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Twenty-seven minus 3/2 of a number (x) is not more than 36. What is the number? A. x > 42 B. x ≥ -6 C. x < 3 D. x ≤ -6

Answer:

m<2 + m<3 = 180°

Step-by-step explanation:

Lines intersected by a transversal are parallel if same-side interior angles are supplementary.

Answer: m<2 + m<3 = 180°

Answer:

this is not my level of math sorry i cant help you :(

Step-by-step explanation:

sorry

Answer: The first option.

Explanation: 376/93 = 4 4/94, while 376/93.01 = 4.04257606709....., which is less than 4 4/94, therefore the first option has the greatest quotient.

Answer:

47.43

Step-by-step explanation:

To find 51% of the number 93, multiply the latter by 0.51:

0.51(93) = 47.43

Answer:

47.43

Step-by-step explanation:

51% of 93

[tex]\frac{51}{100}\times \frac{93}{1}[/tex]

[tex]=\frac{4743}{100\times \:1}[/tex]

[tex]=\frac{4743}{100}[/tex]

Answer:

9.87

Step-by-step explanation:

6%= 0.06

0.06 +6.50 = 6.56

16.43 - 6.50 = 9.87

Answer:

see explanation

Step-by-step explanation:

- 7x = - 105 ( divide both sides by - 7 )

x = 15

A line with equation x = c is a vertical line parallel to the y- axis passing through all points with an x- coordinate of c

Thus x = 15 is a vertical line passing through all points with an x- coordinate of 15

Plot (15, 0 ) , (15, 3 ) and (15, - 3) and join a straight line through them for graph

Answer:

See attachment

Step-by-step explanation:

To write this expression as a positive exponent we use this rule of exponents: xa=1x−a. 5−3=15−−3=153. Use this rule for exponents: xa=1x−a. 5−3=15−−3=153=1125.

Step-by-step explanation:

Are you sure that's the complete question? If yes, there's no valid answer to this question as it's not complete. (Please do comment the full question below  if you have it)

But assuming it's 5^-3 , we can apply the reciprocal law of indices which becomes:

[tex]\frac{1}{5^3}[/tex]

This is our final answer.

The reciprocal indices law states that:

[tex]x^{-n} = \frac{1}{x^n}[/tex]

Hope this helps!

The right choice is: A whole number constant could have been subtracted from the exponential expression.

Let be an exponential function of the form [tex]y = A\cdot e^{B\cdot x}[/tex], where [tex]A[/tex] and [tex]B[/tex] are real numbers. A horizontal asymptote exists when [tex]e^{B\cdot x} \to 0[/tex], which occurs for [tex]B\cdot x \to - \infty[/tex].

For this function, the horizontal asymptote is represented by [tex]y = 0[/tex] and to change the value of the asymptote we must add the parent function by another real number ([tex]C[/tex]), that is to say:

[tex]y = A\cdot e^{B\cdot x} + C[/tex] (1)

In this case, we must use [tex]C = -3[/tex] to obtain an horizontal asymptote of -3. Thus, the right choice is: A whole number constant could have been subtracted from the exponential expression.

To learn more on asymptotes, we kindly invite to check this verified question: https://brainly.com/question/8493280

Answer: C. A whole number constant could have been added to the exponent.

Step-by-step explanation: On Edge!

===================================================

Explanation:

Problem 1

If we had the two vectors u = <a,b> and v = <c,d>, then adding them gives us

u+v = <a+c,b+d>

The corresponding coordinates pair up and add together.

In this case we have

u = <-3,4>

v = <6,8>

So,

u+v = <-3+6,4+8>

u+v = <3,12>

---------------------

Problem 2

We follow the same idea as the previous problem.

w = <8,-1>

g = <-1,1>

w+g = <8+(-1),-1+1>

w+g = <7,0>

---------------------

Problem 3

Similar to addition, subtracting vectors has us subtract the corresponding coordinates.

The general template is:

u = <a,b>

v = <c,d>

u-v = <a-c,b-d>

With this in mind, we can say the following:

g = <-1,1>

z = <-3,-3>

g-z = <-1-(-3),1-(-3)>

g-z = <-1+3,1+3>

g-z = <2,4>

---------------------

Problem 4

Follow the same idea as problem 3 above.

v = <6,8>

u = <-3,4>

v-u = <6-(-3),8-4>

v-u = <6+3,8-4>

v-u = <9,4>

---------------------

Problem 5

Refer to problem 1.

y = <1,1>

v = <6,8>

y+v = <1+6,1+8>

y+v = <7,9>

---------------------

Problem 6

u = <-3,4>

h = v+y = y+v = <7,9>

u+v+y = u + h

u+v+y = <-3,4> + <7,9>

u+v+y = <-3+7,4+9>

u+v+y = <4,13>

Notice how I built off the result of problem 5 when I used h = v+y. The vector v+y is the same as y+v because the order of addition doesn't matter. Also, the idea mentioned in problem 1 can be extended for more than two vectors.

Answer:

1000 ≥ 10.50x + 50

Step-by-step explanation:

≥ is a greater than or equal to sign. We want to know how many she could possibly buy.

Answer: no it doesn’t because -2 doesn’t equal to -6

Step-by-step explanation:

all you have to do is plug 2 for x value and -2 for y

-2= -2(2)+ -2

so -2= -4+ -2 and -4+ -2 is -6

therefor -2 doesn’t equal to -6

Answer:

No, it doesn't pass the vertical line test.

Step-by-step explanation:

Answer:

Step-by-step explanation:

For example, it is more usual to talk about polynomials of degree 6 than to ... Given the polynomials f (x)=3x3 +7x2−5x + 8, g(x) = −x5 + 6x4−2x3+ x−3 ...

The length of side AB from the given coordinate grid is; √20

The formula for distance between two coordinates is;

d = √((y2 - y1)² + (x2 - x1)²)

From the graph attached in the given brainly link, we have;

A(4, 5) and B(2, 1)

Thus;

AB = √((1 - 5)² + (2 - 4)²)

AB = √(16 + 4)

AB = √20

In conclusion, the length of side AB is √20

Read more about Triangle side length at; https://brainly.com/question/3673178

#SPJ1

Answer:

[tex]c=\frac{1}{16}[/tex]

Step-by-step explanation:

[tex]f(x)=\sqrt{2x}[/tex]

[tex]f'(x)=\frac{\sqrt{2x}}{2x}[/tex]

[tex]f'(1)=\frac{\sqrt{2}}{2}[/tex]

[tex]f'(c)=\frac{\sqrt{2c}}{2c}[/tex]

[tex]f'(c)=4f'(1)[/tex]

[tex]\frac{\sqrt{2c}}{2c}=4(\frac{\sqrt{2}}{2})[/tex]

[tex]\frac{\sqrt{2c}}{2c}=2\sqrt{2}[/tex]

[tex]\sqrt{2c}=4c\sqrt{2}[/tex]

[tex]2c=32c^2[/tex]

[tex]2=32c[/tex]

[tex]\frac{1}{16}=c[/tex]

Answer:

[tex]80. \bar{75}[/tex]

Answer:

Step-by-step explanation:

Portf?

Answer:

the initial height of water.

Step-by-step explanation:

when time equals zero, no water has been drained.

the volume of the tank is unknown however the volume in the tank is 12 at time zero

Answer:

1/4

Step-by-step explanation:

We know two points on the line so we can use the slope formula

(0,6) and (8,8)

m = ( y2-y1)/(x2-x1)

   = (8-6)/(8-0)

   = 2/8

   = 1/4

Answer:

1/4

Step-by-step explanation:

slope=rise/run=1/4

Answer:

C. (3, -1) is a solution

Step-by-step explanation:

It is inside in the double shaded area.

Answer:

[tex]9\frac{57}{63}[/tex]

Step-by-step explanation:

First, we need to turn them into improper fractions:

[tex]2\frac{4}{7}[/tex] + [tex]7\frac{3}{9}[/tex]

7 x 2 + 4

7 x 9 + 3

[tex]\frac{18}{7}[/tex] + [tex]\frac{66}{9}[/tex]

Next, we need to find a common multiple of both 7 and 9

7, 14, 21, 28, 35, 42, 49, 56, 63

9, 18, 27, 36, 45, 54, 63

So the denomonator turns into 63.

We've multiplied the denomonater 9 times for the first fraction and 7 times for the second fraction, we therefore have to do the same to the numerator.

18 x 9 = 162

66 x 7 = 462

[tex]\frac{162}{63}[/tex] + [tex]\frac{462}{63}[/tex] = [tex]\frac{624}{63}[/tex]

Next, we have to turn it back into a mixed number.

To work it out: 624 / 63 = 9 (1 s.f) <--- Mixed number.

9 x 63 = 567

624 - 567 = 57 (Working out the remainder.)

Combining them, the answer is therefore [tex]9\frac{57}{63}[/tex]

Hope this helps and have a good day!

i dont understand

what do we need to do?