×10⁶ m + h = 1.00×10⁷ m

h = 3.6×10⁶ m

Answer:

The answer is below

Explanation:

The question is not complete since the distance is not given. But let us assume the object moves a distance of 100 m.

From newton's law for a moving body, we get the equation:

v² = u² + 2as

Where v is the final velocity of the object, u is the initial velocity of the object, s is the distance moved by the object and a is the acceleration of the object.

Given that the object is initially at rest, hence u = 0, final speed (v) = 49 m/s, distance (s) = ?

v² = u² + 2as

Substituting:

49² = 0² + 2as

2401 = 2as

a = 2401 / 2s

Substituting s = 100 m

a = 2401 / (2*100)

a = 12 m/s²

Answer: A

Explanation: a p e x

Answer:

the guy above is right, it is A

Explanation:

A p E x

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value  is [tex]v  = 3.57 \  m/s [/tex]

Explanation:

From the question we are told that

  The depth  is  [tex]d =  979 \  m[/tex]

   The time taken for water to fall to below the river is  [tex]t =  14 \ s[/tex]

   The  horizontal distance from the base of the vertical cliff is  [tex]h  =  50 \  m[/tex]

     Generally  the horizontal speed at the top is mathematically represented as

         [tex]v  =  \frac{h}{t}[/tex]

=>      [tex]v  =  \frac{  50}{ 14 }[/tex]

=>     [tex]v  = 3.57 \  m/s [/tex]

Option C is correct. Frequency can be found by counting the number of troughs per second in a wave diagram.

Frequency is defined as the number of repetitions of waves occurring in 1 second. It can also be said that Frequency is defined as the number of cycles completed in 1 second.

Frequency is given by the formula as,

[tex]\rm f=\frac{1}{t}[/tex] Hz.

Hence option C is correct. Frequency can be found by counting the number of troughs per second in a wave diagram.

To learn more about the frequency refer  to the link;

https://brainly.com/question/4393505

Answer:

C is correct

Explanation:

I believe that the correct answer is reactivity.

Answer:

Explanation:

whatever expenses a business might have like

repairs

buying equipment

employees

Answer:

Explanation:

distance = 300 km

velocity = 80 km/hr.

find: time

time = distance

           velocity

       = 300 km

            80 km/hr.

       = 3.75 hr.

Answer:

(a). The value of distance is 5.043 m

(b). The coefficient of friction is 0.302.

(c). The distance is 10.33 m

Explanation:

Given that,

Speed = 4.50 m/s

Minimum friction = 0.1

Maximum friction = 0.6

Distance = 12.5 m

We know that,

The newton's second law

[tex]F_{net}=-\mu N[/tex]

[tex]F_{net}=-\mu mg[/tex]

We know that,

The frictional coefficient is directly proportional to the distance.

We need to calculate the value of coefficient

Using general equation of frictional coefficient

[tex]\mu(x)=Ax+B[/tex]....(I)

At x= 0,

[tex]\mu(0)=0+B[/tex]

Put the value into the formula

[tex]B=0.1[/tex]  

Now for value of A

Put the value in equation (I)

[tex] 0.6=A12.5+0.1[/tex]

[tex]A=\dfrac{1}{25}[/tex]

Put the value in equation (I)

[tex]\mu(x)=\dfrac{x}{25}+0.1[/tex]......(II)

We need to calculate the work done

Using work energy theorem

[tex]W=\int_{0}^{x}{F_{net} dx}[/tex]

[tex]W=\int_{0}^{x}{-\mu_{x}mgdx}[/tex]

[tex]W=-mg\int_{0}^{x}{(\dfrac{x}{25}+0.1)dx}[/tex]

[tex]W=-mg(\dfrac{x^2}{50}+0.1x)[/tex]....(III)

(a). We need to calculate the distance

Using difference of kinetic energy

[tex]W=\dfrac{1}{2}m(v_{f}^2-v_{0}^2)[/tex]

[tex]-mg(\dfrac{x^2}{50}+0.1x)=\dfrac{1}{2}m(0-(4.50)^2)[/tex]

[tex]\dfrac{x^2}{50}+0.1x=1.013[/tex]

[tex]x^2+5x=50.65[/tex]

[tex]x^2+5x-50.65=0[/tex]

[tex]x=5.043\ m[/tex]

(b). We need to calculate the coefficient of friction at the stopping point

Using equation (III)

[tex]\mu(5.043)=\dfrac{5.043}{25}+0.1[/tex]

[tex]\mu(5.043)=0.302[/tex]

(c). We need to calculate the distance

Using formula work done

[tex]W=-fx_{2}[/tex]

[tex]W=-\mu mgx_{2}[/tex]

[tex]-\dfrac{1}{2}mv_{0}^2=-\mu mgx_{2}[/tex]

[tex]x_{2}=\dfrac{v_{0}^2}{2\mu g}[/tex]

Put the value into the formula

[tex]x_{2}=\dfrac{(4.5)^2}{2\times0.1\times9.8}[/tex]

[tex]x_{2}=10.33\ m[/tex]

Hence, (a). The value of distance is 5.043 m

(b). The coefficient of friction is 0.302.

(c). The distance is 10.33 m